I am a newbie on Liferay and furthermore 100% Windows infrastructure knowledge based. I installed Liferay 6.2 on my Windows 2012R2 server together with Java jdk-8u5 version. All is running perfect as long as I am logged in as user on the Server via remotedesktop having open the tomcat startup.bat window.
What have I to do exactly to start Liferay and/or tomcat as service?
Thanks in advance for your efforts.
Configuring liferay or tomcat to run as a service on a windows server doesn't differ that much.So in order to do that you have to add some files to the LIFERAY_HOME\tomcat\bin directory.
To get those files you have to download a full version of 64-bitWindows tomcat from here :
http://tomcat.apache.org/download-70.cgi.
Extract the zip and go to the bin directory, copy service.bat , tomcat7.exe and tomcat7w.exe to this location : LIFERAY_HOME\tomcat\bin
Setting Up the service
Open the commad prompt (Make sure you have admin rights or run the command prompt as administrator),In Command Prompt go to LIFERAY_HOME\tomcat\bin and Execute the following command
service.bat install tomcat7
This will install the tomcat6 service in windows.
Now execute following commond to setup additional configuration for the service
tomcat7w.exe ES tomcat7.exe
2 . Extra configuration :
-XX:MaxPermSize=512m
-Dfile.encoding=UTF8
-Duser.timezone=GMT
-Djava.security.auth.login.config="%CATALINA_HOME%/conf/jaas.config"
-Dorg.apache.catalina.loader.WebappClassLoader.ENABLE_CLEAR_REFERENCES=false
and make sure to provide enough memory for your service by setting the initial memory pool and the maximum one.
Either go with Rafik Beldi's answer (quite an effort, wow) or just go to tomcat's documentation in case you're still missing some information
I had to delete what was in Java Options completely or it wouldn't start: and then I entered:
-XX:MaxPermSize=512m
-Dfile.encoding=UTF8
-Duser.timezone=America/New_York
-Dorg.apache.catalina.loader.WebappClassLoader.ENABLE_CLEAR_REFERENCES=false
-Djava.net.preferIPv4Stack=true
note that where I am: America/New_York allows for both EST and EDT
Related
I installed Teamcity 2018.1 bundled with Tomcat servlet container on windows 7. I start Teamcity server by running teamcity-server script from bin folder.
But I want to start Teamcity server when windows starts as a windows service.
The most simple approach to make TeamCity start as a service is to use TeamCity .exe distribution and opt for the service configuration in the installation wizard.
If you are proficient with Windows Services, you can also do that later: use "teamcity-server.bat usage" as a starting point for supported service commands.
I installed tomcat server on windows10 bash shell. Though it says apache is running.. its not opening admin panel in browser. Browser says 'Connection can't be reached'
Have someone tried this ever before? Please share your inputs.
Thank you
I am assuming you are referring to Bash for Windows (Ubuntu) on Windows 10. Yes Tomcat server can be installed and run from Bash for Windows with no need to install Tomcat in the Windows environment.
First, you may want to check if any local server is running on Windows 10 port 8080 - the default port for Tomcat, or whatever port you are configuring Tomcat for.
Second, open BASH for Windows and install Java. I used Oracle Java JDK 8 (http://www.oracle.com/technetwork/java/javase/downloads/index.html) and downloaded the tar.gz file.
Extract the tar.gz and copy to a standard directory like /usr/local/java or in the /opt/ directory for easy access.
Create JAVA_HOME and JRE_HOME environment variables that link to your java location.
I also updated the alternatives to map java, javac, and javaws. You can use this link to assist (http://askubuntu.com/questions/56104/how-can-i-install-sun-oracles-proprietary-java-jdk-6-7-8-or-jre)
Then download the tar.gz of Tomcat. Again, I used Tomcat 8.5 for my scenario and extract the files to your chosen directory.
Last, run the startup script located in the bin folder of the tomcat extracted folder. You should have a working Tomcat version.
Use the curl command to validate - curl localhost:8080
If you want to change the admin privileges, edit the tomcat-users.xml file located in the conf folder within the extracted tomcat directory.
Access to the tomcat server can also be done through the Windows system and not just through the Bash for Windows CLI.
Hope this helps!
Our security team has scanned our production server and identified vulnerabilities with Apache Tomcat server v 6.0.20.
They have recommended that Apache be upgraded to 6.0.24. Reading through the forums, I believe this is the process to do so
Take a backup of httpd.conf file
Using add remove programs, uninstall version 6.0.20
Install 6.0.24
But, I have some questions depending on a quick test I did to install 6.0.20 and upgrade it to 6.0.24
Where do I get Tomcat administrator login information?
Is it enough just to backup the HTTPD.CONF file? I was thinking to back up everything in the Apache folder instead.
Is it possible not to upgrade 6.0.20 to 6.0.24 by running the MSI installer over the same Apache folder? Is it due to the HTTP/1.1 Connector Port being busy/used that doesn't allow an update of Tomcat on the same port?
Is a restart of the server required after upgrade?
Last but not the least, I am using these executables to test the upgrade. 6.0.20 gets installed fine but when I run 6.0.24, it prompts me for the JRE path and directing it to 6.0.20 JVM Path gives me a message that "JVM is not found". The JVM info on the Apache manager is in this directory
What am I missing here?
I need your thoughts and advice to make this as easy as possible since this is a production server.
I need to install Tomcat 7 as a Windows service and to start the service manually.
Referring to How to install Tomcat as a Windows service, I believe I would need to specify the following on the command line:
tomcat7 //IS//Tomcat7 --DisplayName="Apache Tomcat 7" --Install="C:\Tomcat7\bin\tomcat7.exe
Do I also need to specify all or some of the following on the command line like in the example? If only some, please specify which ones. If anything in the example is incorrect, please specify.
