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I am writing a Ruby script to unzip a file where each pass through the %x{unzip } will have a different file name.
I have been successful getting
%x{unzip FILENAME.ZIP} to unzip the contents of FILENAME.ZIP
However, I want to be able to pass in the name of the file to unzip.
I've tried variations of
filename = "CONSTANT+variable+"NEXT_CONSTANT.ZIP"
%x{${filename}}
and I have been unable to get the %x to let me construct a filename that I want to unzip.
You can do it the same way you'd do it in a double-quoted string: #{filename}.
filename = "my_files.zip"
%x{unzip #{filename}}
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I'm trying to get the full file path of a configuration file from a nested directory and only need the first result.
directory1/
├──directory2/
| └──configuration.ini
├──directory3/
| └──configuration.ini
What I want is to set only 1 file path to a variable.
e.g.
$ DIRECTORY=*/CODE*/
$ echo ${DIRECTORY};
$ /directory1/directory2/configuration.ini
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i want to copy some files from ../soft to ../copu_new. The name of that tests are in ../sim/soft.txt.
I had en error : cp:cannot stat '../soft/file1.txt\file2.txt\file3.txt': File too long
Follow the code below:
input="../sim/soft.txt"
while read line
do
##to skip the first line of the file
a=$(tail -n +1)
##From string to table
for i in $a
do
table_soft[$i]="$i"
done
for i in "${tabke_soft[#]}"
do
cp ../soft/$i ../copy_new
done
done < $input
The file Soft.txt is :
###This all tests:
file1.txt
file2.txt
file3.txt
It's most likely the classic bash issue where trying to run an array through a for loop gives you all the content unless you wrap it in double quotes first. Try this..
a="$(tail -n +1)"
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This is my text file and I want to remove every first line:
aaaa
bbbb/bbbb
/cccc/cccc
/Dddd/zzzz/wwww
.gggg
.oooo/sssss
/.vvvvv
!#%#/$%
How can I remove all first "/" from my text file?
I want the result text file to be like:
aaaa
bbbb/bbbb
cccc/cccc
Dddd/zzzz/wwww
.gggg
.oooo/sssss
.vvvvv
!#%#/$%
if it's any help, I'm using sed command.
sed can be instructed to replace the first / of each line with nothing:
sed 's_^/__' 'my text file name'
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I want rename bunch of filenames. The rename is based on the calculation of the filename. That means the actual filename + 3600 = new filename.
Important is that the underscore in the pid files have to stay.
Thanks in advance!
My system is Debian Stretch.
Actual Filename:
134235.error
134235_.pid
134235.tiff
13893.error
13893_.pid
13893.tiff
1.error
1_.pid
1.tiff
Rename to:
137835.error
137835_.pid
137835.tiff
17493.error
17493_.pid
17493.tiff
3601.error
3601_.pid
3601.tiff
for fname in *; do
echo mv -- "$fname" "${fname/*[[:digit:]]/$((${fname%%[^[:digit:]]*}+3600))}"
done
If everything looks ok, remove echo.
With Perl's standalone rename command. Some distributions call it prename.
rename -n 's/(\d+)(.+)/${\($1+3600)}$2/' *
If everything looks fine, remove -n.
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I have many tsv files that are headerless, and would like to add the same header to each of them. How can I do this through the terminal or bash?
Thanks!
sed -i '1i \here comes header' files
files could be glob exp, like *.txt
Assume you have header in "head", tsv files as "body", how about cat head body | tee body