i don't know how to decode hexacidemal values to decimal ones with springboot
Is There a default fonctions That can help me or should i develop functions by myself
thank You
You just need JAVA APIs,
From Hexadecimal to Decimal
String hexNumber = ...
int decimal = Integer.parseInt(hexNumber, 16);
System.out.println("Hex value is " + decimal);
From Decimal to Hex
If you have the value that you want to convert in an int variable, then you can simply call:
int i = ...
String hex = Integer.toHexString(i);
System.out.println("Hex value is " + hex);
If you have the decimal number in a String, then you first call Integer.parseInt() but this time you don't need any second parameter— decimal is the default:
String string = ...
int no = Integer.parseInt(string);
String hex = Integer.toHexString(no);
System.out.println("Hex value is " + hex);
Check out the full paper here.
Related
I have a byte array and I need to print the elements in a single line.
I tried using 'snprintf()' but it won't take a byte array as its input parameter.
I tried copying the byte array into an integer array and then used the snprintf(), but instead of printing the HEX values, corresponding ASCII values are printed.
You can try this code :
variables
{
int ar[100];
}
on diagResponse TCCM.*
{
char tmp[8]; // Temporary buffer containing single HEX value
char out[301]; // Bigger output string and "local" to function
// Better to place them there (i and response) if they are not global
int i;
byte response[100];
out[0] = 0; // Clear output string
s1 = DiagGetPrimitiveData(this, response, elcount(response));
for (i = 0; i < s1; i++)
{
ar[i] = response[i];
snprintf(tmp, elcount(tmp), "%.2X ", response[i]); // byte to HEX convert
strncat(out, tmp, elcount(out)); // Concatenate HEX value to output string
}
write("HEX Response : %s", out);
}
Olivier
It causes discomfort when you can do that:
val string = " abc "
val integer = 8
val result = string + integer
and can't do:
val result = integer + string
It has hidden meaning or it's an omission?
Kotlin is static typed language and in basicly you can't add String to Integer. But there are possible to overload operators, so we can now.
In case when we want add any object to string, it's clear: every object can be implicitly converted to String (Any#toString())
But in case of Int + smthg it's not so clear, so only Int + kotlin.Number is defined in standard library.
I suggest to use string interpolation:
val result = "${integer}${string}"
Or define own overloaded plus operator:
operator fun Int.plus(string: String): String = string + this
I have stored hex values in a text file with .ini extension along with address. But when i read it, it will not be in hex format it will be in character so is there any way to read value as hex and store it in byte in C language or in CAPL script?
I assume that you know how to read a text file in CAPL...
You can convert a hex string to a number using strtol(char s[], long result&):long. See the CAPL help (CAPL Function Overview -> General -> strol):
The number base is
haxadecimal if the string starts with "0x"
octal if the string starts with "0"
decimal otherwise
Whitespace (space or tabs) at the start of the staring are ignored.
Example:
on start
{
long number1, number2;
strtol("0xFF", number1);
strtol("-128", number2);
write("number1 = %d", number1);
write("number2 = %d", number2);
}
Output:
number1 = 255
number2 = -128
See also: strtoll(), strtoul(), strtoull(), strtod() and atol()
Update:
If the hex string does not start with "0x"...
on message 0x200
{
if (this.byte(0) == hextol("38"))
write("byte(0) == 56");
}
long hextol(char s[])
{
long res;
char xs[8];
strncpy(xs, "0x", elcount(xs)); // cpy "0x" to 'xs'
strncat(xs, s, elcount(xs)); // cat 'xs' and 's'
strtol(xs, res); // convert to long
return res;
}
Hello i would like to create a app that changes characters into binary code and i was wondering if there is a way to add multiple stringByReplacingOccurrencesOfString on one String or if i should take another approach to this "Problem".
Here is what i have so far
func textToBinary(theString: String) -> String {
return theString.stringByReplacingOccurrencesOfString("a",
withString: "01100001")
}
textArea.text = textToBinary(lettersCombined)
// lettersCombined is the string that i want to turn into BinaryCode.
Try this:
func textToBinary(theString : String, radix : Int = 2) -> String {
var result = ""
for c in theString.unicodeScalars {
result += String(c.value, radix: radix) + " "
}
return result
}
println(textToBinary("a"))
println(textToBinary("abc", radix: 10))
println(textToBinary("€20", radix: 16))
println(textToBinary("😄"))
(The last one is a smiley face but somehow my browser can't display it).
Edit: if you want to pad your strings to 8-character long, try this:
let str = "00000000" + String(c.value, radix: radix)
result += str.substringFromIndex(advance(str.startIndex, str.characters.count - 8)) + " "
The first line adds eight 0 the left of your string. The second line takes the last 8 characters from the padded string.
I am trying to convert an decimal number to it's character equivalent. For example:
int j = 65 // The character equivalent would be 'A'.
Sorry, forgot to specify the language. I thought I did. I am using the Cocoa/Object-C. It is really frustrating. I have tried the following but it is still not converting correctly.
char_num1 = [working_text characterAtIndex:i]; // value = 65
char_num2 = [working_text characterAtIndex:i+1]; // value = 75
char_num3 = char_num1 + char_num2; // value = 140
char_str1 = [NSString stringWithFormat:#"%c",char_num3]; // mapped value = 229
char_str2 = [char_str2 stringByAppendingString:char_str1];
When char_num1 and char_num2 are added, I get the new ascii decimal value. However, when I try to convert the new decimal value to a character, I do not get the character that is mapped to char_num3.
Convert a character to a number in C:
int j = 'A';
Convert a number to a character in C:
char ch = 65;
Convert a character to a number in python:
j = ord('A')
Convert a number to a character in Python:
ch = chr(65)
Most languages have a 'char' function, so it would be Char(j)
I'm not sure what language you're asking about. In Java, this works:
int a = 'a';
It's quite often done with "chr" or "char", but some indication of the language / platform would be useful :-)
string k = Chr(j);