I have something like this:
Table 1: Training Name, created_at, user_id (Plan_Treninga)
Table 2: user_id, created_at, expire_at (InvoiceUser)
I want to pull all from Table 1 where created_at is between Table 2 created_at and expire_at.
This is something what i am trying to..
$plan = Plan_Treninga::whereBetween(function($q) use ($id){
$inv = InvoiceUser::where([
["user_id",$id],
["status","paid"],
])->latest("id")->first();
})
I haven't finished it yet, but my brain stopped working so I have to ask here.
If I understand what you want clearly is. you want to query all from table 1 which created exist between table 2 created and expire_at right? if so you can use where exist query to achieve this.
// assume your table name is plan_treningas & invoice_users
Plan_Treninga::whereExists(function ($query) {
$query->select(DB::raw(1))
->from('invoice_users')
->whereRaw('plan_treningas.created_at BETWEEN invoice_users.created_at AND invoice_users.expire_at'); // add more query depend your logic
})->get();
for more you can take a look at docs
or if you want to use raw query
SELECT
*
FROM plan_treningas
WHERE EXISTS (
SELECT 1 FROM invoice_users WHERE plan_treningas.created_at BETWEEN invoice_users.created_at AND invoice_users.expire_at
)
Take a look at joins https://laravel.com/docs/7.x/queries#joins
I am not saying this is the exact solution but I have something similar that I have changed to point you in the right direction.
With joins you can do lots of things.
$results = DB::table('table1')
->join('table2', function ($join) {
$join->on('table1.user_id', '=', 'table2.user_id')
->where('table2.status', '=', 'paid')
->where('table2.created_at', '>', 'table1.created_at');
})
->get();
Also look at relationships. There is some good answers for setting up many to many relationships.
https://laravel.com/docs/7.x/eloquent-relationships#many-to-many
Related
in sql query this commando do exactly i wanted:
SELECT
v.id,
(
SELECT sv.status_id
FROM status_viagem sv
WHERE sv.viagem_id = v.id
ORDER BY sv.created_at DESC LIMIT 1 ) AS status_id
FROM viagens v
Here is the sql results:
But i have no idea how can i do this using Laravel eloquent
Basically, a viagem entry can has a lot of status, but i need to get each viagem and their last status entry from status_viagem table (the pivot table)
by the way viagem/viagens means travel.
My class mapping:
class Viagem extends Model
{
...
public function status()
{
return $this->belongsToMany('App\Status')->withTimestamps();
}
...
}
class Status extends Model
{
public function viagens()
{
return $this->belongsToMany('App\Viagem')->withTimestamps();
}
}
The belongsToMany at both classes gets me a many-to-many:
can someone help me? thanks
---------- Temporary Solution -------
Thanks for all help guys. In fact i can't find a nice solution using only eloquent.
Step 1/3 - To bypass this situation i first execute the above sql to grab only the viagens under the desired status_id (last status_viagem entry):
$viagens_ids = DB::select(
"SELECT viagem_id FROM (
SELECT
v.id AS viagem_id,
(
SELECT sv.status_id
FROM status_viagem sv
WHERE sv.viagem_id = v.id
ORDER BY sv.id DESC LIMIT 1 ) AS status_id
FROM viagens v
) AS tt
WHERE tt.status_id = {$status->id}"
);
Step 2/3 - then i used the array_map to organize my viagens ids
$a = array_map(
function($obj) { return $obj->viagem_id; },
$viagens_ids
);
Step 3/3 - And at last i used elequent whereIn to fetch my viagens:
Viagem::with( 'status')->whereIn('id', $a)->get();
In fact i have solved the problem by a-old-sashion-way but i not happy with it because i wish i learn how to do it using eloquent. what bad to me.
There are many ways to query in laravel. I have created a test project for you to try. The gist are:
1. Eloquent ORM
Eloquent ORM is Laravel's magic which have some limitations in eager loading - which i just come across while contemplating your question for hours. It wont play nicely with first(), last(), and some more functions in the constrained eager loading closure.
In your case, our almost there can be fixed:
App\Models\Viagem::with(['status' => function($query){
return $query->orderBy('pivot_created_at', 'desc');
}])
->get()
It will return entire field for Viagem and Status including its pivot table (the status_viagem).
However, if you wanted to retrieve only viagem.id and status_viagem.status_id, you can map() it as such:
App\Models\Viagem::with(['status' => function($query){
return $query->orderBy('pivot_created_at', 'desc');
}])
->get()
->map(function($data){
$o = new stdClass();
$o->id = $data->id;
$o->status_id = $data->status->first()->id;
return $o;
});
Please take note that the statement above require sql query to be ran twice. Eager loading basically works by querying all the Viagem first then queries the Status and map them in memory based on the foreign keys. You can observe that replacing get with toSql will only give you the first query. Please enable Query Logging to see the second query.
2. Query Builder
Embarking from Ryan Adhitama Putra answer, you could do something like:
App\Models\Viagem::join('status_viagem', 'viagens.id', '=', 'status_viagem.viagem_id')
->orderBy('status_viagem.created_at', 'desc')
->groupBy(['status_viagem.status_id', 'viagens.id'])
->select(['viagens.id', 'status_viagem.status_id'])
->get();
This query builder approach guaranteed to be ran only once, you can replace the get() with toSql() to see the resulting query.
3. Raw Queries
Throwing DB::raw() can help sometime, but i really did not want to mention it.
