Why can't I assign a *Struct to an *Interface? - go

I'm just working through the Go tour, and I'm confused about pointers and interfaces. Why doesn't this Go code compile?
package main
type Interface interface {}
type Struct struct {}
func main() {
var ps *Struct
var pi *Interface
pi = ps
_, _ = pi, ps
}
i.e. if Struct is an Interface, why wouldn't a *Struct be a *Interface?
The error message I get is:
prog.go:10: cannot use ps (type *Struct) as type *Interface in assignment:
*Interface is pointer to interface, not interface

When you have a struct implementing an interface, a pointer to that struct implements automatically that interface too. That's why you never have *SomeInterface in the prototype of functions, as this wouldn't add anything to SomeInterface, and you don't need such a type in variable declaration (see this related question).
An interface value isn't the value of the concrete struct (as it has a variable size, this wouldn't be possible), but it's a kind of pointer (to be more precise a pointer to the struct and a pointer to the type). Russ Cox describes it exactly here :
Interface values are represented as a two-word pair giving a pointer
to information about the type stored in the interface and a pointer to
the associated data.
This is why Interface, and not *Interface is the correct type to hold a pointer to a struct implementing Interface.
So you must simply use
var pi Interface

This is perhaps what you meant:
package main
type Interface interface{}
type Struct struct{}
func main() {
var ps *Struct
var pi *Interface
pi = new(Interface)
*pi = ps
_, _ = pi, ps
}
Compiles OK. See also here.

Here's a very simple way of assigning a struct to an interface:
package main
type Interface interface{}
type Struct struct{}
func main() {
ps := new(Struct)
pi := Interface(ps)
_, _ = pi, ps
}
https://play.golang.org/p/BRTaTA5AG0S

Im using the following way of interface{} while im just consuming eventsI interface{} as arguments, im still able to send a Struct Pointers as you can see below.
func Wait(seconds float64) *WaitEvent {
return WaitEventCreate(seconds)
}
main.go
var introScene = []interface{}{
storyboard.Wait(5),
storyboard.Wait(2),
}
var storyboardI = storyboard.Create(stack, introScene)
stack.Push(&storyboardI)
Now inside storyboard.go file Create function
type Storyboard struct {
Stack *gui.StateStack
Events []interface{} //always keep as last args
}
func Create(stack *gui.StateStack, eventsI interface{}) Storyboard {
sb := Storyboard{
Stack: stack,
}
if eventsI != nil {
events := reflect.ValueOf(eventsI)
if events.Len() > 0 {
sb.Events = make([]interface{}, events.Len())
for i := 0; i < events.Len(); i++ {
sb.Events[i] = events.Index(i).Interface()
}
}
}
return sb
}
As you can see above the Storyboard.go is consuming just Events []interface{} but in-fact Im sending is a Struct pointer and it works fine.
another more example here

Related

Go Reflect field name to specific interface

I have a struct type with a number of fields that all implement a Renderer interface. The field types implement the interface with pointer receivers. I would like to have a function that takes the field name and calls the Render method on that field. I am able to locate the field and get lots of information about it, but doing the type assertion seems to be biting me because of the pointer receivers. Here's some code that shows my problem:
package main
import (
"fmt"
"reflect"
)
type Renderer interface {
Render()
}
type First struct {
ExampleField Field
}
type Field []int
func (f *Field) Render() {
fmt.Println("Hello from first")
}
func main() {
f := First{
Field{1, 2, 3},
}
f.ExampleField.Render()
renderField("ExampleField", &f)
renderField2("ExampleField", &f)
}
func renderField(field string, f *First) {
structVal := reflect.ValueOf(*f)
renderType := reflect.TypeOf((*Renderer)(nil)).Elem()
fieldToRender := structVal.FieldByName(field)
fieldPtr := reflect.PtrTo(fieldToRender.Type())
fmt.Printf("Implements? %v\n", fieldPtr.Implements(renderType))
fmt.Printf("Addressable? %v\n", fieldToRender.CanAddr())
fieldInter := fieldToRender.Interface()
if renderer, ok := fieldInter.(Renderer); ok {
// Pointer receiver so this never gets called
fmt.Print("Able to cast")
renderer.Render()
}
}
func renderField2(field string, f *First) {
structVal := reflect.ValueOf(*f)
fieldToRender := structVal.FieldByName(field)
vp := reflect.New(reflect.TypeOf(fieldToRender))
vp.Elem().Set(reflect.ValueOf(fieldToRender))
vpAddr := vp.Elem().Addr()
typeVal := vpAddr.Interface()
fmt.Println(typeVal) // <main.Field Value>⏎
renderer := typeVal.(Renderer)
renderer.Render()
// interface conversion: *reflect.Value is not main.Renderer: missing method Render
}
renderField2 seems to get me close but Addr() gives me a *Reflect.Value and when I call Interface() that seems to be the underlying type instead. If I switch to a non-pointer receiver then the first function works. I found reflect value Interface and pointer receiver which seems to be almost exactly what I'm asking, and the question is answered but if I actually call the isZeroer method presented in the playground link it's always false so it doesn't actually seem to answer the question.
It seems like Addr is the key because it specifically mentions pointer receivers but I'm struggling to coerce it back into an interface.
Use this code:
func renderField(name string, f *First) {
structVal := reflect.ValueOf(f).Elem()
field := structVal.FieldByName(name).Addr().Interface()
if renderer, ok := field.(Renderer); ok {
renderer.Render()
}
}
The key point is to change:
structVal := reflect.ValueOf(*f)
to:
structVal := reflect.ValueOf(f).Elem()
The statement used in the question creates a non-addressable struct value. The fields in a non-addressable struct are also not addressable, therefore it's not possible to access the pointer receiver on the fields.
The statement used in this answer creates an addressable struct value.

