I have below query but instead of to be putting range of week like '22-OCT-2012 AND 28-OCT-2012' I woulk to put a code like CurrentWeek -2 or CurrentWeek-1, that will avoid to edit the query every week that I need to run it.
Do you know how make this?
tHANKS
LD
SELECT WO.USER_6 AS STYLE
,SUM (CASE WHEN (OPERATION.STATUS ='C' AND OPERATION.CLOSE_DATE BETWEEN '22-OCT-2012' AND '28-OCT-2012') THEN OPERATION.RUN_HRS ELSE 0 END) WEEK43
,SUM (CASE WHEN (OPERATION.STATUS ='C' AND OPERATION.CLOSE_DATE BETWEEN '29-OCT-2012' AND '04-NOV-2012') THEN OPERATION.RUN_HRS ELSE 0 END) WEEK44
FROM WORK_ORDER WO, OPERATION
WHERE WO.BASE_ID = OPERATION.WORKORDER_BASE_ID
AND WO.Lot_ID = Operation.Workorder_Lot_ID
AND WO.Sub_ID = Operation.Workorder_Sub_ID
AND WO.Split_ID = Operation.Workorder_Split_ID
AND WO.TYPE ='W'
AND WO.WAREHOUSE_ID ='MEX-04'
AND OPERATION.CLOSE_DATE BETWEEN '22-OCT-2012' AND '04-NOV-2012'
AND OPERATION.RESOURCE_ID IN ('171-4','171-ADD','171-3' ,'BAMEX-SEWCONC','BAMEX-SEWPATC')
AND OPERATION.RUN > 0
GROUP BY
WO.USER_6
If I understood your question then u can use this to pass the current week days like this
SUM (CASE WHEN (OPERATION.STATUS ='C' AND OPERATION.CLOSE_DATE BETWEEN to_char(trunc(sysdate),'DD-MON-YYYY') and to_char(trunc(sysdate)-6,'DD-MON-YYYY')) THEN OPERATION.RUN_HRS ELSE 0 END) WEEK43
Hope this help u
In this case I will use trunc function:
currentweek will be trunc(sysdate,'D')
current_week - 1 will be trunc(sysdate,'D') - 7
current week - 2 will be trunc(sysdate,'D') - 2 * 7
Attention this will give first day of week sunday. If you want monday you should and one day:
current week - 2 will be trunc(sysdate,'D') - 2 * 7 + 1
UPDATE:
Frank is right, the behavior on first day of week depends on NLS_TERITORY
alter session set NLS_TERRITORY ='UNITED KINGDOM';
select trunc(sysdate,'D') from dual;
05-11-2012
alter session set NLS_TERRITORY ='AMERICA';
select trunc(sysdate,'D') from dual;
04-11-2012
Related
My tables are as below
MS_ISM_ISSUE
ISSUE_ID ISSUE_DUE_DATE ISSUE_SOURCE_TYPE
I1 25-11-2018 1
I2 25-12-2018 1
I3 27-03-2019 2
MS_ISM_SOURCE_SETUP
SOURCE_ID MODULE_NAME
1 IT-Compliance
2 Risk Assessment
I have written following query.
with rs as
(select
count(ISSUE_ID) as ISSUE_COUNT, src.MODULE_NAME,
case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end as date_range
from MS_ISM_ISSUE issue, MS_ISM_SOURCE_SETUP src
where issue.Issue_source_type = src.source_id
group by src.MODULE_NAME, case
when ISSUE_DUE_DATE<sysdate then 'Overdue'
when ISSUE_DUE_DATE between sysdate and sysdate + 90 then 'Within 3 months'
when ISSUE_DUE_DATE>sysdate+90 then 'Beyond 90 days'
end)
select ISSUE_COUNT,MODULE_NAME, DATE_RANGE,
(select count(ISSUE_COUNT) from rs where rs.MODULE_NAME=MODULE_NAME) as total from rs;
The output of the code is as below.
ISSUE_COUNT MODULE_NAME DATE_RANGE Total
1 IT-Compliance Overdue 3
1 IT-Compliance Within 3 months 3
1 Risk Assessment Beyond 90 days 3
The result is correct till 3rd column. In 4th column what I want is, total of Issue count for given module name. Hence in above case Total column will have value as 2 for first and second row (since there are 2 Issues for IT-Compliance) and value 1 for the third row (since one issue is present for Risk Assessment).
