I need sorting the Records data according to Relationship.
I am trying below Query.
$data = Lead::with('bdm', 'status_code', 'bdm.bdm')->get()->sortByDesc('bdm.bdm.name');
It works fine but I need data with pagination which is giving by Laravel 5 by default.
So If I am trying with below query . It is giving error.
$data = Lead::with('bdm', 'status_code', 'bdm.bdm')->pagination(20)->sortByDesc('bdm.bdm.name');
I am trying an other way to do the same task. It works fine but it is not sorting the records.
$data = Lead::with(['bdm','status_code', 'bdm.bdm' => function ($query) {
$query->orderBy('name', 'desc');
}])->paginate(20);
So kindly can anyone give me solution how to adjust this query.
Any Help will be appreciated.
Thanks
You should be using a join statement to do that.
If I were to assume your column names it should look something like this:
$data = Lead::with(['status_code', 'bdm.bdm'])
->join('bdms', 'bdms.id', '=', 'leads.bdm_id')
->orderBy('bdms.name', 'desc')
->paginate(20);
And the first bdm parameter in your query is redundant. It will be handled during bdm.bdm anyway.
Related
Does someone know how to speed up such a query? When loading <3000 items it takes like ages until I get a result.
$data = Data::select('updated_at', 'data')
->where('device', $request->id)
->where('type', $request->type)
->get();
Just search the word Paginate and read laravel documentation. You don't get all data and show it, you paginate them.
$konten = Konten::all()->where('kategori','Announcement' AND 'kategori','Activities')->sortByDesc('id');
It's not work what is the right query for using AND Logic in query sir ? im so sorry i don't have much knowledge to find out the way.. the point is i want $konten contains the row from Konten where the kategori is Announcement and Activities.. how to make it happen ? it just showing konten where the kategori is activities the announcement not passed..
You can chain several where to achieve AND:
$konten = Konten::where('kategori', 'Announcement')
->where('kategori', 'Activities')
->orderBy('id', 'desc')
->get();
Or use whereIn like this:
$konten = Konten::whereIn('kategori', ['Announcement', 'Activities'])
->orderBy('id', 'desc')
->get();
To achieve an AND in Laravel, you simply chain ->where() calls:
$konten = Konten::where('kategori','Announcement')->where('kategori','Activities') ...
As a side note, Konten::all() returns a Collection, and is no longer database logic. You shouldn't call ::all() unless you specifically need every record in the database.
Refactor to the following:
$konten = Konten::where('kategori','Announcement')
->where('kategori','Activities')
->orderBy('id', 'desc')
->get();
This will leverage the database to perform the filtering/ordering, instead of offloading every record into a Collection and allowing PHP to perform the same logic, which can be incredibly inefficient depending on the number of records.
try this:
$konten = Konten::whereIn('kategori', ['Announcement', 'Activities'])->orderBy('id', 'desc')->get();
I have a strong feeling that you probably seek for 'orWhere' clause... If you want ALL records when kategori column equals 'Announcement' and all records when kategori equals 'Activities' you sholud use orWhere clause like so:
$konten = Konten::where('kategori', 'Announcement')
->orWhere('kategori', 'Activities')
->orderBy('id', 'desc')
->get();
Or as mentioned in answers below you can use whereIn statement.
Database Structure:
Table: sales_payments
columns: id, payer_id, payment_status, amount , ...
Please see this eloquent query. it's working fine but now i need the sum of amount key along with this given eloquent query and where conditions.
$query = SalesPayment::with(['abc.xyz'])
->whereHas('abc.xyz', function ($query) use ($options) {
$query->where('xyz_id',$options['xyz_id']);
});
$query->where(['key3' => key3(), 'payment_status' => PAYMENT_STATUS_SUCCESS]);
$query->orderBy('created_at', 'desc');
return $query->paginate(config('constants.PAGE_LIMIT'));
Possible Solution
Just put a select as mentioned below
$query = SalesPayment::select('*', \DB::raw('SUM(amount) AS total_sale_amount')->with ....
I have tested this solution it's working fine.
Please let me know if there is a better solution than this. And I'm looking for some other solutions Also.
Edit: But there is one problem with this solution that it returning me only one record when i put aggregate function (sum) in select otherwise it was returning more than one records.
You could use the sum method on the query.
