I have a comma separated strings inside brackets and I need to replace the string in matches the pattern.
And we have unknown string at the start and at the end. In the below example I need to replace c++ string with c if the row has string ruby.
I tried below sed command but it didnt work.
```
("java","php","ruby",".net","scala","c++",...n),
(".net","ruby","php","java","c++",...n),
("java",".net","ruby","php","c++",...n),
("ruby","java",".net","php","c++",...n);
```
```
sed -e "s/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g"
```
("java","php","ruby",".net","scala","c++",...n),
(".net","ruby","php","java","c++",...n),
("java",".net","ruby","php","c++",...n),
("ruby","java",".net","php","c++",...n);
'
{m,n,g}awk '/\42ruby\42/ ? NF = NF : NF' FS='"c[+][+]"' OFS='"c"'
'
("java","php","ruby",".net","scala","c",...n),
(".net","ruby","php","java","c",...n),
("java",".net","ruby","php","c",...n),
("ruby","java",".net","php","c",...n);
it seems like your sed command is not escaping double quotes
sed -e "s/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g"
change it to single quotes.
sed -e 's/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g' file.txt
or more simply use the below one...
sed -e 's/\("ruby"\),\(.*\),"c++"/\1,\2,"c"/g' my_file.txt
which will output
("jsjs","java",".net","php","c++",...n);
("java","php","ruby",".net","scala","c",...n),
(".net","ruby","php","java","c",...n),
("java",".net","ruby","php","c",...n),
("ruby","java",".net","php","c",...n);
("rubys","java",".net","php","c++",...n);
Related
I have a sed expression in a function that I pass parameters to.
insert_after_new_line() {
if ! grep -q "${2}" "${3}"; then
sed -i "/${1}/{N;N;a ${2}}" "${3}"
fi
}
insert_after_new_line search insert textfile.txt
I am trying to have a blank line inserted below the search string and the insert string inserted after.
so
text
text
search
text
becomes
text
text
search
insert
text
but I keep getting the error
sed: -e expression #1, char 0: unmatched `{'
I tested this. works in command line
sed -i '/search/a \\ninsert' file
sed really delimiters commands by a newline. There is a ; but it does not work for all commands, mostly these which take file name as an argument. ; does not work for r R or for example a. Sed will read everything after a command, so sed interprets is like a ${2}} as a single command, in result it does not find enclosing }, cause it's been eaten by a command. You need a newline:
sed -i "/${1}/{N;N;a ${2}
}" "${3}"
or
sed -i "/${1}/{N;N;a ${2}"$'\n'"}" "${3}"
this should work:
sed -i '/search/{G;ainsert
}' file
You can replace the text by shell variable, but replace the single quotes by double quotes too.
I have this shell line to concatenate 2 string:
new_group="second result is: ${result},\"${policyActivite}_${policyApplication}\""
echo "result is: ${new_group}"
The result:
result is: "Team","Application_Team"
How can change the result to: result is: "Team, Application_Team"
Use sed:
echo "$new_group" | sed 's/"//g;s/^\(.*\)$/"\1"/'
The first statement is removing all double quotes. The second one add double at the start and the end of the line.
Alternatively, if you want to replace "," with ,, use this sed command: sed 's/","/, /g'
I have strings which contain double quotes like this one:
"[{"clientid":"*", "identityzone":"*"}]"
I would like to use set or grep to delete the double quotes at the beginning and at the end of it, the output should look like :
[{"clientid":"*", "identityzone":"*"}]
I have used : sed -e 's/\"//g' but this deletes all the " in a string
You need to use line anchors
$ echo '"[{"clientid":"*", "identityzone":"*"}]"' | sed 's/^"//; s/"$//'
[{"clientid":"*", "identityzone":"*"}]
^" match " only at start of line
"$ match " only at end of line
You can also combine them using | as sed 's/^"\|"$//g'
See Overview of basic regular expression syntax
easy:
sed 's/^\"\(.*\)\"$/\1/g' <<<'"[{"clientid":"*", "identityzone":"*"}]"'
I have a string in which I need to replace "," with "\," using shell script. I thought I can use sed to do this but no luck.
You can do that without sed:
string="${string/,/\\,}"
To replace all occurrences of "," use this:
string="${string//,/\\,}"
Example:
#!/bin/bash
string="Hello,World"
string="${string/,/\\,}"
echo "$string"
Output:
Hello\,World
You need to escape the back slash \/
I'm not sure what your input is but this will work:
echo "teste,test" |sed 's/,/\\/g'
output:
teste\test
Demo:
http://ideone.com/JUTp1X
If the string is on a file, you can use:
sed -i 's/,/\//g' myfile.txt
i want to replace a special string inside a file.txt. my strings are like this :
-> Old String
tech=/lsf/dfg/a.v,/ldf/fgh/b.v
-> New String
tech=$var
i have tried following
sed -i 's/tech=/lsf/dfg/a.v,/ldf/fgh/b.v/tech=$var/g' file.txt
it doesnt work.
sed -i 's#tech=/lsf/dfg/a.v,/ldf/fgh/b.v#tech=$var#g' file.txt
Just replace the delimiters '/' for the sed expression with '#' (or another character that is not in the string you are trying to match and replace).