I have a scenario where I need to compare 2 or more dates for given period.
I'm able to succeed when comparing 1 date to a period using between function. But challenge is when I have 2 dates to compare in parallel, getting single row sub query error
select A
from ORDER
where Date1 between sysdate and (sysdate-10)
Above query works fine for single date, please help to get a solution when I have Date 1 and Date 2 and need to compare against the same period (sysdate and (sysdate-10)) and I may have more than 2 dates as well.
Thanks
Shankar
Not having a proper description of your tables or the data they contain, it is difficult to know what you want.
Perhaps something like:
SELECT A
FROM ORDER
GROUP BY A
HAVING COUNT( CASE WHEN datecolumn BETWEEN SYSDATE - 10 AND SYSDATE THEN 1 ELSE NULL END ) > 0
Related
In Oracle SQL Developer, I have a table called t1 who have two columns col1 defined as NUMBER(19,0) and col2 defined as TIMESTAMP(3).
I have these rows
col1 col2
1 03/01/22 12:00:00,000000000
2 03/01/22 13:00:00,000000000
3 26/11/21 10:27:11,750000000
4 26/11/21 10:27:59,606000000
5 16/12/21 11:47:04,105000000
6 16/12/21 12:29:27,101000000
My sysdate looks like this:
select sysdate from dual;
SYSDATE
03/03/22
I want to create a stored procedure (SP) which will delete rows older than 2 months and displayed message n rows are deleted
But when i execute this statement
select * from t1 where to_date(TRUNC(col2), 'DD/MM/YY') < add_months(sysdate, -2);
I don't get the first 2 rows of my t1 table. I get more than 2 rows
1 03/01/22 12:00:00,000000000
2 03/01/22 13:00:00,000000000
How can i get these rows and deleted it please ?
In Oracle, a DATE data type is a binary data type consisting of 7 bytes (century, year-of-century, month, day, hour, minute and second). It ALWAYS has all of those components and it is NEVER stored with a particular formatting (such as DD/MM/RR).
Your client application (i.e. SQL Developer) may choose to DISPLAY the binary DATE value in a human readable manner by formatting it as DD/MM/RR but that is a function of the client application you are using and not the database.
When you show the entire value:
SELECT TO_CHAR(ADD_MONTHS(sysdate, -2), 'YYYY-MM-DD HH24:MI:SS') AS dt FROM DUAL;
Then it outputs (depending on time zone):
DT
2022-01-03 10:11:28
If you compare that to your values then you can see that 2022-01-03 12:00:00 is not "more than 2 months ago" so it will not be matched.
What you appear to want is not "more than 2 months ago" but "equal to or more than 2 months, ignoring the time component, ago"; which you can get using:
SELECT *
FROM t1
WHERE col2 < add_months(TRUNC(sysdate), -2) + INTERVAL '1' DAY;
or
SELECT *
FROM t1
WHERE TRUNC(col2) <= add_months(TRUNC(sysdate), -2);
(Note: the first query would use an index on col2 but the second query would not; it would require a function-based index on TRUNC(col2) instead.)
Also, don't use TO_DATE on a column that is already a DATE or TIMESTAMP data type. TO_DATE takes a string as the first argument and not a DATE or TIMESTAMP so Oracle will perform an implicit conversion using TO_CHAR and if the format models do not match then you will introduce errors (and since any user can set their own date format in their session parameters at any time then you may get errors for one user that are not present for other users and is very hard to debug).
db<>fiddle here
Perhaps just:
select *
from t1
where col2 < add_months(sysdate, -2);
I'm trying to generate my total session by month. I've tried using two different ways.
I'm using date field for the first column
I'm using month field that is extracted from date field using EXTRACT(MONTH FROM date) AS month
I have tried using below code for the 1st one:
with
session1 as(
select date,
session_id
from table
where date >= '2019-05-20' AND date <= '2019-05-21')
SELECT date_key, COUNT(DISTINCT session_id) AS sessions from session1
GROUP BY 1
For the 2nd one I tried using this code:
with
session1 as(
select date,
session_id
from table
where date >= '2019-05-20' AND date <= '2019-05-21')
SELECT EXTRACT (MONTH FROM date_key) AS month, COUNT(DISTINCT session_id) AS sessions from session1
GROUP BY 1
For the result, I got the output as per below:
20 May: 1,548 Sessions; 21 May: 1,471 Sessions; Total: 3,019
May: 2,905
So, there's 114 session discrepancy and I'd like to know why.
