Ruby Rack - mounting a simple web server that reads index.html as default - ruby

Question

I'm trying to get some information from this tutorial: http://m.onkey.org/2008/11/18/ruby-on-rack-2-rack-builder
basically I want to have a file config.ru that tell rack to read the current directory so I can access all the files just like a simple apache server and also read the default root with the index.html file...is there any way to do it?
my current config.ru looks like this:
run Rack::Directory.new('')
#this would read the directory but it doesn't set the root to index.html
map '/' do
file = File.read('index.html')
run Proc.new {|env| [200, {'Content-Type' => 'text/html'}, file] }
end
#using this reads the index.html mapped as the root but ignores the other files in the directory
So I don't know how to proceed from here...
I've also tried this following the tutorials example but thin doesn't starts properly.
builder = Rack::Builder.new do
run Rack::Directory.new('')
map '/' do
file = File.read('index.html')
run Proc.new {|env| [200, {'Content-Type' => 'text/html'}, file] }
end
end
Rack::Handler::Thin.run builder, :port => 3000
Thanks in advance

Answer 1

I think that you are missing the the rackup command. Here is how it is used:
rackup config.ru
This is going to run your rack app on port 9292 using webrick. You can read "rackup --help" for more info how you can change these defaults.
About the app that you want to create. Here is how I think it should look like:
# This is the root of our app
#root = File.expand_path(File.dirname(__FILE__))
run Proc.new { |env|
# Extract the requested path from the request
path = Rack::Utils.unescape(env['PATH_INFO'])
index_file = #root + "#{path}/index.html"
if File.exists?(index_file)
# Return the index
[200, {'Content-Type' => 'text/html'}, File.read(index_file)]
# NOTE: using Ruby >= 1.9, third argument needs to respond to :each
# [200, {'Content-Type' => 'text/html'}, [File.read(index_file)]]
else
# Pass the request to the directory app
Rack::Directory.new(#root).call(env)
end
}

Answer 2

I ended up on this page looking for a one liner...
If all you want is to serve the current directory for a few one-off tasks, this is all you need:
ruby -run -e httpd . -p 5000
Details on how it works: http://www.benjaminoakes.com/2013/09/13/ruby-simple-http-server-minimalist-rake/

Answer 3

You can do this using Rack::Static
map "/foo" do
use Rack::Static,
:urls => [""], :root => File.expand_path('bar'), :index => 'index.html'
run lambda {|*|}
end

Answer 4

For me, using Ruby 2.0 and Rack 1.5.2, sinm solution worked for serving the index page (both as default page for root and loaded explicitly), but for other files I obtained errors similar to the following:
Rack::Lint::LintError: Status must be >=100 seen as integer
I combined sinm solution with this SO answer and the snippet found on Heroku documentation to obtain the desired behavior (assuming that the entire site is contained in a folder called public):
use Rack::Static,
:urls => ["/images", "/js", "/css"],
:root => "public",
:index => 'index.html'
run Rack::File.new("public")

Answer 5

My example for doing the exact same below:
module Rack
class DirectoryIndex
def initialize(app)
#app = app
end
def call(env)
index_path = ::File.join($documentRoot, Rack::Request.new(env).path.split('/'), 'index.html')
if ::File.exists?(index_path)
return [200, {"Content-Type" => "text/html"}, [::File.read(index_path)]]
else
#app.call(env)
end
end
end
end
require 'rack_directory_index.rb'
$documentRoot = File.expand_path(File.join(File.dirname(__FILE__), '..', '..', 'build'))
Capybara.app = Rack::Builder.new do |builder|
puts "Creating static rack server serving #{$documentRoot}"
use Rack::DirectoryIndex
run Rack::Directory.new($documentRoot)
end
Capybara.configure do |config|
config.run_server = true
end
The solution is mostly a copy and paste from different answers but it works fine. You can find it as a gist here aswell, good luck