Here is what I am trying to do.
File1:
abc
bcd
cde
def
efg
fgh
ghi
File2:
ip:/vol0/scratch/&
ip:/vol0/sysbuild/
ip:/vol0/cde
ip:/vol0/mnt/cm/&
ip:/vol0/&
ip:/vol0/mnt/fgh
ip:/vol0/mnt/&
As you can see File2 has & at the end of some lines, I need to replace the & with corresponding line in File1 and ignore the lines without the & For example, if line 2 and line 3 doesn't have & the script would skip line 2 and 3 in both files and go to line 4 to replace the &
How would I achieve this with shell script.
Using paste and awk:
$ paste file2 file1 | awk 'sub(/&\s+/,"")'
ip:/vol0/scratch/abc
ip:/vol0/mnt/cm/def
ip:/vol0/efg
ip:/vol0/mnt/ghi
Wasn't 100% clear if you wanted the lines not ending in & in the output:
$ paste file2 file1 | awk '{sub(/&\s+/,"");print $1}'
ip:/vol0/scratch/abc
ip:/vol0/sysbuild/
ip:/vol0/cde
ip:/vol0/mnt/cm/def
ip:/vol0/efg
ip:/vol0/mnt/fgh
ip:/vol0/mnt/ghi
With sed:
$ paste file2 file1 | sed -rn '/&/s/&\s+//p'
ip:/vol0/scratch/abc
ip:/vol0/mnt/cm/def
ip:/vol0/efg
ip:/vol0/mnt/ghi
awk 'NR==FNR{a[NR]=$0;next} sub(/&/,a[FNR])' file1 file2
paste file1 file2 | awk 'gsub( /&/, $1 )' | cut -f2-
try this
awk '{if (NR == FNR){f[NR]= $0;}else {gsub("&",f[FNR],$0); print $0}}' file1.txt file2.txt
This might work for you (GNU sed):
sed = file1 | sed -r 'N;s/(.*)\n(.*)/\1s|\&$|\2|/' | sed -f - file2
sed = file1 generate line numbers
sed -r 'N;s/(.*)\n(.*)/\1s|\&$|\2|/' combine line number with data line and produce a sed substitution command using the line number as an address.
sed -f - file2 feed the above commands into a sed invocation using the -f switch and the standard input -
Related
What's the easiest/quickest way to interleave the lines of two (or more) text files? Example:
File 1:
line1.1
line1.2
line1.3
File 2:
line2.1
line2.2
line2.3
Interleaved:
line1.1
line2.1
line1.2
line2.2
line1.3
line2.3
Sure it's easy to write a little Perl script that opens them both and does the task. But I was wondering if it's possible to get away with fewer code, maybe a one-liner using Unix tools?
paste -d '\n' file1 file2
Here's a solution using awk:
awk '{print; if(getline < "file2") print}' file1
produces this output:
line 1 from file1
line 1 from file2
line 2 from file1
line 2 from file2
...etc
Using awk can be useful if you want to add some extra formatting to the output, for example if you want to label each line based on which file it comes from:
awk '{print "1: "$0; if(getline < "file2") print "2: "$0}' file1
produces this output:
1: line 1 from file1
2: line 1 from file2
1: line 2 from file1
2: line 2 from file2
...etc
Note: this code assumes that file1 is of greater than or equal length to file2.
If file1 contains more lines than file2 and you want to output blank lines for file2 after it finishes, add an else clause to the getline test:
awk '{print; if(getline < "file2") print; else print ""}' file1
or
awk '{print "1: "$0; if(getline < "file2") print "2: "$0; else print"2: "}' file1
#Sujoy's answer points in a useful direction. You can add line numbers, sort, and strip the line numbers:
(cat -n file1 ; cat -n file2 ) | sort -n | cut -f2-
Note (of interest to me) this needs a little more work to get the ordering right if instead of static files you use the output of commands that may run slower or faster than one another. In that case you need to add/sort/remove another tag in addition to the line numbers:
(cat -n <(command1...) | sed 's/^/1\t/' ; cat -n <(command2...) | sed 's/^/2\t/' ; cat -n <(command3) | sed 's/^/3\t/' ) \
| sort -n | cut -f2- | sort -n | cut -f2-
With GNU sed:
sed 'R file2' file1
Output:
line1.1
line2.1
line1.2
line2.2
line1.3
line2.3
Here's a GUI way to do it: Paste them into two columns in a spreadsheet, copy all cells out, then use regular expressions to replace tabs with newlines.
cat file1 file2 |sort -t. -k 2.1
Here its specified that the separater is "." and that we are sorting on the first character of the second field.
