When i m using has many without select it returns all fields from userTrancastion table
Invoicemodule.php
$invoice = UserInvoiceDetail::with('transaction')
->select('Id','UserId','TotalPrice')
->where('UserId','=',$playerId)
->get();
return $invoice;
UserInvoiceDetail.php
class UserInvoiceDetail extends Model
{
protected $table = 'user_invoice_details';
protected $primaryKey ='Id';
public function transaction()
{
return $this->hasMany(UserTransaction::class, 'InvoiceId');
}
}
Output
"Invoices":
[
{
"Id": 1,
"UserId": 5,
"TotalPrice": 110,
"transaction": [
{
"Id": 1,
"InvoiceId": 1,
"UserId": 5,
"ReferenceTransactionId": null,
"CategoryId": 1,
"ProductId": 140,
"Price": 5,
"Quantity": 5,
"CustomerId": 1,
},
{
"Id": 2,
"InvoiceId": 1,
"UserId": 5,
"ReferenceTransactionId": null,
"CategoryId": 2,
"ProductId": 3,
"Price": 15,
"Quantity": 3,
"CustomerId": 1,
}
]
}
]
But When i m using has many with select it returns nothing userTrancastion table
UserInvoiceDetail.php
class UserInvoiceDetail extends Model
{
protected $table = 'user_invoice_details';
protected $primaryKey ='Id';
public function transaction()
{
return $this->hasMany(UserTransaction::class, 'InvoiceId')->select('user_transactions.Id','user_transactions.ProductId');
}
}
Output
"Invoices": [
{
"Id": 1,
"UserId": 5,
"TotalPrice": 110,
"transaction": []
},
{
"Id": 2,
"UserId": 5,
"TotalPrice": 110,
"transaction": []
}
]
why this is happening, I want to use join in transaction() function, so i need only selective fields.
How can use select with hasmany()?
Thank you in advance.
The relation need to the column that by which it related so add InvoiceId
also, it doesn't need to add user_transactions
public function transaction()
{
return $this->hasMany(UserTransaction::class, 'InvoiceId')->select('Id','ProductId','InvoiceId');
}
Related
I want to filter users based on their subscription_status which s stored in a pivot table.
I have Three tables users , subscription_packages , subscription_package_user
$user=User::with(['studentDetails','subscriptionsSatus.courses'])
->withPagination($offset,$perPage)
->get()
->sortBy('first_name')->values();
this code return the response is
[
{
"id": 44,
"first_name": "Abcd Test",
"last_name": "Test lastname",
"student_details": null,
"subscriptions_satus": [
{
"id": 1,
"name": "Gold",
"price": 3000,
"user_id": "2"
"pivot": {
"user_id": 44,
"subscription_package_id": 1,
"subscription_status": "on_free_trial",
"expires_on": null,
"id": 9
},
"courses": [
{
"id": 18,
"title": "English Grammar for Class 3",
"price": 400,
"strikethrough_price": null,
"status": "draft",
"user_id": 2,
"image": "http://127.0.0.1:8000/courses/1615702915.png",
"description": null,
"pivot": {
"subscription_package_id": 1,
"course_id": 18,
}
}
]
}
]
}]
i want to return only users who having subscription_status =$filter.
