I have stored hex values in a text file with .ini extension along with address. But when i read it, it will not be in hex format it will be in character so is there any way to read value as hex and store it in byte in C language or in CAPL script?
I assume that you know how to read a text file in CAPL...
You can convert a hex string to a number using strtol(char s[], long result&):long. See the CAPL help (CAPL Function Overview -> General -> strol):
The number base is
haxadecimal if the string starts with "0x"
octal if the string starts with "0"
decimal otherwise
Whitespace (space or tabs) at the start of the staring are ignored.
Example:
on start
{
long number1, number2;
strtol("0xFF", number1);
strtol("-128", number2);
write("number1 = %d", number1);
write("number2 = %d", number2);
}
Output:
number1 = 255
number2 = -128
See also: strtoll(), strtoul(), strtoull(), strtod() and atol()
Update:
If the hex string does not start with "0x"...
on message 0x200
{
if (this.byte(0) == hextol("38"))
write("byte(0) == 56");
}
long hextol(char s[])
{
long res;
char xs[8];
strncpy(xs, "0x", elcount(xs)); // cpy "0x" to 'xs'
strncat(xs, s, elcount(xs)); // cat 'xs' and 's'
strtol(xs, res); // convert to long
return res;
}
Related
i don't know how to decode hexacidemal values to decimal ones with springboot
Is There a default fonctions That can help me or should i develop functions by myself
thank You
You just need JAVA APIs,
From Hexadecimal to Decimal
String hexNumber = ...
int decimal = Integer.parseInt(hexNumber, 16);
System.out.println("Hex value is " + decimal);
From Decimal to Hex
If you have the value that you want to convert in an int variable, then you can simply call:
int i = ...
String hex = Integer.toHexString(i);
System.out.println("Hex value is " + hex);
If you have the decimal number in a String, then you first call Integer.parseInt() but this time you don't need any second parameter— decimal is the default:
String string = ...
int no = Integer.parseInt(string);
String hex = Integer.toHexString(no);
System.out.println("Hex value is " + hex);
Check out the full paper here.
I have a byte array and I need to print the elements in a single line.
I tried using 'snprintf()' but it won't take a byte array as its input parameter.
I tried copying the byte array into an integer array and then used the snprintf(), but instead of printing the HEX values, corresponding ASCII values are printed.
You can try this code :
variables
{
int ar[100];
}
on diagResponse TCCM.*
{
char tmp[8]; // Temporary buffer containing single HEX value
char out[301]; // Bigger output string and "local" to function
// Better to place them there (i and response) if they are not global
int i;
byte response[100];
out[0] = 0; // Clear output string
s1 = DiagGetPrimitiveData(this, response, elcount(response));
for (i = 0; i < s1; i++)
{
ar[i] = response[i];
snprintf(tmp, elcount(tmp), "%.2X ", response[i]); // byte to HEX convert
strncat(out, tmp, elcount(out)); // Concatenate HEX value to output string
}
write("HEX Response : %s", out);
}
Olivier
If the below code is compiled with UNICODE as compiler option, the GetComputerNameEx API returns junk characters.
Whereas if compiled without UNICODE option, the API returns truncated value of the hostname.
This issue is mostly seen with Asia-Pacific languages like Chinese, Japanese, Korean to name a few (i.e., non-English).
Can anyone throw some light on how this issue can be resolved.
# define INFO_SIZE 30
int main()
{
int ret;
TCHAR infoBuf[INFO_SIZE+1];
DWORD bufSize = (INFO_SIZE+1);
char *buf;
buf = (char *) malloc(INFO_SIZE+1);
if (!GetComputerNameEx((COMPUTER_NAME_FORMAT)1,
(LPTSTR)infoBuf, &bufSize))
{
printf("GetComputerNameEx failed (%d)\n", GetLastError());
return -1;
}
ret = wcstombs(buf, infoBuf, (INFO_SIZE+1));
buf[INFO_SIZE] = '\0';
return 0;
}
In the languages you mentioned, most characters are represented by more than one byte. This is because these languages have alphabets of much more than 256 characters. So you may need more than 30 bytes to encode 30 characters.
