Trying to figure out how to fetch two related models(obviously united) of my Many To Many(Polymorphic) relationship.
What we have:
3 models: Bucket, Template and DesignPack.
Bucket has Many-To-Many(Polymorphic) relationship with Template and DesignPack(It means we have pivot table bucketables).In essence Bucket can have(be related with) both: Template and DesignPack.
Laravel 6.*
What I want to get:
I want to get a Bucket templates and design packs united in one collection and paginated!
Please check one of the solutions I've tried:
$templates = Bucket::find($bucket_id)->templates()->select(['id', 'file_name as name', 'size', 'preview']);
$design_packs = Bucket::find($bucket_id)->dps()->select(['id', 'name', 'size', 'preview']);
$all = $templates ->union($design_packs )->paginate(10);
Unfortunately that solution throws me the error(thought I checked what each request returns and it returns the same fields, not different):
"SQLSTATE[21000]: Cardinality violation: 1222 The used SELECT statements have a different number of columns (SQL: (select `id`, `size`, `preview`, `bucketables`.`bucket_id` as `pivot_bucket_id`, `bucketables`.`bucketable_id` as `pivot_bucketable_id`, `bucketables`.`bucketable_type` as `pivot_bucketable_type` from `design_packs` inner join `bucketables` on `design_packs`.`id` = `bucketables`.`bucketable_id` where `bucketables`.`bucket_id` = 3 and `bucketables`.`bucketable_type` = App\DesignPack and `design_packs`.`deleted_at` is null) union (select `id`, `size`, `preview` from `templates` inner join `bucketables` on `templates`.`id` = `bucketables`.`bucketable_id` where `bucketables`.`bucket_id` = 3 and `bucketables`.`bucketable_type` = App\Template and `templates`.`deleted_at` is null))"
Are there any different way to get what I want?
May be examples, documentation links or any helpful ideas?
Will be so grateful guys for any help!
Thank you!
You can pass closure to queries:
$templates = Bucket::whereHas('templates', function($query) use $bucket_id {
$query->where('bucket_id', $bucket_id);
})->get();
$designPacks = Bucket::whereHas('dps', function($query) use $bucket_id {
$query->where('bucket_id', $bucket_id);
})->get();
then merge 2 eloquent collections:
$mergedCollections = $templates->merge($designPacks);
now you have a collection of both results, you can select specific fields, limit the results or etc. you may want take a look at Laravel collection helpers.
also if you insist to use the union, you may want to take a look at this treat:
The used SELECT statements have a different number of columns (REDUX!!)
Related
I have something like this:
Table 1: Training Name, created_at, user_id (Plan_Treninga)
Table 2: user_id, created_at, expire_at (InvoiceUser)
I want to pull all from Table 1 where created_at is between Table 2 created_at and expire_at.
This is something what i am trying to..
$plan = Plan_Treninga::whereBetween(function($q) use ($id){
$inv = InvoiceUser::where([
["user_id",$id],
["status","paid"],
])->latest("id")->first();
})
I haven't finished it yet, but my brain stopped working so I have to ask here.
If I understand what you want clearly is. you want to query all from table 1 which created exist between table 2 created and expire_at right? if so you can use where exist query to achieve this.
// assume your table name is plan_treningas & invoice_users
Plan_Treninga::whereExists(function ($query) {
$query->select(DB::raw(1))
->from('invoice_users')
->whereRaw('plan_treningas.created_at BETWEEN invoice_users.created_at AND invoice_users.expire_at'); // add more query depend your logic
})->get();
for more you can take a look at docs
or if you want to use raw query
SELECT
*
FROM plan_treningas
WHERE EXISTS (
SELECT 1 FROM invoice_users WHERE plan_treningas.created_at BETWEEN invoice_users.created_at AND invoice_users.expire_at
)
Take a look at joins https://laravel.com/docs/7.x/queries#joins
I am not saying this is the exact solution but I have something similar that I have changed to point you in the right direction.
With joins you can do lots of things.
$results = DB::table('table1')
->join('table2', function ($join) {
$join->on('table1.user_id', '=', 'table2.user_id')
->where('table2.status', '=', 'paid')
->where('table2.created_at', '>', 'table1.created_at');
})
->get();
Also look at relationships. There is some good answers for setting up many to many relationships.
https://laravel.com/docs/7.x/eloquent-relationships#many-to-many
in sql query this commando do exactly i wanted:
SELECT
v.id,
(
SELECT sv.status_id
FROM status_viagem sv
WHERE sv.viagem_id = v.id
ORDER BY sv.created_at DESC LIMIT 1 ) AS status_id
FROM viagens v
Here is the sql results:
But i have no idea how can i do this using Laravel eloquent
Basically, a viagem entry can has a lot of status, but i need to get each viagem and their last status entry from status_viagem table (the pivot table)
by the way viagem/viagens means travel.
