How to compile different c files with different CFLAGS using Makefile? - makefile

all. Let's say I have a program that contains a long list of C source files, A.c, B.c, ...., Z.c, now I want to compile A.c, B.c with certain CFLAGS, and compile the rest part of source files with a different CFLAGS value.
How to write a Makefile to do the above described job? currently what I am doing in my Makefile is:
OBJ=[all other .o files here, e.g. D.o, D.o, E.o .... Z.o]
SPECIAL_OBJS=A.o B.o
all: $(OBJ) $(SPECIAL_OBJS)
$(SPECIAL_OBJS):
#echo [Compiling]: $(#:.o=.c)
$(CC) [SOME OTHER GCC OPTIONS HERE] $(CFLAGS) -c $(#:.o=.c) -o $#
%.o: %.c
#echo [Compiling]: $<
$(CC) $(CFLAGS) -o $# -c $<
It works, but looks just stupid/complicated. Can anyone help to point out what is the recommended way of doing this in Makefile? thanks!

Try using target-specific variables. A target-specific variable is declared like this:
TARGET: VAR := foo # Any valid form of assignment may be used ( =, :=, +=, ?=)
Now when the target named TARGET is being made, the variable named VAR will have the value "foo".
Using target-specific variables, you could do this, for example:
OBJ=[all other .o files here, e.g. D.o, D.o, E.o .... Z.o]
SPECIAL_OBJS=A.o B.o
all: $(OBJ) $(SPECIAL_OBJS)
$(SPECIAL_OBJS): EXTRA_FLAGS := -std=c99 # Whatever extra flags you need
%.o: %.c
#echo [Compiling]: $<
$(CC) $(CFLAGS) $(EXTRA_FLAGS) -o $# -c $<

The approach taken by linux kernel build system:
CFLAGS += $(CFLAGS-$#)
And then,
CFLAGS-A.o += -DEXTRA
CFLAGS-B.o += -DEXTRA

I can't answer the question for raw makefiles, but if you are willing to use automake it is trivial:
foo_CFLAGS = [options passed to CC only when building foo]

Related

Makefile not executing to the end

I have the following makefile but it just executes the 1st command where it builds me the .o files and not the .so files. What am I doing wrong?
Thanks,
SHELL = /bin/sh
CC = gcc
CFLAGS = -g -Wall
LDFLAGS = -shared
TARGET = Stepper.so
SOURCES = $(shell echo ./*.c)
HEADERS = $(shell echo ./*.h)
OBJECTS = $(SOURCES:.c=.o)
LIBS = liblua523.a
PREFIX = $(DESTDIR)/usr/local
BINDIR = $(PREFIX)/bin
$(OBJECTS): $(SOURCES) $(HEADERS)
$(CC) $(CFLAGS) -c $(SOURCES) -o $(OBJECTS)
$(TARGET): $(OBJECTS)
$(CC) $(LDFLAGS) -o $(TARGET) $(OBJECTS) $(LIBS)
clean:
rm $(OBJECTS)
Unless you specify a different target on the command line, make always builds the first real target found in the makefile. In this case, the first real target is the first object file, so that's all that's built.
This is why you typically see makefiles with a first target of all or similar, which just depends on the various other targets you want built during a standard invocation of "make" with no arguments.
However, your makefile is really not right, in a number of ways. The fact that it's running it all means you actually only have one source file. As soon as you have >1 it will fail.
This:
SOURCES = $(shell echo ./*.c)
is not very efficient; you should use wildcard here:
SOURCES = $(wildcard ./*.c)
This rule:
$(OBJECTS): $(SOURCES) $(HEADERS)
$(CC) $(CFLAGS) -c $(SOURCES) -o $(OBJECTS)
Tells make, "for every object file, if any source file or any header file has changed, recompile it". Basically, it means that if you change ANYTHING in the directory, EVERYTHING will rebuild. If you want that you might as well write a shell script and not bother with make at all.
Further, the compiler will fail when you have >1 source file, as it will try to run:
gcc -g -Wall -c foo.c bar.c -o foo.o bar.o
which is not right.
You don't need to define this rule at all; make has a built-in rule which knows how to build an object file from a source file. Just replace it with this:
$(OBJECTS): $(HEADERS)
(no recipe) so make knows that the objects depend on the headers as well as the source. Note this is not ideal since all objects rebuild if any header changes but it's fine for a simple program.

