I am using the following, where I am converting NUMBER variable to Datetime stamp.
to_char(
(to_timestamp('01-JAN-1970 00:00:00','DD-MON-YYYY HH24:MI:SS') +
(END_SAMPLE_TS_5MIN_MS/(1000*60*60*24)),'DD-MON-YYYY HH24:MI:SS')
But I notice the output resulting from above is behind by 1 second from actual value.
Say for example if END_SAMPLE_TS_5MIN_MS=1388984699999.
Instead of showing : 06Jan2014 05:04:59
It is showing it as 06Jan2014 05:05:00
The milliseconds are rounded to nearest second.
Please help!
You can use numtodsinterval, something like:
select to_timestamp('01-JAN-1970 00:00:00.000','DD-MON-YYYY HH24:MI:SS.FF3') +
numtodsinterval(1388984699.999, 'SECOND')
from dual;
Output:
1/6/2014 5:04:59.999000000 AM
Hope that helps
If you're not interested in utilizing the milliseconds to round up, you can effectively take the "floor" of your epoch with a substring:
select to_char((to_timestamp('01-JAN-1970 00:00:00','DD-MON-YYYY HH24:MI:SS')+(substr(1388984699999,1,length(1388984699999)-3)/(60*60*24))),'DD-MON-YYYY HH24:MI:SS')
from dual
We're really just taking the substring of our string minus the last 3 digits (milliseconds in this unix timestamp format) and then adding it to the epoch to get your time.
Related
I want to SELECT a TIMESTAMP(6) with milliseconds, but at the same time I need to subtract 3 hours (0.125 of a day) from that TIMESTAMP to convert it to my timezone. So I tried:
SELECT To_Char(UTCSCANTIME-0.125,'YYYY-MM-DD HH24:MI:SS') AS LOCALSCANTIME
Outcome: 2018-08-01 19:22:39
If I append "FF" to show milliseconds:
SELECT To_Char(UTCSCANTIME-0.125,'YYYY-MM-DD HH24:MI:SS.FF') AS LOCALSCANTIME
Outcome: ORA-01821: date format not recognized
However if I keep the "FF" but I don't subtract 0.125:
SELECT To_Char(UTCSCANTIME,'YYYY-MM-DD HH24:MI:SS.FF') AS LOCALSCANTIME
Outcome: 2018-08-01 22:22:39.259000
How can I achieve both things?
Thanks in advance!
Subtract a 3 hour INTERVAL instead of 0.125.
SELECT To_Char(UTCSCANTIME-INTERVAL '3' HOUR,'YYYY-MM-DD HH24:MI:SS.FF') AS LOCALSCANTIME
Subtracting a number like 0.125 implicitly converts the result to a DATE, losing your fractional seconds.
Also, note, there are better ways in Oracle to convert time zones than to add and subtract intervals.
How can i convert the result of select statement of time interval field in respective time in Am/Pm format.
My Field is:
Interval Day(2) To Second(6)
I tried this:
select To_Char(Att_EntranceTime , 'HH:MI AM') From EMPLOYEEATTENDENCETABLE;
however this does not help me, i have also tried to add the basetime from systime to my interval field but that did not help.. can someone suggest me what to do?
Intervals can't be directly formatted, as you've discovered. You can add your interval to any date which has its time set to midnight, and then format the resulting date to show the time in your desired format. For example you could add it to today's date using trunc(sysdate):
to_char(trunc(sysdate) + my_interval, 'HH:MI AM')
You need to truncate it to set the time to midnight; otherwise the result will be your interval plus the current system time.
Or you can use any fixed date; here's an example with some dummy data set-up:
create table my_table (my_interval interval day(2) to second(6));
insert into my_table (my_interval) values (interval '0 12:34:56.78' day to second);
insert into my_table (my_interval) values (interval '99 01:02:03.456' day to second);
select my_interval, to_char(date '1970-01-01' + my_interval, 'HH:MI AM') as formatted
from my_table;
MY_INTERVAL FORMATTED
-------------------- ---------
+00 12:34:56.780000 12:34 PM
+99 01:02:03.456000 01:02 AM
The second value shows a potential problem. Your interval is defined to allow a two-digit day number, which means the interval can span anything less than 100 days. If you only extract the time portion you lose that information about the number of days. That may be what you want to happen though. If the interval is supposed to be representing a time of day, which wanting to show AM/PM implies - and it's unusual to store an actual time separate from its date - then having or allowing a number of days seems strange.
