I wanted to apply some condition in foodOrders. Is it possible to apply condition inside map function that acts as where $foodOrder->foodOrders->where('invoice_id',null)->get();
public function getTableList(Request $request){
$skip =$request->skip;
$limit=$request->limit;
$totaltable = Table::get()->count();
$table = Table::skip($skip)->take($limit)->orderBy('id', 'DESC')->get();
$table->map(function($foodOrder){
$foodOrder->foodOrders;
});
}
Below is the output that this query returns. But I only want the data with null invoice_id
{
"success": true,
"message": "Lists of Table.",
"data": [
{
"id": 2,
"table_number": "TN02",
"food_orders": [
{
"id": 16,
"food_items_id": 1,
"table_id": 2,
"invoice_id": null,
"quantity": 2,
"price": "2000.00"
},
{
"id": 17,
"food_items_id": 2,
"table_id": 2,
"invoice_id": null,
"quantity": 3,
"price": "150.00"
}
]
},
{
"id": 1,
"table_number": "TN01",
"created_at": "2020-10-25 10:44:31",
"updated_at": "2020-10-25 10:44:31",
"food_orders": [
{
"id": 14,
"food_items_id": 1,
"table_id": 1,
"invoice_id": 39,
"quantity": 1,
"price": "2000.00"
}
]
}
]
}
Not the best approach, bu this should do the trick
$table->map(function($foodOrder){
$foodOrder->foodOrders=$foodOrder->foodOrders()->where('invoice_id',null)->get();
});
Note the scopes, you need them to apply where condition. And we say = so the further changes are propagated.
I think what you need to use is a filter and not a map. Or am I wrong ?
You can filter out the whitelisted records for the food_orders.
$table->map(function($record){
$record->food_orders = collect($record->food_orders)
->filter(fn($foodOrder) => is_null($foodOrder->invoice_id));
return $record;
});
From the output data you have shown above it seems that the food_orders is a hasMany relation on the model, so it would be easy to filter out the relation when eager loading
Assuming that Table model has a relation defined for food_orders
class Table extends Model
{
public function food_orders()
{
return $this->hasMany(FoodOrder::class);
}
//... rest of the class code
}
You can constrain the related models when eager loading
$table = Table::with([
'food_orders' => fn($query) => $query->whereNull('invoice_id')
])
->skip($skip)
->take($limit)
->orderBy('id', 'desc')
->get();
Related
Let me make it simple, In my models, I have countries and cities. My goal is, I want to select and display only the cities that has shops and it should also have datas and the employees should not be NULL
In the below given array, my city has two shops where id - 13 that doesn't have any datas and id - 19 which is having data.
[
{
"id": 1,
"created_at": "2022-06-02T06:07:31.000000Z",
"updated_at": "2022-06-02T06:07:31.000000Z",
"name": "Niue",
"cities": [
{
"id": 13,
"created_at": "2022-06-02T06:07:44.000000Z",
"updated_at": "2022-06-02T06:07:44.000000Z",
"country_id": 1,
"name": "North Michealbury",
"shops": [] //empty
},
{
"id": 19,
"created_at": "2022-06-02T06:07:44.000000Z",
"updated_at": "2022-06-02T06:07:44.000000Z",
"country_id": 1,
"name": "Millsmouth",
"shops": [
{
"id": 1,
"created_at": "2022-06-02T06:14:37.000000Z",
"updated_at": "2022-06-02T06:14:37.000000Z",
"city_id": 19,
"name": "Roberts-Okuneva",
"employees_count": 146
}
]
}
]
}
]
This is the code that, I have written in my controller. The goal is, I want to select and show only those cities that has shops with employees.
return Country::with(['cities','cities.shops'=>function($employee){
$employee->withCount('employees')->where('city_id',19);
}])->whereHas('cities',function($city){
$city->where('cities.id',19);
})->get();
These are my models, each of them has a hasMany relationship
Country model
public function Cities(){
return $this->hasMany(City::class);
}
City model
public function shops(){
return $this->hasMany(Shop::class);
}
Shop model
public function employees(){
return $this->belongsToMany(User::class,'shop_employees','shop_id','employee_id');
}
You can try
//Get all cities which have shops having at least one employee
return Country::with([
'cities',
'cities.shops' => function($query) {
$query->withCount('employees');
}
])
->whereHas('cities', function($query) {
$query->whereHas('shops', function($query) {
$query->has('employees');
});
})
->get();
i found another solution querying with clause.