$amount = $query->sum('amount');
A new query with the same conditions will be executed to calculate the sum of a column.
https://laravel.com/docs/6.x/queries#aggregates
I was searching for making a GROUP BY name Eloquent ORM docs but I haven't find anything, neither on google.
Does anyone know if it's possible ? or should I use query builder ?
Eloquent uses the query builder internally, so you can do:
$users = User::orderBy('name', 'desc')
->groupBy('count')
->having('count', '>', 100)
->get();
Laravel 5
WARNING: As #Usama stated in comments section, this groups by AFTER fetching data from the database. The grouping is not done by the database server.
I wouldn't recommend this solution for large data set.
This is working for me (i use laravel 5.6).
$collection = MyModel::all()->groupBy('column');
If you want to convert the collection to plain php array, you can use toArray()
$array = MyModel::all()->groupBy('column')->toArray();
try: ->unique('column')
example:
$users = User::get()->unique('column');
I'm stuck on a simple task.
I just need to order results coming from this call
$results = Project::all();
Where Project is a model. I've tried this
$results = Project::all()->orderBy("name");
But it didn't work. Which is the better way to obtain all data from a table and get them ordered?
You can actually do this within the query.
$results = Project::orderBy('name')->get();
This will return all results with the proper order.
You could still use sortBy (at the collection level) instead of orderBy (at the query level) if you still want to use all() since it returns a collection of objects.
Ascending Order
$results = Project::all()->sortBy("name");
Descending Order
$results = Project::all()->sortByDesc("name");
Check out the documentation about Collections for more details.
https://laravel.com/docs/5.1/collections
In addition, just to buttress the former answers, it could be sorted as well either in descending desc or ascending asc orders by adding either as the second parameter.
$results = Project::orderBy('created_at', 'desc')->get();
DO THIS:
$results = Project::orderBy('name')->get();
Why?
Because it's fast! The ordering is done in the database.
DON'T DO THIS:
$results = Project::all()->sortBy('name');
Why?
Because it's slow. First, the the rows are loaded from the database, then loaded into Laravel's Collection class, and finally, ordered in memory.
2017 update
Laravel 5.4 added orderByDesc() methods to query builder:
$results = Project::orderByDesc('name')->get();
While you need result for date as desc
$results = Project::latest('created_at')->get();
In Laravel Eloquent you have to create like the query below it will get all the data from the DB, your query is not correct:
$results = Project::all()->orderBy("name");
You have to use it in this way:
$results = Project::orderBy('name')->get();
By default, your data is in ascending order, but you can also use orderBy in the following ways:
//---Ascending Order
$results = Project::orderBy('name', 'asc')->get();
//---Descending Order
$results = Project::orderBy('name', 'desc')->get();
Check out the sortBy method for Eloquent: http://laravel.com/docs/eloquent
Note, you can do:
$results = Project::select('name')->orderBy('name')->get();
This generate a query like:
"SELECT name FROM proyect ORDER BY 'name' ASC"
In some apps when the DB is not optimized and the query is more complex, and you need prevent generate a ORDER BY in the finish SQL, you can do:
$result = Project::select('name')->get();
$result = $result->sortBy('name');
$result = $result->values()->all();
Now is php who order the result.
You instruction require call to get, because is it bring the records and orderBy the catalog
$results = Project::orderBy('name')
->get();
Example:
$results = Result::where ('id', '>=', '20')
->orderBy('id', 'desc')
->get();
In the example the data is filtered by "where" and bring records greater than 20 and orderBy catalog by order from high to low.
Try this:
$categories = Category::all()->sortByDesc("created_at");
One interesting thing is multiple order by:
according to laravel docs:
DB::table('users')
->orderBy('priority', 'desc')
->orderBy('email', 'asc')
->get();
this means laravel will sort result based on priority attribute. when it's done, it will order result with same priority based on email internally.
EDIT:
As #HedayatullahSarwary said, it's recommended to prefer Eloquent over QueryBuilder. off course i didn't encourage using QueryBuilder and we all know that each has own usecases.
Any way so why i wrote an answer with QueryBuilder? As we see in eloquent documents:
You can think of each Eloquent model as a powerful query builder allowing you to fluently query the database table associated with the model.
BTWS the above code with eloquent should be something like this:
Project::orderBy('priority', 'desc')
->orderBy('email', 'asc')
->get();