WHERE (ResTRRequest.RequestTime BETWEEN TO_CHAR(TRUNC(TO_DATE('2012-12-01 20:10:10', 'HH')), 'YYYY-MM-DD HH24:MI:SS')
AND TO_CHAR(TRUNC(CURRENT_TIMESTAMP, 'HH') + INTERVAL '59:59' MINUTE TO SECOND, 'YYYY-MM-DD HH24:MI:SS'))
I have above where condition in query when i execute it,it gives me hours must be between 1 to 12 due to static date I have given i.e ''2012-12-01 20:10:10', 'HH')' if I put sysdate the its working fine but due to static date it gives me error.
Let's break this down a bit:
WHERE (ResTRRequest.RequestTime
BETWEEN TO_CHAR(TRUNC(TO_DATE('2012-12-01 20:10:10', 'HH')), 'YYYY-MM-DD HH24:MI:SS')
AND TO_CHAR(TRUNC(CURRENT_TIMESTAMP, 'HH') + INTERVAL '59:59' MINUTE TO SECOND, 'YYYY-MM-DD HH24:MI:SS'))
In the first place, I don't think you mean this: TRUNC(TO_DATE('2012-12-01 20:10:10', 'HH')), I think maybe you mean this: TRUNC(TO_DATE('2012-12-01 20:10:10'), 'HH'). The number from 1-12 error comes from the fact that you have an hour of 20 and are trying to convert it into a date with the mask of HH. But as I said I think that's a typo. You can also use a TIMESTAMP literal here rather than TO_DATE():
TRUNC(TIMESTAMP'2012-12-01 20:10:10', 'HH')
Second, and just to get this out of the way, are you storing dates or timestamps as strings? That's not a good idea.
Third, it's not a good idea to use BETWEEN in date comparisons because you can miss the edge cases. It might be better to rewrite this as follows:
WHERE ( ResTRRequest.RequestTime >= TO_CHAR(TRUNC(TO_DATE('2012-12-01 20:10:10'), 'HH'), 'YYYY-MM-DD HH24:MI:SS')
AND ResTRRequest.RequestTime < TO_CHAR(TRUNC(CURRENT_TIMESTAMP, 'HH') + INTERVAL '1' HOUR, 'YYYY-MM-DD HH24:MI:SS') )
Problem is in mask:
TO_DATE('2012-12-01 20:10:10', 'HH')
Replace with this one:
TO_DATE('2012-12-01 20:10:10', 'HH24')
Assuming that ResTRRequest.RequestTime is of a date type, this Where clause will work:
where ResTRRequest.RequestTime
BETWEEN TRUNC(TO_DATE('2015-02-26 20:10:10', 'YYYY-MM-DD HH24:MI:SS'), 'HH')
AND TRUNC(CURRENT_TIMESTAMP, 'HH') + INTERVAL '59:59' MINUTE TO SECOND
If you have to compare character representations, keep in mind that you compare in lexicographic order, meaning that prefixes of strings are sorted before their strings! Avoid ensueing complications by using identical formatting models with componnents arranged in the order of decreasing significance. E.g.
TO_CHAR(<whatever>, 'YYYY-MM-DD HH24:MI:SS')
but not
TO_CHAR(<whatever>, 'MM/DD/YYYY HH24:MI:SS')
If the language setting on Oracle is set for using the 12 hours time, this problem will occur when converting the 24 hours time format.
There are two solutions to this :
Convert TIMESTAMP/DATE format in Oracle client
alter session set nls_timestamp_format='YYYY-MM-DD HH24:MI:SS.FF6';
Convert query to match 24hr format
SELECT * FROM TEST_ WHERE DOB > TRUNC(TIMESTAMP'1970-01-01 20:10:10', 'HH');
or
SELECT * FROM TEST_ WHERE DOB > to_date('1970-01-01 20:00:00','YYYY-MM-DD HH24:MI:SS');
One more thing to watch out for in the case you get this error is the data itself.
