I want to convert this value "2167.124" to "2167.13" using round function in oracle 11g. Problem is that it converts LIKE "2167.12"
But i need "2167.13".
Please help, Thanks in advance
If you want to convert given value 2167.12" to "2167.13" Please use this
select ceil(2167.124*100)/100 from dual;
Expanding on Sam's example, multiplying by 100 effectively moves the decimal point two places to the right, so your value becomes 216712.4:
select 2167.124*100 as step1 from dual;
STEP1
----------
216712.4
You then call ceil on that, to find "the smallest integer that is greater than or equal to n":
select ceil(216712.4) as step2 from dual;
STEP2
----------
216713
Then dividing by 100 effectively moves the decimal point back the same two places to the left:
select 216713/100 as step3 from dual;
STEP3
----------
2167.13
Putting the three steps together into one statement gets:
select ceil(2167.124*100)/100 as result from dual;
RESULT
----------
2167.13
Related
In the below code, I am trying to get the amount in words for the value in the AMOUNT column but can't seem to get it right. Anyone with an idea? Below the CREATE VIEW statement:
SELECT GLR3 AS RECEIPT_DOC_NO,
GLANI AS ACCOUNT_NUMBER,
GLSBL AS JDE_NO,
(SELECT YAALPH FROM PRODDTA.F060116 WHERE YAAN8 = T1.GLSBL) AS STAFF_NAME,
CASE GLDGJ WHEN 0 THEN TO_DATE (TO_CHAR (1 + 1900000), 'YYYYDDD')
ELSE TO_DATE (TO_CHAR (GLDGJ + 1900000), 'YYYYDDD') END AS GL_DATE,
GLEXA AS NARRATIVE,
GLLT AS LEDGER_TYPE,
GLSBLT AS SUBLEDGER_TYPE,
GLCRCD AS CURRENCY_CODE,
CASE GLAA WHEN 100 THEN ROUND (GLAA / 100, 2) ELSE ROUND (GLAA / 100, 2)
END AS AMOUNT,
(SELECT TO_CHAR(TO_DATE(T1.GLAA,'J'),'JSP')) FROM DUAL) AS AMOUNT_INWORDS
FROM PRODDTA.F0911 T1;
My code is failing with
ORA-00923: FROM keyword not found where expected.
ORA-00923: FROM keyword not found where expected.
Indicates a syntax error. In this case you have three ( and four ):
(SELECT TO_CHAR(TO_DATE(T1.GLAA,'J'),'JSP')) FROM DUAL) AS AMOUNT_INWORDS
The compiler is not expecting the second ) after 'JSP'.
The scalar cursor is unnecessary, so the simplified and corrected version would be:
TO_CHAR(TO_DATE(T1.GLAA,'J'),'JSP') AS AMOUNT_INWORDS
ORA-01854: julian date must be between 1 and 5373484
5373484 is the Julian date for 31-DEC-9999 which is the maximum date allowed in Oracle. This poses an absolute limit on the number which we can spell using JSP mask ... in one go. However, we can use PL/SQL to break larger numbers into chunks and spell those instead. The inestimable Tom Kyte wrote such a function and published it on the AskTom site. Find it here.
I think the value i'm trying to write in words has decimal values (400.00) hence the ORA-01854 error.
The Tom Kyte I linked to does address that issue further down the page. It's this comment here.
Data retrieved in amount column is preceded by a negative symbol when it shouldn't be,
If you simply want to ignore negative values then apply the ABS() function to give you the absolute value.
when I execute the next SQL:
select 1/3 from dual;
the result is ,333333333
but the result that I expected was 0,333333333
Why doesn't oracle show the zero ? is there any parameter that can affect it?
Thanks
Edit: I checked this behaviour from an aplication that uses the oo4o (oracle object for ole), and confirmed with the sqlDeveloper (when I execute the sql with F5, not with ctrl+intro). The real problem is with the oo4o Dynaset object: when I try to sum the value of two fields, what I get is a concatenation, not a sum: ,3 + ,2 = ,3,2.
What I want to know is if there is some parameter or configuration that makes the oracle engine return the number without the zero, so I can turn on|off in order to return de zero as integer part.
SQL*Plus will show that by default (using your territory's decimal separator):
SQL> select 1/3 from dual;
1/3
----------
.333333333
You could use set numformat to change the behaviour:
SQL> set numformat "0D9999"
SQL> select 1/3 from dual;
1/3
-------
0.3333
... where the D represents the decimal separator. Or you could use column formatting, with a column alias:
SQL> set numformat ""
SQL> column answer format 0.000
SQL> select 1/3 as answer from dual;
ANSWER
------
0.333
Other clients have different ways of controlling the default output; SQL Developer behaves much the same, but PL/SQL Developer, Toad etc. might not.
