I am trying to build some simulation software using makefile provided by them after I have made some changes to the libraries. But when I run make clean, it stops midway and I get the following error
rm: invalid option -- 'l'
Try `rm --help' for more information.
make: *** [neat] Error 1
I checked the man page for rm and there is no -l option, but I don't know why this command is being executed with -l option. Is there anyway to ignore this, or find out which specific file is causing the problem?
EDIT:
I have figured out the source of the error, but dont know how to edit it to make it work properly. Below is a snippet from an included Makefile with the faulty line:
UDP_INTERFACE_SRCS = \
$(UDP_INTERFACE_DIR)/interfaceudp_app.cpp \
$(UDP_INTERFACE_DIR)/interfaceudp.cpp \
$(UDP_INTERFACE_DIR)/external_interface_udp.cpp \
$(UDP_INTERFACE_DIR)/packet_send.cpp \
$(UDP_INTERFACE_DIR)/addr.cpp \
$(UDP_INTERFACE_DIR)/packet_capture.cpp -lpcap \
$(UDP_INTERFACE_DIR)/queue.cpp
In particular, the line: $(UDP_INTERFACE_DIR)/packet_capture.cpp -lpcap \
is causing the error. What does the "-lpcap" added after "packet_capture.cpp" do? Now if I try to remove it, "make" gives an error saying:
./interfaces/extinterface/src/packet_capture.o: In function pcap_sniff_packets(void*)': /home/qualnet/4.5/main/../interfaces/extinterface/src/packet_capture.cpp:63: undefined reference to pcap_setdirection' make: *** [../bin/qualnet] Error 1
I checked the line number 63 in packet_capture.cpp in an effort to understand what -lpcap means. But I have no idea what that code does.
(This is clearly an iterative process, and the comments are getting long, so I'd better start an answer.)
You say: "When I put echo SIM_JOBS: $(SIM_OBJS) in the rule, i get the following when i run make clean: rm -f ../bin/qualnet ../bin/radio_range"
This doesn't make sense. You should get something like
SIM_JOBS: ../bin/qualnet ../bin/radio_range
rm -f ../bin/qualnet ../bin/radio_range
or
SIM_JOBS: something/else
rm -f ../bin/qualnet ../bin/radio_range
or at least
SIM_JOBS:
rm -f ../bin/qualnet ../bin/radio_range
This suggests that you are looking at the wrong rule: the rule which produces rm -f ../bin/qualnet ../bin/radio_range is not the rule in which you put the echo ... command. If it is the rule and you were just being imprecise in the report, put this right above the clean rule:
SIM_JOBS=../bin/qualnet ../bin/radio_range
and tell us what happens.
EDIT:
Sorry, I wrote `SIM_JOBS` when I meant `SIM_OBJS`.
The `echo` command was outside the rule, where it cannot work.
It looks as if the problem. Could you edit your question to show the line you mentioned to #thiton, and a few previous lines? It looks as if the flag "-lpcap" is getting into a variable, where it doesn't belong.
EDIT:
The "-lpcap" is a kludge. My guess is that it's an option intended for the linker. Suppose you want to link a bunch of object files into an executable, and you want to search a certain library called "pcap":
gcc foo.o -lpcap bar.o baz.o
The order is very important; when the linker is searching for something, you want it to search foo.o first, then pcap, then bar, then baz. It's a question of precedence. But you want to store those filenames in a nice tidy variable, and how will you insert the lpcap at the right place? You could do it a good way, or use a lazy hack like this:
OBJECTS = foo.o -lpcap bar.o baz.o
gcc $(OBJECTS)
And if you're deducing the OBJECTS from the SOURCES, you have to put the hack in earlier:
SOURCES = foo.cc -lpcap bar.cc baz.cc
OBJECTS = $(SOURCES:.cc=.o)
Whoever wrote these makefiles saved half an hour with this kludge, and it's taking you days to fix it. If you can confirm that this is what's happening, the easiest way is probably to split the list in two:
SOURCES_LEFT = foo.cc
SOURCES_RIGHT = bar.cc baz.cc
OBJECTS_LEFT = $(SOURCES_LEFT:.cc=.o)
OBJECTS_RIGHT = $(SOURCES_RIGHT:.cc=.o)
gcc $(OBJECTS_LEFT) -lcap $(OBJECTS_RIGHT)
Like #AndrejPanjkov noted in the comments, the standard tool to find out what exactly is going on in Makefiles is the -n (--dry-run) switch of make. It prints all commands as they would be run by the shell, even those normally silenced (e.g. via #).
