I have a comma separated strings inside brackets and I need to replace the string in matches the pattern.
And we have unknown string at the start and at the end. In the below example I need to replace c++ string with c if the row has string ruby.
I tried below sed command but it didnt work.
```
("java","php","ruby",".net","scala","c++",...n),
(".net","ruby","php","java","c++",...n),
("java",".net","ruby","php","c++",...n),
("ruby","java",".net","php","c++",...n);
```
```
sed -e "s/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g"
```
("java","php","ruby",".net","scala","c++",...n),
(".net","ruby","php","java","c++",...n),
("java",".net","ruby","php","c++",...n),
("ruby","java",".net","php","c++",...n);
'
{m,n,g}awk '/\42ruby\42/ ? NF = NF : NF' FS='"c[+][+]"' OFS='"c"'
'
("java","php","ruby",".net","scala","c",...n),
(".net","ruby","php","java","c",...n),
("java",".net","ruby","php","c",...n),
("ruby","java",".net","php","c",...n);
it seems like your sed command is not escaping double quotes
sed -e "s/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g"
change it to single quotes.
sed -e 's/(\(.*\),\("ruby"\),\(.*\),"c++",\(.*\))/(\1,\2,\3,"c",\4)/g' file.txt
or more simply use the below one...
sed -e 's/\("ruby"\),\(.*\),"c++"/\1,\2,"c"/g' my_file.txt
which will output
("jsjs","java",".net","php","c++",...n);
("java","php","ruby",".net","scala","c",...n),
(".net","ruby","php","java","c",...n),
("java",".net","ruby","php","c",...n),
("ruby","java",".net","php","c",...n);
("rubys","java",".net","php","c++",...n);
I want to search for a string and then from that string i want to replace 10 characters with another 10 characters.
For Example,
/prd/edm/hadoop/ifrs/eglex/hdata/ifrs_sri_open/eglex_*_txnacbal/ods=2020_02_23/
i want to search for string "ods=" and replace "2020_02_23" with "2020_02_30"
Since that date "2020_02_23" is not consistent i wanted to search with "ods=" which is static and one time for a line.
Like this more lines are there in the file.
I tried:
cat dta_1.sh | sed 's/.*ods=//' | cut -c1-10
I want to search for string "ods=" and replace "2020_02_23" with
"2020_02_30"
sed 's|\(.*ods=\).*|\12020_02_30/|g' inputfile
The regex inside the parenthesis \( \) is reproduced by \1, and the string after ods= is replaced by 2020_02_30/.
If there could be something else besides / after the date, then go for this:
sed 's|\(.*ods=\)...._.._..|\12020_02_30|g' inputfile
I've completed this using the below,
sed -i '/ods=/ s|ods="[^"]*"|ods='"${DATE_FORMAT2}"'|g' dta_2.sh
Thanks all for the response
I have a sed expression in a function that I pass parameters to.
insert_after_new_line() {
if ! grep -q "${2}" "${3}"; then
sed -i "/${1}/{N;N;a ${2}}" "${3}"
fi
}
insert_after_new_line search insert textfile.txt
I am trying to have a blank line inserted below the search string and the insert string inserted after.
so
text
text
search
text
becomes
text
text
search
insert
text
but I keep getting the error
sed: -e expression #1, char 0: unmatched `{'
I tested this. works in command line
sed -i '/search/a \\ninsert' file
sed really delimiters commands by a newline. There is a ; but it does not work for all commands, mostly these which take file name as an argument. ; does not work for r R or for example a. Sed will read everything after a command, so sed interprets is like a ${2}} as a single command, in result it does not find enclosing }, cause it's been eaten by a command. You need a newline:
sed -i "/${1}/{N;N;a ${2}
}" "${3}"
or
sed -i "/${1}/{N;N;a ${2}"$'\n'"}" "${3}"
this should work:
sed -i '/search/{G;ainsert
}' file
You can replace the text by shell variable, but replace the single quotes by double quotes too.
I am trying to change the following string
FROM java_jre_8#sha256:92f22331226b9b3c43a15eeeb304dd7
to
FROM docker-registry.service.consul:5000/java_jre_8#sha256:92f22331226b9b3c43a15eeeb304dd7
but am having difficult with sed as a result of / character
This is for a build server.
There are two ways of doing this. The first is to escape each / in the string you're replacing:
sed 's/from/to with \/ ... /'
The other, more simple way is to use a delimiter other than /. While most sed examples use / as a delimiter, you can use any character:
sed 's|from|to with / ...|'
Here, the | is the first character following s, and therefore sed knows to use this as a delimiter.
You can use # as the delimiter as it doesn't appear in your string (you can still use / but then you'll have to quote the actual /s that are part of the string).
sed "s#FROM java_jre_8##FROM docker-registry.service.consul:5000/java_jre_8##'
Example:
$ echo "FROM java_jre_8#sha256:92f22331226b9b3c43a15eeeb304dd7" | sed "s#FROM java_jre_8##FROM docker-registry.service.consul:5000/java_jre_8##"
FROM docker-registry.service.consul:5000/java_jre_8#sha256:92f22331226b9b3c43a15eeeb304dd7
I have a file that contains lot of underscores and i have to replace all of them with empty string except the ones that are part of a specific string usr_mstr.
I have tried sed command, it replaces underscore and excludes the words i provided, but it also replaces the character immediately following underscore! Any help will greatly be appreciated..
echo "fname_sname_id_usr_mstr" | sed 's/_[^usr_mstr]//g'
Expected output:
fnamesnameidusr_mstr
Actual Output:
fnamenamedusr_mstr
(s and i got replaced)
This might work for you (GNU sed):
sed -r 's/(usr_mstr)|_/\1/g' file
Globally replace usr_mstr by itsself or replace _ by nothing
[^usr_mstr] is a character class that matches any character that's not u, s, r, m, t, or _.
Perl supports "look-around" assertions, so you can write:
echo "fname_sname_id_usr_mstr_x_usr_other_mstr_y_usrmstr_z" \
| perl -pe 's/(?<!usr)_//g;s/_(?!mstr)//g'
i.e. replace _ if not preceded by usr, and not followed by mstr.
You cannot solve this with standard sed BRE regex alone. With sed you would basically need to replace "usr_mstr" with a placeholder string, then replace all the underscores and then replace the placeholder string with the "usr_master" ..
echo "fname_sname_id_usr_mstr" |
{ null="###"; sed "s/usr_mstr/$null/g; s/_//g; s/$null/usr_mstr/g" ;}
An alternative is to try awk :
echo "fname_sname_id_usr_mstr" |
awk -v s="usr_mstr" 'BEGIN{FS=OFS=s} {for(i=1; i<=NF; i++) gsub("_","",$i)}1'
Which should work as long a s does not contains regular characters that are special in extended regular expressions.