Laravel Eloquent: Ordering results of all() - laravel

Question

I'm stuck on a simple task.
I just need to order results coming from this call
$results = Project::all();
Where Project is a model. I've tried this
$results = Project::all()->orderBy("name");
But it didn't work. Which is the better way to obtain all data from a table and get them ordered?

Answer 1

You can actually do this within the query.
$results = Project::orderBy('name')->get();
This will return all results with the proper order.

Answer 2

You could still use sortBy (at the collection level) instead of orderBy (at the query level) if you still want to use all() since it returns a collection of objects.
Ascending Order
$results = Project::all()->sortBy("name");
Descending Order
$results = Project::all()->sortByDesc("name");
Check out the documentation about Collections for more details.
https://laravel.com/docs/5.1/collections

Answer 3

In addition, just to buttress the former answers, it could be sorted as well either in descending desc or ascending asc orders by adding either as the second parameter.
$results = Project::orderBy('created_at', 'desc')->get();

Answer 4

DO THIS:
$results = Project::orderBy('name')->get();
Why?
Because it's fast! The ordering is done in the database.
DON'T DO THIS:
$results = Project::all()->sortBy('name');
Why?
Because it's slow. First, the the rows are loaded from the database, then loaded into Laravel's Collection class, and finally, ordered in memory.

Answer 5

2017 update
Laravel 5.4 added orderByDesc() methods to query builder:
$results = Project::orderByDesc('name')->get();

Answer 6

While you need result for date as desc
$results = Project::latest('created_at')->get();

Answer 7

In Laravel Eloquent you have to create like the query below it will get all the data from the DB, your query is not correct:
$results = Project::all()->orderBy("name");
You have to use it in this way:
$results = Project::orderBy('name')->get();
By default, your data is in ascending order, but you can also use orderBy in the following ways:
//---Ascending Order
$results = Project::orderBy('name', 'asc')->get();
//---Descending Order
$results = Project::orderBy('name', 'desc')->get();

Answer 8

Check out the sortBy method for Eloquent: http://laravel.com/docs/eloquent

Answer 9

Note, you can do:
$results = Project::select('name')->orderBy('name')->get();
This generate a query like:
"SELECT name FROM proyect ORDER BY 'name' ASC"
In some apps when the DB is not optimized and the query is more complex, and you need prevent generate a ORDER BY in the finish SQL, you can do:
$result = Project::select('name')->get();
$result = $result->sortBy('name');
$result = $result->values()->all();
Now is php who order the result.

Answer 10

You instruction require call to get, because is it bring the records and orderBy the catalog
$results = Project::orderBy('name')
->get();
Example:
$results = Result::where ('id', '>=', '20')
->orderBy('id', 'desc')
->get();
In the example the data is filtered by "where" and bring records greater than 20 and orderBy catalog by order from high to low.

Answer 11

Try this:
$categories = Category::all()->sortByDesc("created_at");

Answer 12

One interesting thing is multiple order by:
according to laravel docs:
DB::table('users')
->orderBy('priority', 'desc')
->orderBy('email', 'asc')
->get();
this means laravel will sort result based on priority attribute. when it's done, it will order result with same priority based on email internally.
EDIT:
As #HedayatullahSarwary said, it's recommended to prefer Eloquent over QueryBuilder. off course i didn't encourage using QueryBuilder and we all know that each has own usecases.
Any way so why i wrote an answer with QueryBuilder? As we see in eloquent documents:
You can think of each Eloquent model as a powerful query builder allowing you to fluently query the database table associated with the model.
BTWS the above code with eloquent should be something like this:
Project::orderBy('priority', 'desc')
->orderBy('email', 'asc')
->get();