I'm new to using makefiles and trying to produce a basic makefile as part of an exercise for university. I have two source code files, chello.c and writeexit.s, which have to be compiled/assembled and then linked to produce chello.
This is the code I have so far for the makefile:
chello: chello.o writeexit.o
ld -N chello.o writeexit.o -o chello
chello.o: chello.c
gcc -c chello.c -o chello.o
writeexit.o: writeexit.s
as writeexit.s -o writeexit.o
The whitespace before ld, gcc and as are all tabs, so I think the whitespacing is fine. When I call 'make makefile', it returns 'make: Nothing to be done for `makefile'.' However, if I change the dependencies of chello, like chello.c, the same message is returned and chello's behaviour is not modified.
From man make:
make executes commands in the makefile to update one or more target
names, where name is typically a program. If no -f option is present,
make will look for the makefiles GNUmakefile, makefile, and Makefile,
in that order.
make makefile will actually execute your "makefile" (because it is listed among the default names in the man page) file, trying to build the "makefile" target (because of the argument you are passing), which already exists
What you need is to build the "chello" binary, so you have to type:
make chello
Or alternatively:
make -f makefile chello
Alternative account here, it seems to work fine if I just call "make" instead of "make makefile". This question can be ignored.
Related
I am very much new to make files , I am facing very basic problem , My Makefile doesn't detect changes I made to source files . The problem is , when I first time generate consoleapp binary from my source file i get expected output . But When I change source file again and when I run make again it says
make: 'consoleapp' is up to date , So what changes I have to give to make file so that it detects my changes
Below is my Makefile :
consoleapp:
g++ consoleapp.cpp -o consoleapp
clean:
rm -rf *.o consoleapp
This is my Source File :
#include <iostream>
using namespace std;
int main()
{
cout<<"I am ok \n"; // I am changing this line again after giving make
return 0;
}
make relies on the makefile author to tell it what each target's prerequisites are -- that is, which other targets or files affect the construction of the target in question, so that if they are newer or themselves out of date then the target is out of date and should be rebuilt. As your other answer already indicates, you do not designate any prerequisites for your targets, so make considers them out of date if and only if they don't exist at all.
That's actually problematic for both targets, albeit in different ways. For target consoleapp, which represents an actual file that you want to build, the failure to specify any prerequisites yields the problem you ask about: make does not recognize that changes to the source file necessitate a rebuild. The easiest way to fix that would be to just add the source file name to the recipe's header line, after the colon:
consoleapp: consoleapp.cpp
g++ consoleapp.cpp -o consoleapp
Generally speaking, however, it is wise to minimize duplication in your makefile code, and to that end you can use some of make's automatic variables to avoid repeating target and prerequisite names in your rule's recipe. In particular, I recommend always using $# to designate the rule's target inside its recipe:
consoleapp: consoleapp.cpp
g++ consoleapp.cpp -o $#
It's a bit more situational for prerequisites. In this case, all the prerequisites are source files to be compiled, and furthermore there is only one. If you are willing to rely on GNU extensions then in the recipe you might represent the sources via either $< (which represents the first prerequisite), or as $^ (which represents the whole prerequisite list, with any duplicates removed). For example,
consoleapp: consoleapp.cpp
g++ $^ -o $#
If you are not using GNU make, however, or if you want to support other people who don't, then you are stuck with some repetition here. You can still save yourself some effort, especially in the event of a change to the source list, by creating a make variable for the sources and duplicating that instead of duplicating the source list itself:
consoleapp_SRCS = consoleapp.cpp
consoleapp: $(consoleapp_SRCS)
g++ $(consoleapp_SRCS) -o $#
I mentioned earlier that there are problems with both of your rules. But what could be wrong with the clean rule, you may ask? It does not create a file named "clean", so its recipe will be run every time you execute make clean, just as you want, right? Not necessarily. Although that rule does not create a file named "clean", if such a file is created by some other means then suddenly your clean rule will stop working, as that file will be found already up to date with respect to its (empty) list of prerequisites.
