I'm a newbie to scripting languages trying to learn bash programming.
I have very basic question. Suppose I want to create three folders like $HOME/folder/
with two child folders folder1 and folder2.
If I execute command in shell like
mkdir -p $HOME/folder/{folder1,folder2}
folder will be created along with child folder.
If the same thing is executed through script I'm not able get expected result. If sample.sh contains
#!/bin/sh
mkdir -p $HOME/folder/{folder1,folder2}
and I execute sh ./sample.sh, the first folder will be created then in that a single {folder1,folder2} directory is created. The separate child folders are not created.
My query is
How the script file works when we compared to as terminal command? i.e., why is it not the same?
How to make it work?
bash behaves differently when invoked as sh, to more closely mimic the POSIX standard. One of the things that changes is that brace expansion (which is absent from POSIX) is no longer recognized. You have several options:
Run your script using bash ./sample.sh. This ignores the hashbang and explicitly uses bash to run the script.
Change the hashbang to read #!/bin/bash, which allows you to run the script by itself (assuming you set its execute bit with chmod +x sample.sh).
Note that running it as sh ./sample.sh would still fail, since the hashbang is only used when running the file itself as the executable.
Don't use brace expansion in your script. You could still use as a longer method for avoiding duplicate code:
for d in folder1 folder2; do
mkdir -p "$HOME/folder/$d"
done
Brace expansion doesn't happen in sh.
In sh:
$ echo {1,2}
produces
{1,2}
In bash:
$ echo {1,2}
produces
1 2
Execute your script using bash instead of using sh and you should see expected results.
This is probably happening because while your tags indicate you think you are using Bash, you may not be. This is because of the very first line:
#/bin/sh
That says "use the system default shell." That may not be bash. Try this instead:
#!/usr/bin/env bash
Oh, and note that you were missing the ! after #. I'm not sure if that's just a copy-paste error here, but you need the !.
Related
I am trying to run the next code on bash. It is suppose to work but it does not.
Can you help me to fix it? I am starting with programming.
The code is this:
for i in {1:5}
do
cd path-to-folder-number/"$i"0/
echo path-to-folder-number/"$i"0/
done
EXAMPLE
I want to iterate over folders which have numbers (10,20..50), and so it changes directory from "path-to-folder-number/10/" to "path-to-folder-number/20/" ..etc
I replace : with .. but it is not working yet. When the script is applied i get:
can't cd to path-to-folder-number/{1..5}0/
I think there are three problems here: you're using the wrong shell, the wrong syntax for a range, and if you solved those problems you may also have trouble with successive cds not doing what you want.
The shell problem is that you're running the script with sh instead of bash. On some systems sh is actually bash (but running in POSIX compatibility mode, with some advanced features turned off), but I think on your system it's a more basic shell that doesn't have any of the bash extensions.
The best way to control which shell a script runs with is to add a "shebang" line at the beginning that says what interpreter to run it with. For bash, that'd be either #!/bin/bash or #!/usr/bin/env bash. Then run the script by either placing it in a directory that's in your $PATH, or explicitly giving the path to the script (e.g. with ./scriptname if you're in the same directory it's in). Do not run it with sh scriptname, because that'll override the shebang and use the basic shell, and it won't work.
(BTW, the name "shebang" comes from the "#!" characters the line starts with -- the "#" character is sometimes called "sharp", and "!" is sometimes called "bang", so it's "sharp-bang", which gets abbreviated to "shebang".)
In bash, the correct syntax for a range in a brace expansion is {1..5}, not {1:5}. Note that brace expansions are a bash extension, which is why getting the right shell matters.
Finally, a problem you haven't actually run into yet, but may when you get the first two problems fixed: you cd to path-to-folder-number/10/, and then path-to-folder-number/20/, etc. You are not cding back to the original directory in between, so if the path-to-folder-number is relative (i.e. doesn't start with "/"), it's going to try to cd to path-to-folder-number/10/path-to-folder-number/20/path-to-folder-number/30/path-to-folder-number/40/path-to-folder-number/50/.
IMO using cd in scripts is generally a bad idea, because there are a number of things that can go wrong. It's easy to lose track of where the script is going to be at which point. If any cd fails for any reason, then the rest of the script will be running in the wrong place. And if you have any files specified by relative paths, those paths become invalid as soon as you cd someplace other than the original directory.
