How do I make a Ruby script into a bash command? - ruby

I have a Ruby file, and I run it as ruby file.rb "parameters". I prefer to run it as regtask parameters without having to include ruby and the filename every time. I want it to be on the same level as ls. How would I accomplish this?

Edit your file, make sure this is the first line, so your system knows how to execute your file:
#!/usr/bin/env ruby
Next, change the file's permissions to make it executable:
chmod a+x file.rb
And finally, rename it and move it somewhere where it will be executed without having to write its full path:
mkdir -p ~/bin
mv file.rb ~/bin/regtask
(Most systems will automatically add ~/bin to PATH if it exists; if not, you will have to add it to PATH yourself in your startup files.)

This should help.. Please let me know if you run into any issues.
http://commandercoriander.net/blog/2013/02/16/making-a-ruby-script-executable/
Making a Ruby Script Executable
It's common knowledge in the *nix community, but for many new developers turning a Ruby script into an executable command line program is akin to magic. While there are other references on the internet, for the post here, I will briefly explain how to go from running a Ruby script by invoking Ruby directly, to running the script by its name alone.
We will start by assuming we have a simple Ruby script which prints "hello" on the command line. Our script's name will be greeter.rb. The file holds one line of Ruby code:
puts "Hello!"`
To run the script, we must type ruby greeter.rb. Wouldn't it be nice to just type greeter instead and still get the script to run? Yes, it would.
First, we need to tell Bash what to do with our file since we won't be passing the script to Ruby directly. To do that, we add the following to the very top of our script:
#!/usr/bin/env ruby
puts "Hello!"
The first line is a Bash directive and basically tells Bash what program to run our file with by asking for the current configured version of Ruby as specified by the env command. For more on how env works, try typing man env into the command line.
Second, we need to make our script executable, which requires changing the file permissions. If the concept of file permissions is new, read about it here. Bascially, files have three types of permissions. They can be read, written, and executed. Most files typically start out as only having read and write access. Since we want to execute our script, we're going to have to grant it execute permissions.
Doing that is just a simple Bash command. On the command line, navigate to the directory holding the greeter.rb file. Now, to check the permissions, run:
ls -l greeter.rb
The output will look something like this:
-rw-r--r-- 1 username staff 13 Feb 16 21:10 greeter.rb
Your own username will show up in the place of username, and the creation date will naturally be different, but otherwise the output will be almost identical. The first part of the line is the revelant part. The letters r and w specify read and write permissions.
We're going to add execute permissions which will appear as an x in that line. To add execute permissions, run the following command.
chmod 755 greeter.rb
Now, if you check the file permissions again with ls -l greeter.rb, the output should be a little different.
-rwxr-xr-x 1 username staff 13 Feb 16 21:20 greeter.rb
The presence of x indicates that the file can be run directly without calling Ruby first. The following command should get our file to say "hello."
./greeter.rb
Almost there. Now, we just need to get rid of the prefix ./, which tells Bash where to look for greeter.rb, i.e., in the current directory. Before we complete this last step, though, let's rename our file to just greeter.
mv greeter.rb greeter
Now, for the last step. Everytime we call a Bash program, e.g., ls, chmod, mv, etc., Bash searches through a predefined list of folders looking for those programs. This is called the path. To see what the path is set to on your computer, try:
echo "$PATH"
The output should be a long string of various system-critical folders. We need to put our application into one of these folders. Traditionally, it's best to leave folders like /usr/bin/ and /bin/ alone. Instead, any kind of user additions should be placed in /usr/local/bin/. If that folder doesn't exist, create it with:
mkdir -p /usr/local/bin/
Now, we can either move our greeter into that folder, or leave the application where it is and just create a softlink (or an alias in OS X terms) within the /usr/local/bin/ folder. To create an alias, we'll use the ln command. From the directory where greeter lives, type:
ln -s $PWD/greeter /usr/local/bin/
Note that the $PWD variable will expand to an absolute path to our greeter script. Now, we're done and we can simply type greeter to invoke our Ruby script!
As a footnote, if any of the above Bash commands seem confusing, trying looking up their man page by typing man <command>.

