I have a bash script in Ubuntu, I want it to run every 10 minutes for example after it's done. How can I do this? Thanks!
You can check watch.
From the man pages of watch the description says watch - execute a program periodically, showing output fullscreen, you can try watch -n 600 my_script.sh which will execute myscript.sh every 600 seconds i.e. 10 minutes. watch shows the output to full screen, you can redirect it to say /dev/null in case you are not interested in the output to the screen.
Hope this helps!
Cronjobs is what you need.
My blog post:- http://linux-junky.blogspot.com/2010/10/guide-to-add-cronjob-simplified.html
Or you can also use sleep 600 in your script.
You can use at to reschedule the script from within the script. At the end of the script put:
at now + 10 minutes << END
"$0" "$#"
END
Or with crontab -e, or another option, to check the date. for example, if you want to do something every 10 minutes, you can write:
if [ $((`date +%M`%10)) -eq 0 ] && [ `date +%S` -lt 10 ]; then
#your code
fi
Related
I have an Shell script that runs a PHP script every 8 seconds as seen below:
enter code here
#!/bin/bash
while true; do
php /var/www/html/folder1/scripts/processtask.php /var/www/html/folder1/app
sleep 8;
done
enter code here
I need it to continue this way, however I need it to stop running at 2am until 3am then resume after that on a daily basis
You can use cronetab for the same. Check the below link for configuration:
https://www.baeldung.com/linux/schedule-script-execution
If you only want to start the script if not between 2am and 3am (but an allready started script does not need to be stopped) this could be easily checked with an additional if-statement:
#!/bin/bash
while true; do
if [[ 2 -le $(date '+%H') && $(date '+%H') -le 3 ]]; then
sleep 60
else
php /var/www/html/folder1/scripts/processtask.php /var/www/html/folder1/app
sleep 8
fi
done
I'm working on a bash script that will run for appoximately 30 minutes at a time. I've got it running stable as far as that part goes. I've been looking for a way to make it fire certain commands at inervals of every 3 minutes while running. I've not had any luck, so I turn to those of you that may know more about bash than I.
Any suggestions?
Here is what I have in mind of doing.
START=$(date +%s);
while read LINE <&3; do
END=$(date +%s);
if [[ $(($END-$START)) > 180 || $(($END-$START)) == 180 ]]
then
$START=$(date +%s);
run command
fi
done
Add a cron job to make it run every 3 minutes.
*/3 * * * * /path/to/script
What about the watch command?? (https://unix.stackexchange.com/questions/10646/repeat-a-unix-command-every-x-seconds-forever)
(Second answer on here: Run command every second)
You can run a loop in the background:
{ while /bin/true; do some_command; sleep 180; done; } &
loop_pid=$!
Then before the main script exits, kill the background loop:
kill $loop_pid
You can also call the same script from same script.
$ cat script.sh
#!/bin/bash
# commands
# commands
sleep 1800
sh $0
I have only found how to wait for user input. However, I only want to pause so that my while true doesn't crash my computer.
I tried pause(1), but it says -bash: syntax error near unexpected token '1'. How can it be done?
Use the sleep command.
Example:
sleep .5 # Waits 0.5 second.
sleep 5 # Waits 5 seconds.
sleep 5s # Waits 5 seconds.
sleep 5m # Waits 5 minutes.
sleep 5h # Waits 5 hours.
sleep 5d # Waits 5 days.
One can also employ decimals when specifying a time unit; e.g. sleep 1.5s
And what about:
read -p "Press enter to continue"
In Python (question was originally tagged Python) you need to import the time module
import time
time.sleep(1)
or
from time import sleep
sleep(1)
For shell script is is just
sleep 1
Which executes the sleep command. eg. /bin/sleep
Run multiple sleeps and commands
sleep 5 && cd /var/www/html && git pull && sleep 3 && cd ..
This will wait for 5 seconds before executing the first script, then will sleep again for 3 seconds before it changes directory again.
