I have googled this extensively before posting it here. I've been trying to find out a way to enable JMX Access on a Tomcat instance installed as Windows service. Its quite straightforward when Tomcat is invoked via the startup.bat script, one just needs to set the CATALINA_OPTS environment variable to something like "-Dcom.sun.management.jmxremote.port=1234 -Dcom.sun.management.jmxremote.authenticate=false -Dcom.sun.management.jmxremote.ssl=false"
But how do i get the Tomcat Windows service to read these options? I tried this:
C:>tomcat\server\bin> service.bat install #install the Tomcat7 windows service
C:>tomcat\server\bin> tomcat7.exe //US//Tomcat7 ++JvmOptions "-Djava.io.tmpdir=$INSTDIR\server\temp;-XX:MaxPermSize
=256m;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.au
thenticate=false;-Dcom.sun.management.jmxremote.ssl=false" --JvmMs 256 --JvmMx 1
024 #update the installed service using the //US switch; set tmpdir, JMX access and heap size
When i start the service from Services panel, the service fails to start and i get the following error on the logs\tomcat7-stderr-yyyy-mm-dd.log file:
yyyy-mm-dd hh:mm:ss Commons Daemon procrun stderr initialized
Error: Invalid com.sun.management.jmxremote.port number: 8090 -Dcom.sun.management.jmxremote.authenticate=false -Dcom.sun.management.jmxremote.ssl=false
I don't have a Java background, am i trying to achieve something outlandish here? Please advise.
Answering my own question; turned out to be easier than i thought.
Following needs to be done, for enabling JMX access for Tomcat installed as a Windows service, that has a name "ApacheTomcatWindowsServer" for example:
Install Tomcat as Windows service, either using the command (first cd into \bin\ )
service.bat install
or your custom scripts.
Enable Apache Service Manager for the installed service using the following command:
tomcat7w.exe //MS//ApacheTomcatWindowsServer
This should start Apache Service Monitor program on your system tray. Click on its icon. select 'Configure', click on the 'Java' tab and append the following on the 'Java Options' text box, one option per line:
-Dcom.sun.management.jmxremote.port=8090
-Dcom.sun.management.jmxremote.authenticate=false
-Dcom.sun.management.jmxremote.ssl=false
Save and exit and restart the service.
To connect to the JMX console, fire jconsole from your JDK installation, click 'New Connection', specify 'Remote Process' and enter hostname:8090.
you can also uninstall the service by
service.bat remove
then edit the service.bat and add the parameters in your StartPath and add the options
-Djavax.management.builder.initial=;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.authenticate=false;-Dcom.sun.management.jmxremote.ssl=false
here is the sample StartPath in my file
--StartPath "C:\tomcat7\" --Startup auto --JvmOptions "-Dcatalina.home=%CATALINA_HOME%;-Dcatalina.base=%CATALINA_BASE%;-Djava.endorsed.dirs=%CATALINA_HOME%\endorsed;-Djava.io.tmpdir=%CATALINA_BASE%\temp;-Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager;-Djava.util.logging.config.file=%CATALINA_BASE%\conf\logging.properties;-Djava.rmi.server.hostname=;-Djavax.management.builder.initial=;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.authenticate=false;-Dcom.sun.management.jmxremote.ssl=false" %JAVA_OPTS% ^
re-install the service by
service.bat install
then start Tomcat to apply changes
Related
I installed tomcat 7 in my windows 7.Then ran C:\apache-tomcat-7.0.57\binstartup.bat,one window will open for 1 second and closes.when i hit http //localhost/8080 ,its not dsiplaying anything.I just checked C:\apache-tomcat-7.0.57\conf/server.xml and port is 8080.
Can somebody help on this.
Read RUNNING.txt and create C:\apache-tomcat-7.0.57\bin\setenv.bat file that sets JRE_HOME (or JAVA_HOME) path for Tomcat.
Sample from Tomcat 7 RUNNING.txt file using Java 6 JRE:
set "JRE_HOME=%ProgramFiles%\Java\jre6"
exit /b 0
You need to set Java_Home in Cataline.bat first in order to run TomCat server.