Related

Mistake this is a duplicate [duplicate]

This question already has answers here:
How to obtain the first letter in a Bash variable?
(7 answers)
Closed 3 years ago.
I am trying to my a custom terminal command. I just learned I am supposed to do it using the Unix script? I don't really know much of what that is and am still trying to figure it out. What I do know is that $1 is an arg is it possible to make it a variable and then get the first letter like you could in python?
EX:
str = 'happy'
str[0] = 'h'
You're asking a few different things here.
I am trying to my a custom terminal command.
That could mean a few different things, but the most obvious meaning is that you want to add an executable to your path so that when you type it at the terminal, it runs just like any other executable on your system. This requires just a few things:
the executable permission must be set.
the file must specify how it can be executed. For interpreted programs such as bash scripts or python scripts, you can do so by beginning the file with a "shebang line" that specifies the interpreter for the file.
the file must be in one of the locations specified by your $PATH.
I just learned I am supposed to do it using the Unix script?
there's no such thing as a "unix script", but what you seem to be referring to is a "shell script". Though these are commonly associated with unix, they're no more inherently a unix script than any other language. A shell, such as bash, sh, or any other, is just an interpreted language that is designed so that it is convenient to be used interactively by a human as well as being programmatically executed as part of a saved file.
I don't really know much of what that is and am still trying to figure it out.
Let's get into some specifics.
First I edit a file called 'hello-world' to contain:
#!/bin/bash
echo "Hello, world!"
Note that this filename has no "extension". Though heuristics based on file extension are sometimes used (espeically in windows) to determine a file type, unix typically sees a file "extension" as part of the arbitrary file name. The thing that makes this a potentially executable bash script is the specification of that interpreter on the shebang line.
We can run our script right now from bash, just as we could if we wrote a python script.
$ bash hello-world
hello, world!
To make the bash implicit, we mark the file as executable. This enables the linux operating system to consult the beginning "magic bytes" of the file to determine how to run it. Thes beginning bytes might signify an ELF file (a compiled executable, written in eg C, C++, or go). Or, it might be #! which just so happens means , "read the rest of this first line to determine the command to run, and pass the rest of this file into that command to be interpreted.
$ chmod +x hello-world
ls -l will show us the "permissions" on the file (more accurately called the "file mode", hence chmod rather than chperm) . The x stands for executable, so we have enabled the use of the leading bytes to determine method of execution. Remember, the first two bytes of this file, and the rest of that first line, then specify that this file should be "run through bash" so to speak.
$ ls -l hello-world
-rwxr-xr-x 1 danfarrell staff 33 Dec 27 20:02 hello-world
Now we can run the file from the current directory:
$ ./hello-world
hello, world!
At this point, the only difference between this command and any other on the system, is that you have to specify its location. That's because my current directory is not in the system path. In short, the path (accessible in a unix shell via the $PATH variable) specifies an ordered list of locations that should be searched for a specified command whose location is not otherwise specified.
For example, there's a very common program called whoami. I can run it directly from my terminal without specifying a location of the executable:
$ whoami
danfarrell
This is because there's a location in my $PATH in which the shell was able to find that command. Let's take a closer look. First, here's my path:
$ echo $PATH
/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/go/bin
And there's also a convenient program called whereis which can help show which path elements supply a named executable:
$ whereis whoami
/usr/bin/whoami
Sure enough, whoami is in one of the elements of the $PATH. (Actually I shared a simplified $PATH. Yours might be somewhat longer).
Finally, then, we can get to the last thing. If I put hello-world in one of the $PATH elements, I will be able to invoke it without a path. There are two ways to do this: we can move the executable to a location specified in the path, or we can add a new location to the path. For simplicity's sake I'll choose the first of these.
$ sudo cp hello-world /usr/local/bin/
Password:
I needed to use sudo to write to /usr/local/bin because it's not accessible as my user directly - that's quite standard.
Finally, I've achieved the goal of being able to run my very important program from any location, without specifying the executable's location.
$ hello-world
hello, world!
$ which hello-world
/usr/local/bin/hello-world
It works! I've created what might be described as a "custom terminal command".
What I do know is that $1 is an arg is it possible to make it a variable and then get the first letter like you could in python?
Well, one option would be to simply write the custom terminal command in python. If python is available,
$ which python
/usr/bin/python
You can specify it in a shebang just like a shell can be:
#!/usr/bin/env python
print("hello, world!"[0])
$ hello-world
h
it works!
Okay, confession time. I actually used #!/usr/bin/env python, not /usr/bin/python. env helps find the correct python to use in the user's environment, rather than hard coding one particular python. If you've been using python during the very long running python 2 to python 3 migration, you can no doubt understand why I"m reticent to hard code a python executable in my program.
It's certainly possible to get the first letter of a string in a bash script. But it's also very possible to write a custom command in a program other than shell. Python is an excellent choice for string manipulation, if you know it. I often use python for shell one-liners that need to interact with json, a format that doesn't lend itself well to standard unix tool stream editing.
Anyway, at the expense of incurring SO community's ire by reanswering an "already answered" question, I'll include a version in shell (Credit goes to David C Rankin)
#!/bin/bash
echo "${1:0:1}"
$ hello-world hiworld
h