$filter='acive'or 'on_free_trail'
my model is
public function subscriptionsSatus()
{
return $this->belongsToMany(SubscriptionPackage::class)->withTimestamps()->withPivot('subscription_status','expires_on','id');
}
I havetried
$filter=$request->input('filter')??"active";
$user=User::with(['studentDetails','subscriptionsStatus.courses'])
->whereHas('subscriptionsStatus', function($query) use($filter){
$query->wherePivot('subscription_status','=',$filter);
})
->withPagination($offset,$perPage)
->get()
->sortBy('first_name')->values();
But Got error Column not found 'pivot'
You need to use wherePivot along with the orWhere like below:
public function subscriptionsStatus()
{
return $this->belongsToMany(SubscriptionPackage::class)
->withTimestamps()
->withPivot('subscription_status','expires_on','id')
->wherePivot(function($q){
return $q->where('subscription_status','=','active')
->orWhere('subscription_status','=','on_free_trail');
});
}
Update
Or in your controller:
$user=User::with(['studentDetails','subscriptionsStatus.courses'])
->whereHas('subscriptionsStatus', function($query) use($filter){
$query->withPivot('subscription_status')
->wherePivot('subscription_status','=',$filter);
})
->withPagination($offset,$perPage)
->get()
->sortBy('first_name')->values();
I wanted to apply some condition in foodOrders. Is it possible to apply condition inside map function that acts as where $foodOrder->foodOrders->where('invoice_id',null)->get();
public function getTableList(Request $request){
$skip =$request->skip;
$limit=$request->limit;
$totaltable = Table::get()->count();
$table = Table::skip($skip)->take($limit)->orderBy('id', 'DESC')->get();
$table->map(function($foodOrder){
$foodOrder->foodOrders;
});
}
Below is the output that this query returns. But I only want the data with null invoice_id
{
"success": true,
"message": "Lists of Table.",
"data": [
{
"id": 2,
"table_number": "TN02",
"food_orders": [
{
"id": 16,
"food_items_id": 1,
"table_id": 2,
"invoice_id": null,
"quantity": 2,
"price": "2000.00"
},
{
"id": 17,
"food_items_id": 2,
"table_id": 2,
"invoice_id": null,
"quantity": 3,
"price": "150.00"
}
]
},
{
"id": 1,
"table_number": "TN01",
"created_at": "2020-10-25 10:44:31",
"updated_at": "2020-10-25 10:44:31",
"food_orders": [
{
"id": 14,
"food_items_id": 1,
"table_id": 1,
"invoice_id": 39,
"quantity": 1,
"price": "2000.00"
}
]
}
]
}
Not the best approach, bu this should do the trick
$table->map(function($foodOrder){
$foodOrder->foodOrders=$foodOrder->foodOrders()->where('invoice_id',null)->get();
});
Note the scopes, you need them to apply where condition. And we say = so the further changes are propagated.
I think what you need to use is a filter and not a map. Or am I wrong ?
You can filter out the whitelisted records for the food_orders.
$table->map(function($record){
$record->food_orders = collect($record->food_orders)
->filter(fn($foodOrder) => is_null($foodOrder->invoice_id));
return $record;
});
From the output data you have shown above it seems that the food_orders is a hasMany relation on the model, so it would be easy to filter out the relation when eager loading
Assuming that Table model has a relation defined for food_orders
class Table extends Model
{
public function food_orders()
{
return $this->hasMany(FoodOrder::class);
}
//... rest of the class code
}
You can constrain the related models when eager loading
$table = Table::with([
'food_orders' => fn($query) => $query->whereNull('invoice_id')
])
->skip($skip)
->take($limit)
->orderBy('id', 'desc')
->get();
I have a Product table related with Image table, one to many relationship.
How do I get Image records not as array? Instead, return only 1 Image record as column_name: value
This code:
$products = $request->user()->products()->orderBy('id', 'desc')->with(['images' => function($query) {
$query->where('featured', 1)->limit(1);
}])->get();
Is returning data like this :
{
"id": 13,
"name": "Shoes",
"price": "3.00",
"stock": 5,
"pivot": {
"user_id": 7,
"product_id": 13
},
"images": [
{
"id": 5,
"file": "5da9d9b493403.png",
"featured" 1,
"pivot": {
"product_id": 13,
"image_id": 5
}
}
]
}
}
How to make it return like this?
{
"id": 13,
"name": "Shoes",
"price": "3.00",
"stock": 5,
"pivot": {
"user_id": 7,
"product_id": 13
},
"images": "5da9d9b493403.png"
}
}
You can append a custom accessor that gets the first image from the relationship
In the Product model
protected $appends = ['images'];
public function getImagesAttribute()
{
return $this->images()->where('featured', 1)->first()->file;
}
public function images()
{
return $this->hasMany('App\Image');
}
Then just return the query without eager loading
$products = $request->user()->products()->orderBy('id', 'desc')->get();
Hope this helps
In the Product model
protected $appends = ['images'];
public function images()
{
return $this->hasMany('App\Image')->select(['name'])->first();
}
select the name only and return first relation
I'm quite new to Laravel,
Let's say I have 2 tables: main_sport and sub_sport. These two tables have a one-to-many relationship. 1 sport can have many sub sports.
