I want to SELECT a TIMESTAMP(6) with milliseconds, but at the same time I need to subtract 3 hours (0.125 of a day) from that TIMESTAMP to convert it to my timezone. So I tried:
SELECT To_Char(UTCSCANTIME-0.125,'YYYY-MM-DD HH24:MI:SS') AS LOCALSCANTIME
Outcome: 2018-08-01 19:22:39
If I append "FF" to show milliseconds:
SELECT To_Char(UTCSCANTIME-0.125,'YYYY-MM-DD HH24:MI:SS.FF') AS LOCALSCANTIME
Outcome: ORA-01821: date format not recognized
However if I keep the "FF" but I don't subtract 0.125:
SELECT To_Char(UTCSCANTIME,'YYYY-MM-DD HH24:MI:SS.FF') AS LOCALSCANTIME
Outcome: 2018-08-01 22:22:39.259000
How can I achieve both things?
Thanks in advance!
Subtract a 3 hour INTERVAL instead of 0.125.
SELECT To_Char(UTCSCANTIME-INTERVAL '3' HOUR,'YYYY-MM-DD HH24:MI:SS.FF') AS LOCALSCANTIME
Subtracting a number like 0.125 implicitly converts the result to a DATE, losing your fractional seconds.
Also, note, there are better ways in Oracle to convert time zones than to add and subtract intervals.
Related
I am unable to get the date column to respect the where clause. Regardless what I do, it does not filter on date. I have tried all combinations of to_char and to_date in vain.
HAVING TO_CHAR(PAYMASTR.CHECK_DATE,'MM/DD/YYYY') > '01/01/2021'
I have also tried the code below with all combinations of to_char and to_date.
HAVING PAYMASTR.CHECK_DATE >= TO_DATE('01-01-2021 12:00:00 AM',
'MM-DD-YYYY HH:MM:SS AM')
The check_date of of type DATE.
Result set:
|COMPANY|EMPLOYEE|PAY_SUM_GRP|PAY_GRADE RATE|WAGE_AMOUNT|NET_PAY_AMT|GROSS_PAY|CHECK_DATE|
|-------|--------|-----------|--------------|-----------|-----------|---------|----------|
|2|5|REG 09|21.98|175.84|1459.96|2263.19|1/19/2007 12:00:00 AM|
|2|5|REG 09|21.98|175.84|1663.93|2589.43|1/5/2007 12:00:00 AM|
If CHECK_DATE column's datatype is DATE (should be! If it is VARCHAR2, you're doing it wrong!), then
having check_date > date '2021-01-01'
i.e. compare date to date literal.
Second code you posted is almost OK:
HAVING PAYMASTR.CHECK_DATE >= TO_DATE('01-01-2021 12:00:00 AM', 'MM-DD-YYYY HH:MI:SS AM')
--
MI for minutes; MM is for month
I found this article on code project that did the trick for me. I was struggling really hard to get the query to respect the date parameter in the queru. Setting the session to NLS_DATE_FORMAT worked. Not sure what other implications it may have. Will have to talk to the DBA.
Code Project
It's all about how Oracle stores and works with date DATATYPE
The date has seven components
Century, year, month, day, hour, minute, seconds
and all these components take seven bytes of storage.
Whenever you fetch a Date column from a table, the date value is formatted in a more readable form and this format is set in the nls_date_format parameter.
I am assuming you are grouping by CHECK_DATE otherwise you need to add this date filter with the WHERE clause.
So first check the datatype of your column CHECK_DATE
If it is date then
HAVING CHECK_DATE >= TO_DATE('01-01-2021', 'MM-DD-YYYY')
You don't have to provide hours, minutes, and seconds if omitted hours are rounded to 12 AM or 00 if the 24-hour format is used;
Or if you want to have hours as well then you used MM instead of MI for minutes.
HAVING CHECK_DATE >= TO_DATE('01-01-2021 00:00:00', 'MM-DD-YYYY HH24:MI:SS')
And this does not make sense
HAVING TO_CHAR(PAYMASTR.CHECK_DATE,'MM/DD/YYYY') > '01/01/2021'
You want to compare dates not characters and to_char will provide you a character string that has no sense of comparing with another string '01/01/2021'.
So if you are not grouping by CHECK_DATE user filter condition with WHERE clause
or check the datatype of CHECK_DATE if it is not DATE change it to DATE.
I'm trying to get a new date from the product of 'date' + 'time interval'.
Something like this.
'15/02/2016 18:00:00' + '+00 02:00:00.000000'
Expected result:
'15/02/2016 20:00:00'
But using the columns in database.
