Filter Data with Pivot Table Laravel Eloquent - laravel

I want to filter users based on their subscription_status which s stored in a pivot table.
I have Three tables users , subscription_packages , subscription_package_user
$user=User::with(['studentDetails','subscriptionsSatus.courses'])
->withPagination($offset,$perPage)
->get()
->sortBy('first_name')->values();
this code return the response is
[
{
"id": 44,
"first_name": "Abcd Test",
"last_name": "Test lastname",
"student_details": null,
"subscriptions_satus": [
{
"id": 1,
"name": "Gold",
"price": 3000,
"user_id": "2"
"pivot": {
"user_id": 44,
"subscription_package_id": 1,
"subscription_status": "on_free_trial",
"expires_on": null,
"id": 9
},
"courses": [
{
"id": 18,
"title": "English Grammar for Class 3",
"price": 400,
"strikethrough_price": null,
"status": "draft",
"user_id": 2,
"image": "http://127.0.0.1:8000/courses/1615702915.png",
"description": null,
"pivot": {
"subscription_package_id": 1,
"course_id": 18,
}
}
]
}
]
}]
i want to return only users who having subscription_status =$filter.
$filter='acive'or 'on_free_trail'
my model is
public function subscriptionsSatus()
{
return $this->belongsToMany(SubscriptionPackage::class)->withTimestamps()->withPivot('subscription_status','expires_on','id');
}
I havetried
$filter=$request->input('filter')??"active";
$user=User::with(['studentDetails','subscriptionsStatus.courses'])
->whereHas('subscriptionsStatus', function($query) use($filter){
$query->wherePivot('subscription_status','=',$filter);
})
->withPagination($offset,$perPage)
->get()
->sortBy('first_name')->values();
But Got error Column not found 'pivot'

You need to use wherePivot along with the orWhere like below:
public function subscriptionsStatus()
{
return $this->belongsToMany(SubscriptionPackage::class)
->withTimestamps()
->withPivot('subscription_status','expires_on','id')
->wherePivot(function($q){
return $q->where('subscription_status','=','active')
->orWhere('subscription_status','=','on_free_trail');
});
}
Update
Or in your controller:
$user=User::with(['studentDetails','subscriptionsStatus.courses'])
->whereHas('subscriptionsStatus', function($query) use($filter){
$query->withPivot('subscription_status')
->wherePivot('subscription_status','=',$filter);
})
->withPagination($offset,$perPage)
->get()
->sortBy('first_name')->values();

Related

Retrieves the latest data from a foreign key in a relation

I want to ask, can I retrieve the last foreign key data in the relation ?.
In this case I want to retrieve the last user transaction data.
for example in the transaction table between 3 months ago and now there are some transaction data as follows.
{
"current_page": 1,
"data": [
{
"id": 8,
"user_id": 1,
"type": "sell",
"created_at": "2019-12-11 11:55:31",
"updated_at": "2019-12-11 11:55:31",
"tax": null,
"invoice_number": null,
"name": "Fredy"
},
{
"id": 7,
"user_id": 1,
"type": "buy",
"created_at": "2019-11-20 17:14:55",
"updated_at": "2019-11-20 17:14:55",
"tax": null,
"tax_percent": "0.90",
"invoice_number": null,
"name": "Fredy"
},
{
"id": 6,
"user_id": 8,
"type": "buy",
"created_at": "2019-11-20 16:28:33",
"updated_at": "2019-11-20 16:28:33",
"tax": null,
"name": "Tommy"
},
{
"id": 5,
"user_id": 2,
"type": "buy",
"created_at": "2019-11-20 15:47:57",
"updated_at": "2019-11-20 15:47:57",
"tax": null,
"name": "Sarah"
},
{
"id": 4,
"user_id": 3,
"type": "buy",
"created_at": "2019-11-20 15:47:31",
"updated_at": "2019-11-20 15:47:31",
"tax": null,
"name": "John Doe"
},
],
}
This is the sample code that i made
public function index()
{
$start = Carbon::now()->subMonths(3)->format('Y-m-d') . ' 00:00:00';
$end = Carbon::now()->format('Y-m-d') . ' 23:59:59';
return $query = DB::table('transaction')
->join('users', 'users.id', '=', 'gold_transaction.user_id')
->select('transaction.id', 'user_id', 'users.*')
->whereBetween('transaction.created_at', [$start, $end])
->whereIn('transaction.id', [DB::raw("SELECT MAX(transaction.id) FROM transaction GROUP BY user_id")])->get();
}
What do i do if i only want to display users who did't make transaction more than 7 days from the last transaction for all users ?
Thank you.
Then you can do it like below,
Get user's transaction
$transaction = User::with(['transactions' => function ($q) use($start, $end){
$q->whereBetween('transactions.created_at', [$start, $end]);
])->find($user_id);
Get all users with their transactions
$transaction = User::with(['transactions' => function ($q) use($start, $end){
$q->whereBetween('transactions.created_at', [$start, $end]);
])->get();
assuming that you have transactions relation in your user model like below
public function transactions() {
return $this->hasMany('App\Transaction', 'user_id');
}

