method for merging two files, opinion needed - bash

Question

Problem: I have two folders (one is Delta Folder-where the files get updated, and other is Original Folder-where the original files exist). Every time the file updates in Delta Folder I need merge the file from Original folder with updated file from Delta folder.
Note: Though the file names in Delta folder and Original folder are unique, but the content in the files may be different. For example:
$ cat Delta_Folder/1.properties
account.org.com.email=New-Email
account.value.range=True
$ cat Original_Folder/1.properties
account.org.com.email=Old-Email
account.value.range=False
range.list.type=String
currency.country=Sweden
Now, I need to merge Delta_Folder/1.properties with Original_Folder/1.properties so, my updated Original_Folder/1.properties will be:
account.org.com.email=New-Email
account.value.range=True
range.list.type=String
currency.country=Sweden
Solution i opted is:
find all *.properties files in Delta-Folder and save the list to a temp file(delta-files.txt).
find all *.properties files in Original-Folder and save the list to a temp file(original-files.txt)
then i need to get the list of files that are unique in both folders and put those in a loop.
then i need to loop each file to read each line from a property file(1.properties).
then i need to read each line(delta-line="account.org.com.email=New-Email") from a property file of delta-folder and split the line with a delimiter "=" into two string variables.
(delta-line-string1=account.org.com.email; delta-line-string2=New-Email;)
then i need to read each line(orig-line=account.org.com.email=Old-Email from a property file of orginal-folder and split the line with a delimiter "=" into two string variables.
(orig-line-string1=account.org.com.email; orig-line-string2=Old-Email;)
if delta-line-string1 == orig-line-string1 then update $orig-line with $delta-line
i.e:
if account.org.com.email == account.org.com.email then replace
account.org.com.email=Old-Email in original folder/1.properties with
account.org.com.email=New-Email
Once the loop finishes finding all lines in a file, then it goes to next file. The loop continues until it finishes all unique files in a folder.
For looping i used for loops, for splitting line i used awk and for replacing content i used sed.
Over all its working fine, its taking more time(4 mins) to finish each file, because its going into three loops for every line and splitting the line and finding the variable in other file and replace the line.
Wondering if there is any way where i can reduce the loops so that the script executes faster.

Answer 1

With paste and awk :
File 2:
$ cat /tmp/l2
account.org.com.email=Old-Email
account.value.range=False
currency.country=Sweden
range.list.type=String
File 1 :
$ cat /tmp/l1
account.org.com.email=New-Email
account.value.range=True
The command + output :
paste /tmp/l2 /tmp/l1 | awk '{print $NF}'
account.org.com.email=New-Email
account.value.range=True
currency.country=Sweden
range.list.type=String
Or with a single awk command if sorting is not important :
awk -F'=' '{arr[$1]=$2}END{for (x in arr) {print x"="arr[x]}}' /tmp/l2 /tmp/l1

Answer 2

I think your two main options are:
Completely reimplement this in a more featureful language, like perl.
While reading the delta file, build up a sed script. For each line of the delta file, you want a sed instruction similar to:
s/account.org.com.email=.*$/account.org.email=value_from_delta_file/g
That way you don't loop through the original files a bunch of extra times. Don't forget to escape & / and \ as mentioned in this answer.

Answer 3

Is using a database at all an option here?
Then you would only have to write code for extracting data from the Delta files (assuming that can't be replaced by a database connection).
It just seems like this is going to keep getting more complicated and slower as time goes on.