I am running this query currently for one scenario but I have two scenarios: If SYSDATE = Monday, then run "SYSDATE - 2", otherwise run "SYSDATE - 1". I'm connecting to the database via an OLE connection from Excel so I'm not sure I can use a stored procedure. Is there a way to write the query to accomplish both scenarios? Thanks for all help.
SELECT
DISTINCT VERSION_NAME VERSION, MIN(RECONCILE_START_DT) DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -1
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
You may use a CASE statement in your WHERE condition to subtract either 2 for Mondays or 1 for the rest of the week. TO_CHAR(DATE, 'D') delivers the day of week beginning with Sundays = 1. Therefore Mondays are 2.
Try this:
SELECT
VERSION_NAME AS VERSION,
MIN(RECONCILE_START_DT) AS DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -
CASE TO_CHAR(SYSDATE, 'D')
WHEN '2' THEN 2
ELSE 1 END
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
Also you don't need the DISTINCT keyword as you're already use GROUP BY.
Related
Just had a user answer this correctly for TSQL, but wondering how best to achieve this now in SQL Developer/PLSQL seeing as there is no DATEDIFF function.
Table I want to query on has some 'CODE' values, which can naturally have multiple primary key records ('OccsID') in a table 'Occs'. There is also a datetime column called 'CreateDT' for each OccsID.
Just want to find the maximum possible time variance between any 2 consecutive rows in 'Occs', per 'CODE'.
If you subtract the "next" date and "this" date (using the LEAD analytic function), you'll get the date difference. Then fetch the maximum difference per code. Something like this:
with diff as
(select occsid,
code,
nvl(lead(createdt) over (partition by code order by createdt), createdt) - createdt date_diff
from test
)
select code,
max(date_diff)
from diff
group by code;
Assuming that this T-SQL version works for you (from the prior question)
SELECT x.code, MAX(x.diff_sec) FROM
(
SELECT
code,
DATEDIFF(
SECOND,
CreateDT,
LEAD(CreateDT) OVER(PARTITION BY CODE ORDER BY CreateDT) --next row's createdt
) as diff_sec
FROM Occs
)x
GROUP BY x.code
The simplest option is just to subtract the two dates to get a difference in days. You can then multiply to get the difference in hours, minutes, or seconds
SELECT x.code, MAX(x.diff_day), MAX(x.diff_sec)
FROM
(
SELECT
code,
CreateDT -
LEAD(CreateDT) OVER(PARTITION BY CODE ORDER BY CreateDT) as diff_day,
24*60*60* (CreateDT -
LEAD(CreateDT) OVER(PARTITION BY CODE ORDER BY CreateDT)) as diff_sec
FROM Occs
)x
GROUP BY x.code
I'm trying to generate my total session by month. I've tried using two different ways.
I'm using date field for the first column
I'm using month field that is extracted from date field using EXTRACT(MONTH FROM date) AS month
I have tried using below code for the 1st one:
with
session1 as(
select date,
session_id
from table
where date >= '2019-05-20' AND date <= '2019-05-21')
SELECT date_key, COUNT(DISTINCT session_id) AS sessions from session1
GROUP BY 1
For the 2nd one I tried using this code:
with
session1 as(
select date,
session_id
from table
where date >= '2019-05-20' AND date <= '2019-05-21')
SELECT EXTRACT (MONTH FROM date_key) AS month, COUNT(DISTINCT session_id) AS sessions from session1
GROUP BY 1
For the result, I got the output as per below:
20 May: 1,548 Sessions; 21 May: 1,471 Sessions; Total: 3,019
May: 2,905
So, there's 114 session discrepancy and I'd like to know why.
Thank you in advance.
For simplicity sake - let's say there is only one session during two consecutive days. So if you will count by day and then sum result - you will get 2 sessions, while if you will count distinct sessions for whole two days - you will get just 1 session
Hope this shows you the reason why - you are counting some sessions twice on different days - maybe when they go over end of one and start of next day
The following query should show you which sessions_ids occur on both dates.
select session_id, count(distinct date) as num_dates
from table
where date >= '2019-05-20' AND date <= '2019-05-21'
group by 1
having num_dates > 1
This is either a data processing issue, or your session definition is allowed to span multiple days. Google Analytics, for example, traditionally ends a session and begins a new session at midnight. Other sessionization schemes might not impose this restriction.
My tables are as below
MS_ISM_ISSUE
ISSUE_ID ISSUE_DUE_DATE ISSUE_SOURCE_TYPE
I1 25-11-2018 1
I2 25-12-2018 1
I3 27-03-2019 2
MS_ISM_SOURCE_SETUP
SOURCE_ID MODULE_NAME
1 IT-Compliance
2 Risk Assessment
I have written following query.
with rs as
(select
count(ISSUE_ID) as ISSUE_COUNT, src.MODULE_NAME,
case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end as date_range
from MS_ISM_ISSUE issue, MS_ISM_SOURCE_SETUP src
where issue.Issue_source_type = src.source_id
group by src.MODULE_NAME, case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end)
select ISSUE_COUNT,MODULE_NAME, DATE_RANGE,
(select count(ISSUE_COUNT) from rs where rs.MODULE_NAME=MODULE_NAME) as total from rs;
The output of the code is as below.