It's much less fragile to just use explicit paths to refer to file locations within the script. So, for example, instead of cd "path-to-folder-number/${i}0/"; ls, use ls "path-to-folder-number/${i}0/".
For up ranges the syntax is:
for i in {1..5}
do
cd path-to-folder-number/"$i"0/
echo $i
done
So replace the : with ..
To get exactly what you want you can use this:
for i in 10 {20..50}
do
echo $i
done
You can also use seq :
for i in $(seq 10 10 50); do
cd path-to-folder-number/$i/
echo path-to-folder-number/$i/
done
im trying to get my server to execute a simple bash script:
#!/bin/bash
echo Hello World
After saving this to /var/www/script (im saving it to the web directory for no reason in particular) i try and execute it with
exec /var/www/script
This fails returning i don't have permission to execute it, sudo exec isn't a thing so i do sudo -i then run exec /var/www/script as root and i still have permission denied. I fairly uncertain why executing it as root doesn't work. Im wondering if i'm
A) using the wrong command to execute a bash script
B) have incorrect formatting in the script
C) shouldn't have saved it to /var/www/
D) done some other thing that i'm not even aware of.
Im running ubuntu server 16.04 if that helps.
File Permissions
First, make sure that you have the correct file permissions:
chmod +x /var/www/script_name #Gives the current user execute permissions
Executing Your Bash Script
In order to execute your bash script, the easiest option is to just simply call it (without any additional commands) by typing in the relative path to the script:
/var/www/script_name
There are other options for explicitly executing your script from the shell (in your case, use the bash shell to execute your script as a bash script). From TLDP documentation...
A script can also explicitly be executed by a given shell, but generally we only do this if we want to obtain special behavior, such as checking if the script works with another shell or printing traces for debugging:
rbash script_name.sh # Execute using the restricted bash shell
sh script_name.sh # Execute using the sh shell
bash -x script_name.sh # Execute using the bash shell
A Note on File Extensions: "Shebang" line > File extension
It is not an advised practice to use file extensions with your scripts, especially if you think your code may evolve beyond its current functionality.
Just in case you were wondering if the file extension may be your problem... it is not. It is important that you know that the file extension of a script isn't necessary at all. What matter is what you put in the "shebang" line:
To use the sh shell:
#!/bin/sh
To use the bash shell:
#!/bin/bash
It won't matter what file extension you use - the "shebang" line indicates what shell will be used to execute the script. You could save a script with the "shebang" of #!/bin/bash as script_name.py, but it would remain a bash script. If you attempt to execute it, ./script_name.py, it would be executed as a bash script.
As #Arjan mentioned in the comments, using file extensions for your script could lead to unnecessary complications if you decide to change the implementation of your project (i.e., a different shell / language):
I could decide later to shift my project to sh, python, perl, C, etc. Perhaps because I want to add functionality. Perhaps because I want to make it portable to a system without bash. It would be much more difficult if I used the .sh file extension, since then I'd need to change all my references to the script just because I changed its implementation.
You have two choices:
Run it as an argument to bash:
bash /var/www/script
Alternatively, set the execute bit:
chmod +x /var/www/script
And, now you can execute it directly:
/var/www/script
I am attempting to create a recursive directory tree with some nested directories along the way.
While testing this manually in bash it functions without issue. However while testing this command in a bash script it is broken...instead of creating the directory tree, it creates two directories '{dir1,dir2/' and then {subdir1,subdir2},dir3,dir4} inside of the first.
Here is the command:
mkdir -p main/{dir1,dir2/{subdir1,subdir2},dir3,dir4}
Any thoughts?
Thanks!
Your script is being run by /bin/sh, which in your case is not bash but rather some Posix-compatible shell, quite possibly dash.
Brace expansion is a shell extension implemented by quite a few shells, including bash, ksh and zsh, but it is not available in dash.
Make sure that your shebang line specifies bash:
#!/bin/bash
I am trying to create an AppleScript with commands below. An issue I am having is there is an error at the third line. I have no problem using the lame command in the terminal directly. In addition, lame is not a native Mac utility; I installed it on my own. Does anybody have a solution?
do shell script "cd ~/Downloads"
do shell script "say -f ~/Downloads/RE.txt -o ~/Downloads/recording.aiff"
do shell script "lame -m m ~/Downloads/recording.aiff ~/Downloads/recording.mp3"
-- error "sh: lame: command not found" number 127
do shell script "rm recording.aiff RE.txt"
To complement Paul R's helpful answer:
The thing to note is that do shell script - regrettably - does NOT see the same $PATH as shells created by Terminal.app - a notable absence is /usr/local/bin.