I have two files - file1 & file2.
file1 contains (only words) says-
ABC
YUI
GHJ
I8O
..................
file2 contains many para.
dfghjo ABC kll njjgg bla bla
GHJ njhjckhv chasjvackvh ..
ihbjhi hbhibb jh jbiibi
...................
I am using below command to get the matching lines which contains word from file1 in file2
grep -Ff file1 file2
(Gives output of lines where words of file1 found in file2)
I also need the words which doesn't match/found in file 2 and unable to find Un-matching word.
Can anyone help in getting below output
YUI
I8O
i am looking one liner command (via grep,awk,sed), as i am using pssh command and can't use while,for loop
You can print only the matched parts with -o.
$ grep -oFf file1 file2
ABC
GHJ
Use that output as a list of patterns for a search in file1. Process substitution <(cmd) simulates a file containing the output of cmd. With -v you can print lines that did not match. If file1 contains two lines such that one line is a substring of another line you may want to add -x (only match whole lines) to prevent false positives.
$ grep -vxFf <(grep -oFf file1 file2) file1
YUI
I8O
Using Perl - both matched/non-matched in same one-liner
$ cat sinw.txt
ABC
YUI
GHJ
I8O
$ cat sin_in.txt
dfghjo ABC kll njjgg bla bla
GHJ njhjckhv chasjvackvh ..
ihbjhi hbhibb jh jbiibi
$ perl -lne '
BEGIN { %x=map{chomp;$_=>1} qx(cat sinw.txt); $w="\\b".join("\|",keys %x)."\\b"}
print "$&" and delete($x{$&}) if /$w/ ;
END { print "\nnon-matched\n".join("\n", keys %x) }
' sin_in.txt
ABC
GHJ
non-matched
I8O
YUI
$
Getting only the non-matched
$ perl -lne '
BEGIN {
%x = map { chomp; $_=>1 } qx(cat sinw.txt);
$w = "\\b" . join("\|",keys %x) . "\\b"
}
delete($x{$&}) if /$w/;
END { print "\nnon-matched\n".join("\n", keys %x) }
' sin_in.txt
non-matched
I8O
YUI
$
Note that even a single use of $& variable used to be very expensive for the whole program, in Perl versions prior to 5.20.
Assuming your "words" in file1 are in more than 1 line :
while read line
do
for word in $line
do
if ! grep -q $word file2
then echo $word not found
fi
done
done < file1
For Un-matching words, here's one GNU awk solution:
awk 'NR==FNR{a[$0];next} !($1 in a)' RS='[ \n]' file2 file1
YUI
I8O
Or !($0 in a), it's the same. Since I set RS='[ \n]', every space as line separator too.
And note that I read file2 first, and then file1.
If file2 could be empty, you should change NR==FNR to different file checking methods, like ARGIND==1 for GNU awk, or FILENAME=="file2", or FILENAME==ARGV[1] etc.
Same mechanism for only the matched one too:
awk 'NR==FNR{a[$0];next} $0 in a' RS='[ \n]' file2 file1
ABC
GHJ
>cat file1.txt
aa bb
ccc dd
ee fff
>cat file2.txt
1
2
3
I want to get the result like below:
aa1bb
ccc2dd
ee3fff
The space in file1.txt will be replaced by number in file2.txt.
paste + awk approach:
paste file1.txt file2.txt | awk '{ print $1$3$2 }'
The output:
aa1bb
ccc2dd
ee3fff
A straight forward way by awk,
$ awk 'NR==FNR{a[NR]=$0;next}{sub(/\ /,a[FNR])}1' file2 file1
aa1bb
ccc2dd
ee3fff
Brief explanation,
NR==FNR{a[NR]=$0;next}: store each record in file2 to array a
sub(/\ /,a[FNR]): substitute the space by a[FNR] in file2, where FNR would be the record number in the file2.
Appended 1would print each processed line in file2
This works:
$ paste <(cut -d " " -f1 file1.txt) file2.txt <(cut -d " " -f2 file1.txt) | tr -d $'\t'
aa1bb
ccc2dd
ee3fff
with a bash while-read loop
while read -u3 a b; read -u4 n; do
echo "$a$n$b"
done 3<file1.txt 4<file2.txt
I have two files. one has list of names (only one column) and the second file is with three columns with names, phone number, country.
