get average value from a tree of nodes - algorithm

Question

I have to implement this method:
public int GetAverage(Node root){
//TODO implement
}
this method should get average value of all nodes of root tree. where :
public interface Node {
int getValue();
List<Node> getNodes();
}
do you have any ideas how to implement this method?
thank you
my attempt:
public static double value;
public static int count;
public static double getAverage(Node root) {
count++;
value += root.getValue();
for (Node node : root.getNodes()) {
getAverage(node);
}
return value / count;
}
but how to do it without the static fields outside of the method?

Answer 1

Simply traverse through all nodes and remember the count and the overall sum of all values. Then calculate the average. This is an example written in Java.
public interface INode {
int getValue();
List<INode> getNodes();
}
public class Node implements INode {
private List<INode> children = new ArrayList<INode>();
private int value;
#Override
public int getValue() {
return value;
}
#Override
public List<INode> getNodes() {
return children;
}
public static int getAverage(INode root) {
if (root == null)
return 0;
Counter c = new Counter();
calculateAverage(root, c);
return c.sum / c.count;
}
class Counter {
public int sum;
public int count;
}
private static void calculateAverage(INode root, Counter counter) {
if (root == null)
return;
counter.sum += root.getValue();
counter.count++;
// recursively through all children
for (INode child : root.getNodes())
calculateAverage(child, counter);
}
}

Answer 2

public static double getAverage(Node root) {
Pair p = new Pair(0,0);
algo(root, p);
return ((double) p.element1) / ((double) p.element2);
}
private static void algo(Node root, Pair acc) {
for(Node child : root.getNodes()) {
algo(child, acc);
}
acc.sum += root.getValue();
acc.nbNodes++;
}
With Pair defined as follows:
public class Pair {
public int sum;
public int nbNodes;
public Pair(int elt1, int elt2) {
this.sum = elt1;
this.nbNodes = elt2;
}
}