On my OS X 10.9.3 system, running do shell script "echo $PATH" yields merely:
/usr/bin:/bin:/usr/sbin:/sbin
There are various ways around this:
Use the full path to executables, as in Paul's solution.
Manually prepend/append /usr/local/bin, where many non-system executables live, to the $PATH - worth considering if you invoke multiple executables in a single do shell script command; e.g.:
do shell script "export PATH=\"/usr/local/bin:$PATH\"
cd ~/Downloads
say -f ~/Downloads/RE.txt -o ~/Downloads/recording.aiff
lame -m m ~/Downloads/recording.aiff ~/Downloads/recording.mp3
rm recording.aiff RE.txt"
Note how the above use a single do shell script command with multiple commands in a single string - commands can be separated by newlines or, if on the same line, with ;.
This is more efficient than multiple invocations, though adding error handling both inside the script code and around the do shell script command is advisable.
To get the same $PATH that interactive shells see (except additions made in your bash profile), you can invoke eval $(/usr/libexec/path_helper -s); as the first statement in your command string.
Other important considerations with do shell script:
bash is invoked as sh, which results in changes in behavior, most notably:
process substitution (<(...)) is not available
echo by default accepts no options and interprets escape sequences such as \n.
other, subtle changes in behavior; see http://www.gnu.org/software/bash/manual/html_node/Bash-POSIX-Mode.html
You could address these issues manually by prepending shopt -uo posix; shopt -u xpg_echo; to your command string.
The locale is set to the generic "C" locale instead of to your system's; to fix that, manually prepend export LANG='" & user locale of (system info) & ".UTF-8' to your command string.
No startup files (profiles) are read; this is not surprising, because the shell created is a noninteractive (non-login) shell, but sometimes it's handy to load one's profile by manually by prepending . ~/.bash_profile to the command string; note, however, that this makes your AppleScript less portable.
do shell script command reference: http://developer.apple.com/library/mac/#technotes/tn2065/_index.html
Probably a PATH problem - use the full path for lame, e.g.
do shell script "/usr/local/bin/lame -m m ~/Downloads/recording.aiff ~/Downloads/recording.mp3"
I have been struggling to get the path of an installed BASH command via Applescript for a long time. Using the information here, I finally succeeded.
tell me to set sox_path to (do shell script "eval $(/usr/libexec/path_helper -s); which sox")
Thanks.
Url:http://sourceforge.net/project/showfiles.php?group_id=290&package_id=309
./configure
make install
I am writing a bash script (called gotodir.sh) and would like to change directories during the course of the script, depending on some variables, say cd /home/username/${FOO}/${BAR}.
Just running this as is doesn't work when the process exits, since the directory was changed in the subshell only.
My shell is tcsh. (Yeah, I know... not my choice here.) In my .cshrc file, I want to alias the keyword gotodir to gotodir.sh.
I have read that executing the script with a . or source prefix will cause the script to be run in the same shell (i.e. not a subshell).
I have tried putting the following in my .cshrc file:
alias gotodir . /home/username/bin/gotodir.sh
but this results in the error: /bin/.: Permission denied.
I have also tried using source instead of .
alias gotodir source /home/username/bin/gotodir.sh
but this results in the error: if: Expression Syntax.
How do I accomplish this using a bash script while running tcsh?
When you source a file from tcsh, it tcsh runs the commands. The #! is ignored as a comment because you're not running the file as a script, just reading commands from it as if they'd been entered at the shell prompt.
Your mission is doomed to failure. Only a tcsh cd command can change the current directory of a tcsh process.
But if you're willing to bend a little, you can write a script which runs as a separate process and outputs the name of the directory to cd to. Then set the alias like
alias gotodir 'cd `/blah/blah/thescript`'
Addendum
Adding an argument is possible, but tricky. Alias arguments look like history expansion, with !:1 expanding to the first argument. But quotes don't protect the ! character. You have to backslash it to prevent it being expanded during creation of the aliase, so it can do its work during the execution of the alias.
alias gotodir 'cd `/blah/blah/thescript \!:1`'
Additional quoting may be required to handle arguments and directories with spaces in them.