I can't find the 1 matching node for this code.
I have tried: //a[#href,'/index.php?r=site%2Flogout'] this is showing incorrect.
Xpath for this code line
xpath: //a[#href,'/index.php?r=site%2Flogout']
change the comma , with the equal =
//a[#href='/index.php?r=site%2Flogout']
Kindly try below:
//a[contains(#href,'/index.php?r=site%2Flogout')]
As you can see below in my application as well I am having similar outer html and here I am using link text for clicking on it.Could you please try out the same and let me know whether it works out for you or not.
a class="fxpage-userpanel-button" id="fxpage-userpanel-logoutbutton" href="javascript:void(0);" onclick="showConfirm('Are you sure you want to log out?','http://asd/auth/logout?module=module')">
Log out
Try this out:
driver.findElement(By.linkText("Log Out")).click();
I am new to NUNIT and am stumped on how to close a dialog box.
The site I am experimenting with is Google Translate. Part of the code "clicks" on the "Send Feedback Link".
Below is the function I am using:
public void CloseModalWindow(string className)
{
WebController wPage = new WebController(driver);
wPage.waitUntilExistsByXPath(className);
wPage.waitUntilVisibleByXPath(className);
IWebElement clickButtonXPATH = driver.FindElement(By.XPath(className));
clickButtonXPATH.Click();
}
The basic logic is that I am trying to simulate is to click the "X" on the upper right hand side of the Google Feedback popup that appears.
Please note that:
The web driver is FireFox.
I am sending the XPath value (derived from Google Translate directly using FireBug) /html/body/div[3]/div/span[2].
I've also tried using the CSSSelector method instead of XPATH, sending the value span[class='modal-dialog-title'] into the function.
Nunit will in complete without any errors, but the popup does not close as I am anticipating.
Thank you in advance for your input and insight.
From your XPath I see that the "X" is not a natively clickable element - like <a> or <button> are. I experienced that calling Click() on such elements does not what one expects. Instead you could try using the action builder functionality which will simulate a general mouse or keyboard input. Replace
clickButtonXPATH.Click();
with
new Actions(driver).Click(clickButtonXPATH).Build().Perform();
EDIT:
I have cleaned this up a bit.
I have a button that looks like this:
<input id="applyRuleButton" class="Button" name="filtersContainer:applyRuleButton"
value="Apply" onclick="wicketShow('applyRuleButton--ajax-indicator');var
wcall=wicketSubmitFormById('id256', '?wicket:interface=:23:form:filtersContainer:applyRuleButton:
:IActivePageBehaviorListener:0:&wicket:ignoreIfNotActive=true',
'filtersContainer:applyRuleButton' ,function() { ;wicketHide('applyRuleButton--
ajax-indicator');}.bind(this),function() { ;wicketHide('applyRuleButton--
ajax-indicator');}.bind(this), function() {return
Wicket.$$(this)&&Wicket.$$('id256')}.bind(this));;; return false;" type="submit">
Firebug:
<input id="applyRuleButton" class="Button" type="submit"
onclick="wicketShow('applyRuleButton--ajax-indicator');var
wcall=wicketSubmitFormById('id2ee',
'?wicket:interface=:29:form:filtersContainer:applyRuleButton::IActivePageBehaviorListener:0
:&wicket:ignoreIfNotActive=true', 'filtersContainer:applyRuleButton' ,function() {
;wicketHide('applyRuleButton--ajax-indicator');}.bind(this),function() {
;wicketHide('applyRuleButton--ajax-indicator');}.bind(this), function() {return
Wicket.$$(this)&&Wicket.$$('id2ee')}.bind(this));;; return false;" value="Apply"
name="filtersContainer:applyRuleButton">
I'm trying to click it and have tried pretty much everything for 2 days, webdriver does not find the element, IDE does find it:
//This was my first approach, it should work.
It works in IDE, but not Webdriver:
driver.findElement(By.id("applyRuleButton")).click();
//then perhaps this should do the trick, hint: It doesn't:
WebElement element3 = driver.findElement(By.id("applyRuleButton"));
JavascriptExecutor executor3 = (JavascriptExecutor)driver;
executor3.executeScript("arguments[0].click();", element3);
Ok, Id not working, I get it.
Then this should work at least:
driver.findElement(By.xpath("//table/tbody/tr/td/div/div/table/tbody/tr[6]/td/input[#id='applyRuleButton']")).click();
It feels like I am missing something obvious here, some help please?