change hasManyThrough() relation attribute name through accessor

I have 3 Models
Campaign PK(id)
CampaignMedium FK(campaign_id)
AccountReceivable FK(campaign_medium_id) (has an amount column)
Controller function:
public function all()
{
return Campaign::with(['customer', 'receivedPayments'])->get();
}
In Campaign Model relationships are defined as follows:
public function customer()
{
return $this->belongsTo(Customer::class);
}
public function accountReceivable()
{
return $this->hasManyThrough(AccountReceivable::class, CampaignMedium::class);
}
public function receivedPayments()
{
return $this->accountReceivable()
->selectRaw('sum(account_receivables.amount) as total')
->groupBy('campaign_id');
}
public function getReceivedPaymentsAttribute()
{
if (!array_key_exists('receivedPayments', $this->relations)) {
$this->load('receivedPayments');
}
$relation = $this->getRelation('receivedPayments')->first();
return ($relation) ? $relation->total : 0;
}
Final Output:
{
"data": [
{
"id": 8,
"name": "example",
"image": "campaign/90375849f6c3cc6b0e542a0e3e6295b890375849f6c3cc6b0e542a0e3e6295b8.jpeg",
"amount": 10,
"description": "saddsa",
"start_at": "2019-02-12 00:00:00",
"end_at": "2019-02-12 00:00:00",
"due_at": "2019-02-12 00:00:00",
"status": "active",
"customer": {
"id": 1,
"name": "test",
"email": "info#test.com",
"image": "customer/ec812116705ff3ae85298234fe6c4e97ec812116705ff3ae85298234fe6c4e97.jpeg",
"address": "sample address"
},
"received_payments": [
{
"total": "700",
"laravel_through_key": 8
}
]
},
{
"id": 9,
"name": "example",
"image": "campaign/fff9fadc92a809513dc28134379851aafff9fadc92a809513dc28134379851aa.jpeg",
"amount": 10,
"description": "saddsa",
"start_at": "2019-02-12 00:00:00",
"end_at": "2019-02-12 00:00:00",
"due_at": "2019-02-12 00:00:00",
"status": "active",
"customer": {
"id": 1,
"name": "test",
"email": "info#test.com",
"image": "customer/ec812116705ff3ae85298234fe6c4e97ec812116705ff3ae85298234fe6c4e97.jpeg",
"address": "sample address"
},
"received_payments": []
}
]
}
summary: trying to get the sum of AccountReceivable amount attribute, which is working fine but the getReceivedPaymentsAttribute() isn't working which needs to return the total value only. also can anyone please help me to explain why laravel_through_key is added with received_payments?
I've never tried to use an attribute modifier to modify a relation this way. You are overriding the expected result of receivedPayments(). You might be better off to define a separate attribute like so:
public function getSumReceivedPaymentsAttribute()
{
// ...your code...
}
Now you can access the attribute using $model->sum_received_payments or always preload it using:
// model.php
protected $appends = ['sum_received_payments'];