--Jvm=auto
--StartMode=jvm
--StopMode=jvm
--StartClass=org.apache.catalina.startup.Bootstrap
--StartParams=start
--StopClass=org.apache.catalina.startup.Bootstrap
--StopParams=stop
What I need for sure is to specify the following because I need to tell Tomcat to use a specific java home and not the java home set by the environment variable JAVA_HOME on the server where this will be installed.
--JavaHome="C:\Program Files\Java\jdk1.7.0_51
The reason: the server already has a different version of Tomcat (5.5) and it uses an older version of the JDK (1.5). I must not change JAVA_HOME on the server. I simply need to ensure Tomcat 7 uses JDK 1.7 and I have tried this line:
C:\tomcat7\bin>tomcat7 //IS//Tomcat7 --DisplayName="Apache Tomcat 7" --Install="C:\Tomcat7\bin\tomcat7.exe" --JavaHome="C:\Program Files\Java\jdk1.7.0_51"
When I attempt to Start the service, the following error message is displayed:
Windows could not start the Apache Tomcat 7 on Local Computer. For
more information, review the System Event Log. If this is a
non-Microsoft service, contact the service vendor, and refer to
service-specific error code 1.
I had a look at the System Event Viewer and it provides the following information:
The Apache Tomcat 7 service terminated with service-specific error Incorrect function..
I need to figure out these steps because I then need to provide the support team with the information to install this service on the production server. So any help would be greatly appreciated!
Use Chocolatey from Powershell command line:
first install Chocolatey
PS:\> iex ((new-object net.webclient).DownloadString('https://chocolatey.org/install.ps1'))
To install Tomcat
PS:\> choco install tomcat
To upgrade
PS:\> choco upgrade tomcat
Seems like a mismatch in your java JVM and tomcat version.
The tomcat7.exe wrapper program actually
"runs" the JVM, it must match the type of JVM that it runs, in terms
of 32bit/64bit version. If you try to start a 64-bit JVM with a 32-bit
tomcat7.exe, it won't work, and vice-versa.
Reference
This is because of shortage in physical RAM.
Check the Minimum System Requirements on Tomcat docs and try to close unnecessary programs if possible.
Use Chocolatey from Powershell command line:
PS> iex ((new-object net.webclient).DownloadString('https://chocolatey.org/install.ps1'))
To install Tomcat:
PS> choco install tomcat
To upgrade:
PS> choco upgrade tomcat
I have googled this extensively before posting it here. I've been trying to find out a way to enable JMX Access on a Tomcat instance installed as Windows service. Its quite straightforward when Tomcat is invoked via the startup.bat script, one just needs to set the CATALINA_OPTS environment variable to something like "-Dcom.sun.management.jmxremote.port=1234 -Dcom.sun.management.jmxremote.authenticate=false -Dcom.sun.management.jmxremote.ssl=false"
But how do i get the Tomcat Windows service to read these options? I tried this:
C:>tomcat\server\bin> service.bat install #install the Tomcat7 windows service
C:>tomcat\server\bin> tomcat7.exe //US//Tomcat7 ++JvmOptions "-Djava.io.tmpdir=$INSTDIR\server\temp;-XX:MaxPermSize
=256m;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.au
thenticate=false;-Dcom.sun.management.jmxremote.ssl=false" --JvmMs 256 --JvmMx 1
024 #update the installed service using the //US switch; set tmpdir, JMX access and heap size
When i start the service from Services panel, the service fails to start and i get the following error on the logs\tomcat7-stderr-yyyy-mm-dd.log file:
yyyy-mm-dd hh:mm:ss Commons Daemon procrun stderr initialized
Error: Invalid com.sun.management.jmxremote.port number: 8090 -Dcom.sun.management.jmxremote.authenticate=false -Dcom.sun.management.jmxremote.ssl=false
I don't have a Java background, am i trying to achieve something outlandish here? Please advise.
Answering my own question; turned out to be easier than i thought.
Following needs to be done, for enabling JMX access for Tomcat installed as a Windows service, that has a name "ApacheTomcatWindowsServer" for example:
Install Tomcat as Windows service, either using the command (first cd into \bin\ )
service.bat install
or your custom scripts.
Enable Apache Service Manager for the installed service using the following command:
tomcat7w.exe //MS//ApacheTomcatWindowsServer
This should start Apache Service Monitor program on your system tray. Click on its icon. select 'Configure', click on the 'Java' tab and append the following on the 'Java Options' text box, one option per line:
-Dcom.sun.management.jmxremote.port=8090
-Dcom.sun.management.jmxremote.authenticate=false
-Dcom.sun.management.jmxremote.ssl=false
Save and exit and restart the service.
To connect to the JMX console, fire jconsole from your JDK installation, click 'New Connection', specify 'Remote Process' and enter hostname:8090.
you can also uninstall the service by
service.bat remove
then edit the service.bat and add the parameters in your StartPath and add the options
-Djavax.management.builder.initial=;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.authenticate=false;-Dcom.sun.management.jmxremote.ssl=false
here is the sample StartPath in my file
--StartPath "C:\tomcat7\" --Startup auto --JvmOptions "-Dcatalina.home=%CATALINA_HOME%;-Dcatalina.base=%CATALINA_BASE%;-Djava.endorsed.dirs=%CATALINA_HOME%\endorsed;-Djava.io.tmpdir=%CATALINA_BASE%\temp;-Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager;-Djava.util.logging.config.file=%CATALINA_BASE%\conf\logging.properties;-Djava.rmi.server.hostname=;-Djavax.management.builder.initial=;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.authenticate=false;-Dcom.sun.management.jmxremote.ssl=false" %JAVA_OPTS% ^
re-install the service by
service.bat install
then start Tomcat to apply changes