Hi i have tables with one to many relation
sectors
id
name
position
seat_plans
id
name
sector_id
I just want to select all seat plans order by sectors.position. I tried
$seat_plans = SeatPlan::with(['sector' => function($q){
$q->orderBy('position');
}
])->get();
but it is not working. when i check The SQL it is generating query like
select * from seat_plans
can anybody please tell me how to do this?
I don't think you need a custom function for your use case. Instead try this:
$users = DB::table('seat_plans')
->join('sectors', 'seat_plans.sector_id, '=', 'sectors.id')
->select('seat_plans.*')
->orderBy('sectors.position')
->get();
Related
I have something like this:
Table 1: Training Name, created_at, user_id (Plan_Treninga)
Table 2: user_id, created_at, expire_at (InvoiceUser)
I want to pull all from Table 1 where created_at is between Table 2 created_at and expire_at.
This is something what i am trying to..
$plan = Plan_Treninga::whereBetween(function($q) use ($id){
$inv = InvoiceUser::where([
["user_id",$id],
["status","paid"],
])->latest("id")->first();
})
I haven't finished it yet, but my brain stopped working so I have to ask here.
If I understand what you want clearly is. you want to query all from table 1 which created exist between table 2 created and expire_at right? if so you can use where exist query to achieve this.
// assume your table name is plan_treningas & invoice_users
Plan_Treninga::whereExists(function ($query) {
$query->select(DB::raw(1))
->from('invoice_users')
->whereRaw('plan_treningas.created_at BETWEEN invoice_users.created_at AND invoice_users.expire_at'); // add more query depend your logic
})->get();
for more you can take a look at docs
or if you want to use raw query
SELECT
*
FROM plan_treningas
WHERE EXISTS (
SELECT 1 FROM invoice_users WHERE plan_treningas.created_at BETWEEN invoice_users.created_at AND invoice_users.expire_at
)
Take a look at joins https://laravel.com/docs/7.x/queries#joins
I am not saying this is the exact solution but I have something similar that I have changed to point you in the right direction.
With joins you can do lots of things.
$results = DB::table('table1')
->join('table2', function ($join) {
$join->on('table1.user_id', '=', 'table2.user_id')
->where('table2.status', '=', 'paid')
->where('table2.created_at', '>', 'table1.created_at');
})
->get();
Also look at relationships. There is some good answers for setting up many to many relationships.
https://laravel.com/docs/7.x/eloquent-relationships#many-to-many
I have two tables in my database
My first table
And my second table
I would like to count how many gold members exists and how many silver members exists... I want to do a single count for each category... The rif can be repeated in the column but is the key to join the two tables.. I'm working with Query Builder and I would like to continue work with that. Someone can help me?
I tried with this code but didn't work
$count = DB::table('table1')
->join('table2', 'table1.rif', '=', 'table2.rif')
->select(DB::raw('category')
->count();
Try this:
use Illuminate\Support\Facades\DB;
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->select(DB::raw('count(*) as count'), 'table1.category as category')
->groupBy('category')
->get();
If you want to count only a specific category:
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->where('table1.category', 'Silver')
->count()
See Laravel docs for more info.
I have two database tables items and measurement_units - item has measurement unit.
Now the problem is I want to select a particular column from items and some column from measurement_unit. I want to use Eager loading
e.g.
$items_with_mu = Item::with("measurement_unit")->select(["item_name", "item_stock"])->first();
When accessing measurement_unit. It returns null. Without the select function it returns data(measurement_unit).
$items_with_mu->measurement_unit;
can anyone help me and sorry for my English.
Try this
Item::with(['measurement_unit' => function($q) {
$q->select('id','unit_column'); //specified measurement_unit column
}])
->select('id','measurement_unit_id','item_name')
->get();
If your laravel version is >=5.5 then you can write in a single line
Item::with('measurement_unit:id,unit_column')
->select('id','measurement_unit_id','item_name')
->get()
You have to select the primary column of the main model like below.
items_with_mu = Item::with("measurement_unit")->select(["item_name", "item_stock", "primary_key"])->first();
I have the following query:
$items = UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->get();
I need to order it by item.type so I tried:
$items = UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy('item.type')
->get();
but I get Unknown column 'item.type' in 'order clause'
What I am missing?
join() worked fine thanks to #rypskar comment
$items = UserItems
::where('user_id','=',$this->id)
->where('quantity','>',0)
->join('items', 'items.id', '=', 'user_items.item_id')
->orderBy('items.type')
->select('user_items.*') //see PS:
->get();
PS: To avoid the id attribute (or any shared name attribute between the two tables) to overlap and resulting in the wrong value, you should specify the select limit with select('user_items.*').
