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I want rename bunch of filenames. The rename is based on the calculation of the filename. That means the actual filename + 3600 = new filename.
Important is that the underscore in the pid files have to stay.
Thanks in advance!
My system is Debian Stretch.
Actual Filename:
134235.error
134235_.pid
134235.tiff
13893.error
13893_.pid
13893.tiff
1.error
1_.pid
1.tiff
Rename to:
137835.error
137835_.pid
137835.tiff
17493.error
17493_.pid
17493.tiff
3601.error
3601_.pid
3601.tiff
for fname in *; do
echo mv -- "$fname" "${fname/*[[:digit:]]/$((${fname%%[^[:digit:]]*}+3600))}"
done
If everything looks ok, remove echo.
With Perl's standalone rename command. Some distributions call it prename.
rename -n 's/(\d+)(.+)/${\($1+3600)}$2/' *
If everything looks fine, remove -n.
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i want to copy some files from ../soft to ../copu_new. The name of that tests are in ../sim/soft.txt.
I had en error : cp:cannot stat '../soft/file1.txt\file2.txt\file3.txt': File too long
Follow the code below:
input="../sim/soft.txt"
while read line
do
##to skip the first line of the file
a=$(tail -n +1)
##From string to table
for i in $a
do
table_soft[$i]="$i"
done
for i in "${tabke_soft[#]}"
do
cp ../soft/$i ../copy_new
done
done < $input
The file Soft.txt is :
###This all tests:
file1.txt
file2.txt
file3.txt
It's most likely the classic bash issue where trying to run an array through a for loop gives you all the content unless you wrap it in double quotes first. Try this..
a="$(tail -n +1)"
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I have a '.GS3' file with multiple lines like this one:
0123456789 aaa.aaa3456
I want to separate it like this:
01234;56789 ;aaa.aaa;3456
I know the start and end of each part of the line. Is it possible to do this considering multiple lines? For example:
0123456789 aaa.aaa3456
aaaaabbbbbbbxxxxxxxwwww
Into
01234;56789 ;aaa.aaa;3456
aaaaa;bbbbbbb;xxxxxxx;wwww
.. but if it does have fixed lengths you can do it this way:
$ sed -r 's/^(.{5})(.{7})(.{7})(.{4})$/\1;\2;\3;\4/' test.txt
01234;56789 ;aaa.aaa;3456
aaaaa;bbbbbbb;xxxxxxx;wwww
I think .{5} is self explanatory. Due to the -r option the first group (.{5}) can be referenced by \1. It's a group due to ( and ).
The characters ^ and $ represent the beginning and ending of every line in the file test.txt.
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I have lots of different strings that look like redhat-ubi-ubi7-7.8
I want to use the string to make variables so that I end up having something like
vendor=redhat
product=ubi
image=ubi7
tag=7.8
How can I do this?
With bash and a here string:
string='redhat-ubi-ubi7-7.8'
IFS=- read -r vendor product image tag <<< "$string"
echo "$vendor"
Output:
redhat
Using P.E. parameter expansion.
string='redhat-ubi-ubi7-7.8'
vendor=${string%%-*}
tag=${string##*-}
image=${string%-*}
product=${image#*-}
product=${product%-*}
image=${image##*-}
printf '%s\n' vendor=$vendor product=$product image=$image tag=$tag
Output
vendor=redhat
product=ubi
image=ubi7
tag=7.8
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I am writing a Ruby script to unzip a file where each pass through the %x{unzip } will have a different file name.
I have been successful getting
%x{unzip FILENAME.ZIP} to unzip the contents of FILENAME.ZIP
However, I want to be able to pass in the name of the file to unzip.
I've tried variations of
filename = "CONSTANT+variable+"NEXT_CONSTANT.ZIP"
%x{${filename}}
and I have been unable to get the %x to let me construct a filename that I want to unzip.
You can do it the same way you'd do it in a double-quoted string: #{filename}.
filename = "my_files.zip"
%x{unzip #{filename}}
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I have many tsv files that are headerless, and would like to add the same header to each of them. How can I do this through the terminal or bash?
Thanks!
sed -i '1i \here comes header' files
files could be glob exp, like *.txt
Assume you have header in "head", tsv files as "body", how about cat head body | tee body