bash commands to remote hosts - errors with writing local output files

I'm trying to run several sets of commands in parallel on a few remote hosts.
I've created a script that constructs these commands, and then writes the output in a local file, something along the lines of:
ssh <me>#<ip1> "command" 2> ./path/to/file/newFile1.txt & ssh <me>#<ip2>
"command" 2> ./path/to/file/newFile2.txt & ssh <me>#<ip2> "command" 2>
./path/to/file/newFile3.txt; ...(same repeats itself, with new commands and new
file names)...
My issue is that, when my script runs these commands, I am getting the following errors:
bash: ./path/to/file/newFile1.txt: No such file or directory
bash: ./path/to/file/newFile2.txt: No such file or directory
bash: ./path/to/file/newFile3.txt: No such file or directory
...
These files do NOT exist but will be written. That being said, the directory paths are valid.
The strange thing is that, if I copy and paste the whole big command, then it works without any issue. I'd rather have it automated tho ;).
Any ideas?
Edit - more information:
My filesystem is the following:
- home
- User
- Desktop
- Servers
- Outputs
- ...
I am running the bash script from home/User/Desktop/Servers.
The script creates the commands that need to be run on the remote servers. First thing first, the script creates the directories where the files will be stored.
outputFolder="./Outputs"
...
mkdir -p ${outputFolder}/f{fileNumb}
...
The script then continues to create the commands that will be called on remotes hosts, and their respective outputs will be placed in the created directories.
The directories are there. Running the commands gives me the errors, however printing and then copying the commands into the same location works for some reason. I have also tried to give the full path to directory, still same issue.
Hope I've been a bit clearer.
If this is the exact error message you get:
bash: ./path/to/file/newFile1.txt: No such file or directory
Then you'll note that there's an extra space between the colon and the dot, so it's actually trying to open a file called " ./path/to/file/newFile1.txt" (without the quotes).
However, to accomplish that, you'd need to use quotes around the filename in the redirection, as in
something ... 2> " ./path/to/file/newFile1.txt"
Or the first character would have to something else than a regular space. A non-breaking space perhaps, possible something that some editor might create if you hit alt-space or such.
I don't believe you've shown enough to correctly answer the question.
This doesn't look like a problem with ssh, but the way you are calling the (ssh) commands.
You say that you are writing the commands into a file... presumably you are then running that file as a script. Could you show the code you use to do that. I believe that's your problem.
I suspect you have made a false assumption about the way the working directory changes when you run a script. It doesn't. You are listing relative paths, so its important to know what they are relative to. That is the most likely reason for it working when you copy and paste it... You are executing from a different working directory.
I am new to bash scripting and was building my script based on another one I had seen. I was "running" the command by simply calling the variable where the command was stored:
$cmd
Solved by using:
eval $cmd
instead. My bad, should have given the full script from the start.