My class mapping:
class Viagem extends Model
{
...
public function status()
{
return $this->belongsToMany('App\Status')->withTimestamps();
}
...
}
class Status extends Model
{
public function viagens()
{
return $this->belongsToMany('App\Viagem')->withTimestamps();
}
}
The belongsToMany at both classes gets me a many-to-many:
can someone help me? thanks
---------- Temporary Solution -------
Thanks for all help guys. In fact i can't find a nice solution using only eloquent.
Step 1/3 - To bypass this situation i first execute the above sql to grab only the viagens under the desired status_id (last status_viagem entry):
$viagens_ids = DB::select(
"SELECT viagem_id FROM (
SELECT
v.id AS viagem_id,
(
SELECT sv.status_id
FROM status_viagem sv
WHERE sv.viagem_id = v.id
ORDER BY sv.id DESC LIMIT 1 ) AS status_id
FROM viagens v
) AS tt
WHERE tt.status_id = {$status->id}"
);
Step 2/3 - then i used the array_map to organize my viagens ids
$a = array_map(
function($obj) { return $obj->viagem_id; },
$viagens_ids
);
Step 3/3 - And at last i used elequent whereIn to fetch my viagens:
Viagem::with( 'status')->whereIn('id', $a)->get();
In fact i have solved the problem by a-old-sashion-way but i not happy with it because i wish i learn how to do it using eloquent. what bad to me.
There are many ways to query in laravel. I have created a test project for you to try. The gist are:
1. Eloquent ORM
Eloquent ORM is Laravel's magic which have some limitations in eager loading - which i just come across while contemplating your question for hours. It wont play nicely with first(), last(), and some more functions in the constrained eager loading closure.
In your case, our almost there can be fixed:
App\Models\Viagem::with(['status' => function($query){
return $query->orderBy('pivot_created_at', 'desc');
}])
->get()
It will return entire field for Viagem and Status including its pivot table (the status_viagem).
However, if you wanted to retrieve only viagem.id and status_viagem.status_id, you can map() it as such:
App\Models\Viagem::with(['status' => function($query){
return $query->orderBy('pivot_created_at', 'desc');
}])
->get()
->map(function($data){
$o = new stdClass();
$o->id = $data->id;
$o->status_id = $data->status->first()->id;
return $o;
});
Please take note that the statement above require sql query to be ran twice. Eager loading basically works by querying all the Viagem first then queries the Status and map them in memory based on the foreign keys. You can observe that replacing get with toSql will only give you the first query. Please enable Query Logging to see the second query.
2. Query Builder
Embarking from Ryan Adhitama Putra answer, you could do something like:
App\Models\Viagem::join('status_viagem', 'viagens.id', '=', 'status_viagem.viagem_id')
->orderBy('status_viagem.created_at', 'desc')
->groupBy(['status_viagem.status_id', 'viagens.id'])
->select(['viagens.id', 'status_viagem.status_id'])
->get();
This query builder approach guaranteed to be ran only once, you can replace the get() with toSql() to see the resulting query.
3. Raw Queries
Throwing DB::raw() can help sometime, but i really did not want to mention it.
I am not sure what viagens and viagem represent, but I think one of the relationships has to be belongsToMany() and the other hasMany().
then after you set relationships correctly, you can use Eloquent like this :
$status_id = Viagem::with('status')->orderBy('created_at', 'desc')->first()->pluck('status_id');
Try this.
$status_id = Viagem::join('status','viagem.id','status_viagem.viagem_id')
->select('viagem.id','status_viagem.status_id')
->get();
Faced a really strange error and can't understand why it's happening. Please see the explanation below to understand the issue!
What I have:
3 models: Bucket, Template and DesignPack.
Bucket has Many-To-Many(Polymorphic) relationship with Template and DesignPack(It means we have pivot table bucketables).
In essence Bucket can have(be related with) both: Template and DesignPack.
