Oracle to_char function with a number format that has an arbitrary precision and certain scale - oracle

This one is pretty simple actually yet I wasn't able to find anything useful.
In my SQL query I have some rounded numbers with a single scale value - round(number,1). If the numbers are rounded to some decimal digit it prints in the format '9,9'.
On the other hand if the numbers are rounded to an integer, only the integer value without the zero after comma is printed although I want my query to select the numbers in '9,9' format even the decimal digit is zero.
In short, I think I need something like for example
to_char((select round(121.01,1), from dual), '*,1') ; to output 121,0.
What is the best way to do this? Thanks in advance
Korhan

All you have to do is specify the number of decimal points you want in your to_char. The problem with using format masks is that you need to specify the number of numbers you want in front of your decimal point.
SQL> select to_char(round(121.01,1),'999.9') from dual;
TO_CHA
------
121.0
SQL> select to_char(round(121.4,1),'999.9') from dual;
TO_CHA
------
121.4
SQL> select to_char(round(121,1),'999.9') from dual;
TO_CHA
------
121.0
SQL> select to_char(round(5121,1),'999.9') from dual;
TO_CHA
------
######
SQL>
There are a number of other formatting options.

Use 0 instead 9 for decimal places:
SELECT TO_CHAR( ROUND( 121.01, 1 ), '990D0' ) num FROM DUAL;
NUM
------
121.0

This simple query may help you,
select to_char(round(121.01,1), '999.0') from dual;
In to_char function:
9 - indicate to block/hide zeros in the output.
0 - indicate to show zero in the output at anywhere in before/after decimal point.
Note:
No. of '9/0's in before/after decimal point is number of digits which you want to display beore/after decimal point.

Related

Why oracle doesn't show the integer part of a decimal

when I execute the next SQL:
select 1/3 from dual;
the result is ,333333333
but the result that I expected was 0,333333333
Why doesn't oracle show the zero ? is there any parameter that can affect it?
Thanks
Edit: I checked this behaviour from an aplication that uses the oo4o (oracle object for ole), and confirmed with the sqlDeveloper (when I execute the sql with F5, not with ctrl+intro). The real problem is with the oo4o Dynaset object: when I try to sum the value of two fields, what I get is a concatenation, not a sum: ,3 + ,2 = ,3,2.
What I want to know is if there is some parameter or configuration that makes the oracle engine return the number without the zero, so I can turn on|off in order to return de zero as integer part.
SQL*Plus will show that by default (using your territory's decimal separator):
SQL> select 1/3 from dual;
1/3
----------
.333333333
You could use set numformat to change the behaviour:
SQL> set numformat "0D9999"
SQL> select 1/3 from dual;
1/3
-------
0.3333
... where the D represents the decimal separator. Or you could use column formatting, with a column alias:
SQL> set numformat ""
SQL> column answer format 0.000
SQL> select 1/3 as answer from dual;
ANSWER
------
0.333
Other clients have different ways of controlling the default output; SQL Developer behaves much the same, but PL/SQL Developer, Toad etc. might not.
Or you can format the number as part of the query, which isn't client-dpendent:
SQL> select to_char(1/3, '9990D99999') from dual;
TO_CHAR(1/3
-----------
0.33333
You need to provide enough digits for the integer part of whatever you're calculating though. Anything less than zero is simple, but if there are too many digits before the decimal separator then it won't display at all:
SQL> select to_char(100000/3, '9990D99999') from dual;
TO_CHAR(100
-----------
###########

How to rounding up in oracle

I want to convert this value "2167.124" to "2167.13" using round function in oracle 11g. Problem is that it converts LIKE "2167.12"
But i need "2167.13".
Please help, Thanks in advance
If you want to convert given value 2167.12" to "2167.13" Please use this
select ceil(2167.124*100)/100 from dual;
Expanding on Sam's example, multiplying by 100 effectively moves the decimal point two places to the right, so your value becomes 216712.4:
select 2167.124*100 as step1 from dual;
STEP1
----------
216712.4
You then call ceil on that, to find "the smallest integer that is greater than or equal to n":
select ceil(216712.4) as step2 from dual;
STEP2
----------
216713
Then dividing by 100 effectively moves the decimal point back the same two places to the left:
select 216713/100 as step3 from dual;
STEP3
----------
2167.13
Putting the three steps together into one statement gets:
select ceil(2167.124*100)/100 as result from dual;
RESULT
----------
2167.13

