I am trying to set between a date range for 6 months in the past for two different fields that will group the data by month. How do I set such a between clause to achieve this?
SELECT TO_CHAR(mopend, 'MM-yyyy') AS month, MOPSTATUS, COUNT(*) MTS_COMPLETE_CNT
FROM MOPUSER.MOPACTIVITY
WHERE UPPER(MOPSTATUS) = 'COMPLETE'
AND TO_CHAR(MOPACTIVITY.MOPSTART, 'yyyy-mm-dd hh24:mi') BETWEEN TO_CHAR(sysdate,'YYYY-MM-DD')||' 06:02:00' AND TO_CHAR(sysdate,'YYYY-MM-DD')||' 22:59:59'
OR TO_CHAR(MOPACTIVITY.MOPEND, 'yyyy-mm-dd hh24:mi') BETWEEN TO_CHAR(SYSDATE,'YYYY-MM-DD')||' 06:02:00' AND TO_CHAR(SYSDATE,'YYYY-MM-DD')||' 22:59:59'
GROUP BY TO_CHAR(mopend, 'MM-yyyy'), MOPSTATUS
ORDER BY TO_CHAR(mopend, 'MM-yyyy'), MOPSTATUS
I will answer one part of your question first, and then based on your comments, I can give you the full query.
The following query returns the end points between which you want to search. T1 is 06:02 in the morning on the date that is six months back in time. T2 is the last second of today.
select sysdate
,add_months( trunc(sysdate) + interval '06:02' hour to minute, -6) as t1
, trunc(sysdate) + interval '23:59:59' hour to second as t2
from dual;
The above query returns the following (using yyyy-mm-dd hh24:mi:ss):
sydate: 2014-04-11 13:54:28
t1: 2013-10-11 06:02:00
t2: 2014-04-11 23:59:59
If I interpret you correctly, this is the time period you want to search?
For the second part of the answer, I'd need to know the following:
Can any of MOPSTART or MOPEND be null? If so, how do you want to treat those rows?
Do you want to include the end points, i.e. rows where MOPSTART >= t1? Or only where MOTSTART > t1?
Same as (2) but for MOPEND
What month do you want to group by (see below)?
For example, row (a), do you want count it once for each month, or only in JAN (started) or only in JUN(ended)?
JAN FEB MAR APR MAY JUN
a: |-------------------|
b: |---|---|
c: |---|
d: |-----------|
e: |--------|
Related
I have the following query that gets the week of a date:
SELECT pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww') semana,
SUM (rta.kms_acumulados) kms,
COUNT
(DISTINCT (CASE
WHEN v.secuencia BETWEEN rta.sec_origen AND rta.sec_destino
THEN v.cod_inc
ELSE '0'
END
)
)
- 1 numincidencias
FROM (SELECT ms.tren, ms.fecha_origen_tren, ms.secuencia, ri.cod_inc
FROM r_incidencias ri, mer_sitra ms
WHERE ri.cod_serv = ms.tren
AND ri.fecha_origen_tren = ms.fecha_origen_tren
AND ri.cod_tipoin IN (SELECT cod_tipo_iincidencia
FROM v_tipos_incidencias
WHERE grupo = '45')
AND ri.punto_desde = ms.cod_estacion) v,
r_trenes_asignar rta,
r_maquinas rm,
planificador.pl_dh_material pdm
WHERE rta.fecha BETWEEN TO_DATE ('21/09/2018', 'dd/mm/yyyy') AND TO_DATE ('21/09/2018',
'dd/mm/yyyy'
)
AND rta.serie >= 4000
AND rta.matricula_ant IS NOT NULL
AND rm.matricula_maq = rta.matricula_ant
AND rm.cod_serie = pdm.id_material
AND rta.grafico BETWEEN pdm.desde AND pdm.hasta
AND v.tren(+) = rta.tren
AND v.fecha_origen_tren(+) = rta.fecha
GROUP BY pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww')
ORDER BY pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww')
For example week 1
I want to display
week 1 : 1 january - 7 january
How can I get this?
Oracle offers the TRUNC(datestamp, format) function to manipulate dates this way. You may use a variety of format strings to get the first day of a quarter, year, or even the top of the hour.