how to return a json response based on database relationship

I'm quite new to Laravel,
Let's say I have 2 tables: main_sport and sub_sport. These two tables have a one-to-many relationship. 1 sport can have many sub sports.
I want the following json format
{
"success": "1",
"sports": [
"id": 1,
"name_of_categories": "Popular Sports",
"sub_sports:[
{
"id": 1,
"name_sub_sport_category": "Badminton"
},
{
"id": 2,
"name_sub_sport_category": "Football"
},
{
"id": 3,
"name_sub_sport_category": "Cricket"
},
]
]
"sports":[
"id": 2,
"name_of_categories": "Team Sports",
"sub_sports:[
{
"id": 4,
"name_sub_sport_category": "Badminton"
},
{
"id": 5,
"name_sub_sport_category": "Football"
},
]
]
}
I try for this function and i am getting following result
public function fetch()
{
$query= DB::table('details')
->join('table_sub_sport_category','table_sub_sport_category.id','=','details.sub_id')
->join('table_main_sport_category','table_main_sport_category.id','=','details.main_id')
->select(DB::raw('table_main_sport_category.id as id'),'table_main_sport_category.name_of_categories','table_sub_sport_category.name_sub_sport_category')
->get()
return response()->json(['success' =>'1','data'=>$query]);
}
{
"success": "1",
"data": [
{
"id": 1,
"name_of_categories": "Popular Sports",
"name_sub_sport_category": "Badminton"
},
{
"id": 1,
"name_of_categories": "Popular Sports",
"name_sub_sport_category": "Football"
},
{
"id": 1,
"name_of_categories": "Popular Sports",
"name_sub_sport_category": "Cricket"
},
]
}
Could you help me to get the desired result?
You should define sub_sport in the main sport Model like this:
class Sport extends Model{
public function sub_sport(){
return $this->hasMany(SubSport::class);
}
}
And in your controller you should write this:
$data = Sport::with('sub_sport')->get();
Use below code
$query= DB::table('details')
->join('table_sub_sport_category','table_sub_sport_category.id','=','details.sub_id')
->join('table_main_sport_category','table_main_sport_category.id','=','details.main_id')
->select(DB::raw('table_main_sport_category.id as id'),'table_main_sport_category.name_of_categories','table_sub_sport_category.name_sub_sport_category')
->get()
return Response::json([
'status' => 'error',
'sports' => $query
], 200);

Laravel get only one column from relation

I have a table user_childrens whose contains id_parent and id_user.
I'm trying to list all childrens of the parent with this:
code:
//relation in model via belongsTo
$idparent = auth('api')->user()->id;
$list = UserChildren::where('id_parent',$idparent)
->with('child:id,name,email')
->get();
return $list->toJson();
The return is:
[
{
"id": 1,
"id_parent": 1,
"id_user": 1,
"created_at": null,
"updated_at": null,
"child": {
"id": 1,
"name": "Mr. Davin Conroy Sr.",
"email": "prempel#example.com"
}
},
{
"id": 4,
"id_parent": 1,
"id_user": 2,
"created_at": null,
"updated_at": null,
"child": {
"id": 2,
"name": "Krystel Lehner",
"email": "cernser#example.net"
}
}
]
But it's API so I want only the child column like:
[
{
"id": 1,
"name": "Mr. Davin Conroy Sr.",
"email": "prempel#example.com"
},
{..}
]
UserChildren Model:
public function child() {
return $this->belongsTo('App\User','id_user','id');
}
I know that I could do this via .map() on collection but maybe there is other solution already on this query
You can use this code
$idparent = auth('api')->user()->id;
$childs = User::whereHas('user_childrens', function ($query) use ($idparent) {
$query->where('id_parent', $idparent);
})->get(['id', 'name', 'email']);
dd($childs->toJson());
And User model define user_childrens relation.
public function user_childrens()
{
return $this->hasMany('App\UserChildren','id_user','id');
}
See also docs https://laravel.com/docs/5.5/eloquent-relationships#querying-relationship-existence

How to join output of models in Laravel?

I have the following code:
$orders = OrderProduct::where(function ($query) use ($request) {
})->with('order_products')->orderBy('status', 'desc')->paginate(50)->toArray();
And order_products function is:
public function order_products()
{
return $this->hasMany("App\Order", "order_id", "order_id");
}
It gives me output result:
{
"user_id": "1",
"created_at": "2016-12-18 14:06:11",
"status": "2",
"note": "34535345",
"order_id": "2",
"address": "Kiev",
"courier_id": null,
"payment_type": "0",
"order_products": [
{
"id": 73,
"product_id": "1265",
"amount": "1"
},
{
"id": 74,
"product_id": "1266",
"amount": "1"
}
]
I need to join order_products with products_details, that to give title of product for each order like as:
"order_products": [
{
"id": 73,
"product_id": "1265",
"amount": "1",
"title": "Product name"
},
{
"id": 74,
"product_id": "1266",
"amount": "1",
"title": "Product name"
}
]
Instead this I get a new model output in response:
"products_details": [
{}, {}
]
How can I join two with models?
without joining, just using your first code:
in order_products, override the toArray() method.
function toArray() {
return [
id => $this->id,
product_id => $this->product_id,
amount => $this->amount,
title => $this->details->name
];
}
wich $this->details->name is the relation between order_products and products_details

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