Or you can format the number as part of the query, which isn't client-dpendent:
SQL> select to_char(1/3, '9990D99999') from dual;
TO_CHAR(1/3
-----------
0.33333
You need to provide enough digits for the integer part of whatever you're calculating though. Anything less than zero is simple, but if there are too many digits before the decimal separator then it won't display at all:
SQL> select to_char(100000/3, '9990D99999') from dual;
TO_CHAR(100
-----------
###########
I have a cursor which selects date from column with NUMBER type containg floating point numbers. Numbers like 4,3433 are returned properly while numbers smaller then 1 have removed leading zero.
For example number 0,4513 is returned as ,4513.
When I execute select used in the cursor on the database, numbers are formatted properly, with leading zeros.
This is how I loop over the recors returned by the cursor:
FOR c_data IN cursor_name(p_date) LOOP
...
END LOOP;
Any ideas why it works that way?
Thank you in advance.
You're confusing number format and number value.
The two strings 0.123 and .123, when read as a number, are mathematically equals. They represent the same number. In Oracle the true number representation is never displayed directly, we always convert a number to a character to display it, either implicitly or explicitly with a function.
You assume that a number between 0 and 1 should be represented with a leading 0, but this is not true by default, it depends on how you ask this number to be displayed. If you don't want unexpected outcome, you have to be explicit when displaying numbers/dates, for example:
to_char(your_number, '9990.99');
It's the default number formatting that Oracle provides.
If you want to specify something custom, you shall use TO_CHAR function (either in SQL query or PL/SQL code inside the loop).
Here is how it works:
SQL>
SQL> WITH aa AS (
2 select 1.3232 NUM from dual UNION ALL
3 select 1.3232 NUM from dual UNION ALL
4 select 332.323 NUM from dual UNION ALL
5 select 0.3232 NUM from dual
6 )
7 select NUM, to_char(NUM, 'FM999990D9999999') FORMATTED from aa
8 /
NUM FORMATTED
---------- ---------------
1.3232 1.3232
1.3232 1.3232
332.323 332.323
.3232 0.3232
SQL>
In this example, 'FM' - suppresses extra blanks, '0' indicates number digit including leading/trailing zeros, and '9' indicates digit suppressing leading/trailing zeros.
You can find many examples here:
http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements004.htm#i34570
I have a currency amount value like this;
22200000
I want to convert this number to;
22,2 (Number format)
How can I do this?
use to_char() function. Example
to_char(3510.78, '$9,999.00')
would return
$3,510.78
I found the answer: SELECT TO_CHAR (22200000 / 1000000, '999,999,999,999.99') FROM dual
You can use Oracle Built-in function round().
The ROUND function accepts a number and returns another number rounded
to the specified number of places to the right of the decimal point.
If you do not specify that number, ROUND will return a number rounded
to the nearest integer
For instance:
select 1/3, round(1/3, 2) from dual;
1/3 ROUND(1/3,2)
---------- ------------
.333333333 .33
More info: Working with Numbers in PL/SQL
This one is pretty simple actually yet I wasn't able to find anything useful.
In my SQL query I have some rounded numbers with a single scale value - round(number,1). If the numbers are rounded to some decimal digit it prints in the format '9,9'.
On the other hand if the numbers are rounded to an integer, only the integer value without the zero after comma is printed although I want my query to select the numbers in '9,9' format even the decimal digit is zero.
In short, I think I need something like for example
to_char((select round(121.01,1), from dual), '*,1') ; to output 121,0.
What is the best way to do this? Thanks in advance
Korhan
All you have to do is specify the number of decimal points you want in your to_char. The problem with using format masks is that you need to specify the number of numbers you want in front of your decimal point.
SQL> select to_char(round(121.01,1),'999.9') from dual;
TO_CHA
------
121.0
SQL> select to_char(round(121.4,1),'999.9') from dual;
TO_CHA
------
121.4
SQL> select to_char(round(121,1),'999.9') from dual;
TO_CHA
------
121.0
SQL> select to_char(round(5121,1),'999.9') from dual;
TO_CHA
------
######
SQL>
There are a number of other formatting options.
Use 0 instead 9 for decimal places:
SELECT TO_CHAR( ROUND( 121.01, 1 ), '990D0' ) num FROM DUAL;
NUM
------
121.0
This simple query may help you,
select to_char(round(121.01,1), '999.0') from dual;
In to_char function:
9 - indicate to block/hide zeros in the output.
0 - indicate to show zero in the output at anywhere in before/after decimal point.
Note:
No. of '9/0's in before/after decimal point is number of digits which you want to display beore/after decimal point.