How to act differently on the first iteration in a Ruby loop? - ruby

Question

I always use a counter to check for the first item (i==0) in a loop:
i = 0
my_array.each do |item|
if i==0
# do something with the first item
end
# common stuff
i += 1
end
Is there a more elegant way to do this (perhaps a method)?

Answer 1

You can do this:
my_array.each_with_index do |item, index|
if index == 0
# do something with the first item
end
# common stuff
end
Try it on ideone.

Answer 2

Using each_with_index, as others have described, would work fine, but for the sake of variety here is another approach.
If you want to do something specific for the first element only and something general for all elements including the first, you could do:
# do something with my_array[0] or my_array.first
my_array.each do |e|
# do the same general thing to all elements
end
But if you want to not do the general thing with the first element you could do:
# do something with my_array[0] or my_array.first
my_array.drop(1).each do |e|
# do the same general thing to all elements except the first
end

Answer 3

Arrays have an "each_with_index" method which is handy for this situation:
my_array.each_with_index do |item, i|
item.do_something if i==0
#common stuff
end

Answer 4

What fits best is depending on the situation.
Another option (if you know your array is not empty):
# treat the first element (my_array.first)
my_array.each do | item |
# do the common_stuff
end

Answer 5

each_with_index from Enumerable (Enumerable is already mixed in with Array, so you can call it on an array without any trouble):
irb(main):001:0> nums = (1..10).to_a
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
irb(main):003:0> nums.each_with_index do |num, idx|
irb(main):004:1* if idx == 0
irb(main):005:2> puts "At index #{idx}, the number is #{num}."
irb(main):006:2> end
irb(main):007:1> end
At index 0, the number is 1.
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Answer 6

If you don't need the array afterwards:
ar = %w(reversed hello world)
puts ar.shift.upcase
ar.each{|item| puts item.reverse}
#=>REVERSED
#=>olleh
#=>dlrow

Answer 7

Ruby's Enumerable#inject provides an argument that can be used for doing something differently on the first iteration of a loop:
> l=[1,2,3,4]
=> [1, 2, 3, 4]
> l.inject(0) {|sum, elem| sum+elem}
=> 10
The argument is not strictly necessary for common things like sums and products:
> l.inject {|sum, elem| sum+elem}
=> 10
But when you want to do something different on the first iteration, that argument might be useful to you:
> puts fruits.inject("I like to eat: ") {|acc, elem| acc << elem << " "}
I like to eat: apples pears peaches plums oranges
=> nil

Answer 8

Here's a solution that doesn't need to be in an immediately enclosing loop and avoids the redundancy of specifying a status placeholder more than once unless you really need to.
do_this if ($first_time_only ||= [true]).shift
Its scope matches the holder: $first_time_only will be globally once; #first_time_only will be once for the instance, and first_time_only will be once for the current scope.
If you want the first several times, etc, you can easily put [1,2,3] if you need to distinguish which of the first iterations you're in, or even something fancy [1, false, 3, 4] if you need something weird.