In golang, struct with a slice variable of any type is possible?

Simple golang app gives below error
.\test.go:13: cannot use ds (type Data_A) as type []interface {} in field value
for below code
package main
type Data_A struct {
a string
}
type DTResponse struct {
Data []interface{} `json:"data"`
}
func main() {
ds := Data_A{"1"}
dtResp := &DTResponse{ Data:ds}
print(dtResp)
}
I would like to have a struct with slice variable of any type. Using struct{} gives the same error.
In Java I could use Object as it is the parent object of any object. But I could not find such one in golang.
Any help would be appreciated.
Yes, as a slice of interface{} which can hold any arbitrary value.
var s = []interface{}{1, 2, "three", SomeFunction}
fmt.Printf("Hello, %#v \n", s)
Output:
Hello, []interface {}{1, 2, "three", (func())(0xd4b60)}
https://play.golang.org/p/MQMc689StO
But I do not recommend simulate dynamic-typed languages (like Python, JavaScript, PHP, etc) this way. Better to use all static-typed benefits from Go, and leave this feature as a last resort, or as a container for user input. Just to receive it and convert to strict types.
Typing
Go is a strongly explicitly typed language thus you can't substitute an object of one type with another (it is already compiled in this way). Also when you do type Data_A struct {... you define new type named Data_A. []interface{} and Data_A are completely different types and these types (like any other) are not interchangeable. Note, even interface{} is not interchangeable with anything. You can pass any type in a function like this func f(a interface{}){... but inside the function you will have exactly interface{} type and you should assert it to use properly.
Fix#1
package main
type Data_A struct {
a string
}
type DTResponse struct {
Data Data_A `json:"data"`
}
func main() {
ds := Data_A{"1"}
dtResp := &DTResponse{ Data:ds}
print(dtResp)
}
Fix#2
package main
type DTResponse struct {
Data []interface{} `json:"data"`
}
func main() {
ds := []interface{}{"1"}
dtResp := &DTResponse{ Data:ds}
print(dtResp)
}
Possibly the cause of confusion: struct is not slice or array.

Golang: cast interface back to its original type

I couldn't really find an answer to this, even though I looked up the Go documentation and examples. Is it possible to cast an interface back to its original type, dynamically? I know I can do something like this:
var myint int = 5
var myinterface interface{}
myinterface = myint
recovered, _ := myinterface.(int)
fmt.Println(recovered)
But here I know the type. I would like to have a map of unknown types (interfaces) and cast them back by using reflection, like this:
// put/pop writes/read to/from a map[string]interface{}
var myint int = 5
put("key" myint)
pop("key", &myint) // this should also work for objects or any other type
Like this it would by possible to store anything within a single map. The type will be handed in by the user when calling pop() (second argument is an interface). Is it possible to achive this using reflection?
You can't assert a type from an interface without knowing what that type is at compile time, but you can set a value from an interface via reflection. Here's an example without any error checks, which panics when any parameters don't match:
var m = map[string]interface{}{}
func put(k string, v interface{}) {
m[k] = v
}
func pop(k string, o interface{}) {
reflect.ValueOf(o).Elem().Set(reflect.ValueOf(m[k]))
}
https://play.golang.org/p/ORcKhtU_3O

Restore type information after passing through function as "interface {}"?