Given a particular datestamp value, Oracle returns midnight on the first day of the present week with this expression:
TRUNC(datestamp,'DY')
You can add days to a datestamp. Therefore this expression gives you midnight on the last day of the week
TRUNC(datestamp,'DY') + 6
A WHERE-clause selector for all rows in the present week might be this.
WHERE datestamp >= TRUNC(SYSDATE,'DY')
AND datestamp < TRUNC(SYSDATE,'DY') + 7
Notice that the end of the range is just before (<) midnight on the first day of the next week. You need that because you may have datestamps after midnight on the last day of the week. (Beware using BETWEEN for datestamp ranges.)
And,
SELECT TO_CHAR(TRUNC(SYSDATE,'DY'),'YYYY-MM-DD'),
TO_CHAR(TRUNC(SYSDATE,'DY')+6,'YYYY-MM-DD')
FROM DUAL;
displays the first and last dates of the present week in ISO-like format.
Date arithmetic is cool. It's worth your trouble to study the date-arithmetic functions in your DBMS at least once a year.
Can someone explain me what does the below oracle query do and what is it's output?
select unique trunc(sysdate-370 + level, 'IW') AS datetime from dual
connect by level <= 360 order by datetime;
select sysdate-370 + level AS datetime
from dual
connect by level <= 360;
Will generate 360 rows starting with the current date/time minus 370 days plus one day per row. So rows between 369 and 10 days before the current date/time.
TRUNC( datetime, 'IW' ) will truncate the date to the start of the ISO week (midnight on Monday of that week - irrespective of the NLS settings for date language and/or territory that affect some other options for truncating dates). So you will end up with duplicate rows for each generated row that is in the same week.
The UNIQUE keyword will get rid of those duplicate rows.
The order by datetime will order the results in ascending date order - however, the rows are generated in ascending order so this clause is unnecessary.
So the output will be 52 or 53 rows (depending on what the current day of the week is) starting with Monday midnight of each week containing the date 369 days before the current day up until the week containing 10 days before the current date.
The output (when run on 13th September 2017) is 52 rows (I skipped a few):
05-SEP-2016
12-SEP-2016
19-SEP-2016
26-SEP-2016
03-OCT-2016
...
31-JUL-2017
07-AUG-2017
14-AUG-2017
21-AUG-2017
28-AUG-2017
According to documentation trunc(dateval, 'IW') truncates to:
Same day of the week as the first day of the calendar week as defined by the ISO 8601 standard, which is Monday
connect by level <= N is a trick for producing a set of N rows with level values from 1 to N.
I need to query 2 tables, one contains a TIMESTAMP(6) column, other contains a DATE column. I want to write a select statement that prints both values and diff between these two in third column.
SB_BATCH.B_CREATE_DT - timestamp
SB_MESSAGE.M_START_TIME - date
SELECT SB_BATCH.B_UID, SB_BATCH.B_CREATE_DT, SB_MESSAGE.M_START_TIME,
to_date(to_char(SB_BATCH.B_CREATE_DT), 'DD-MON-RR HH24:MI:SS') as time_in_minutes
FROM SB_BATCH, SB_MESSAGE
WHERE
SB_BATCH.B_UID = SB_MESSAGE.M_B_UID;
Result:
Error report -
SQL Error: ORA-01830: date format picture ends before converting entire input string
01830. 00000 - "date format picture ends before converting entire input string"
You can subtract two timestamps to get an INTERVAL DAY TO SECOND, from which you calculate how many minutes elapsed between the two timestamps. In order to convert SB_MESSAGE.M_START_TIME to a timestamp you can use CAST.
Note that I have also removed your implicit table join with an explicit INNER JOIN, moving the join condition to the ON clause.
SELECT t.B_UID,
t.B_CREATE_DT,
t.M_START_TIME,
EXTRACT(DAY FROM t.diff)*24*60 +
EXTRACT(HOUR FROM t.diff)*60 +
EXTRACT(MINUTE FROM t.diff) +
ROUND(EXTRACT(SECOND FROM t.diff) / 60.0) AS diff_in_minutes
FROM
(
SELECT SB_BATCH.B_UID,
SB_BATCH.B_CREATE_DT,
SB_MESSAGE.M_START_TIME,
SB_BATCH.B_CREATE_DT - CAST(SB_MESSAGE.M_START_TIME AS TIMESTAMP) AS diff
FROM SB_BATCH
INNER JOIN SB_MESSAGE
ON SB_BATCH.B_UID = SB_MESSAGE.M_B_UID
) t
Convert the timestamp to a date using cast(... as date). Then take the difference between the dates, which is a number - expressed in days, so if you want it in minutes, multiply by 24*60. Then round the result as needed. I made up a small example below to isolate just the steps needed to answer your question. (Note that your query has many other problems, for example you didn't actually take a difference of anything anywhere. If you need help with your query in general, please post it as a separate question.)