Additional information:
I have added a 5 second wait, the page is completely loaded.
This button is located in a table:
The Xpath is
/html/body/div[4]/div[2]/form/div[3]/div/div/table/tbody/tr/td/div/div/table/tbody/tr[6]/td/input
Webdriver error, no matter what I throw at it, is: Unable to locate element
I have used both 'click' and 'submit', still no success.
I think in this case there are two possibilities :
Either there is another element having same id/xpath.
OR Element present in another iframe.
Is the button visible. Selenium click (latest firefox 26 and latest webdriver 2.39.0) does not sometimes implicitly scroll; Or it may not scroll it fully. So scroll it into view - Scroll Element into View with Selenium and then it should work.
Note Selenium Best Practise try to use By.Id,By.CSSSelector and if nothing gets use By.Xpath in the order of priority. ( Use the FireFinder, FireBug plugin to test XPath or CSS)
This might be a synchronization issue. Such issues can be solved using smart waits.
new WebDriverWait(driver, TimeSpan.FromSeconds(10)).Until(ExpectedConditions.ElementExists((By.Id("applyRuleButton"))));
WebElement element3 = driver.findElement(By.id("applyRuleButton"));
And that should work perfectly fine.
There is absolutely nothing wrong with your selector. I just don't think you're invoking the click correctly.
Try:
driver.findElement(By.id("applyRuleButton")).click();
If this doesn't work, then you might have to invoke a WebDriverWait since you have this question marked as [ajax]
Could you post the entire html?
As a simple experiment, I took the html snippet that you posted and wrote a short python script that invokes selenium:
from selenium import webdriver
br = webdriver.Firefox()
br.get("put your path to snippet here")
button = br.find_element_by_id("applyRuleButton")
print button.get_attribute("name")
button.click()
br.close()
I can find the button and extract the attribute "name" which prints "filtersContainer:applyRuleButton". This is admittedly a very limited experiment, but it suggests that the issue is related to not being where you think you are on the page.
Try this:
driver.findElement(By.Name("filtersContainer:applyRuleButton"));
If this doesn't help, check whether this button is located in any other frame. If so, you may have to find and move your focus to that frame and then locate this button.
First try to identify the button by writting correct xpath using firebug, if you are able to identify button by that xpath then use that xpath while writing your script.
driver.findElement(By.xpath("//input[# type='submit' and # id='applyRuleButton'")).click();
This is ajax application use proper explicit/ webdriver wait till the button gets downloaded
I see that this thread is old, but I was looking at it today (Sept/2021) as I was having the same problem: I could see the name / id/ type of the button, but it would never be found.
I discovered that when I had clicked in a prior link, it opened a new tab in my browser, but Selenium did not change the focus to the new tab, so it couldn't find the ID of the button I was looking for.
I solved it with :
driver.find_element_by_id("export").click() #driver
time.sleep(2)
driver.switch_to.window(driver.window_handles[1]) # Change focus to the new tab
driver.find_element_by_id("0001btn").click() #click
driver.close() #close new tab
switching to a specific frame helped me to resolve the same issue. (python + selenium)
I installed the Selenium Recorder extension on chrome and recorded my steps, and found out that the recorder had a step to select a frame = 0, so adding
self.home_page.driver.switch_to.frame(0)
self.home_page.click_on_element_by_id("clickSubmit")
solved the problem.
I'm trying to use below codes to double-click on a cell in a table in my web application (I tried to do Click two times with the hope that they are equal to double-click). However, the cell is not clicked at all, but I expect that after double-clicking on the cell, the text field will be displayed for me to edit info of that cell.
#driver.find_element(:xpath => "//table[#id='gridabc']//tr[1]/td[9]").click
#driver.find_element(:xpath => "//table[#id='gridabc']//tr[1]/td[9]").click
I'm using Selenium Ruby Webdriver. Please help guide me a way to resolve this. Thanks much.
##example Double click an element
el = driver.find_element(:id, "some_id")
driver.action.double_click(el).perform
Code shamelessly copied from the documentation :)
Can anyone help me? I am looking for a javascript.
I would like to add "?print=yes" in my url like http://mywebsite.com/page1.html?print=yes
Once it is click and completely loaded the window.print() must then work.
How to check the value of a querystring
JavaScript query string
How to print from javascript.
https://www.google.com.au/search?q=javascript+print