Thank you in advance.
For simplicity sake - let's say there is only one session during two consecutive days. So if you will count by day and then sum result - you will get 2 sessions, while if you will count distinct sessions for whole two days - you will get just 1 session
Hope this shows you the reason why - you are counting some sessions twice on different days - maybe when they go over end of one and start of next day
The following query should show you which sessions_ids occur on both dates.
select session_id, count(distinct date) as num_dates
from table
where date >= '2019-05-20' AND date <= '2019-05-21'
group by 1
having num_dates > 1
This is either a data processing issue, or your session definition is allowed to span multiple days. Google Analytics, for example, traditionally ends a session and begins a new session at midnight. Other sessionization schemes might not impose this restriction.
I'm trying to get an count based on two dates and I'm not sure how it should look in a query. I have two date fields; I want to get a count based on those dates.
<cfquery>
SELECT COUNT(*)
FROM Table1
Where month of date1 is one month less than month of date2
</cfquery>
Assuming Table1 is your original query, you can accomplish your goal as follows.
Step 1 - Use QueryAddColumn twice to add two empty columns.
Step 2 - Loop through your query and populate these two columns with numbers. One will represent date1 and the other will represent date2. It's not quite as simple as putting in the month numbers because you have to account for the year as well.
Step 3 - Write your Q of Q with a filter resembling this:
where NewColumn1 - NewColumn2 = 1
I am running this query currently for one scenario but I have two scenarios: If SYSDATE = Monday, then run "SYSDATE - 2", otherwise run "SYSDATE - 1". I'm connecting to the database via an OLE connection from Excel so I'm not sure I can use a stored procedure. Is there a way to write the query to accomplish both scenarios? Thanks for all help.
SELECT
DISTINCT VERSION_NAME VERSION, MIN(RECONCILE_START_DT) DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -1
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
You may use a CASE statement in your WHERE condition to subtract either 2 for Mondays or 1 for the rest of the week. TO_CHAR(DATE, 'D') delivers the day of week beginning with Sundays = 1. Therefore Mondays are 2.
Try this:
SELECT
VERSION_NAME AS VERSION,
MIN(RECONCILE_START_DT) AS DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -
CASE TO_CHAR(SYSDATE, 'D')
WHEN '2' THEN 2
ELSE 1 END
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
Also you don't need the DISTINCT keyword as you're already use GROUP BY.
I have a table A which contains a Date type attribute. I want to write a query to select the date in another table B with value one month after the value in A.Any one know how to do it in oracle?
uhm... This was the first hit on google:
http://psoug.org/reference/date_func.html
It seems you're looking for the "add_months" function.
You need to use the ADD_MONTHS function in Oracle.
http://www.techonthenet.com/oracle/functions/add_months.php
Additional info: If you want to use this function with today's date you can use ADD_MONTHS(SYSDATE, 1) to get one month from now.
The question is to select a date_field from table b where date_field of table b is one month ahead of a date_field in table a.
An additional requirement must be taken into consideration which is currently unspecified in the question. Are we interested in whole months (days of month not taken into consideration) or do we want to include the days which might disqualify dates that are one month ahead but only by a couple of days (example: a=2011-04-30 and b=2011-05-01, b is 1 month ahead but only by 1 day).
In the first case, we must truncate both dates to their year and month values:
SELECT TRUNC( TO_DATE('2011-04-22','yyyy-mm-dd'), 'mm') as trunc_date
FROM dual;
gives:
trunc_date
----------
2011-04-01
In the second case we don't have to modify the dates.
At least two approaches can be used to solve the initial problem:
First one revolves around adding one month to the date_field in table a and finding a row in table b with a matching date.
SELECT b.date_field
FROM tab_a as a
,tab_b as b
WHERE ADD_MONTHS( TRUNC( a.date_field, 'mm' ), 1) = TRUNC( b.date_field, 'mm' )
;
Note the truncated dates. Leaving this out will require a perfect day to day match between dates.
The second approaches is based on calculating the difference in months between two dates and picking a calculation that gives a 1 month difference.
SELECT b.date_field
FROM tab_a as a
,tab_b as b
WHERE months_between( TRUNC( b.date_field, 'mm') , TRUNC(a.date_field, 'mm') ) = 1
The order of the fields in months_between is important here. In the provided example:
for b.date_field one month ahead of a.date_field the value is 1
for b.date_field one month before a.date_field the value is -1 (negative one)
Reversing the order will also reverse the results.
Hope this answers your question.