I am struggling to get list of places that matches current category(multiple dataset) and city:
what i did is the following,
$cat = Category::find($request->category_id)->toArray();
$cat_id = $cat['id'];
and
$places = DB::table('places')
->where('category',$cat_id)
->where('city_id', $request->city_id)
->get();
See screenshot of the dataset:
Data in the database
For your current problem, you can use the LIKE operator.
$places = DB::table('places')
->where('category','LIKE', '%"'.$cat_id.'"%')
->where('city_id', $request->city_id)
->get();
but the above code will not solve your problem permanently. It looks like you are trying to create a many to many relationship in this case the best practice to use pivot tables for this. Better if you could update the schema as an example and follow the Laravel standards to achieve this. Example:
table: category_place , having columns ["category_id", "place_id"]
in the same way, you need to update the following schema
Place Type
table: place_place_type, columns ["place_id", "place_type_id"]
Amenities
table: amenity_place, columns ["amenity_id", "place_id"]
Ref. link: https://laravel.com/docs/8.x/eloquent-relationships#many-to-many-polymorphic-relations
I have two tables in my database
My first table
And my second table
I would like to count how many gold members exists and how many silver members exists... I want to do a single count for each category... The rif can be repeated in the column but is the key to join the two tables.. I'm working with Query Builder and I would like to continue work with that. Someone can help me?
I tried with this code but didn't work
$count = DB::table('table1')
->join('table2', 'table1.rif', '=', 'table2.rif')
->select(DB::raw('category')
->count();
Try this:
use Illuminate\Support\Facades\DB;
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->select(DB::raw('count(*) as count'), 'table1.category as category')
->groupBy('category')
->get();
If you want to count only a specific category:
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->where('table1.category', 'Silver')
->count()
See Laravel docs for more info.
in a Laravel application, I have a list of companies. Some of those are related to a subscriptions table in a 1 x n relation.
I want to order the companies in a way that the ones which have a subscription appear before the ones which have no subscription using just one db query.
Any idea is much appreciated!
thanks!
Laravel uses separate queries to eager load relationships. So if you want to do this you will need to join the tables and order by...
Something in the form...
$companies = App\Companies::join('subscriptions as sub', 'sub.company_id', '=', 'company.id')
->orderBy('sub.somefield', 'DESC')
->select(what you need)
->with('if you need the relation data');
You know you can also only query those records that have a relationship with
$companies = App\Companies::has('subscription')->get();
Maybe that is all you need... and
$companies = App\Companies::doesntHave('subscription')->get();
... returns the opposite where the company has no subscription...
I have the following query:
$items = UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->get();
I need to order it by item.type so I tried:
$items = UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy('item.type')
->get();
but I get Unknown column 'item.type' in 'order clause'
What I am missing?
join() worked fine thanks to #rypskar comment
$items = UserItems
::where('user_id','=',$this->id)
->where('quantity','>',0)
->join('items', 'items.id', '=', 'user_items.item_id')
->orderBy('items.type')
->select('user_items.*') //see PS:
->get();
PS: To avoid the id attribute (or any shared name attribute between the two tables) to overlap and resulting in the wrong value, you should specify the select limit with select('user_items.*').
Well, your eager loading is probably not building the query you're expecting, and you can check it by enabling the query log.
But I would probably just use a collection filter:
$items = UserItems::where('user_id','=',$this->id)
->where('quantity','>',0)
->get()
->sortBy(function($useritem, $key) {
return $useritem->item->type;
});
You can use withAggregate function to solve your problem
UserItems::withAggregate('item','type')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy('item_type')
->get();
I know it's an old question, but you can still use an
"orderByRaw" without a join.
$items = UserItems
::where('user_id','=',$this->id)
->where('quantity','>',0)
->orderByRaw('(SELECT type FROM items WHERE items.id = user_items.item_id)')
->get();
For a one to many relationship, there is an easier way. Let's say an order has many payments and we want to sort orders by the latest payment date. Payments table has a field called order_id which is FK.
We can write it like below
$orders = Order->orderByDesc(Payment::select('payments.date')->whereColumn('payments.order_id', 'orders.id')->latest()->take(1))->get()
SQL Equivalent of this code:
select * from orders order by (
select date
from payments
where order_id = payments.id
order by date desc
limit 1
) desc
You can adapt it according to your example. If I understood right, order's equivalent is user and payment's equivalent is item in your situation.
Further reading
https://reinink.ca/articles/ordering-database-queries-by-relationship-columns-in-laravel
I found another way of sorting a dataset using a field from a related model, you can get a function in the model that gets a unique relation to the related table(ex: table room related to room category, and the room is related to a category by category id, you can have a function like 'room_category' which returns the related category based on the category id of the Room Model) and after that the code will be the following:
Room::with('room_category')->all()->sortBy('room_category.name',SORT_REGULAR,false);
This will get you the rooms sorted by category name
I did this on a project where i had a DataTable with Server side processing and i had a case where it was required to sort by a field of a related entity, i did it like this and it works. More easier, more proper to MVC standards.
In your case it will be in a similar fashion:
User::with('item')->where('quantity','>',0)->get()->sortBy('item.type',SORT_REGULAR,false);
$users
->whereRole($role)
->join('address', 'users.id', '=', 'address.user_id')
->orderByRaw("address.email $sortType")
->select('users.*')
you can simply do it by
UserItems::with('item')
->where('user_id','=',$this->id)
->where('quantity','>',0)
->orderBy(
Item::select('type')
->whereColumn('items.useritem_id','useritems.id')
->take(1),'desc'
)
->get();
Hi i have tables with one to many relation
sectors
id
name
position
seat_plans
id
name
sector_id
I just want to select all seat plans order by sectors.position. I tried
$seat_plans = SeatPlan::with(['sector' => function($q){
$q->orderBy('position');
}
])->get();
but it is not working. when i check The SQL it is generating query like
select * from seat_plans
can anybody please tell me how to do this?
I don't think you need a custom function for your use case. Instead try this:
$users = DB::table('seat_plans')
->join('sectors', 'seat_plans.sector_id, '=', 'sectors.id')
->select('seat_plans.*')
->orderBy('sectors.position')
->get();