POSIX standard make has no solution for that, but GNU make provides for it with the special target .PHONY. With GNU make, any targets designated as prerequisites of .PHONY are always considered out of date, and the filesystem is not even checked for them. This is exactly to support targets such as clean, which are used to designate actions to perform that do not produce persistent artifacts on the file system. Although that's a GNU extension, it is portable in the sense that it uses standard make syntax and the target's form is reserved for extensions, so a make that does not support .PHONY in the GNU sense is likely either to just ignore it or to treat it as an ordinary rule:
.PHONY: clean
clean:
rm -rf *.o consoleapp
because your target has no dependence. Please use this codes that rely to all cpp file in current dir to update binary.
SRCS=consoleapp.cpp
consoleapp: $(SRCS)
g++ $< -o $#
I am somewhat of a beginner in C and have a project due where I need to include a makefile to compile my single file program that uses pthreads and semaphores. My makefile looks like:
# Makefile for pizza program
pizza: pizza.o
gcc -lrt -lpthread -g -o pizza pizza.o
pizza.o: pizza.c
gcc -lrt -lpthread -g -c pizza.o pizza.c
and I keep getting:
make: Nothing to be done for 'Makefile'.
I have done several makefiles before and have never gotten this message. I've tried different semantics in the makefile and have only gotten this same message. And yes, the command is tabbed after the target and dependency line.
Using gcc on tcsh. I have read other makefile posts on SO but I wasn't able to use any of the answers to figure it out for my case.
Any help would be greatly appreciated!
The arguments to make are the targets to be built.
You are running make Makefile which is telling make to try to build the Makefile target.
There is no such target in your makefile, make has no built-in rule that applies to that target and the file exists (and is assumed to be up-to-date) which is what that message is telling you.
To run the default target (by default the first target listed) you can just run make (assuming you are using a default name like Makefile for your makefile).
You can also use the -f argument to make to select an alternate makefile name.
So make -f Makefile will in this case (since Makefile is a default searched name) do the same thing as make.
I am trying to compile an OpenCobol program using make. I am always getting "make: Nothing to be done for test1.cob". Here is my makefile. I had put a TAB before cobc. But still I am getting that message. Please help.
Thanks.
COBCWARN = -W
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
And here is my cobol program.
IDENTIFICATION DIVISION.
PROGRAM-ID. TEST1.
PROCEDURE DIVISION.
DISPLAY 'Hello world!'.
STOP RUN.
Your makefile contains no actual targets. You have defined only a pattern rule which tells make how to build targets that match the pattern. But make doesn't go looking for targets out on the filesystem that could match the pattern, it only checks the pattern against targets that have been specifically requested.
You don't have any specific targets (files) listed in your makefile, so the only way make can know about a target is if you give the target to be built on the command line.
You are running this command from within vim, using the % special token, which expands to the name of the file currently being edited. That means you are running the command:
make test1.cob
because you are editing the file test1.cob. So, you are telling make "please try to create the target (file) test1.cob". But, that file already exists (it's the file you're writing). So make says "nothing to do".
If you run make and ask it to create the target you really want created, it will work:
make test1
Now the file test1 doesn't exist, and make can find a pattern rule that knows how to build it, so make will run that rule.
Alternatively, you can edit your makefile to add the specific target, like this:
COBCWARN = -W
test1: test1.cob
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
Then you can run make with no arguments at all. Without any command line arguments, make will look in the makefile for explicit targets and find test1 as the first one. It sees that there is a rule (the pattern rule) that matches that target, so it will build that target.
UPDATE
If you want to allow a simple command make to build multiple programs, write your makefile like this:
COBCWARN = -W
all: test1 test2 test3
.PHONY: all
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
Now from vim you can just say :!make and that's it.
If you run make with no arguments then it will find the first explicit target in the makefile and build that. In this example the first target is all, and its prerequisites are the possible programs to build. To build each one make sees that it can apply the pattern rule, and so it will do so (if the .cob file has been modified since the last time the program was built).