Additional Information for running project using Tomcat Server.
You can cd into the folder where tomcatXX/bin is through command line and run "run startup". So, when you , run startup on command line it tries to run script from startup.bat file, probably it crashed because port to be used by TomCat to run server is already in use. If you try to point your url to localhost:8080, if TomCat's home page appears, that would be because your server is already running. You should ideally also try to point to Windows -> Preference -> Runtime Environment. Check if Tomcat server is added in list under Server Runtime Environment window, if not try to add that server by clicking Add button, and trying to locate where Tomcat/bin is stored. If that still doesn't help, I would suggest you to also try right clicking a project on your IDE then click Run As, then click Run Configuration, it will give you option to run application using TomcatServer. List of servers will be found on left side of Run Configuration window.
I am a newbie on Liferay and furthermore 100% Windows infrastructure knowledge based. I installed Liferay 6.2 on my Windows 2012R2 server together with Java jdk-8u5 version. All is running perfect as long as I am logged in as user on the Server via remotedesktop having open the tomcat startup.bat window.
What have I to do exactly to start Liferay and/or tomcat as service?
Thanks in advance for your efforts.
Configuring liferay or tomcat to run as a service on a windows server doesn't differ that much.So in order to do that you have to add some files to the LIFERAY_HOME\tomcat\bin directory.
To get those files you have to download a full version of 64-bitWindows tomcat from here :
http://tomcat.apache.org/download-70.cgi.
Extract the zip and go to the bin directory, copy service.bat , tomcat7.exe and tomcat7w.exe to this location : LIFERAY_HOME\tomcat\bin
Setting Up the service
Open the commad prompt (Make sure you have admin rights or run the command prompt as administrator),In Command Prompt go to LIFERAY_HOME\tomcat\bin and Execute the following command
service.bat install tomcat7
This will install the tomcat6 service in windows.
Now execute following commond to setup additional configuration for the service
tomcat7w.exe ES tomcat7.exe
2 . Extra configuration :
-XX:MaxPermSize=512m
-Dfile.encoding=UTF8
-Duser.timezone=GMT
-Djava.security.auth.login.config="%CATALINA_HOME%/conf/jaas.config"
-Dorg.apache.catalina.loader.WebappClassLoader.ENABLE_CLEAR_REFERENCES=false
and make sure to provide enough memory for your service by setting the initial memory pool and the maximum one.
Either go with Rafik Beldi's answer (quite an effort, wow) or just go to tomcat's documentation in case you're still missing some information
I had to delete what was in Java Options completely or it wouldn't start: and then I entered:
-XX:MaxPermSize=512m
-Dfile.encoding=UTF8
-Duser.timezone=America/New_York
-Dorg.apache.catalina.loader.WebappClassLoader.ENABLE_CLEAR_REFERENCES=false
-Djava.net.preferIPv4Stack=true
note that where I am: America/New_York allows for both EST and EDT
I need to install Tomcat 7 as a Windows service and to start the service manually.
Referring to How to install Tomcat as a Windows service, I believe I would need to specify the following on the command line:
tomcat7 //IS//Tomcat7 --DisplayName="Apache Tomcat 7" --Install="C:\Tomcat7\bin\tomcat7.exe
Do I also need to specify all or some of the following on the command line like in the example? If only some, please specify which ones. If anything in the example is incorrect, please specify.
--Jvm=auto
--StartMode=jvm
--StopMode=jvm
--StartClass=org.apache.catalina.startup.Bootstrap
--StartParams=start
--StopClass=org.apache.catalina.startup.Bootstrap
--StopParams=stop
What I need for sure is to specify the following because I need to tell Tomcat to use a specific java home and not the java home set by the environment variable JAVA_HOME on the server where this will be installed.