I'm running into a slight architectural problem with Golang right now that's causing me to copy/paste a bit more code than I'd prefer. I feel like there must be a solution, so please let me know if this is perhaps possible:
When I pass things through an interface {}-typed function parameter, I start getting errors such as "expected struct or slice", etc. ... even though what I passed was previously a struct or a slice. I realize that I could manually convert these to another type after receiving them in that function, but then that become tedious in instances such as this:
local interface type *interface {} can only be decoded from remote
interface type; received concrete type
... In this case, the receiving function seems like it'd need to be hard-coded to convert all interface {} items back to their respective original types in order to work properly, because the receiving function needs to know the exact type in order to process the item correctly.
Is there a way to dynamically re-type Golang interface {} typed variables back to their original type? Something like this, How to I convert reflect.New's return value back to the original type ... maybe?
EDIT: To clarify, basically, I'm passing &out to a function and it needs to be its original type by the time it reaches another inner function call.
Example code:
// NOTE: This is sort of pseudo-Golang code, not meant to be compiled or taken too seriously.
func PrepareTwoDifferentThings(keyA string, keyB string) {
var somethingA TypeA;
var somethingB TypeB;
loadFromCache(keyA, &somethingA, nil);
loadFromCache(keyB, &somethingB, nil);
fmt.Printf("Somethings: %v, %v", somethingA, somethingB);
}
func loadFromCache(key string, isNew, out interface {}, saveNewData interface {}) {
if err := cache.load(key, &out); err!=nil { // NOTE: Current issue is that this expects "&out" to be `TypeA`/`TypeB` not "interface {}", but I don't want to copy and paste this whole function's worth of code or whatever.
panic("oh no!");
}
if (saveNewData!=nil) {
cache.save(key, saveNewData); // This doesn't seem to care if "saveNewData" is "interface {}" when saving, but later cache fetches above using the "load()" method to an "interface {}"-typed `&out` parameter throw an exception that the "interface {}" type on `&out` does not match the original when it was saved here (`TypeA`/`TypeB`).
}
}
To change the type of an interface into its rightful type, you can use type assertions:
package main
import r "reflect"
type A struct {
Name string
}
func main() {
// No pointer
aa := A{"name"}
var ii interface{} = aa
bb := ii.(A)
// main.A
// Pointer
a := &A{"name"}
var i interface{} = a
b := *i.(*A)
// main.A
c := i.(*A)
// *main.A
d := r.Indirect(r.ValueOf(i)).Interface().(A)
// main.A
}
Playground 1
When using type assertions, you have to know the underlying type of your interface. In Go, there is no way to use type assertion with a dynamic type. reflect.Type is not a type, it's an interface representing a type. So no, you can't use it this way.
If you have several type possibilities, the solution is the type switch:
package main
import "fmt"
type TypeA struct {
A string
}
type TypeB struct {
B string
}
func doSomethingA(t TypeA) {
fmt.Println(t.A)
}
func doSomethingB(t TypeB) {
fmt.Println(t.B)
}
func doSomething(t interface{}) {
switch t := t.(type) {
case TypeA:
doSomethingA(t)
case TypeB:
doSomethingB(t)
default:
panic("Unrecognized type")
}
}
func main() {
a := TypeA{"I am A"}
b := TypeB{"I am B"}
doSomething(a)
// I am A
doSomething(b)
// I am B
}
Playground 2
It turns out that using JSON instead of Gob for serialization avoids the error that I was encountering entirely. Other functions can handle passing into interfaces, etc.

generic function to get size of any structure in Go

I am writing a generic function to get the size of any type of structure, similar to sizeof function in C.
I am trying to do this using interfaces and reflection but I'm not able to get the correct result. Code is below:
package main
import (
"fmt"
"reflect"
"unsafe"
)
func main() {
type myType struct {
a int
b int64
c float32
d float64
e float64
}
info := myType{1, 2, 3.0, 4.0, 5.0}
getSize(info)
}
func getSize(T interface{}) {
v := reflect.ValueOf(T)
const size = unsafe.Sizeof(v)
fmt.Println(size)
}
This code returns wrong result as 12. I am very new to Go, kindly help me on this.
You're getting the size of the reflect.Value struct, not of the object contained in the interface T. Fortunately, reflect.Type has a Size() method:
size := reflect.TypeOf(T).Size()
This gives me 40, which makes sense because of padding.
Go 1.18
With Go 1.18 you can use a generic function with unsafe.Sizeof:
func getSize[T any]() uintptr {
var v T
return unsafe.Sizeof(v)
}
Note that this will be more performant than using reflect, but it will introduce unsafe in your code base — some static analysis tools may give warnings about that.
However if your goal is to improve code reuse or get sizes at run time (read on for the solution to that), this won't help much because you still need to call the function with proper instantiation:
type myType struct {
a int
b int64
c float32
d float64
e float64
}
func main() {
fmt.Println(getSize[myType]())
}
You might get the most out of this when used as part of some other generic code, e.g. a generic type or function where you pass a type param into getSize. Although if you have the argument v this is equivalent to calling unsafe.Sizeof(v) directly. Using a function could be still useful to hide usage of unsafe. A trivial example:
func printSize[T any](v T) {
// (doing something with v)
// instantiate with T and call
s := getSize[T]()
// s := unsafe.Sizeof(v)
fmt.Println(s)
}
Otherwise you can pass an actual argument to getSize. Then type inference will make it unnecessary to specify the type param. This code perhaps is more flexible and allows you to pass arbitrary arguments at runtime, while keeping the benefits of avoiding reflection:
func getSize[T any](v T) uintptr {
return unsafe.Sizeof(v)
}
func main() {
type myType struct {
a int
b int64
c float32
d float64
e float64
}
info := myType{1, 2, 3.0, 4.0, 5.0}
// inferred type params
fmt.Println(getSize(info)) // 40
fmt.Println(getSize(5.0)) // 8
fmt.Println(getSize([]string{})) // 24
fmt.Println(getSize(struct {
id uint64
s *string
}{})) // 16
}
Playground: https://go.dev/play/p/kfhqYHUwB2S

Resources