The usual pattern for calling a function like wcstombs goes like this: first get the amount of bytes required, then allocate a buffer, then convert the string.
(edit: that actually relies on a POSIX extension, which also got implemented on Windows)
size_t size = wcstombs(NULL, infoBuf, 0);
if (size == (size_t) -1) {
// some character can't be converted
}
char *buf = new char[size + 1];
size = wcstombs(buf, infoBuf, size + 1);
I have a problem in regards of extracting signed int from string in c++.
Assuming that i have a string of images1234, how can i extract the 1234 from the string without knowing the position of the last non numeric character in C++.
FYI, i have try stringstream as well as lexical_cast as suggested by others through the post but stringstream returns 0 while lexical_cast stopped working.
int main()
{
string virtuallive("Images1234");
//stringstream output(virtuallive.c_str());
//int i = stoi(virtuallive);
//stringstream output(virtuallive);
int i;
i = boost::lexical_cast<int>(virtuallive.c_str());
//output >> i;
cout << i << endl;
return 0;
}
How can i extract the 1234 from the string without knowing the position of the last non numeric character in C++?
You can't. But the position is not hard to find:
auto last_non_numeric = input.find_last_not_of("1234567890");
char* endp = &input[0];
if (last_non_numeric != std::string::npos)
endp += last_non_numeric + 1;
if (*endp) { /* FAILURE, no number on the end */ }
auto i = strtol(endp, &endp, 10);
if (*endp) {/* weird FAILURE, maybe the number was really HUGE and couldn't convert */}
Another possibility would be to put the string into a stringstream, then read the number from the stream (after imbuing the stream with a locale that classifies everything except digits as white space).
// First the desired facet:
struct digits_only: std::ctype<char> {
digits_only(): std::ctype<char>(get_table()) {}
static std::ctype_base::mask const* get_table() {
// everything is white-space:
static std::vector<std::ctype_base::mask>
rc(std::ctype<char>::table_size,std::ctype_base::space);
// except digits, which are digits
std::fill(&rc['0'], &rc['9'], std::ctype_base::digit);
// and '.', which we'll call punctuation:
rc['.'] = std::ctype_base::punct;
return &rc[0];
}
};
Then the code to read the data:
std::istringstream virtuallive("Images1234");
virtuallive.imbue(locale(locale(), new digits_only);
int number;
// Since we classify the letters as white space, the stream will ignore them.
// We can just read the number as if nothing else were there:
virtuallive >> number;
This technique is useful primarily when the stream contains a substantial amount of data, and you want all the data in that stream to be interpreted in the same way (e.g., only read numbers, regardless of what else it might contain).
xcode 5.0
when I run following code:
void guessNum(){
int answer = 0;
int guess = 0;
int turn = 0;
answer = arc4random() % 100 + 1;
while (guess != answer) {
turn++;
NSLog(#"Guess #%i: Enter a number between 1 and 100", turn);
scanf("%i", &guess);
if (guess > answer) {
NSLog(#"Lower!");
}
else if (guess < answer) {
NSLog(#"Higher!");
}
else {
NSLog(#"Correct! The answer was %i", answer);
}
} // end of while loop
NSLog(#"It took you %i tries", turn);
}
when I type a character, just like a in xcode debug console, program run automatic and print:
...
2013-11-18 10:47:39.719 donglix[15115:303] Higher!
2013-11-18 10:47:39.719 donglix[15115:303] Guess #1932: Enter a number between 1 and 100
2013-11-18 10:47:39.719 donglix[15115:303] Higher!
2013-11-18 10:47:39.720 donglix[15115:303] Guess #1933: Enter a number between 1 and 100
...
what's the problem?
"scanf()" reads the input you've typed in and, because of your "%i" (integer) format string, is expecting to take that input and drop it into a number.
If you used "%s" as your format string, then you would take the input as a C-style character array (and have to convert those characters if you wanted to get the integer value out of that).
For example, you can replace this line:
scanf("%i", &guess);
with something like this:
char stringToConvert[256]; // if you type more than 256 characters, you'll crash
sscanf("%s",&stringToConvert);
guess = atoi(stringToConvert); // this function converts the string into an integer
If you type in the character "a", scanf converts that to 97 in the ascii table.