Changing directory for User in Ruby script

I'm quite familiar with Dir.chdir("/xyz")
Unfortunately, this changes the directory of the process, but not actually the directory of the user. I'll make the following example to illustrate my need.
$~/: ruby my_script.rb
CHANGING TO PATH FOR USER NOT SCRIPT
$/Projects/Important/Path: pwd
$/Projects/Important/Path
See? I need the script to change the user's path. Performing system/backticks/Dir.chdir all adjust the process path, and end with the user sitting where they started, instead of the path I want them.
From what I've read exec was the way to go, since it takes over the existing process... but to no avail.
You can't, but you can do something which might be good enough. You can invoke another shell from ruby:
Dir.chdir("/xyz")
system("bash")
Running this will create a new bash process, which will start in the /xyz directory. The downside is that changing this process will bring you back to the ruby script, and assuming it ends right away - back to the bash process that started the ruby script.
Another hack that might work is to use the prompt as a hackish hook that will be called after each command. In the ruby script, you can write the new directory's path somewhere that can be read from both bash and ruby(for example a file - but not an environment variable!). In the PROMPT_COMMAND function, you check that file and cd to what's written there. Just make sure you delete that file, so you don't get automatically cded there after every command you run.

Running bash shell in Maemo

I have attempted to run the following bash script on my internet tablet (Nokia N810 running on Maemo Linux). However, it doesn't seem that it is running, and I have no clue of what's wrong with this script (it runs on my Ubuntu system if I change the directories). It would be great to receive some feedback on this or similar experiences of this issue. Thanks.
WORKING="/home/user/.gpe"
SVNPATH="/media/mmc1/gpe/"
cp calendar categories contacts todo $WORKING
What actually happens when you run your script? It's helpful if you include details of error messages or behavior that differs from what's expected and in what way.
If $WORKING contains the name of a directory, hidden or not, then the cp should copy those four files into it. Then ls -l /home/user/.gpe should show them plus whatever else is in there, regardless of whether it's "hidden".
By the way, the initial dot in a file or directory name doesn't really "hide" the entry, it's just that ls and echo * and similar commands don't show them, while these do:
ls -la
ls -d .*
ls -d {.*,*}
echo .*
echo {.*,*}
The bash cp command can copy multiple sources to a single destination, if it's a directory.
Does the directory /home/user/.gpe exist?
Bear in mind that the leading dot in the name can make it hidden unless you use ls -a
I tried your commands in cygwin:
But I used .gpe instead of /home/user/.gpe
I did a touch calendar categories contacts todo to create the files.
It worked fine.
If that's the entirety of your script, it's missing two. possible three, things:
A shebang line, such as #!/bin/sh at the start
Use of $SVNPATH. You probably want to cd $SVNPATH before the cp command. Your script should not assume the current working directory is correct.
Possibly execute permission on the script: chmod a+x script
Do you already have the /home/user/.gpe directory present? And also, try adding a -R parameter so that the directories are copied recursively.

run command in parent shell from ruby

I'm trying to change the directory of the shell I start the ruby script form via the ruby script itself...
My point is to build a little program to manage favorites directories and easily change among them.
Here's what I did
#!/usr/bin/ruby
Dir.chdir("/Users/luca/mydir")
and than tried executing it in many ways...
my_script (this doesn't change the directory)
. my_script (this is interpreted as bash)
. $(ruby my_script) (this is interpreted as bash too!)
any idea?
Cannot be done. Child processes cannot modify their parents environment (including the current working directory of the parent). The . (also known as source) trick only works with shell scripts because you are telling the shell to run that code in the current process (rather than spawning a subprocess to run it). Just for fun try putting exit in a file you run this way (spoiler: you will get logged out).
If you wish to have the illusion of this working you need to create shell functions that call your Ruby script and have the shell function do the actual cd. Since the functions run in the current process, they can change the directory. For instance, given this ruby script (named temp.rb):
#!/usr/bin/ruby
print "/tmp";
You could write this BASH function (in, say, you ~/.profile):
function gotmp {
cd $(~/bin/temp.rb)
}
And then you could say gotmp at the commandline and have the directory be changed.
#!/usr/bin/env ruby
`../your_script`
Like this?
Or start your script in the directory you want it to do something.
Maybe I don't get your question. Provide some more details.

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