Let's say I am having a table orders and having column
LastUpdatedDate, status.
What i am trying to do is -
picks all the Order which are ‘P’ status and lastupdate is two days
back from current date
.
can any one help me in writing a query to get my result.
Thanks
try
select * from yourtable
where status = 'P'
and LastUpdatedDate < sysdate - 2
Related
I'm trying to generate my total session by month. I've tried using two different ways.
I'm using date field for the first column
I'm using month field that is extracted from date field using EXTRACT(MONTH FROM date) AS month
I have tried using below code for the 1st one:
with
session1 as(
select date,
session_id
from table
where date >= '2019-05-20' AND date <= '2019-05-21')
SELECT date_key, COUNT(DISTINCT session_id) AS sessions from session1
GROUP BY 1
For the 2nd one I tried using this code:
with
session1 as(
select date,
session_id
from table
where date >= '2019-05-20' AND date <= '2019-05-21')
SELECT EXTRACT (MONTH FROM date_key) AS month, COUNT(DISTINCT session_id) AS sessions from session1
GROUP BY 1
For the result, I got the output as per below:
20 May: 1,548 Sessions; 21 May: 1,471 Sessions; Total: 3,019
May: 2,905
So, there's 114 session discrepancy and I'd like to know why.
Thank you in advance.
For simplicity sake - let's say there is only one session during two consecutive days. So if you will count by day and then sum result - you will get 2 sessions, while if you will count distinct sessions for whole two days - you will get just 1 session
Hope this shows you the reason why - you are counting some sessions twice on different days - maybe when they go over end of one and start of next day
The following query should show you which sessions_ids occur on both dates.
select session_id, count(distinct date) as num_dates
from table
where date >= '2019-05-20' AND date <= '2019-05-21'
group by 1
having num_dates > 1
This is either a data processing issue, or your session definition is allowed to span multiple days. Google Analytics, for example, traditionally ends a session and begins a new session at midnight. Other sessionization schemes might not impose this restriction.
I have a scenario where I need to compare 2 or more dates for given period.
I'm able to succeed when comparing 1 date to a period using between function. But challenge is when I have 2 dates to compare in parallel, getting single row sub query error
select A
from ORDER
where Date1 between sysdate and (sysdate-10)
Above query works fine for single date, please help to get a solution when I have Date 1 and Date 2 and need to compare against the same period (sysdate and (sysdate-10)) and I may have more than 2 dates as well.
Thanks
Shankar
Not having a proper description of your tables or the data they contain, it is difficult to know what you want.
Perhaps something like:
SELECT A
FROM ORDER
GROUP BY A
HAVING COUNT( CASE WHEN datecolumn BETWEEN SYSDATE - 10 AND SYSDATE THEN 1 ELSE NULL END ) > 0
I am running this query currently for one scenario but I have two scenarios: If SYSDATE = Monday, then run "SYSDATE - 2", otherwise run "SYSDATE - 1". I'm connecting to the database via an OLE connection from Excel so I'm not sure I can use a stored procedure. Is there a way to write the query to accomplish both scenarios? Thanks for all help.
SELECT
DISTINCT VERSION_NAME VERSION, MIN(RECONCILE_START_DT) DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -1
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
You may use a CASE statement in your WHERE condition to subtract either 2 for Mondays or 1 for the rest of the week. TO_CHAR(DATE, 'D') delivers the day of week beginning with Sundays = 1. Therefore Mondays are 2.
Try this:
SELECT
VERSION_NAME AS VERSION,
MIN(RECONCILE_START_DT) AS DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -
CASE TO_CHAR(SYSDATE, 'D')
WHEN '2' THEN 2
ELSE 1 END
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
Also you don't need the DISTINCT keyword as you're already use GROUP BY.
first... sorry for my english.
I have a query like this:
Select *
From tableA
Where (
TO_NUMBER(TO_CHAR(dateA(+),'SYYYY')) = 2013
AND TO_NUMBER(TO_CHAR(dateA(+),'MM')) = 02
AND to_number(to_char(dateA(+),'dd')) <= 25
)
and retrieve me the data from each date until last number that I give as parameter, in this case the day 25. This working but delay very much because the form of "Where" statement... anybody know another way that retrieve the data so fast and with the same functionality?
It sounds like you want
SELECT *
FROM tableA
WHERE dateA BETWEEN trunc( date '2013-02-26', 'MM' ) AND date '2013-02-26'
This will return all the rows where dateA is between the first of the month and the specified date. If there is an index on dateA, Oracle would be able to use it for this sort of query (though whether it actually would is a separate issue).
I have dates in this format in my database "01-APR-12" and the column is a DATE type.
My SQL statement looks like this:
SELECT DISTINCT c.customerno, c.lname, c.fname
FROM customer c, sales s
WHERE c.customerno = s.customerno AND s.salestype = 1
AND (s.salesdate BETWEEN '01-APR-12' AND '31-APR-12');
When I try to do it that way, I get this error -- ORA-01839: date not valid for month specified.
Can I even use the BETWEEN keyword with how the date is setup in the database?
If not, is there another way I can get the output of data that is in that date range without having to fix the data in the database?
Thanks!
April has 30 days not 31.
Change
SELECT DISTINCT c.customerno, c.lname, c.fname
FROM customer c, sales s
WHERE c.customerno = s.customerno AND s.salestype = 1
AND (s.salesdate BETWEEN '01-APR-12' AND '31-APR-12');
to
SELECT DISTINCT c.customerno, c.lname, c.fname
FROM customer c, sales s
WHERE c.customerno = s.customerno AND s.salestype = 1
AND (s.salesdate BETWEEN '01-APR-12' AND '30-APR-12');
and you should be good to go.
In case the dates you are checking for range from 1st day of a month to the last day of a month then you may modify the query to avoid the case where you have to explicitly check the LAST day of the month
SELECT DISTINCT c.customerno, c.lname, c.fname
FROM customer c, sales s
WHERE c.customerno = s.customerno
AND s.salestype = 1 AND (s.salesdate BETWEEN '01-APR-12' AND LAST_DAY(TO_DATE('APR-12', 'MON-YY'));
The LAST_DAY function will provide the last day of the month.
The other answers are missing out on something important and will not return the correct results. Dates have date and time components. If your salesdate column is in fact a date that includes time, you will miss out on any sales that happened on April 30 unless they occurred exactly at midnight.
Here's an example:
create table date_temp (temp date);
insert into date_temp values(to_date('01-APR-2014 15:12:00', 'DD-MON-YYYY HH24:MI:SS'));
insert into date_temp values(to_date('30-APR-2014 15:12:00', 'DD-MON-YYYY HH24:MI:SS'));
table DATE_TEMP created.
1 rows inserted.
1 rows inserted.
select * from date_temp where temp between '01-APR-2014' and '30-APR-2014';
Query Result: 01-APR-14
If you want to get all records from April that includes those with time-components in the date fields, you should use the first day of the next month as the second side of the between clause:
select * from date_temp where temp between '01-APR-2014' and '01-MAY-2014';
01-APR-14
30-APR-14