How to show the makefile after it's been preprocessed? For example, if we have two makefiles:
# Makefile
include Makefile2
# Makefile2
a:a.c
gcc -o a a.c
Then <preprocessor> Makefile should give:
a:a.c
gcc -o a a.c
It's similar to what a C preprocessor does (gcc -E). Is there such a makefile preprocessor?
You didn't specify for which make tool you are writing makefile. Assuming that it is GNU make, you can try running makefile with -n (--just-print) option See Command-Line Options chapter here. That will show what make is going to execute without execution (however, the commands needed for evaluation of variables will be executed). This is probably the closest to what you want to see.
This causes make to read the makefile and print every command it would
normally execute to update the target but without executing them.
Apart from that there is $(warning ) function to debug makefiles. You can place it almost to any part in makefile and the following will show you the values of all defined variables in that place:
$(warning Variables HERE: .VARIABLES)
All,
I'm trying to pass variables to make from the command line. My command is below
make ARCH=arm CROSS_COMPILE=/my_dir/bin/arm-openwrt-linux-g++
The error I received is
g++: error: arm: No such file or directory
But the file 'arm-openwrt-linux-g++' does exist.
I think the problem is I need to pass varibale to sub-make files. Can some help with an example of how to pass varialbes to sub-makefile from the command-line. I have tried using the -e and export options for make, but can't seen to get anything to work.
Thanks
Content of makefile:
# GNU Make solution makefile autogenerated by Premake
# Type "make help" for usage help
ifndef config
config=debug
endif
export config
PROJECTS := json openjaus
.PHONY: all clean help $(PROJECTS)
all: $(PROJECTS)
json:
#echo "==== Building json ($(config)) ===="
#${MAKE} --no-print-directory -C .build -f json.make
openjaus: json
#echo "==== Building openjaus ($(config)) ===="
#${MAKE} --no-print-directory -C .build -f openjaus.make
So, your problem is not related to sending variables over the command line.
Your problem is that in one of the makefiles in your sub-directories, which you haven't shown us, you're using the variable $(ARCH) in an incorrect way such that the expansion of the command line is not a legal g++ command line.
Based on the error message, most likely you're adding a space somewhere where it shouldn't be, so instead of something like -fmarch=arm you're getting -fmarch= arm. Obviously this is just an example because you didn't provide nearly enough information.
One other note: we can't know how your makefiles work but typically makefiles that support a variable like CROSS_COMPILE expect it to be set to just the prefix of the cross-compilation command; in your case it would be CROSS_COMPILE=/my_dir/bin/arm-openwrt-linux-. But, your makefiles might be different.
When asking questions, it's best to if you don't immediately jump to a guess about what the answer is. First describe the problem, and that includes showing the error line as well as a few lines before it. For example in this case you're getting an error from g++ so the command line that make printed out showing you how it invoked g++ would have helped greatly.
Once you've given the underlying detail, then if you think you have an idea about what the problem is go ahead and suggest it, and/or ask about it.
If you provide the rule that invokes g++ and/or the output from make showing the g++ command line, then we can help more.
Cheers!
Here's what I think needs to happen:
You need to make sure that your sub-makefiles actually respect the $(ARCH) and $(CROSS_COMPILE) variables. Are they also generated by Premake? If so, is that how it handles cross-compilation? Check the docs.
In my test (below), I found that variables set on the command line are propagated to sub-makes, which makes me think that your sub-makefiles aren't respecting $(ARCH):
Makefile:
a:
$(MAKE) -C z
z/Makefile:
a:
#echo "MAKE=$(MAKE)"
#echo "ARCH=$(ARCH)"
Running make with no arguments:
$ make
make -C z
make[1]: Entering directory `/home/foo/test/z'
MAKE=make
ARCH=
make[1]: Leaving directory `/home/foo/test/z'
Running make ARCH=bar:
$ make ARCH=bar
make -C z
make[1]: Entering directory `/home/foo/z/z'
MAKE=make
ARCH=bar
make[1]: Leaving directory `/home/foo/z/z'