I am not sure what viagens and viagem represent, but I think one of the relationships has to be belongsToMany() and the other hasMany().
then after you set relationships correctly, you can use Eloquent like this :
$status_id = Viagem::with('status')->orderBy('created_at', 'desc')->first()->pluck('status_id');
Try this.
$status_id = Viagem::join('status','viagem.id','status_viagem.viagem_id')
->select('viagem.id','status_viagem.status_id')
->get();
I have two tables in my database
My first table
And my second table
I would like to count how many gold members exists and how many silver members exists... I want to do a single count for each category... The rif can be repeated in the column but is the key to join the two tables.. I'm working with Query Builder and I would like to continue work with that. Someone can help me?
I tried with this code but didn't work
$count = DB::table('table1')
->join('table2', 'table1.rif', '=', 'table2.rif')
->select(DB::raw('category')
->count();
Try this:
use Illuminate\Support\Facades\DB;
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->select(DB::raw('count(*) as count'), 'table1.category as category')
->groupBy('category')
->get();
If you want to count only a specific category:
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->where('table1.category', 'Silver')
->count()
See Laravel docs for more info.
I have two tables, one called companies and one called leads. Using Laravel's Eloquent I'd like to get a count of leads for each company. Which is pretty straight forward, but I also need to group these by the Leads status.
e.g.
Company A has
3 hot leads
2 cold leads
Company B has
6 cold leads
0 hot leads
Companies table has the following structure:
id
name
Leads table has the following structure
id
company_id
status (hot, cold)
I have tried the following, which gets the count of leads out for each company, but this needs to be further grouped by the status of the leads
DB::table('companies')
->selectRaw('companies.id, companies.name, COUNT(*) as count')
->join('leads', 'leads.company_id', '=', 'companies.id')
->groupBy('id')
->get();
When using aggregates such as count, you need to make sure to group by all selected non-aggregate columns.
MySQL will usually let you get away with out doing this but the query results can come out being non-sensical.
$companies = DB::table('companies')
->select(['companies.name', 'leads.status', \DB::raw('COUNT(*) as count')])
->join('leads', 'leads.company_id', '=', 'companies.id')
->groupBy('companies.name', 'leads.status')
->get();
If you have multiple records in the companies table with the same name (but different ids), this will group all the counts together for each duplicate company name. If that's the case, you should also select and group by companies.id as well.
If you want to key this by the company, and then by the status, the following should work...
$companies = $companies->groupBy('name')->map(function ($company) {
return $company->groupBy('status')->map(function ($company) {
return $company->first()['count'];
});
});
Then you can use it like...
echo $companies['testCompanyName']['hot'];
echo $companies['testCompanyName']['cold'];
Hi i have tables with one to many relation
sectors
id
name
position
seat_plans
id
name
sector_id
I just want to select all seat plans order by sectors.position. I tried
$seat_plans = SeatPlan::with(['sector' => function($q){
$q->orderBy('position');
}
])->get();
but it is not working. when i check The SQL it is generating query like
select * from seat_plans
can anybody please tell me how to do this?
I don't think you need a custom function for your use case. Instead try this:
$users = DB::table('seat_plans')
->join('sectors', 'seat_plans.sector_id, '=', 'sectors.id')
->select('seat_plans.*')
->orderBy('sectors.position')
->get();
Some help with many to many relationships in Laravel:
Using the example for roles and users - basically:
a table for all the roles
a table for the users
and table with user_id and role_id.
I want to add to the third table, eg Year. basically the pivot table will have user_id, role_id and year_id.
I want to be able to make a query to pull for example all users assigned a specific role in a specific year. Eg All users with role_id = 2, and year_id = 1.
Any help will be appreciated
Before answering, I would like to suggest you not to put year on database like this.
All your tables should have created_at and updated_at which should be enough for that.
To filter users like you want. You could do this:
// This queries all users that were assigned to 'admin' role within 2013.
User::join('role_users', 'role_users.user_id', '=', 'users.id')
->join('roles', 'roles.id', '=', 'role_users.role_id')
->where('roles.name', '=', 'admin')
->where(DB::raw('YEAR(role_users.created_at)', '=', '2013')
->get();
This example may not be the precise query you are looking for, but should be enough for you to come up with it.
The best way to achieve a three way relation with Eloquent is to create a model for the table representing this relation. Pivot tables is meant to be used for two way relations.
You could have then a table called roles_users_year which could have data related to this 3 way relation like a timestamp or whatever...
A very late answer to a very old question, but Laravel has supported additional intermediate (pivot) table columns of at least Laravel 5.1 judging from the documentation, which hasn't changed at least through Laravel 6.x.
You can describe these extra columns when defining your many-to-many relationship:
return $this->belongsToMany(Role::class)->withPivot('column1', 'column2');
or in your case, the below would also do the job:
return $this->belongsToMany(Role::class)->withTimestamps();
which you can then access via the pivot attribute on your model:
$user = User::find(1);
foreach ($user->roles as $role) {
echo $role->pivot->created_at;
}
Note that the pivot attribute is on the distant relationship model (a single Role) and not on the relationship itself.
To get all the Roles assigned to Users in any given year, you might create a special relationship:
// User.php
public function rolesInYear($year) {
return $this->belongsToMany(Role::class)
->wherePivot('created_at', '>=', Carbon::create($year))
->wherePivot('created_at', '<', Carbon::create($year + 1));
}