Can anyone help me? I am looking for a javascript.
I would like to add "?print=yes" in my url like http://mywebsite.com/page1.html?print=yes
Once it is click and completely loaded the window.print() must then work.
How to check the value of a querystring
JavaScript query string
How to print from javascript.
https://www.google.com.au/search?q=javascript+print
Related
I have a REST Url http://localhost/issues presenting me a search form for querying issues of a bug tracker system. The search form has a textfield with name="f". The action of the form is action="/issues" and the method=GET. So if I type "foobar" into the textfield, I am getting redirected to http://localhost/issues?f=foobar.
To prevent page reload, I use AJAX with jquery. So I used $(document).on('submit',...) to bind an AJAX query function to the submit function of the form. I used firebug to proove, that jquery sends the request and no page reload is taken. I also have a function to fill results of the response into my site presented in the browser. Everything works fine for the first search attempt.
But if I type another search string "anotherfoobar" into the textfield and resend the request, the request URL is http://localhost/issues?f=foobar&f=anotherfoobar, so the search parameter is only appended to the URL, not updatedas I thought it would happen.
I've read about "hashing" the URL parameters to prevent this behaviour here on stackoverflow, but do not fully understand what and why this is happening and what "hashing" means exactly. Perhaps it's not the right solution for me. So I kindly ask someone to explain me how I can solve this.
I've solved it! Don't ask how exactly, what I did was the following:
The AJAX response is the whole Web page as I would get it with a page reload. with jquery I select a div which includes the search form AND the results.
I simply defined a div only for the results, and update only the content of the results div. After doing so, everything works fine, and the results div updates with multiple search attempts.
Another case of not knowing what I do, but I do it fine ;)
Perhaps someone still can explain me my error so wisdom can rise.
var formSerializeArray = $('QDiv').serializeArray();
QDiv contains all the input controls... I have used serializeArray() and serialize() as well... But it is not working... meaning it is returning "null" eventhought the div contains controls.
some one please help me... what am i missing?
It's important to take #Maciej's answer into consideration first.
You should also check if your form elements have a name attribute or else they won't be included when you trigger serialize() or serializeArray().
Source: http://www.mail-archive.com/jquery-en#googlegroups.com/msg32998.html
If you’re using some recent jQuery, make sure you’re using "#" with id selectors, ie.:
var formSerializeArray = $('#QDiv').serializeArray();
I put a Ajax link using the following code:
echo chtml::ajaxLink('GO', 'http://localhost/index.php?r=user/delete', array('method'=>'POST'));
But, regardless of giving the second parameter as URL i,e 'http://localhost/index.php?r=user/delete'. It generates link with the current URL in the browser not the URL I just specified.
What is the issue? How could I create AJAX link? Google several hours but can't solve the issue.
Any kind of help is highly appreciated.
First of all, you should always try and create normalized urls.
But i think your doubt lies in the # that is generated/appended. If you go and check the source of yii ajaxLink you'll see this:
public static function ajaxLink($text,$url,$ajaxOptions=array(),$htmlOptions=array())
{
if(!isset($htmlOptions['href']))
$htmlOptions['href']='#';
$ajaxOptions['url']=$url;
$htmlOptions['ajax']=$ajaxOptions;
self::clientChange('click',$htmlOptions);
return self::tag('a',$htmlOptions,$text);
}
so if you don't set the href property of the a tag in the htmloptions array, the # will be appended.
You should also understand that yii uses jquery, so if you check out the source of the page, you'll see at the bottom, how jquery is used to carry out an ajax request, your actual url that is called will also be seen in that script. So the third option/parameter in ajaxLink is for options for jquery's ajax function. You can create better ajax links using this option.
Regardless of where(which controller) your url points to in your project, the action associated with that url will be called.
So anyway, you can modify your code like this if you want the url to be shown and not a # :
echo CHtml::ajaxLink('GO', 'http://localhost/index.php?r=user/delete',
array('type'=>POST), //there are various other options for jquery ajax
array('href'=>'http://localhost/index.php?r=user/delete'));
To make better ajax links i would suggest going through jquery's ajax documentation. There is an option for a success function, that you can use to let the user know that the operation was completed.
Hope this helps, don't hesitate to leave comments if i haven't answered your question completely.
Have you tried:
echo CHtml::ajaxLink('GO', array('/user/delete'), array('method'=>'POST'));
as the ajaxLink documentation suggests...? Look also at the normalizeUrl method.
Using these methods, which in turn are using createUrl, is usually better since it will take care to create a valid url for your site.
I had the same issue(or maybe similar).
I've used renderPartial to load view and later in that view i was using ajaxLink and it was not working.
What i have found, that when using renderPartial, there was no jquery script for ajax action.
What you have to do is to add 4th argument(true) in renderPartial function to generate jquery script.
See the documentation: http://www.yiiframework.com/doc/api/1.1/CController/#renderPartial-detail
Hope it helps and saves time to figure it out.
After processing a jQuery Ajax Post from an HTML form successfully within a Go program, how do I load a new form? I first tried sending the form as the response and the Javascript displayed it, but it did not clear the old (existing) form. I then tried within the HTML Javascript to set the URL using "window.location = 'localhost:8088/MaintForm/'". That resulted in a warning from the browser but did not load the form and did not change the URL. I would like to ideally know both methods - via the Go program acting as a server, and via Javascript. If I manually change the URL, the form loads OK. What I am trying to do is receive a response in Javascript (jQuery Ajax), and then request the new form if the response is positive. I would prefer to do this without changing the URL. As I said above, this partially worked.
You would have to put your original form inside a tag, for example a div, and use your JQuery code to replace the contents of that tag with the new form. This way you are not changing the URL.
This is more of a javascript/JQuery question than a go-specific one.
In javascript:
location.href = '/MaintForm/';
In golang, you can use the http.Redirect function, like this:
http.Redirect(w, r, "/MaintForm/", http.StatusFound)
Please note: this appears to be solved by : I just need to do an "document.write(data);" in Javascript. "Data" contains the new HTML.
How to use Server.Transfer or Response.Redirect from ajax UpdatePanel?
Without being harsh, it really doesn't make sense to be able to. I think some reading about AJAX would make it clear.
But you could write following to the browser.
<script type="text/javascript">window.location = "URL"</script>
Never mind, i just found out myself
use javascript inside ur Updatepanel like the code below.
c# code:
String TransferPage =
"window.open('Gallery-Page.aspx','_self');";
ScriptManager.RegisterStartupScript(Page,
Page.GetType(), "temp", TransferPage,
false);
Even u can give hyperlink instead of "Gallery-Page.aspx"
Thanks,
Asem Ibohal
UpdatePanel supports Response.Redirect. It works OK for me. What error do you get?