Have a long, hard look in this output for any pattern like ' -l' (piping the output to less and using / helps). If that doesn't help, try running all commands output by -n by hand in make's shell (normally /bin/sh) or try removing all the silencers (# characters at a rule's start) from the Makefile and running make clean, checking the last line of output.
Related
In a makefile I use there is #-, that is not mentioned in any makefile tutorial I could find.. Could you please explain what #- is for?
For example:
#- $(RM) *.o
The at-sign # tells Make to not print the command line before executing it.
(Manual: Recipe echoing)
The minus sign - tells Make to ignore the result of the command and not fail the target if it was unsuccessful.
(Manual: Errors in recipes)
In your case it's just both of them being used, because somebody did not want to pollute the output with the erase command, and did not want to fail the build if anything goes wrong with the deletion either.
Ive got some large make files for a third party project that are not building due to linker issues.
From looking at the make files, I think it should be executing something like:
LIBS = -lm
CC = gcc
bin = bin
myapp: $(bin)/main.o $(bin)/other.o $(bin)/etc.o
$(CC) $(bin)/main.o $(bin)/other.o $(bin)/etc.o $(LIBS) -o myapp
gcc bin/main.o bin/other.o bin/etc.o -lm -o myapp
Instead from the error it seems to be failing on something like: It also didn't put any of the .o files in the expected bin/ location, but just left them in the source directory...
cc main.o -o myapp
But I cant locate anywhere that might come from. Is there some way to get some kind of stacktrace through the make files?
I am aware of -n and -d, but neither seems to tell me what target line and file yeilded that command, or which series of targets led there and the values of any $() expansions (The one im expecting is the only myapp: I can find in any of the makefiles...)
Check out the --debug option. From my manpage:
--debug[=FLAGS]
Print debugging information in addition to normal processing. If the
FLAGS are omitted, then the behavior is the same as if -d was specified.
FLAGS may be a for all debugging output (same as using -d), b for basic
debugging, v for more verbose basic debugging, i for showing implicit
rules, j for details on invocation of commands, and m for debugging
while remaking makefiles.
remake is a very good choice but in a pinch something like the following (saved as debug.mk) can be a good help too. It won't tell you as much as remake but it might tell you enough to start with.
# Use as: MAKEFILES=debug.mk make
OLD_SHELL := $(SHELL)
ifneq (undefined,$(origin X))
override X = -x
endif
SHELL = $(if $#,$(warning Running $#$(if $<, (from: $<))$(if $?, (newer: $?))))$(OLD_SHELL) $(X)
You can print out the other automatic variables there too if you wanted to see a bit more about what was going on.
I created a Makefile.in where I read the content out of a file and pass it to CFLAGS. Calling ./configure ... the Makefile will be generated an all works well.
Makefile.in:
...
MY_REVISION_FILE=my-revision.txt
MY_REVISION=$(shell cat $(top_srcdir)/$(MY_REVISION_FILE))
AM_CFLAGS = -I$(EXTRAS_INCLUDE_DIR) -I$(top_srcdir) -DMY_REVISION=$(MY_REVISION)
...
The problem arises once I moved the Makefile.in code into Makefile.am to allow the auto generation of Makefile.in. There calling autoreconf -i --force stops with the following error:
server/Makefile.am:9: cat $(top_srcdir: non-POSIX variable name
server/Makefile.am:9: (probably a GNU make extension)
autoreconf: automake failed with exit status: 1
This problem hunts me now since quite some time. I searched everywhere but did not find anything that could help me finding a solution for that. In short, the only thing I need is a way to get an uninterpreted text such as "$(shell cat $(top_srcdir)/$(MY_REVISION_FILE))" copied from Makefile.am to Makefile.in
Any idea?
Thanks,
Oliver
As it says, the problem is you're using a GNUism in your Makefile.am, when it's only meant to contain portable Makefile code.
Either rewrite your code so it's portable (you should use AM_CPPFLAGS because you're passing flags to the preprocessor, not the compiler):
AM_CPPFLAGS = -I$(EXTRAS_INCLUDE_DIR) -I$(top_srcdir) -DMY_REVISION=`cat $(top_srcdir)/$(MY_REVISION_FILE)`
If you don't want to invoke cat on every compile, you could find the value in configure.ac and either AC_SUBST it into Makefile or AC_DEFINE it so it goes into config.h.
Or if you want to be non-portable (ಠ_ಠ), you can take -Werror out of your AM_INIT_AUTOMAKE or AUTOMAKE_OPTIONS, or add -Wno-portability.
After long testing back and forth I decided to use AC_SUBST.
My solution might not be the cleanest but it works for me.