Makefile: target with pattern does not work

My Makefile looks like this:
BIN = bin
OBJECTS = object1.o \
object2.o \
object3.o
HDR = $(OBJECTS:%.o=%.h) header1.h header2.h
MAIN = main.c
CC = gcc
CFLAGS = -Wall -g -std=c99 -fstack-protector-all
LDFLAGS = -lpthread
$(BIN): $(OBJECTS) $(MAIN)
$(CC) $(CFLAGS) $(LDFLAGS) -o $# $^
%.o: %.c $(HDR)
$(CC) $(CFLAGS) -c $< -o $#
It seems that the %.o: %.c $(HDR) rule is not used. When invoking with option make -r it says that there's no rule to make target object.o. The build of each object file should depend on every header file. What am I missing?
Edit: I should mention that when doing echo $(HDR) than it looks like the variable contains the right values:
object1.h object2.h object3.h header1.h header2.h
In the declaration of HDR, try $(OBJECTS:.o=.h) instead. Or, better yet, use gcc -MM or the like to generate your dependencies instead.
A pattern rule can't have auxilliary dependencies like ${HDR}.
Use:
%.o : %.c
$(CC) $(CFLAGS) -c $< -o $#
${OBJECTS}: ${HDR}
Ok, the given Makefile should work, I had a typo in one of the header file names.
It's a pitty, but make doesn't warn about that. It seems that when a pattern based rule is missing a prerequisite than it's just ignored. The built-in .o creation rule is used instead.
Jonathan Leffler's proposal of ${OBJECTS}: ${HDR} brought that up, because than there's an error regarding "no rule to make target misspelled.h" - I would have expected that from my rule too.
So I can just agree to fluffy, it's better to use auto-generated dependencies instead.

How to write a simpler makefile for a lot of single-c-file programmes?

I want to write a lot of tiny example programmes for one same library, each needs gcc $(OtherOpt) -o xxx -lthelibname xxx.c.
How to write a Makefile without dozens of tagret lines ?
Pattern rules are your friend for these situations. As long as your targets all match a predictable pattern -- and they do in this case, as they are all of the form "create foo from foo.c" -- you can write a single pattern rule that will be used for all of the targets:
OtherOpt=-Wall -g
all: $(patsubst %.c,%,$(wildcard *.c))
%: %.c
gcc $(OtherOpt) -o $# -lthelibname $<
Now you can either run simply make to build all your apps, or make appname to build a specific app. Here I've created a single pattern rule that will be used anytime you want to create something from something.c. I used the $# automatic variable, which will expand to the name of the output, and the $< variable, which will expand to the name of the first prerequisite, so that the command-line is correct regardless of the specific app being built. Technically you don't need the all line, but I figured you probably didn't want to always have to type in the name(s) of the apps you want to build.
Also, technically you can probably get away without having any of this makefile, because GNU make already has a built-in pattern rule for the %: %.c relationship! I mention this option only for completeness; personally, I prefer doing things the way I've shown here because it's a little bit more explicit what's going on.
%.o: %.c
gcc $(OtherOpt) -c -o $# -lthelibname $<
That compiles all .c files to their .o files (object code) of the same base name. Then in your actual target(s), you would include all necessary .o files as dependencies and use gcc $(OtherOpt) -o $# $^ -lthelibname, assuming I'm not misunderstanding how your build is set up.
Some versions of make also support the suffix rule .c.o to be ALMOST the same thing as %.o: %.c, but the suffix rules can't have any dependencies. Writing .c.o: foo.h tells make to compile "foo.h" to "foo.c.o" rather than requiring "foo.h" as a dependency of any file with a .c suffix as %.o: %.c foo.h would correctly do.
I learnd from http://sourceforge.net/projects/gcmakefile/
LDLIB = -lpthread
LDFLAGS = -Wl,-O1 -Wl,--sort-common -Wl,--enable-new-dtags -Wl,--hash-style=both $(LDLIB)
SRCDIRS =
SRCEXTS = .c .C .cc .cpp .CPP .c++ .cxx .cp
CFLAGS = -pipe -march=core2 -mtune=generic -Wfloat-equal \
#-Wall -pedantic
ifeq ($(SRCDIRS),)
SRCDIRS = .
endif
SOURCES = $(foreach d,$(SRCDIRS),$(wildcard $(addprefix $(d)/*,$(SRCEXTS))))
TARGET = $(addprefix bin/,$(basename $(SOURCES)))
all: $(TARGET)
ls -l $(TARGET)
bin/%: %.c dir
gcc $(CFLAGS) $(LDFLAGS) -o $# $<
dir:
#-mkdir bin
.PHONY : clean
clean:
-rm $(TARGET)
-rmdir bin