CREATE TABLE timerest
(
DATE_ASIGN DATE,
TIME_ASIGN INTERVAL DAY(2) TO SECOND(0)
);
Thanks for your help.
You can just add them together:
insert into timerest (date_asign, time_asign)
values (to_date('15/02/2016 18:00:00', 'DD/MM/YYYY HH24:MI:SS'),
to_dsinterval('+00 02:00:00.000000'));
alter session set NLS_DATE_FORMAT = 'DD/MM/YYYY HH24:MI:SS';
select date_asign + time_asign from timerest;
DATE_ASIGN+TIME_ASIGN
---------------------
15/02/2016 20:00:00
This follows the rules for datetime/interval arithmetic: date + interval = date.
If you have a date in DATE format you can simply add the a numeric interval that represents days (for example 1.5 is 1 day and a half)
You can extract from the time interval days and hours and then add them to to you date because, if I remember correctly, you can't add directly them to a date type (maybe to a timestamp type you can)
To extract the days you can use the extract function:
(
extract(second from TIME_ASIGN)/3600)+(extract(hour from TIME_ASIGN)/24)+(extract(day from TIME_ASIGN)/24)
then you add the number to your DATE_ASIGN
How can i convert the result of select statement of time interval field in respective time in Am/Pm format.
My Field is:
Interval Day(2) To Second(6)
I tried this:
select To_Char(Att_EntranceTime , 'HH:MI AM') From EMPLOYEEATTENDENCETABLE;
however this does not help me, i have also tried to add the basetime from systime to my interval field but that did not help.. can someone suggest me what to do?
Intervals can't be directly formatted, as you've discovered. You can add your interval to any date which has its time set to midnight, and then format the resulting date to show the time in your desired format. For example you could add it to today's date using trunc(sysdate):
to_char(trunc(sysdate) + my_interval, 'HH:MI AM')
You need to truncate it to set the time to midnight; otherwise the result will be your interval plus the current system time.
Or you can use any fixed date; here's an example with some dummy data set-up:
create table my_table (my_interval interval day(2) to second(6));
insert into my_table (my_interval) values (interval '0 12:34:56.78' day to second);
insert into my_table (my_interval) values (interval '99 01:02:03.456' day to second);
select my_interval, to_char(date '1970-01-01' + my_interval, 'HH:MI AM') as formatted
from my_table;
MY_INTERVAL FORMATTED
-------------------- ---------
+00 12:34:56.780000 12:34 PM
+99 01:02:03.456000 01:02 AM
The second value shows a potential problem. Your interval is defined to allow a two-digit day number, which means the interval can span anything less than 100 days. If you only extract the time portion you lose that information about the number of days. That may be what you want to happen though. If the interval is supposed to be representing a time of day, which wanting to show AM/PM implies - and it's unusual to store an actual time separate from its date - then having or allowing a number of days seems strange.
I am using the following, where I am converting NUMBER variable to Datetime stamp.
to_char(
(to_timestamp('01-JAN-1970 00:00:00','DD-MON-YYYY HH24:MI:SS') +
(END_SAMPLE_TS_5MIN_MS/(1000*60*60*24)),'DD-MON-YYYY HH24:MI:SS')
But I notice the output resulting from above is behind by 1 second from actual value.
Say for example if END_SAMPLE_TS_5MIN_MS=1388984699999.
Instead of showing : 06Jan2014 05:04:59
It is showing it as 06Jan2014 05:05:00
The milliseconds are rounded to nearest second.
Please help!
You can use numtodsinterval, something like:
select to_timestamp('01-JAN-1970 00:00:00.000','DD-MON-YYYY HH24:MI:SS.FF3') +
numtodsinterval(1388984699.999, 'SECOND')
from dual;
Output:
1/6/2014 5:04:59.999000000 AM
Hope that helps
If you're not interested in utilizing the milliseconds to round up, you can effectively take the "floor" of your epoch with a substring:
select to_char((to_timestamp('01-JAN-1970 00:00:00','DD-MON-YYYY HH24:MI:SS')+(substr(1388984699999,1,length(1388984699999)-3)/(60*60*24))),'DD-MON-YYYY HH24:MI:SS')
from dual
We're really just taking the substring of our string minus the last 3 digits (milliseconds in this unix timestamp format) and then adding it to the epoch to get your time.
I need to add 30 minutes to values in a Oracle date column. I do this in my SELECT statement by specifying
to_char(date_and_time + (.000694 * 31)
which works fine most of the time. But not when the time is on the AM/PM border. For example, adding 30 minutes to 12:30 [which is PM] returns 1:00 which is AM. The answer I expect is 13:00. What's the correct way to do this?