return Country::whereHas('cities',function($cities){
$cities->where('country_id',1);
})->with(['cities'=>function($shops){
$shops->has('shops')->where('cities.country_id',1);
},'cities.shops'=>function($employee){
$employee->withCount('employees');
}])->get();
I have this query which is working just fine except when i call ->first() function on it, the data from certain relations disappear.
What I am trying to achieve:
I am trying to get the sp_services where price is lowest. The first object (id: 1) in data array has two sp_services, the second object inside data array (id: 13) has only one sp_services. When i do $query->orderBy('sp_services.price', 'DESC')->first(); The object from first one is there but the second one where (id: 6, name: car wash) disappears and there is only empty array.
In the below mentioned JSON I'm only showing the relevant data here. Can anyone please tell me what am i doing wrong here ? and why is it not working. Also is there a better way to achieve desired result.
Query:
$branchesQuery = SpBranch::query();
$branchesQuery->where('status', true);
$branchesQuery->when($request->filled('price'), function($query) use($request) {
return $query->with(['service_provider' => function($query) use($request) {
$query->whereHas('sp_services')
->with(['sp_services' => function($query) use($request) {
$query->orderBy('sp_services.price', 'DESC'); //->first();
}]);
}]);
});
$branches = $branchesQuery->paginate($perPageLimit);
return $branches;
Models:
class SpBranch extends Model
{
public function service_provider()
{
return $this->belongsTo(ServiceProvider::class, 'sp_id');
}
}
class ServiceProvider extends Model
{
public function sp_services()
{
return $this->hasMany(SpService::class, 'sp_id', 'id');
}
}
JSON:
{
"data": [
{
"id": 1,
"sp_id": 1,
"name": "Branch 01",
"status": 1,
"service_provider": {
"id": 1,
"name": "Service Provider 01",
"sp_services": [
{
"id": 3,
"sp_id": 1,
"branch_id": null,
"name": "Service 03",
"price": 50
},
{
"id": 4,
"sp_id": 1,
"branch_id": null,
"name": "Service 04",
"price": 70
}
]
}
},
{
"id": 13,
"sp_id": 5,
"name": "Branch 13",
"status": 1,
"service_provider": {
"id": 5,
"name": "Service Provider 05",
"sp_services": [
{
"id": 6,
"sp_id": 5,
"branch_id": null,
"name": "car wash",
"price": 300
}
]
}
}
]
}
You cannot order or group by a eager loaded table on database, because what WITH method does is that it fires a new query meaning that is not connected to the first one at all, what you can do is you can order or group them in collections meaning after the data is fetch from db you can order them, I think function is called ->sortBy() which will order by the field you want, but it will cost you on performance. If performance is important in your case, you can always use joins to join both tables which will enable you order results directly from database.
class ServiceProvider extends Model
{
public function sp_services()
{
return $this->hasMany(SpService::class, 'sp_id', 'id')->orderBy('price', 'asc');
}
}
I have a Product table related with Image table, one to many relationship.
How do I get Image records not as array? Instead, return only 1 Image record as column_name: value
This code:
$products = $request->user()->products()->orderBy('id', 'desc')->with(['images' => function($query) {
$query->where('featured', 1)->limit(1);
}])->get();
Is returning data like this :
{
"id": 13,
"name": "Shoes",
"price": "3.00",
"stock": 5,
"pivot": {
"user_id": 7,
"product_id": 13
},
"images": [
{
"id": 5,
"file": "5da9d9b493403.png",
"featured" 1,
"pivot": {
"product_id": 13,
"image_id": 5
}
}
]
}
}
How to make it return like this?