In configure.ac I added the following line
AC_SUBST([DOLLAR_SIGN],[$])
In the Makefile.am I changed my previous line into
MY_REVISION=#DOLLAR_SIGN#(shell cat $(SRC_DIR)/$(MY_REVISION_FILE))
And it works.
Again, thanks for your help.
I'm new to using makefiles and trying to produce a basic makefile as part of an exercise for university. I have two source code files, chello.c and writeexit.s, which have to be compiled/assembled and then linked to produce chello.
This is the code I have so far for the makefile:
chello: chello.o writeexit.o
ld -N chello.o writeexit.o -o chello
chello.o: chello.c
gcc -c chello.c -o chello.o
writeexit.o: writeexit.s
as writeexit.s -o writeexit.o
The whitespace before ld, gcc and as are all tabs, so I think the whitespacing is fine. When I call 'make makefile', it returns 'make: Nothing to be done for `makefile'.' However, if I change the dependencies of chello, like chello.c, the same message is returned and chello's behaviour is not modified.
From man make:
make executes commands in the makefile to update one or more target
names, where name is typically a program. If no -f option is present,
make will look for the makefiles GNUmakefile, makefile, and Makefile,
in that order.
make makefile will actually execute your "makefile" (because it is listed among the default names in the man page) file, trying to build the "makefile" target (because of the argument you are passing), which already exists
What you need is to build the "chello" binary, so you have to type:
make chello
Or alternatively:
make -f makefile chello
Alternative account here, it seems to work fine if I just call "make" instead of "make makefile". This question can be ignored.
All,
I'm trying to pass variables to make from the command line. My command is below
make ARCH=arm CROSS_COMPILE=/my_dir/bin/arm-openwrt-linux-g++
The error I received is
g++: error: arm: No such file or directory
But the file 'arm-openwrt-linux-g++' does exist.
I think the problem is I need to pass varibale to sub-make files. Can some help with an example of how to pass varialbes to sub-makefile from the command-line. I have tried using the -e and export options for make, but can't seen to get anything to work.
Thanks
Content of makefile:
# GNU Make solution makefile autogenerated by Premake
# Type "make help" for usage help
ifndef config
config=debug
endif
export config
PROJECTS := json openjaus
.PHONY: all clean help $(PROJECTS)
all: $(PROJECTS)
json:
#echo "==== Building json ($(config)) ===="
#${MAKE} --no-print-directory -C .build -f json.make
openjaus: json
#echo "==== Building openjaus ($(config)) ===="
#${MAKE} --no-print-directory -C .build -f openjaus.make
So, your problem is not related to sending variables over the command line.
Your problem is that in one of the makefiles in your sub-directories, which you haven't shown us, you're using the variable $(ARCH) in an incorrect way such that the expansion of the command line is not a legal g++ command line.
Based on the error message, most likely you're adding a space somewhere where it shouldn't be, so instead of something like -fmarch=arm you're getting -fmarch= arm. Obviously this is just an example because you didn't provide nearly enough information.
One other note: we can't know how your makefiles work but typically makefiles that support a variable like CROSS_COMPILE expect it to be set to just the prefix of the cross-compilation command; in your case it would be CROSS_COMPILE=/my_dir/bin/arm-openwrt-linux-. But, your makefiles might be different.
When asking questions, it's best to if you don't immediately jump to a guess about what the answer is. First describe the problem, and that includes showing the error line as well as a few lines before it. For example in this case you're getting an error from g++ so the command line that make printed out showing you how it invoked g++ would have helped greatly.
Once you've given the underlying detail, then if you think you have an idea about what the problem is go ahead and suggest it, and/or ask about it.
If you provide the rule that invokes g++ and/or the output from make showing the g++ command line, then we can help more.
Cheers!
Here's what I think needs to happen:
You need to make sure that your sub-makefiles actually respect the $(ARCH) and $(CROSS_COMPILE) variables. Are they also generated by Premake? If so, is that how it handles cross-compilation? Check the docs.
In my test (below), I found that variables set on the command line are propagated to sub-makes, which makes me think that your sub-makefiles aren't respecting $(ARCH):
Makefile:
a:
$(MAKE) -C z
z/Makefile:
a:
#echo "MAKE=$(MAKE)"
#echo "ARCH=$(ARCH)"
Running make with no arguments:
$ make
make -C z
make[1]: Entering directory `/home/foo/test/z'
MAKE=make
ARCH=
make[1]: Leaving directory `/home/foo/test/z'
Running make ARCH=bar:
$ make ARCH=bar
make -C z
make[1]: Entering directory `/home/foo/z/z'
MAKE=make
ARCH=bar
make[1]: Leaving directory `/home/foo/z/z'