select ts, dt, round( (sysdate - cast(ts as date))*24*60, 2) as time_diff_in_minutes
from (select to_timestamp('2016-08-23 03:22:44.734000', 'yyyy-mm-dd hh24:mi:ss.ff') as ts,
sysdate as dt from dual )
;
TS DT TIME_DIFF_IN_MINUTES
-------------------------------- ------------------- --------------------
2016-08-23 03:22:44.734000000 2016-08-23 08:09:15 286.52
I'm currently trying to do a comparison in my select. If the current date is before August 1st of the current year then display august 1st of the last year, otherwise display august 1st of this year. Essentially I'm trying to do:
CASE
WHEN (SYSDATE < 08/01/2015) THEN
08/01/2014
ELSE
08/01/2015
But I am at a loss as to how to get august for the month. So far I have:
TRUNC(SYSDATE, 'MON')
To get /01/ but how would I get it to constantly return august as the month? Would it be better to hardcode in the date and month and dynamically get the year instead? like 01/08/
Try something like this:
1 select sysdate,
2 trunc(sysdate,'YEAR'),
3 add_months(trunc(sysdate,'YEAR'),7),
4 add_months(trunc(sysdate,'YEAR'),7-12)
5* from dual
SQL> /
SYSDATE TRUNC(SYSDA ADD_MONTHS( ADD_MONTHS(
----------- ----------- ----------- -----------
31-jul-2015 01-jan-2015 01-aug-2015 01-aug-2014
SQL>
the columns are:
1) pulling the current sysdate.
2) converting to the first day of the year.
3) adding 7 months to get Aug 1 of current year.
4) -12 months to get Aug 1 of last year.
(that shows you the usage, you can figure out how to plug those suckers into your CASE statement ;) )
I have a table A which contains a Date type attribute. I want to write a query to select the date in another table B with value one month after the value in A.Any one know how to do it in oracle?
uhm... This was the first hit on google:
http://psoug.org/reference/date_func.html
It seems you're looking for the "add_months" function.
You need to use the ADD_MONTHS function in Oracle.
http://www.techonthenet.com/oracle/functions/add_months.php
Additional info: If you want to use this function with today's date you can use ADD_MONTHS(SYSDATE, 1) to get one month from now.
The question is to select a date_field from table b where date_field of table b is one month ahead of a date_field in table a.
An additional requirement must be taken into consideration which is currently unspecified in the question. Are we interested in whole months (days of month not taken into consideration) or do we want to include the days which might disqualify dates that are one month ahead but only by a couple of days (example: a=2011-04-30 and b=2011-05-01, b is 1 month ahead but only by 1 day).
In the first case, we must truncate both dates to their year and month values:
SELECT TRUNC( TO_DATE('2011-04-22','yyyy-mm-dd'), 'mm') as trunc_date
FROM dual;
gives:
trunc_date
----------
2011-04-01
In the second case we don't have to modify the dates.
At least two approaches can be used to solve the initial problem:
First one revolves around adding one month to the date_field in table a and finding a row in table b with a matching date.
SELECT b.date_field
FROM tab_a as a
,tab_b as b
WHERE ADD_MONTHS( TRUNC( a.date_field, 'mm' ), 1) = TRUNC( b.date_field, 'mm' )
;
Note the truncated dates. Leaving this out will require a perfect day to day match between dates.
The second approaches is based on calculating the difference in months between two dates and picking a calculation that gives a 1 month difference.
SELECT b.date_field
FROM tab_a as a
,tab_b as b
WHERE months_between( TRUNC( b.date_field, 'mm') , TRUNC(a.date_field, 'mm') ) = 1
The order of the fields in months_between is important here. In the provided example:
for b.date_field one month ahead of a.date_field the value is 1
for b.date_field one month before a.date_field the value is -1 (negative one)
Reversing the order will also reverse the results.
Hope this answers your question.