Essentially, I want to achieve is to replace current row's MODULE_NAME in last where clause. How do I achieve this using query?
OK, this condition
where rs.MODULE_NAME=MODULE_NAME
is essentially the same as if you wrote
where MODULE_NAME = MODULE_NAME
which is simply always true (if there are no nulls in module_name).
Try using different table alias for inner query and outer query, e.g.
select count(ISSUE_COUNT) from rs rs2 where rs2.MODULE_NAME=rs.MODULE_NAME
You can also try to use analytic function here, something like
select ISSUE_COUNT,
MODULE_NAME,
DATE_RANGE,
COUNT(ISSUE_COUNT) OVER (PARTITION BY RS.MODULE_NAME) AS TOTAL
from rs
instead of your subquery
I have the following query that gets the week of a date:
SELECT pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww') semana,
SUM (rta.kms_acumulados) kms,
COUNT
(DISTINCT (CASE
WHEN v.secuencia BETWEEN rta.sec_origen AND rta.sec_destino
THEN v.cod_inc
ELSE '0'
END
)
)
- 1 numincidencias
FROM (SELECT ms.tren, ms.fecha_origen_tren, ms.secuencia, ri.cod_inc
FROM r_incidencias ri, mer_sitra ms
WHERE ri.cod_serv = ms.tren
AND ri.fecha_origen_tren = ms.fecha_origen_tren
AND ri.cod_tipoin IN (SELECT cod_tipo_iincidencia
FROM v_tipos_incidencias
WHERE grupo = '45')
AND ri.punto_desde = ms.cod_estacion) v,
r_trenes_asignar rta,
r_maquinas rm,
planificador.pl_dh_material pdm
WHERE rta.fecha BETWEEN TO_DATE ('21/09/2018', 'dd/mm/yyyy') AND TO_DATE ('21/09/2018',
'dd/mm/yyyy'
)
AND rta.serie >= 4000
AND rta.matricula_ant IS NOT NULL
AND rm.matricula_maq = rta.matricula_ant
AND rm.cod_serie = pdm.id_material
AND rta.grafico BETWEEN pdm.desde AND pdm.hasta
AND v.tren(+) = rta.tren
AND v.fecha_origen_tren(+) = rta.fecha
GROUP BY pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww')
ORDER BY pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww')
For example week 1
I want to display
week 1 : 1 january - 7 january
How can I get this?
Oracle offers the TRUNC(datestamp, format) function to manipulate dates this way. You may use a variety of format strings to get the first day of a quarter, year, or even the top of the hour.
Given a particular datestamp value, Oracle returns midnight on the first day of the present week with this expression:
TRUNC(datestamp,'DY')
You can add days to a datestamp. Therefore this expression gives you midnight on the last day of the week
TRUNC(datestamp,'DY') + 6
A WHERE-clause selector for all rows in the present week might be this.
WHERE datestamp >= TRUNC(SYSDATE,'DY')
AND datestamp < TRUNC(SYSDATE,'DY') + 7
Notice that the end of the range is just before (<) midnight on the first day of the next week. You need that because you may have datestamps after midnight on the last day of the week. (Beware using BETWEEN for datestamp ranges.)
And,
SELECT TO_CHAR(TRUNC(SYSDATE,'DY'),'YYYY-MM-DD'),
TO_CHAR(TRUNC(SYSDATE,'DY')+6,'YYYY-MM-DD')
FROM DUAL;
displays the first and last dates of the present week in ISO-like format.
Date arithmetic is cool. It's worth your trouble to study the date-arithmetic functions in your DBMS at least once a year.
Hi I need a formula that will give me the difference in working days (M,T,W,Th) between two dates. So in other words just excluding weekends.
My current formula is: ROUND({systemnotes.date}-{trandate})
This works great except for that it counts Saturday and Sunday.
Thanks for the help!
Here is a formula that will get you the difference between two dates excluding Saturday and Sunday as a number of days. Put this into a formula(numeric) field in your search.