{
"id": 13,
"name": "Shoes",
"price": "3.00",
"stock": 5,
"pivot": {
"user_id": 7,
"product_id": 13
},
"images": "5da9d9b493403.png"
}
}
You can append a custom accessor that gets the first image from the relationship
In the Product model
protected $appends = ['images'];
public function getImagesAttribute()
{
return $this->images()->where('featured', 1)->first()->file;
}
public function images()
{
return $this->hasMany('App\Image');
}
Then just return the query without eager loading
$products = $request->user()->products()->orderBy('id', 'desc')->get();
Hope this helps
In the Product model
protected $appends = ['images'];
public function images()
{
return $this->hasMany('App\Image')->select(['name'])->first();
}
select the name only and return first relation
I have a table user_childrens whose contains id_parent and id_user.
I'm trying to list all childrens of the parent with this:
code:
//relation in model via belongsTo
$idparent = auth('api')->user()->id;
$list = UserChildren::where('id_parent',$idparent)
->with('child:id,name,email')
->get();
return $list->toJson();
The return is:
[
{
"id": 1,
"id_parent": 1,
"id_user": 1,
"created_at": null,
"updated_at": null,
"child": {
"id": 1,
"name": "Mr. Davin Conroy Sr.",
"email": "prempel#example.com"
}
},
{
"id": 4,
"id_parent": 1,
"id_user": 2,
"created_at": null,
"updated_at": null,
"child": {
"id": 2,
"name": "Krystel Lehner",
"email": "cernser#example.net"
}
}
]
But it's API so I want only the child column like:
[
{
"id": 1,
"name": "Mr. Davin Conroy Sr.",
"email": "prempel#example.com"
},
{..}
]
UserChildren Model:
public function child() {
return $this->belongsTo('App\User','id_user','id');
}
I know that I could do this via .map() on collection but maybe there is other solution already on this query
You can use this code
$idparent = auth('api')->user()->id;
$childs = User::whereHas('user_childrens', function ($query) use ($idparent) {
$query->where('id_parent', $idparent);
})->get(['id', 'name', 'email']);
dd($childs->toJson());
And User model define user_childrens relation.
public function user_childrens()
{
return $this->hasMany('App\UserChildren','id_user','id');
}
See also docs https://laravel.com/docs/5.5/eloquent-relationships#querying-relationship-existence
I am using Laravel 5.5.13.
I am trying to fetch all Extensions but with certain extra properties based on their relations.
My goal is to get data like this, I am trying to get the latest_comment_date, thumbs_count, and thumbs_yes_count:
[
{
"id": 3,
"name": "Pull Refresh",
"created_at": "2017-11-10 06:04:44",
"updated_at": "2017-11-10 06:04:44",
"latest_comment_date": "2017-11-10 05:46:25",
"thumbs_count": 10,
"thumbs_yes_count": 2
}
]
I tried this:
return Extension::with([
'comments' => function($query) { // rename to 'latest_comment_date'
$query->orderBy('created_at', 'desc')->take(1);
},
'thumbs' => function($query) { // rename to 'thumbs_count'
$query->count();
},
'thumbs' => function($query) { // rename to 'thumbs_yes_count'
$query->where('like', '=', true)->count();
}
])->get();
This gives me data like this:
[
{
"id": 3,
"name": "Pull Refresh",
"created_at": "2017-11-10 06:04:44",
"updated_at": "2017-11-10 06:04:44",
"comments": [
{
"id": 10,
"body": "heck ya baby",
"displayname_id": 2,
"extension_id": 3,
"created_at": "2017-11-10 18:31:31",
"updated_at": "2017-11-10 18:31:31"
}
],
"thumbs": []
}
]
May you please help me to "pick as" stuff as I showed at top most?
For counting you should use withCount like so:
return Extension::withCount(
'thumbs',
'thumbs as thumbs_yes_count' => function($query) {
$query->where('like', '=', true);
})->get();
Reference: Counting related models
And for taking latest comment, you should create extra relationship like so:
public function latestComment()
{
return $this->hasOne(Comment::class)->orderBy('created_at', 'desc');
}
so the whole code would look like this:
return Extension::with('latestComment')->withCount(
'thumbs',
'thumbs as thumbs_yes_count' => function($query) {
$query->where('like', '=', true);
})->get();