I've had date stored in xml tag that I had to parse and convert with TO_DATE with this format specifier 'MM/dd/YYYY HH:MI:SS AM'. SQL broke with "ORA-01849: hour must be between 1 and 12" because some records were written like this: "12/20/2017 16:45:00 PM". Pay attention to 16h and PM specfier...
I need help to write query do the following:
subtract between two columns (start date and end date), and please note that the type for the columns are char not date, this is the exact format: 10-MAR-12 11.11.40.288389000 AM), then get the average for the result.
I assume this is homework, so some hints...
First don't ever store dates as varchar, it will cause you and the optimiser all sorts of problems.
Second, Oracle's date datatype can only store to second precision, and your string has fractions of a second, so you are looking at timestamp rather than date. You can convert your string to a timestamp with the to_timestamp() function, passing a suitable format mask. Oh OK, I'm feeling generous:
select to_timestamp(start_date, 'DD-Mon-RR HH.MI.SS.FF9 AM') from your_table;
Third, subtracting two timestamps will give you an interval data type, from which you will need to extract the information you want in a readable format. Search this site or elsewhere for timestamp subtraction, but I'll point you at this recent one as a sample.
The average is a bit trickier, so you may want to convert your intervals to numbers for that; again search for previous questions, such as this one. The size of the intervals, the precision you actually care about, and the way you want the output formatted, etc. will have some bearing on the approach you want to take.
If you need an approximate result then #Joachim Isaksson's answer will give you that - 'approximate' because of rounding; a duration of less than a second will show up as zero, for example. The same effect can be seen with timestamps cast to dates, which also loses the fractional seconds:
select 24*60*60*avg(
cast(to_timestamp(step_ending_time, 'DD-Mon-RR HH.MI.SS.FF9 AM') as date)
- cast(to_timestamp(step_starting_time, 'DD-Mon-RR HH.MI.SS.FF9 AM') as date)
) as avg_duration
from process_audit;
A more accurate answer can be found by extracting the various components of the timestamps, as in a question I linked to earlier. You may not need them all if you know that your durations are always less then an hour, say, but if you need more than one (i.e. if a duration could be more than a minute) then using an intermediate common table expression simplifies things a bit:
with cte as (
select to_timestamp(step_ending_time, 'DD-Mon-RR HH.MI.SS.FF9 AM')
- to_timestamp(step_starting_time, 'DD-Mon-RR HH.MI.SS.FF9 AM') as duration
from process_audit
)
select avg(extract(second from duration)
+ extract(minute from duration) * 60
+ extract(hour from duration) * 60 * 60
+ extract(day from duration) * 60 * 60 * 24) as avg_duration
from cte;
With two sample rows, one with a gap of exactly a second and one with exactly 1.5 seconds, this gives the result 1.25.
Comments about storing times in VARCHAR aside; Oracle's to_date to the rescue; this should work for you to show the average number of seconds between the times. Since you're a bit low on details on precision, I didn't bother about the "sub seconds";
SELECT 24*3600*AVG(
to_date(enddate, 'DD-Mon-YY HH.Mi.SS.????????? AM') -
to_date(startdate, 'DD-Mon-YY HH.Mi.SS.????????? AM')) avg_seconds
FROM TableA;
Demo here.
I need to add 30 minutes to values in a Oracle date column. I do this in my SELECT statement by specifying
to_char(date_and_time + (.000694 * 31)
which works fine most of the time. But not when the time is on the AM/PM border. For example, adding 30 minutes to 12:30 [which is PM] returns 1:00 which is AM. The answer I expect is 13:00. What's the correct way to do this?
In addition to being able to add a number of days to a date, you can use interval data types assuming you are on Oracle 9i or later, which can be somewhat easier to read,
SQL> ed
Wrote file afiedt.buf
SELECT sysdate, sysdate + interval '30' minute FROM dual
SQL> /
SYSDATE SYSDATE+INTERVAL'30'
-------------------- --------------------
02-NOV-2008 16:21:40 02-NOV-2008 16:51:40
All of the other answers are basically right but I don't think anyone's directly answered your original question.