Decimal place require in Oracle

case 1: SELECT TO_CHAR(12345.6789, '99999D99') FROM dual;
Output: 12345.67
case 2: SELECT TO_CHAR(12345.6789, '999D99') FROM dual;
Output: ######
case 3: SELECT TO_CHAR(12345, '99999D99') FROM dual;
Output: 12345.00
case 4: SELECT TO_CHAR(12345.1, '99999D99') FROM dual;
Output: 12345.10
Here Problem is if we don't know how many digits before decimal then how to manage for correct answer.[only case 1,3,4 can resolved using by TO_CHAR but how to solve for case 2.]
In this case the simplest answer might be to not supply a format model at all, but truncate or round the value to two decimal places:
SELECT TO_CHAR(ROUND(12345.6789, 2)) as rounded,
TO_CHAR(TRUNC(12345.6789, 2)) as truncated
FROM dual;
ROUNDED TRUNCATED
-------- ---------
12345.68 12345.67
From the documentation:
If you omit fmt, then n is converted to a VARCHAR2 value exactly long enough to hold its significant digits.
Otherwise you'd need to supply a format model that allowed for the maximum size of your number; if it's unrestricted you'd need 36 nines, the decimal separator, and two more nines. The result would be padded with spaces so you might also want to trim it, depending on how you'll use the string value.
SELECT TO_CHAR(12345.6789, '999999999999999999999999999999999999D99') as val
FROM dual;
VAL
----------------------------------------
12345.68
You could also do that flexibly by using the length of the truncated value (i.e. once the decimal places have been removed):
SELECT TO_CHAR(12345.6789,
lpad('9', length(trunc(12345.6789)), '9') || 'D99') as val
FROM dual;
VAL
---------
12345.68
But that seems unnecessarily complicated when you can let Oracle work it out for you.
However, if you want the decimals to show trailing zeros then you might need to use that method; but with zeros after the decimal separator:
SELECT TO_CHAR(12345.6, lpad('0', length(trunc(12345.6)), '9') || 'D00') as val
FROM dual;
VAL
---------
12345.60
... which addresses the 3rd and 4th cases you added. I've made it show a leading zero for values less than 1 as well; the generated format model in this case is '99990D00'. The number of nines will still vary depending on the size of your number.
By default Oracle still leaves a space at the start for a potential minus sign. You can avoid that with the FM format modifier:
SELECT TO_CHAR(12345.6, 'FM'
|| lpad('0', length(trunc(12345.6)), '9') || 'D00') as val
FROM dual;
VAL
--------
12345.60
You could always go with the maximum number of digits you expect to be present in the input. If there are fewer digits in the input than your format specifier, it wouldn't affect the outcome in anyway. For instance,
select to_char(12323.5553,'99999D99') from dual
would produce,
123.56
As you said, the length of the input is unknwon. So why would you use a fixed length formater for somthing that is unknown? Does not work. Read your input as String from the beginning and manipulate it as String or even better - BLOB.
Well, to do the rounding correct might be tricky.
So, best check your data if the numbers will realy get so big, because that would mean a lot of work and trouble.
If not more than 38 Digits are needed, you can go with decimal or numeric datatype and (if you insist on a formatter) use the TM formatter for example.
SELECT to_char(cast(1234.456 as decimal( *,2)), 'TM') as a FROM dual
or take the advice that was given above by the other posters.

Oracle cursor removes leading zero

I have a cursor which selects date from column with NUMBER type containg floating point numbers. Numbers like 4,3433 are returned properly while numbers smaller then 1 have removed leading zero.
For example number 0,4513 is returned as ,4513.
When I execute select used in the cursor on the database, numbers are formatted properly, with leading zeros.
This is how I loop over the recors returned by the cursor:
FOR c_data IN cursor_name(p_date) LOOP
...
END LOOP;
Any ideas why it works that way?
Thank you in advance.
You're confusing number format and number value.
The two strings 0.123 and .123, when read as a number, are mathematically equals. They represent the same number. In Oracle the true number representation is never displayed directly, we always convert a number to a character to display it, either implicitly or explicitly with a function.
You assume that a number between 0 and 1 should be represented with a leading 0, but this is not true by default, it depends on how you ask this number to be displayed. If you don't want unexpected outcome, you have to be explicit when displaying numbers/dates, for example:
to_char(your_number, '9990.99');
It's the default number formatting that Oracle provides.
If you want to specify something custom, you shall use TO_CHAR function (either in SQL query or PL/SQL code inside the loop).
Here is how it works:
SQL>
SQL> WITH aa AS (
2 select 1.3232 NUM from dual UNION ALL
3 select 1.3232 NUM from dual UNION ALL
4 select 332.323 NUM from dual UNION ALL
5 select 0.3232 NUM from dual
6 )
7 select NUM, to_char(NUM, 'FM999990D9999999') FORMATTED from aa
8 /
NUM FORMATTED
---------- ---------------
1.3232 1.3232
1.3232 1.3232
332.323 332.323
.3232 0.3232
SQL>
In this example, 'FM' - suppresses extra blanks, '0' indicates number digit including leading/trailing zeros, and '9' indicates digit suppressing leading/trailing zeros.
You can find many examples here:
http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements004.htm#i34570

Number format converting

I have a currency amount value like this;
22200000
I want to convert this number to;
22,2 (Number format)
How can I do this?
use to_char() function. Example
to_char(3510.78, '$9,999.00')
would return
$3,510.78
I found the answer: SELECT TO_CHAR (22200000 / 1000000, '999,999,999,999.99') FROM dual
You can use Oracle Built-in function round().
The ROUND function accepts a number and returns another number rounded
to the specified number of places to the right of the decimal point.
If you do not specify that number, ROUND will return a number rounded
to the nearest integer
For instance:
select 1/3, round(1/3, 2) from dual;
1/3 ROUND(1/3,2)
---------- ------------
.333333333 .33
More info: Working with Numbers in PL/SQL

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