What I want is to extract the data of the people whose names are not present in file 1, but only present in file2.
#!/bin/bash
for i in `cat file1 `
do
cat file2 | awk '{ if ($1 != "'$i'") {print $1 "\t" $2 "\t" $3 }}'>>NonResp
done
What I get is a weird result with more data than expected.
Kindly help.
You can do this with grep:
grep -v -F -f file1 file2
awk '{print $1}' file2 | comm -1 -3 file1 - | join file2 -
The files must already be sorted for this to work properly.
Explanation:
=> awk '{print $1}' file2 |
print only the first fileld of file2 and feed it to the next command (|)
=> comm -1 -3 file1 - |
compare file1 and the output of the last command (-) and suppress lines only in file1 (-1) as well as lines in both files (-3); that leaves lines in file2 only and feed this to the next command (|)
=> join file2 -
join the original file2 and the output from the last command (-) and write out the fields fo the matching lines (whitespace between fields is truncated, however)
Testcase:
cat <<EOF >file1
alan
bert
cindy
dave
fred
sunny
ted
EOF
cat <<EOF >file2
bert 01 AU
cindy 03 CZ
ginny 05 CN
ted 07 CH
zorro 09 AG
EOF
awk '{print $1}' file2 | comm -1 -3 file1 - | join file2 -
assuming the field delimiter as "," in file2
awk -F, 'FNR==NR{a[$1];next}!($1 in a)' file1 file2
if "," is not the delimiter ,then simply
awk 'FNR==NR{a[$1];next}!($1 in a)' file1 file2
would be sufficient.
This question already has answers here:
How to remove the lines which appear on file B from another file A?
(12 answers)
Closed 6 years ago.
I have two files:
file 1
dsf
sdfsd
dsfsdf
file 2
ljljlj
lkklk
dsf
sdfsd
dsfsdf
I want to display what is in file 2 but not in file 1, so file 3 should look like
ljljlj
lkklk
grep -Fxvf file1 file2
What the flags mean:
-F, --fixed-strings
Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.
-x, --line-regexp
Select only those matches that exactly match the whole line.
-v, --invert-match
Invert the sense of matching, to select non-matching lines.
-f FILE, --file=FILE
Obtain patterns from FILE, one per line. The empty file contains zero patterns, and therefore matches nothing.
You can try
grep -f file1 file2
or
grep -v -F -x -f file1 file2
You can use the comm command to compare two sorted files
comm -13 <(sort file1) <(sort file2)
I successfully used
diff "${file1}" "${file2}" | grep "<" | sed 's/^<//g' > "${diff_file}"
Outputting the difference to a file.
if you are expecting them in a certain order, you can just use diff
diff file1 file2 | grep ">"
join -v 2 <(sort file1) <(sort file2)
A tried a slight variation on Luca's answer and it worked for me.
diff file1 file2 | grep ">" | sed 's/^> //g' > diff_file
Note that the searched pattern in sed is a > followed by a space.
file1
m1
m2
m3
file2
m2
m4
m5
>awk 'NR == FNR {file1[$0]++; next} !($0 in file1)' file1 file2
m4
m5
>awk 'NR == FNR {file1[$0]++; next} ($0 in file1)' file1 file2
m2
> What's awk command to get 'm1 and m3' ?? as in file1 and not in file2?
m1
m3
If you want to use loops You can try like this: (diff and cmp are much more efficient. )
while read line
do
flag = 0
while read line2
do
if ( "$line" = "$line2" )
then
flag = 1
fi
done < file1
if ( flag -eq 0 )
then
echo $line > file3
fi
done < file2
Note: The program is only to provide a basic insight into what can be done if u dont want to use system calls such as diff n comm..
an awk answer:
awk 'NR == FNR {file1[$0]++; next} !($0 in file1)' file1 file2
With GNU sed:
sed 's#[^^]#[&]#g;s#\^#\\^#g;s#^#/^#;s#$#$/d#' file1 | sed -f- file2
How it works:
The first sed produces an output like this:
/^[d][s][f]$/d
/^[s][d][f][s][d]$/d
/^[d][s][f][s][d][f]$/d
Then it is used as a sed script by the second sed.