In addition to being able to add a number of days to a date, you can use interval data types assuming you are on Oracle 9i or later, which can be somewhat easier to read,
SQL> ed
Wrote file afiedt.buf
SELECT sysdate, sysdate + interval '30' minute FROM dual
SQL> /
SYSDATE SYSDATE+INTERVAL'30'
-------------------- --------------------
02-NOV-2008 16:21:40 02-NOV-2008 16:51:40
All of the other answers are basically right but I don't think anyone's directly answered your original question.
Assuming that "date_and_time" in your example is a column with type DATE or TIMESTAMP, I think you just need to change this:
to_char(date_and_time + (.000694 * 31))
to this:
to_char(date_and_time + (.000694 * 31), 'DD-MON-YYYY HH24:MI')
It sounds like your default date format uses the "HH" code for the hour, not "HH24".
Also, I think your constant term is both confusing and imprecise. I guess what you did is calculate that (.000694) is about the value of a minute, and you are multiplying it by the number of minutes you want to add (31 in the example, although you said 30 in the text).
I would also start with a day and divide it into the units you want within your code. In this case, (1/48) would be 30 minutes; or if you wanted to break it up for clarity, you could write ( (1/24) * (1/2) ).
This would avoid rounding errors (except for those inherent in floating point which should be meaningless here) and is clearer, at least to me.
UPDATE "TABLE"
SET DATE_FIELD = CURRENT_TIMESTAMP + interval '48' minute
WHERE (...)
Where interval is one of
YEAR
MONTH
DAY
HOUR
MINUTE
SECOND
from http://www.orafaq.com/faq/how_does_one_add_a_day_hour_minute_second_to_a_date_value
The SYSDATE pseudo-column shows the current system date and time. Adding 1 to SYSDATE will advance the date by 1 day. Use fractions to add hours, minutes or seconds to the date
SQL> select sysdate, sysdate+1/24, sysdate +1/1440, sysdate + 1/86400 from dual;
SYSDATE SYSDATE+1/24 SYSDATE+1/1440 SYSDATE+1/86400
-------------------- -------------------- -------------------- --------------------
03-Jul-2002 08:32:12 03-Jul-2002 09:32:12 03-Jul-2002 08:33:12 03-Jul-2002 08:32:13
I prefer using an interval literal for this, because interval '30' minute or interval '5' second is a lot easier to read then 30 / (24 * 60) or 5 / (24 * 60 * 69)
e.g.
some_date + interval '2' hour
some_date + interval '30' minute
some_date + interval '5' second
some_date + interval '2' day
You can also combine several units into one expression:
some_date + interval '2 3:06' day to minute
Adds 2 days, 3 hours and 6 minutes to the date value
The above is also standard SQL and also works in several other DBMS.
More details in the manual: https://docs.oracle.com/database/121/SQLRF/sql_elements003.htm#SQLRF00221
If the data type of the field is date or timestamp, Oracle should always give the correct result if you add the correct number given in number of days (or a the correct fraction of a day in your case). So if you are trying to bump the value in 30 minutes, you should use :
select field + 0.5/24 from table;
Based on the information you provided, I believe this is what you tried to do and I am quite sure it works.
Can we not use this
SELECT date_and_time + INTERVAL '20:00' MINUTE TO SECOND FROM dual;
I am new to this domain.
like that very easily
i added 10 minutes to system date and always in preference use the Db server functions not custom one .
select to_char(sysdate + NUMTODSINTERVAL(10,'MINUTE'),'DD/MM/YYYY HH24:MI:SS') from dual;
Be sure that Oracle understands that the starting time is PM, and to specify the HH24 format mask for the final output.
SELECT to_char((to_date('12:40 PM', 'HH:MI AM') + (1/24/60) * 30), 'HH24:MI') as time
FROM dual
TIME
---------
13:10
Note: the 'AM' in the HH:MI is just the placeholder for the AM/PM meridian indicator. Could be also 'PM'
Oracle now has new built in functions to do this:
select systimestamp START_TIME, systimestamp + NUMTODSINTERVAL(30, 'minute') end_time from dual
Based on what you're asking for, you want the HH24:MI format for to_char.
To edit Date in oracle you can try
select to_char(<columnName> + 5 / 24 + 30 / (24 * 60),
'DD/MM/RRRR hh:mi AM') AS <logicalName> from <tableName>
SELECT to_char(sysdate + (1/24/60) * 30, 'dd/mm/yy HH24:MI am') from dual;
simply you can use this with various date format....