How to instruct Makefile to use different compilers

I have to build my code for two different platforms at once using two different compilers and libraries. How can I do this with single make file.
Currently my makefile contents are given below. How can I instruct it to change the compiler to gcc within the same makefile?
VPATH = /root/Documents/project/src
CROSS_COMPILE = /opt/compilers/bin/compiler1
CXX = $(CROSS_COMPILE)-g++
CC = $(CROSS_COMPILE)-gcc
AS = $(CROSS_COMPILE)-as
AR = $(CROSS_COMPILE)-ar
NM = $(CROSS_COMPILE)-nm
LD = $(CROSS_COMPILE)-ld
OBJDUMP = $(CROSS_COMPILE)-objdump
OBJCOPY = $(CROSS_COMPILE)-objcopy
RANLIB = $(CROSS_COMPILE)-ranlib
STRIP = $(CROSS_COMPILE)-strip
CFLAGS = -c -Wall -D_REENTRANT -DACE_HAS_AIO_CALLS -D_GNU_SOURCE -DACE_HAS_EXCEPTIONS -D__ACE_INLINE__
LDFLAGS = -L. -L/etc/ACE_wrappers/lib
CPPFLAGS += -I/etc/ACE_wrappers -I/etc/ACE_wrappers/ace
LDLIBS = -lACE
OUTPUT_DIRECTORY=/root/Documents/bin
OBJ=/root/Documents/obj
ifneq ($(OUTPUT_DIRECTORY),)
all: $(OUTPUT_DIRECTORY)
$(OUTPUT_DIRECTORY):
-#$(MKDIR) "$(OUTPUT_DIRECTORY)"
endif
ifneq ($(OBJ),)
all: $(OBJ)
$(OBJ_DIR):
-#$(MKDIR) "$(OBJ)"
endif
SOURCES=File_1.cpp File_2.cpp
OBJECTS=$(SOURCES:%.cpp=$(OBJ)/%.o)
$(OBJ)/%.o: %.cpp
#echo Building Objects
$(CC) $(CFLAGS) $(CPPFLAGS) $(CXXFLAGS) -c -o $# $<
EXECUTABLE=MyExecutable
all: $(SOURCES) $(EXECUTABLE)
$(EXECUTABLE): $(OBJECTS)
#echo $(SOURCES)
$(CC) $(LDFLAGS) $(OBJECTS) $(LDLIBS) -o $(OUTPUT_DIRECTORY)/$#
File_1.o:File_1.cpp
File_1.o:File_1.cpp
.PHONY: clean
clean:
rm $(OBJECTS) $(OUTPUT_DIRECTORY)/$(EXECUTABLE)
I'd start by putting all the platform-specific defines in a separate makefile. That way you can do:
include $(TARGET).make
Where $(TARGET).make defines CC and other variables for each particular platform. Then you can call make recursively setting TARGET to what you want. Something like:
build:
$(MAKE) TARGET=platform1 all
$(MAKE) TARGET=platform2 all
But really there are many, many ways in which you can achieve the same thing.
Use autoconf. When you configure the project with ./configure, it will automatically choose the one available.
That would be a lot easier to read if the linebreaks were properly preserved in your post.
Anyway, I expect that you're going to have to have two copies of a number of things in the Makefile, such that it's of the form
all : all-platform1 all-platform2
stuff-platform1 : requirements
$(CC1) whatever
stuff-platform2 : requirements
$(CC2) whatever
It's possible that you might be able to auto-generate a makefile like this, to save some effort though.

Change Makefile variable value depending on a target

I am not proficient with makefiles, but am used to simple ones. Right now, I have a task on hand.
I need to compile and link a test application with a different library and different include path based on the given target. If target is TARGET1, then link against LIB1 and include INCLUDEPATH1 during compilation. Similarly, if given target is TARGET2, then compile with INCLUDEPATH2 in CFLAGS and link with LIB2.
%.o: %.c
#echo [CC] $< ...
$(CC) $(CFLAGS) -o $*.o $<
Now I have a rule as above which compiles my test application. Now how can the CFLAGS be changed based on the target.
If you are using GNU Make, you can use target-specific variables:
target1: CFLAGS = -IINCLUDEPATH1
target1: LDLIBS = -lLIB1
target2: CFLAGS = -IINCLUDEPATH2
target2: LDLIBS = -lLIB2
all: target1 target2
target1: target1.o misc.o
target2: target2.o
However this doesn't work quite as well as you'd like: if target1 and target2 share some source files, you'll need to arrange for them to each be compiled twice and to differently-named .o files -- which will rather complexify your makefile.
Also, if you type make target1 then -IINCLUDEPATH1 will be propagated to the compilation of misc.c, as desired. However if you type make misc.o it has no way to know that this is eventually destined for target1 and the compilation of misc.c will get no special $CFLAGS value (though it'll get the global one, if there is one).
So this is really only useful in simple cases. But maybe your case is sufficiently simple.
I don't think you can alter variable depending on a target. Assume you invoke
make TARGET1 TARGET2
What value would the CFLAGS have then?
In this case, you can use non-pattern rules to distinguish targets.
TARGET1: a.c
#echo [CC] $< ...
$(CC) -I INCLUDEPATH1 ...
TARGET2: a.c
#echo [CC] $< ...
$(CC) -I INCLUDEPATH2 ...
To decrease repetition, you may also use variables and "functions". Then, you could re-use what would be the body of your pattern rule in different rules.
define compile_cmd
#echo [CC] $< ...
$(CC) -I $1 -l$2 $(CFLAGS)
endef
TARGET1: a.c
$(call compile_cmd,INCLUDEPATH1,LIB1) -o $# $<
TARGET2: a.c
$(call compile_cmd,INCLUDEPATH2,LIB2) -o $# $<
%.o: %.c
$(call compile_cmd,INCLUDEPATH_DEFAULT,LIB_DEFAULT) -o $# $<
That would make a nice enough and flexible makefile that suits your needs.

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