--JavaHome="C:\Program Files\Java\jdk1.7.0_51
The reason: the server already has a different version of Tomcat (5.5) and it uses an older version of the JDK (1.5). I must not change JAVA_HOME on the server. I simply need to ensure Tomcat 7 uses JDK 1.7 and I have tried this line:
C:\tomcat7\bin>tomcat7 //IS//Tomcat7 --DisplayName="Apache Tomcat 7" --Install="C:\Tomcat7\bin\tomcat7.exe" --JavaHome="C:\Program Files\Java\jdk1.7.0_51"
When I attempt to Start the service, the following error message is displayed:
Windows could not start the Apache Tomcat 7 on Local Computer. For
more information, review the System Event Log. If this is a
non-Microsoft service, contact the service vendor, and refer to
service-specific error code 1.
I had a look at the System Event Viewer and it provides the following information:
The Apache Tomcat 7 service terminated with service-specific error Incorrect function..
I need to figure out these steps because I then need to provide the support team with the information to install this service on the production server. So any help would be greatly appreciated!
Use Chocolatey from Powershell command line:
first install Chocolatey
PS:\> iex ((new-object net.webclient).DownloadString('https://chocolatey.org/install.ps1'))
To install Tomcat
PS:\> choco install tomcat
To upgrade
PS:\> choco upgrade tomcat
Seems like a mismatch in your java JVM and tomcat version.
The tomcat7.exe wrapper program actually
"runs" the JVM, it must match the type of JVM that it runs, in terms
of 32bit/64bit version. If you try to start a 64-bit JVM with a 32-bit
tomcat7.exe, it won't work, and vice-versa.
Reference
This is because of shortage in physical RAM.
Check the Minimum System Requirements on Tomcat docs and try to close unnecessary programs if possible.
Use Chocolatey from Powershell command line:
PS> iex ((new-object net.webclient).DownloadString('https://chocolatey.org/install.ps1'))
To install Tomcat:
PS> choco install tomcat
To upgrade:
PS> choco upgrade tomcat
I'm unable to find an option to setup remote debugging in JBossWeb 2.1.4 on Windows. It is not installed as a service and there are no .bat scripts where I can edit the JAVA_OPTS environment variable to include:
-Xdebug -Xrunjdwp:transport=dt_socket,server=y,suspend=n,address=4142
The only thing in the jboss web bin directory are jbossweb.exe files.
I've tried editing the run configuration in eclipse to start the container by running jbossweb.exe and setting the environment variable JAVA_OPTS to the above, but it doesn't listen on port 4142 on startup (ie, there seems to be no effect in adding the environment variable to the run configuration).
Any ideas here?
If you control the server from eclipse with for instance JBoss Tools, you can just click "debug" instead of "start" in the Server pane in order to start up in debug mode.
You can create such bat script by yourself. Just add jboss.bat file to bin subdirectory of JBoss install directory and put there:
java -Xdebug -Xrunjdwp:transport=dt_socket,server=y,suspend=n,address=4142 -jar "D:\JBoss.org\JBoss Web 2.1\bin\bootstrap.jar" start
When you run this script, you will get JBoss running in debug mode. Probably, it won't help you in all situations, but it worked for me.
I saw something once for wrappers used to do this but it asked for a licensing fee. Is there an open source way to do this?
"JBoss AS comes with Windows service executable as part of JBossNative
that can run JBoss Application Server as service.
The service executable jbosssvc.exe transforms the run.bat and
shutdown.bat batch scripts to services. This means that any change
made to those scripts will be used both in service and command
line mode."
http://www.jboss.org/community/wiki/JBossNativeWindows
A Problem I had was the remote Access to JBoss. In JBoss 4.2.3 you must start it with the Parameter run.bat -b 0.0.0.0 to have access from other hosts.
I think since JBoss 4.2 remote access is turned off by default.
My solution was to adjust the :RESTART Section in the file run.bat like this:
:RESTART
"%JAVA%" %JAVA_OPTS% ^
-Djava.endorsed.dirs="%JBOSS_ENDORSED_DIRS%" ^
-classpath "%JBOSS_CLASSPATH%" ^
org.jboss.Main -b "0.0.0.0" %*