I realize that I'm a bit late with this, but you can also call sleep and pass the disired time in. For example, If I wanted to wait for 3 seconds I can do:
/bin/sleep 3
4 seconds would look like this:
/bin/sleep 4
On Mac OSX, sleep does not take minutes/etc, only seconds. So for two minutes,
sleep 120
Within the script you can add the following in between the actions you would like the pause. This will pause the routine for 5 seconds.
read -p "Pause Time 5 seconds" -t 5
read -p "Continuing in 5 Seconds...." -t 5
echo "Continuing ...."
read -r -p "Wait 5 seconds or press any key to continue immediately" -t 5 -n 1 -s
To continue when you press any one button
for more info check read manpage ref 1, ref 2
You can make it wait using $RANDOM, a default random number generator. In the below I am using 240 seconds. Hope that helps #
> WAIT_FOR_SECONDS=`/usr/bin/expr $RANDOM % 240` /bin/sleep
> $WAIT_FOR_SECONDS
use trap to pause and check command line (in color using tput) before running it
trap 'tput setaf 1;tput bold;echo $BASH_COMMAND;read;tput init' DEBUG
press any key to continue
use with set -x to debug command line
I was hoping somebody would be able to help me with this
I need a loop for a shell script that will run what is inside the loop for 15 seconds. SO for example
if (true)
run command for 15 seconds
fi
kill PID
I am new to shell scripting, so i am lost with this.
Also I am using a debian instll if that makes any difference
Any help is appreciated
Are you looking for the timeout command?
The following bash script might work for you. The script will set the initial epoch time as a variable prior to beginning a loop. While the loop runs an additional variable will be set with the current epoch time. Both epoch times will be compared and as long as the difference is less than or equal to 15 your command will continue to run. Note that in the script below the current command running is 'echo "counting ${COUNTER}"'. You should change this portion of the script to match what you are trying to accomplish. Once the difference of the two epoch times is greater than 15 the script will exit. You will need to initate your kill command at this point. If an error does occur you should see "ERROR... YourScript.sh failed" in "YourLogFile" (set your log file to what you would like)
NOTE: Whatever you are attempting to run while inside this loop may run many many many times within the 15 second period. By utilizing the script below as a test you will see that the echo command runs more than 50 times per second.
#!/bin/bash
LOOP="true"
INITIAL_TIME=$(date "+%s")
while [[ ${LOOP} == true ]]; do
CURRENT_TIME=$(date "+%s")
COUNTER=$(expr ${CURRENT_TIME} - ${INITIAL_TIME})
if [[ ${COUNTER} -le "15" ]]; then
echo "counting ${COUNTER}"
# RUN YOUR COMMAND IN PLACE OF THE ABOVE echo COMMAND
elif [[ ${COUNTER} -gt "15" ]]; then
exit 0
#INITIATE YOUR KILL COMMAND IN PLACE OF OR BEFORE THE exit
else
echo "ERROR... YourScript.sh failed" >> /YourLogFile
fi
done
this shell explain the issue ,
after executing the .sh file halt and nothing happen , any clue where is my mistake
its kill httpd if there is more than 10 sleep process and start the httpd with zero sleep process
#!/bin/bash
#this means loop forever
while [ 1 ];
do HTTP=`ps auwxf | grep httpd | grep -v grep | wc -l`;
#the above line counts the number of httpd processes found running
#and the following line says if there were less then 10 found running
if [ $[HTTP] -lt 10 ];
then killall -9 httpd;
#inside the if now, so there are less then 10, kill them all and wait 1 second
sleep 1;
#start apache
/etc/init.d/httpd start;
fi;
#all done, sleep for ten seconds before we loop again
sleep 10;done
Why would you kill the child processes? If you do that you killing all ongoing sessions. Would it not be easier to setup your Webserver configuration so that it matches your needs?
As Dennis has mentioned already your script should look like:
#!/bin/bash
BINNAME=httpd # Name of the process
TIMEOUT=10 # Seconds to wait until next loop
MAXPROC=10 # Maximum amount of procs for given daemon
while true
do
# Count number of procs
HTTP=`pgrep $BINNAME | wc -l`
# Check if more then $MAXPROC are running
if [ "$HTTP" -gt "$MAXPROC" ]
then
# Kill the procs
killall-9 $BINNAME
sleep 1
# start http again
/etc/init.d/httpd start
fi
sleep $TIMEOUT
done
Formating makes code more readable ;)
I can't see anything wrong with it.
This line:
if [ $[HTTP] -lt 10 ];
should probably be:
if [ ${HTTP} -lt 10 ];
even though yours works.
If you add this as the last line, you should never see its output since you're in an infinite while loop.
echo "At end"
If you do, then that's really weird.
Make your first line look like this and it will display the script line-by-line as it executes to help you see where it's going wrong:
#!/bin/bash -x
Watch out for killall if you are trying to write portable scripts. It doesn't mean the same thing on every system: while on linux it means "kill processes named like this" on some systems it means "kill every process I have permission to kill".
If you run the later version as root, one of the things you kill is init. Oops.