I'm trying to build an html table from a 2D array using a row for each array element and a cell for each string in the row. I get a cell for each character instead. I've tried some combinations for splitting the strings by comma, but haven't one that works. How do I get
onetwothree
http://jsfiddle.net/johnpoole/BfTWP/
var json_data = ["one,two,three","red,green,blue"];
var table = d3.select("body").append("table");
var rows = table.selectAll("tr").data(json_data).enter().append("tr");
rows.selectAll("td").data(function(d){return d;}).enter().append("td").text(function(d) {return d;});
The last line needs to return d.split(",") to break the string into an array. Otherwise, JS iterates through the characters in the string.
Alternatively, you could keep the code as is and change the data to:
var json_data = [["one","two","three"],["red","green","blue"]];
jsFiddle updated both ways.
Related
How do I modify this equation so I can use it with an array function instead of dragging it down.
SUBSTITUTE(JOIN(", ", UNIQUE(QUERY(A:D,"SELECT B WHERE C = '"&G2&"'"))), ", , ", "")
Explanation of the equation:
Have a function is used to extract and concatenate unique values from column B of a sheet named A:D, where the values in column C match a specific criteria. The function is made up of several parts:
It uses the QUERY function to extract all values from column B of sheet A:D where the values in column C match the specific criteria in G.
UNIQUE removes any duplicate values from previous step.
JOIN to concatenate into a single string separated by a comma to returns a string of unique values that match the criteria
SUBSTITUTE to replace occurrences of ", , " with an empty string.
can you try:
=BYROW(G2:G,LAMBDA(gx,IF(gx="",,TEXTJOIN(", ",1,IFNA(UNIQUE(FILTER(B:B,C:C=gx)))))))
I have so much trouble with leading zeros in general. Importing into Sheets using JDBC connection, I haven't figured out a way to keep the zeros. The column types are varchar() for values of varied length, and char() for static length.
In the past with other data I have added a leading ' to values, or chosen to getDisplayValue() to keep them. What would work here?
while (results.next()){
var tmpArr = [];
var rowString = '';
for (var col = 0; col < numCols; col++) {
rowString += results.getString(col + 1) + '\t';
tmpArr.push(results.getString(col + 1));
}
valArr.push(tmpArr);
}
sheet.getRange(3, 1 , valArr.length, numCols).setValues(valArr);
Data Exmaple varchar column:
0110205361
0201206352
140875852
LFCP01367
LGLM00017
You are retrieving data into a Google Sheet from a MySQL database table using Jdbc. One of the database columns is formatted as "varchar" and includes some all-numeric values that have one or more leading zeros. When you update the database values to your Google Sheet, the leading zeros are not displayed.
Why
The reason for this is that the all-numeric values are displayed without the leading zeros is that the cells are formatted as Number, Automatic (or otherwise as a number). This means that they are 'interpreted' by Google Sheets as a number and, by default, all leading zeros are dropped.
On the other hand, if the cells are formatted as Number, Plain Text, then the all-numeric values are 'interpreted' as strings, and any leading zeros are retained.
The effect of formatting can be clearly seen in the following images, which also include istext and isnumber formula to confirm how they are interpreted under each format type.
Formatted as Number - Plain Text - treated as strings
Formatted as Number - Automatic - treated as numbers
Formatting on the fly
An alternative to pre-formatting (which wasn't successful in the OP's case) is to set the format as a part of the setValues() method using setNumberFormat
For example:
sheet.getRange(3, 1 , valArr.length, numCols).setNumberFormat('#STRING#').setValues(valArr);
There is a useful discussion of this methid in Format a Google Sheets cell in plaintext via Apps Script
I have this simple code
string[] sequences = {"red,green,blue","orange","white,pink"};
var allWords = sequences.Select(s => s.Split(','));
foreach (var letter in allWords)
{
Console.WriteLine(letter);
}
The problem is that in output I get System.String[] insted of splitted array.
How to display result at console?
Use SelectMany if you want an array of strings and not an array of arrays of strings.
See https://dotnetfiddle.net/0vsjfN
SelectMany concatenates the lists, which are generated by using .Split(','), into a single list.
I am writing a script to convert JSON data to an ordered CSV spreadsheet.
The JSON data itself does not necessarily contain all keys (some fields in the spreadsheet should say "NA").
Typical JSON data looks like this:
json = {"ReferringUrl":"N","PubEndDate":"2010/05/30","ItmId":"347628959","ParentItemId":"46999"}
I have a list of the keys found in each column of the spreadsheet:
keys = ["ReferringUrl", "PubEndDate", "ItmId", "ParentItemId", "OtherKey", "Etc"]
My thought was that I could iterate through each line of JSON like this:
parsed = JSON.parse(json)
result = (0..keys.length).map{ |i| parsed[keys[i]] || 'NA'} #add values associated with keys to an array, using NA if no value is present
CSV.open('file.csv', 'wb') do |csv|
csv << keys #create headings on spreadsheet
csv << result #load data associated with headings into the next line
end
Ideally, this would create a CSV file with the proper information in the proper order in a spreadsheet. However, what happens is the result data comes in completely out of order, and contains an extra column that I don't know what to do with.
Looking at the actual data, since there are actually about 100 keys and most of the fields contain NA, it is very difficult to determine what is happening.
Any advice?
The extra column comes from 0..keys.length which includes the end of the range. The last value of result is going to be parsed[keys[keys.length]] i.e. parsed[nil] i.e. nil. You can avoid that entirely by mapping keys directly
result = keys.map { |key| parsed.fetch(key, 'NA') }
As for the random order of the values, I suspect you aren't giving us all of the relevant information, because I tested your code and the result came out in the same order as keys.
Range has two possible notations
..
and
...
... is exclusive, meaning the range (A...B) would be not include B.
Change to
result = (0...keys.length).map{ |i| parsed[keys[i]] || 'NA'} #add values associated with keys to an array, using NA if no value is present
And see if that prevents the last value in that range from evaluating to nil.
Sorry for this extreme beginner question. I have a string variable originaltext containing some multiline text. I can convert it into an array of lines like so:
lines = originaltext.split("\n");
But I need help sorting this array. This DOES NOT work:
lines.sort;
The array remains unsorted.
And an associated question. Assuming I can sort my array somehow, how do I then convert it back to a single variable with no separators?
Your only issue is a small one - sort is actually a method, so you need to call lines.sort(). In order to join the elements together, you can use the join() method:
var originaltext = "This\n\is\na\nline";
lines = originaltext.split("\n");
lines.sort();
joined = lines.join("");