Laravel 6.*
What I want to do:
I want to get all Bucket's Template and DesignPack models merged(using union) with specific columns only. Want to get it with pagination also off course as we can have too many items :)
What I did:
I tried a few solutions but none of the worked, had the same errors. Please see example below what I've tried:
$templates = Bucket::find($bucket_id)->templates()->select('id', 'file_name as name', 'size', 'preview');
$design_packs = Bucket::find($bucket_id)->dps()->select('id', 'name', 'size', 'preview');
$bt_uploads = $templates->union($design_packs)->paginate(20);
return UserUploadResource::collection($bt_uploads);
The error I get constantly is:
"SQLSTATE[21000]: Cardinality violation: 1222 The used SELECT
statements have a different number of columns (SQL: select count() as
aggregate from ((select id, file_name as name, size,
preview, templates., bucketables.bucket_id as
pivot_bucket_id, bucketables.bucketable_id as
pivot_bucketable_id, bucketables.bucketable_type as
pivot_bucketable_type from templates inner join bucketables on
templates.id = bucketables.bucketable_id where
bucketables.bucket_id = 3 and bucketables.bucketable_type =
App\Template and templates.deleted_at is null) union (select id,
name, size, preview from design_packs inner join bucketables
on design_packs.id = bucketables.bucketable_id where
bucketables.bucket_id = 3 and bucketables.bucketable_type =
App\DesignPack and design_packs.deleted_at is null)) as
temp_table)"
Many thanks guys for any help and ideas!
I have the following query:
$items = UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->get();
I need to order it by item.type so I tried:
$items = UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy('item.type')
->get();
but I get Unknown column 'item.type' in 'order clause'
What I am missing?
join() worked fine thanks to #rypskar comment
$items = UserItems
::where('user_id','=',$this->id)
->where('quantity','>',0)
->join('items', 'items.id', '=', 'user_items.item_id')
->orderBy('items.type')
->select('user_items.*') //see PS:
->get();
PS: To avoid the id attribute (or any shared name attribute between the two tables) to overlap and resulting in the wrong value, you should specify the select limit with select('user_items.*').
Well, your eager loading is probably not building the query you're expecting, and you can check it by enabling the query log.
But I would probably just use a collection filter:
$items = UserItems::where('user_id','=',$this->id)
->where('quantity','>',0)
->get()
->sortBy(function($useritem, $key) {
return $useritem->item->type;
});
You can use withAggregate function to solve your problem
UserItems::withAggregate('item','type')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy('item_type')
->get();
I know it's an old question, but you can still use an
"orderByRaw" without a join.
$items = UserItems
::where('user_id','=',$this->id)
->where('quantity','>',0)
->orderByRaw('(SELECT type FROM items WHERE items.id = user_items.item_id)')
->get();
For a one to many relationship, there is an easier way. Let's say an order has many payments and we want to sort orders by the latest payment date. Payments table has a field called order_id which is FK.
We can write it like below
$orders = Order->orderByDesc(Payment::select('payments.date')->whereColumn('payments.order_id', 'orders.id')->latest()->take(1))->get()
SQL Equivalent of this code:
select * from orders order by (
select date
from payments
where order_id = payments.id
order by date desc
limit 1
) desc
You can adapt it according to your example. If I understood right, order's equivalent is user and payment's equivalent is item in your situation.
Further reading
https://reinink.ca/articles/ordering-database-queries-by-relationship-columns-in-laravel
I found another way of sorting a dataset using a field from a related model, you can get a function in the model that gets a unique relation to the related table(ex: table room related to room category, and the room is related to a category by category id, you can have a function like 'room_category' which returns the related category based on the category id of the Room Model) and after that the code will be the following:
Room::with('room_category')->all()->sortBy('room_category.name',SORT_REGULAR,false);
This will get you the rooms sorted by category name
I did this on a project where i had a DataTable with Server side processing and i had a case where it was required to sort by a field of a related entity, i did it like this and it works. More easier, more proper to MVC standards.
In your case it will be in a similar fashion:
User::with('item')->where('quantity','>',0)->get()->sortBy('item.type',SORT_REGULAR,false);
$users
->whereRole($role)
->join('address', 'users.id', '=', 'address.user_id')
->orderByRaw("address.email $sortType")
->select('users.*')
you can simply do it by
UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy(
Item::select('type')
->whereColumn('items.useritem_id','useritems.id')
->take(1),'desc'
)
->get();
Hi i have tables with one to many relation
sectors
id
name
position
seat_plans
id
name
sector_id
I just want to select all seat plans order by sectors.position. I tried
$seat_plans = SeatPlan::with(['sector' => function($q){
$q->orderBy('position');
}
])->get();
but it is not working. when i check The SQL it is generating query like
select * from seat_plans
can anybody please tell me how to do this?
I don't think you need a custom function for your use case. Instead try this:
$users = DB::table('seat_plans')
->join('sectors', 'seat_plans.sector_id, '=', 'sectors.id')
->select('seat_plans.*')
->orderBy('sectors.position')
->get();