ISSUE_COUNT MODULE_NAME DATE_RANGE Total
1 IT-Compliance Overdue 3
1 IT-Compliance Within 3 months 3
1 Risk Assessment Beyond 90 days 3
The result is correct till 3rd column. In 4th column what I want is, total of Issue count for given module name. Hence in above case Total column will have value as 2 for first and second row (since there are 2 Issues for IT-Compliance) and value 1 for the third row (since one issue is present for Risk Assessment).
Essentially, I want to achieve is to replace current row's MODULE_NAME in last where clause. How do I achieve this using query?
OK, this condition
where rs.MODULE_NAME=MODULE_NAME
is essentially the same as if you wrote
where MODULE_NAME = MODULE_NAME
which is simply always true (if there are no nulls in module_name).
Try using different table alias for inner query and outer query, e.g.
select count(ISSUE_COUNT) from rs rs2 where rs2.MODULE_NAME=rs.MODULE_NAME
You can also try to use analytic function here, something like
select ISSUE_COUNT,
MODULE_NAME,
DATE_RANGE,
COUNT(ISSUE_COUNT) OVER (PARTITION BY RS.MODULE_NAME) AS TOTAL
from rs
instead of your subquery
I have a scenario where I need to compare 2 or more dates for given period.
I'm able to succeed when comparing 1 date to a period using between function. But challenge is when I have 2 dates to compare in parallel, getting single row sub query error
select A
from ORDER
where Date1 between sysdate and (sysdate-10)
Above query works fine for single date, please help to get a solution when I have Date 1 and Date 2 and need to compare against the same period (sysdate and (sysdate-10)) and I may have more than 2 dates as well.
Thanks
Shankar
Not having a proper description of your tables or the data they contain, it is difficult to know what you want.
Perhaps something like:
SELECT A
FROM ORDER
GROUP BY A
HAVING COUNT( CASE WHEN datecolumn BETWEEN SYSDATE - 10 AND SYSDATE THEN 1 ELSE NULL END ) > 0
I'm pulling two pieces of information over a specific time period, but I would like to fetch the daily average of one tag and the daily count of another tag. I'm not sure how to do daily averages over a specific time period, can anyone provide some advice? Below were my first ideas on how to handle this however to change every date would be annoying. Any help is appreciated thanks
SELECT COUNT(distinct chargeno), to_char(chargetime, 'mmddyyyy') AS chargeend
FROM batch_index WHERE plant=1 AND chargetime>to_date('2012-06-18:00:00:00','yyyy-mm-dd:hh24:mi:ss')
AND chargetime<to_date('2012-07-19:00:00:00','yyyy-mm-dd:hh24:mi:ss')
group by chargetime;
The working version of the daily sum
SELECT to_char(bi.chargetime, 'mmddyyyy') as chargtime, SUM(cv.val)*0.0005
FROM Charge_Value cv, batch_index bi WHERE cv.ValueID =97
AND bi.chargetime<=to_date('2012-07-19','yyyy-mm-dd')
AND bi.chargeno = cv.chargeno AND bi.typ=1
group by to_char(bi.chargetime, 'mmddyyyy')
seems like in the first one you want to change the group to the day - not the time... (plus i dont think you need to specify all those 0's for seconds..)
SELECT COUNT(distinct chargeno), to_char(chargetime, 'mmddyyyy') AS chargeend
FROM batch_index WHERE plant=1 AND chargetime>to_date('2012-06-18','yyyy-mm-dd')
AND chargetime<to_date('2012-07-19','yyyy-mm-dd')
group by to_char(chargetime, 'mmddyyyy') ;
not 100% I'm following your question, but if you just want to do aggregates (sums, avg), then do just that. I threw in the rollup just in case that is what you were looking for
with fakeData as(
select trunc(level *.66667) nr
, trunc(2*level * .33478) lvl --these truncs just make the doubles ints
,trunc(sysdate+trunc(level*.263784123)) dte --note the trunc, this gets rid of the to_char to drop the time
from dual
connect by level < 600
) --the cte is just to create fake data
--below is just some aggregates that may help you
select sum(nr) daily_sum_of_nr
, avg(nr) daily_avg_of_nr
, count(distinct lvl) distinct_lvls_per_day
, count(lvl) count_of_nonNull_lvls_per_day
, dte days
from fakeData
group by rollup(dte)
--if you want the query to supply a total for the range, you may use rollup ( http://psoug.org/reference/rollup.html )