Well, your eager loading is probably not building the query you're expecting, and you can check it by enabling the query log.
But I would probably just use a collection filter:
$items = UserItems::where('user_id','=',$this->id)
->where('quantity','>',0)
->get()
->sortBy(function($useritem, $key) {
return $useritem->item->type;
});
You can use withAggregate function to solve your problem
UserItems::withAggregate('item','type')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy('item_type')
->get();
I know it's an old question, but you can still use an
"orderByRaw" without a join.
$items = UserItems
::where('user_id','=',$this->id)
->where('quantity','>',0)
->orderByRaw('(SELECT type FROM items WHERE items.id = user_items.item_id)')
->get();
For a one to many relationship, there is an easier way. Let's say an order has many payments and we want to sort orders by the latest payment date. Payments table has a field called order_id which is FK.
We can write it like below
$orders = Order->orderByDesc(Payment::select('payments.date')->whereColumn('payments.order_id', 'orders.id')->latest()->take(1))->get()
SQL Equivalent of this code:
select * from orders order by (
select date
from payments
where order_id = payments.id
order by date desc
limit 1
) desc
You can adapt it according to your example. If I understood right, order's equivalent is user and payment's equivalent is item in your situation.
Further reading
https://reinink.ca/articles/ordering-database-queries-by-relationship-columns-in-laravel
I found another way of sorting a dataset using a field from a related model, you can get a function in the model that gets a unique relation to the related table(ex: table room related to room category, and the room is related to a category by category id, you can have a function like 'room_category' which returns the related category based on the category id of the Room Model) and after that the code will be the following:
Room::with('room_category')->all()->sortBy('room_category.name',SORT_REGULAR,false);
This will get you the rooms sorted by category name
I did this on a project where i had a DataTable with Server side processing and i had a case where it was required to sort by a field of a related entity, i did it like this and it works. More easier, more proper to MVC standards.
In your case it will be in a similar fashion:
User::with('item')->where('quantity','>',0)->get()->sortBy('item.type',SORT_REGULAR,false);
$users
->whereRole($role)
->join('address', 'users.id', '=', 'address.user_id')
->orderByRaw("address.email $sortType")
->select('users.*')
you can simply do it by
UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy(
Item::select('type')
->whereColumn('items.useritem_id','useritems.id')
->take(1),'desc'
)
->get();
I have an eloquent query where I am not getting the expected results and I was hoping someone could explain to me what the correct way to write the query.
I have three tables:
records (belongsToMany users)
users (belongsToMany records)
record_user (pivot)
The record_user table also has a column for role.
I attempt to get all the records where the user has the role of either singer or songwriter:
$results = User::find(Auth::user()->id)
->records()
->wherePivot('role', 'singer')
->orWherePivot('role', 'songwriter')
->get();
Below is how the SQL syntax is generated:
select `records`.*, `record_user`.`user_id` as `pivot_user_id`,
`record_user`.`record_id` as `pivot_record_id` from `records`
inner join `record_user` on `records`.`id` = `record_user`.`property_id`
where
`record_user`.`user_id` = '1' and `record_user`.`role` = 'singer' or
`record_user`.`role` = 'songwriter'
The results for singer role are what is expected: All records where the user is the singer. The problem is the results for the songwriter: I am getting ALL songwriters and the query is not constrained by the user_id. For some reason I was expecting the songwriter role to also be constrained by the user_id - what is the correct way to write this using the eloquent syntax?
Hmm..I think you need to use an advanced where clause.
$results = Auth::user()
->records()
->where(function($query) {
$query->where('record_user.role', '=', 'singer')
->orWhere('record_user.role', '=', 'songwriter');
})
->get();
It is Laravel issue. In my case I solve it like this:
$results = Auth::user()
->records()
->wherePivot('role', 'singer')
->orWherePivot('role', 'songwriter')
->where('user_id', Auth::id())
->get();
Or use advance where clause
If your trying to get records I would do something similar to this:
User::find(Auth::user()->id)
->records()
->where(function($q){
$q->where('records.role', 'singer')
->orWhere('records.role', 'songwriter');
})->get();