ROUND(((TO_CHAR({systemnotes.date}, 'J') - TO_CHAR({trandate}, 'J'))) + MOD(({systemnotes.date} - {trandate}), 1) - ((((TRUNC({systemnotes.date}, 'D')) - (TRUNC({trandate}, 'D')))/7)*2) - (CASE WHEN TO_CHAR({trandate}, 'DY') = 'SUN' THEN 1 ELSE 0 END) - (CASE WHEN TO_CHAR({systemnotes.date}, 'DY') = 'SAT' THEN 1 ELSE 0 END), 2)
Sorry, it's a bit of a long one, but in the formula {systemnotes.date} is your start date and {trandate} is your end date.
I am trying to set between a date range for 6 months in the past for two different fields that will group the data by month. How do I set such a between clause to achieve this?
SELECT TO_CHAR(mopend, 'MM-yyyy') AS month, MOPSTATUS, COUNT(*) MTS_COMPLETE_CNT
FROM MOPUSER.MOPACTIVITY
WHERE UPPER(MOPSTATUS) = 'COMPLETE'
AND TO_CHAR(MOPACTIVITY.MOPSTART, 'yyyy-mm-dd hh24:mi') BETWEEN TO_CHAR(sysdate,'YYYY-MM-DD')||' 06:02:00' AND TO_CHAR(sysdate,'YYYY-MM-DD')||' 22:59:59'
OR TO_CHAR(MOPACTIVITY.MOPEND, 'yyyy-mm-dd hh24:mi') BETWEEN TO_CHAR(SYSDATE,'YYYY-MM-DD')||' 06:02:00' AND TO_CHAR(SYSDATE,'YYYY-MM-DD')||' 22:59:59'
GROUP BY TO_CHAR(mopend, 'MM-yyyy'), MOPSTATUS
ORDER BY TO_CHAR(mopend, 'MM-yyyy'), MOPSTATUS
I will answer one part of your question first, and then based on your comments, I can give you the full query.
The following query returns the end points between which you want to search. T1 is 06:02 in the morning on the date that is six months back in time. T2 is the last second of today.
select sysdate
,add_months( trunc(sysdate) + interval '06:02' hour to minute, -6) as t1
, trunc(sysdate) + interval '23:59:59' hour to second as t2
from dual;
The above query returns the following (using yyyy-mm-dd hh24:mi:ss):
sydate: 2014-04-11 13:54:28
t1: 2013-10-11 06:02:00
t2: 2014-04-11 23:59:59
If I interpret you correctly, this is the time period you want to search?
For the second part of the answer, I'd need to know the following:
Can any of MOPSTART or MOPEND be null? If so, how do you want to treat those rows?
Do you want to include the end points, i.e. rows where MOPSTART >= t1? Or only where MOTSTART > t1?
Same as (2) but for MOPEND
What month do you want to group by (see below)?
For example, row (a), do you want count it once for each month, or only in JAN (started) or only in JUN(ended)?
JAN FEB MAR APR MAY JUN
a: |-------------------|
b: |---|---|
c: |---|
d: |-----------|
e: |--------|
I am running this query currently for one scenario but I have two scenarios: If SYSDATE = Monday, then run "SYSDATE - 2", otherwise run "SYSDATE - 1". I'm connecting to the database via an OLE connection from Excel so I'm not sure I can use a stored procedure. Is there a way to write the query to accomplish both scenarios? Thanks for all help.
SELECT
DISTINCT VERSION_NAME VERSION, MIN(RECONCILE_START_DT) DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -1
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
You may use a CASE statement in your WHERE condition to subtract either 2 for Mondays or 1 for the rest of the week. TO_CHAR(DATE, 'D') delivers the day of week beginning with Sundays = 1. Therefore Mondays are 2.
Try this:
SELECT
VERSION_NAME AS VERSION,
MIN(RECONCILE_START_DT) AS DATES
FROM
SDE.GDBM_RECONCILE_HISTORY
WHERE
RECONCILE_RESULT = 'Conflicts'
AND
RECONCILE_START_DT > SYSDATE -
CASE TO_CHAR(SYSDATE, 'D')
WHEN '2' THEN 2
ELSE 1 END
GROUP BY VERSION_NAME
ORDER BY 2 ASC NULLS LAST
Also you don't need the DISTINCT keyword as you're already use GROUP BY.