I want the following json format
{
"success": "1",
"sports": [
"id": 1,
"name_of_categories": "Popular Sports",
"sub_sports:[
{
"id": 1,
"name_sub_sport_category": "Badminton"
},
{
"id": 2,
"name_sub_sport_category": "Football"
},
{
"id": 3,
"name_sub_sport_category": "Cricket"
},
]
]
"sports":[
"id": 2,
"name_of_categories": "Team Sports",
"sub_sports:[
{
"id": 4,
"name_sub_sport_category": "Badminton"
},
{
"id": 5,
"name_sub_sport_category": "Football"
},
]
]
}
I try for this function and i am getting following result
public function fetch()
{
$query= DB::table('details')
->join('table_sub_sport_category','table_sub_sport_category.id','=','details.sub_id')
->join('table_main_sport_category','table_main_sport_category.id','=','details.main_id')
->select(DB::raw('table_main_sport_category.id as id'),'table_main_sport_category.name_of_categories','table_sub_sport_category.name_sub_sport_category')
->get()
return response()->json(['success' =>'1','data'=>$query]);
}
{
"success": "1",
"data": [
{
"id": 1,
"name_of_categories": "Popular Sports",
"name_sub_sport_category": "Badminton"
},
{
"id": 1,
"name_of_categories": "Popular Sports",
"name_sub_sport_category": "Football"
},
{
"id": 1,
"name_of_categories": "Popular Sports",
"name_sub_sport_category": "Cricket"
},
]
}
Could you help me to get the desired result?
You should define sub_sport in the main sport Model like this:
class Sport extends Model{
public function sub_sport(){
return $this->hasMany(SubSport::class);
}
}
And in your controller you should write this:
$data = Sport::with('sub_sport')->get();
Use below code
$query= DB::table('details')
->join('table_sub_sport_category','table_sub_sport_category.id','=','details.sub_id')
->join('table_main_sport_category','table_main_sport_category.id','=','details.main_id')
->select(DB::raw('table_main_sport_category.id as id'),'table_main_sport_category.name_of_categories','table_sub_sport_category.name_sub_sport_category')
->get()
return Response::json([
'status' => 'error',
'sports' => $query
], 200);
I have a table user_childrens whose contains id_parent and id_user.
I'm trying to list all childrens of the parent with this:
code:
//relation in model via belongsTo
$idparent = auth('api')->user()->id;
$list = UserChildren::where('id_parent',$idparent)
->with('child:id,name,email')
->get();
return $list->toJson();
The return is:
[
{
"id": 1,
"id_parent": 1,
"id_user": 1,
"created_at": null,
"updated_at": null,
"child": {
"id": 1,
"name": "Mr. Davin Conroy Sr.",
"email": "prempel#example.com"
}
},
{
"id": 4,
"id_parent": 1,
"id_user": 2,
"created_at": null,
"updated_at": null,
"child": {
"id": 2,
"name": "Krystel Lehner",
"email": "cernser#example.net"
}
}
]
But it's API so I want only the child column like:
[
{
"id": 1,
"name": "Mr. Davin Conroy Sr.",
"email": "prempel#example.com"
},
{..}
]
UserChildren Model:
public function child() {
return $this->belongsTo('App\User','id_user','id');
}
I know that I could do this via .map() on collection but maybe there is other solution already on this query
You can use this code
$idparent = auth('api')->user()->id;
$childs = User::whereHas('user_childrens', function ($query) use ($idparent) {
$query->where('id_parent', $idparent);
})->get(['id', 'name', 'email']);
dd($childs->toJson());
And User model define user_childrens relation.
public function user_childrens()
{
return $this->hasMany('App\UserChildren','id_user','id');
}
See also docs https://laravel.com/docs/5.5/eloquent-relationships#querying-relationship-existence