Assuming that "date_and_time" in your example is a column with type DATE or TIMESTAMP, I think you just need to change this:
to_char(date_and_time + (.000694 * 31))
to this:
to_char(date_and_time + (.000694 * 31), 'DD-MON-YYYY HH24:MI')
It sounds like your default date format uses the "HH" code for the hour, not "HH24".
Also, I think your constant term is both confusing and imprecise. I guess what you did is calculate that (.000694) is about the value of a minute, and you are multiplying it by the number of minutes you want to add (31 in the example, although you said 30 in the text).
I would also start with a day and divide it into the units you want within your code. In this case, (1/48) would be 30 minutes; or if you wanted to break it up for clarity, you could write ( (1/24) * (1/2) ).
This would avoid rounding errors (except for those inherent in floating point which should be meaningless here) and is clearer, at least to me.
UPDATE "TABLE"
SET DATE_FIELD = CURRENT_TIMESTAMP + interval '48' minute
WHERE (...)
Where interval is one of
YEAR
MONTH
DAY
HOUR
MINUTE
SECOND
from http://www.orafaq.com/faq/how_does_one_add_a_day_hour_minute_second_to_a_date_value
The SYSDATE pseudo-column shows the current system date and time. Adding 1 to SYSDATE will advance the date by 1 day. Use fractions to add hours, minutes or seconds to the date
SQL> select sysdate, sysdate+1/24, sysdate +1/1440, sysdate + 1/86400 from dual;
SYSDATE SYSDATE+1/24 SYSDATE+1/1440 SYSDATE+1/86400
-------------------- -------------------- -------------------- --------------------
03-Jul-2002 08:32:12 03-Jul-2002 09:32:12 03-Jul-2002 08:33:12 03-Jul-2002 08:32:13
I prefer using an interval literal for this, because interval '30' minute or interval '5' second is a lot easier to read then 30 / (24 * 60) or 5 / (24 * 60 * 69)
e.g.
some_date + interval '2' hour
some_date + interval '30' minute
some_date + interval '5' second
some_date + interval '2' day
You can also combine several units into one expression:
some_date + interval '2 3:06' day to minute
Adds 2 days, 3 hours and 6 minutes to the date value
The above is also standard SQL and also works in several other DBMS.
More details in the manual: https://docs.oracle.com/database/121/SQLRF/sql_elements003.htm#SQLRF00221
If the data type of the field is date or timestamp, Oracle should always give the correct result if you add the correct number given in number of days (or a the correct fraction of a day in your case). So if you are trying to bump the value in 30 minutes, you should use :
select field + 0.5/24 from table;
Based on the information you provided, I believe this is what you tried to do and I am quite sure it works.
Can we not use this
SELECT date_and_time + INTERVAL '20:00' MINUTE TO SECOND FROM dual;
I am new to this domain.
like that very easily
i added 10 minutes to system date and always in preference use the Db server functions not custom one .
select to_char(sysdate + NUMTODSINTERVAL(10,'MINUTE'),'DD/MM/YYYY HH24:MI:SS') from dual;
Be sure that Oracle understands that the starting time is PM, and to specify the HH24 format mask for the final output.
SELECT to_char((to_date('12:40 PM', 'HH:MI AM') + (1/24/60) * 30), 'HH24:MI') as time
FROM dual
TIME
---------
13:10
Note: the 'AM' in the HH:MI is just the placeholder for the AM/PM meridian indicator. Could be also 'PM'
Oracle now has new built in functions to do this:
select systimestamp START_TIME, systimestamp + NUMTODSINTERVAL(30, 'minute') end_time from dual
Based on what you're asking for, you want the HH24:MI format for to_char.
To edit Date in oracle you can try
select to_char(<columnName> + 5 / 24 + 30 / (24 * 60),
'DD/MM/RRRR hh:mi AM') AS <logicalName> from <tableName>
SELECT to_char(sysdate + (1/24/60) * 30, 'dd/mm/yy HH24:MI am') from dual;
simply you can use this with various date format....