Mapping of oneToMany with composite key using eclipselink gives me ORA-01400 - oracle

I am trying to map the classic bi-directional oneToMany using eclipselink.
My problem is that when i want to insert a new 'child' i get
SQLIntegrityConstraintViolationException.
The database is described like this :
#Entity
#IdClass(KuponPK.class)
#Table(name = "KUPON", schema = "POST", catalog = "")
public class Kupon implements Serializable {
private Integer id;
private String spil;
private Collection<Kombination> kombinationList;
#OneToMany(mappedBy = "kupon", cascade = CascadeType.PERSIST)
public Collection<Kombination> getKombinationList() {
return kombinationList;
}
public class KuponPK implements Serializable {
private Integer id;
private String spil;
#Id
#Column(name = "ID", nullable = false, insertable = true, updatable = true, precision = 0)
public Integer getId() {
return id;
}
#Id
#Column(name = "SPIL", nullable = false, insertable = true, updatable = true, length = 5)
public String getSpil() {
return spil;
}
#Entity
#Table(name = "KOMBINATION", schema = "POST", catalog = "")
public class Kombination {
private Integer id;
private String sorteringOrden;
private Integer sorteringNr;
private Integer antalSpillede;
private BigDecimal odds;
private Kupon kupon;
#ManyToOne
#JoinColumns({#JoinColumn(name = "KUPON_ID", referencedColumnName = "ID", nullable = false, insertable=false, updatable=false),
#JoinColumn(name = "KUPON_SPIL", referencedColumnName = "SPIL", nullable = false, insertable=false, updatable=false)})
public Kupon getKupon() {
return kupon;
}
In my stateless session i have a Kupon object and i create a new Kombination where i set the Kupon and try to merge, but im getting
Internal Exception: java.sql.SQLIntegrityConstraintViolationException: ORA-01400: cannot insert NULL into ("KOMBINATION"."KUPON_ID")
which is obvious since its part of primary key
I am setting the Kombination to Kupon and the Kupon to Kombination, but that doesnt make any difference
How can can i tell that the key is inside the Kupon object which im setting in the Kombination object ??

Related

#JoinColumn "occurs out of order" when upgrading to spring-boot-3 (Hibernate 6 )

I have the following usage in JoinColumns
#Entity
public class EntityOne{
private String action;
private String type;
#ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
#NotFound(action = NotFoundAction.IGNORE)
#JoinColumns({
#JoinColumn(name = "action", referencedColumnName = "action_name", updatable = false, insertable = false),
#JoinColumn(name = "type", referencedColumnName = "type_name", updatable = false, insertable = false)
})
private Entitytwo entitytwo;
}
And
#Entity
public class EntityTwo {
#Id
#Column(name = "type_name")
private String typeName;
#Id
#Column(name = "action_name")
private String actionName;
}
This setup causes hibernate error of
Referenced column '" + column.getName()
+ "' mapped by target property '" + property.getName()
+ "' occurs out of order in the list of '#JoinColumn's
If i change the order inside the #JoinColumns it seems to work, but can stop working at the next time the application starts.
The hibernate comments at the begining of the relevant code states:
// Now we need to line up the properties with the columns in the
// same order they were specified by the #JoinColumn annotations
// this is very tricky because a single property might span
// multiple columns.
// TODO: For now we only consider the first property that matched
// each column, but this means we will reject some mappings
// that could be made to work for a different choice of
// properties (it's also not very deterministic)
And on the relevant code itself:
// we have the first column of a new property
orderedProperties.add( property );
if ( property.getColumnSpan() > 1 ) {
if ( !property.getColumns().get(0).equals( column ) ) {
// the columns have to occur in the right order in the property
throw new AnnotationException("Referenced column '" + column.getName()
+ "' mapped by target property '" + property.getName()
+ "' occurs out of order in the list of '#JoinColumn's");
}
currentProperty = property;
lastPropertyColumnIndex = 1;
}
How should i set the #JoinColumn for it to consistently work?
If the action and type attributes of EntityOne are meant to refer to the corresponding attributes of EntityTwo, they are useless and misleading.
The attribute private Entitytwo entitytwo is enough to design the #ManytoOne relation.
Remove these two attributes and if you need to get the action and type value of the entityTwo linked to an entityOne, simply use entityOne.entitytwo.getAction() (or entityOne.entitytwo.getType()).
I just tried the code you posted in Hibernate 6.1, and I observed no error. Even after permuting various things, still no error. So then to make things harder, I added a third column to the FK and tried permuting things. Still no error.
I now have:
#Entity
public class EntityOne {
#Id #GeneratedValue
Long id;
String action;
String type;
int count;
#ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
#NotFound(action = NotFoundAction.IGNORE)
#JoinColumns({
#JoinColumn(name = "count", referencedColumnName = "count", updatable = false, insertable = false),
#JoinColumn(name = "action", referencedColumnName = "action_name", updatable = false, insertable = false),
#JoinColumn(name = "type", referencedColumnName = "type_name", updatable = false, insertable = false),
})
EntityTwo entitytwo;
}
#Entity
public class EntityTwo {
#Id
#Column(name = "type_name")
String typeName;
#Id
#Column(name = "count")
int count;
#Id
#Column(name = "action_name")
String actionName;
}
and the test code:
#DomainModel(annotatedClasses = {EntityOne.class, EntityTwo.class})
#SessionFactory
public class BugTest {
#Test
public void test(SessionFactoryScope scope) {
scope.inTransaction( session -> {
EntityOne entityOne = new EntityOne();
entityOne.action = "go";
entityOne.type = "thing";
EntityTwo entityTwo = new EntityTwo();
entityTwo.actionName = "go";
entityTwo.typeName = "thing";
entityOne.entitytwo = entityTwo;
session.persist( entityOne );
} );
}
}
Perhaps there's something you're not telling us? Like, for example, something to do with the #Id of EntityOne which is missing in your original posted code?
Just in case, also tried this variation:
#Entity
public class EntityOne {
#Id
String action;
#Id
String type;
#Id
int count;
#ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
#NotFound(action = NotFoundAction.IGNORE)
#JoinColumns({
#JoinColumn(name = "action", referencedColumnName = "action_name", updatable = false, insertable = false),
#JoinColumn(name = "count", referencedColumnName = "count", updatable = false, insertable = false),
#JoinColumn(name = "type", referencedColumnName = "type_name", updatable = false, insertable = false),
})
EntityTwo entitytwo;
}
But still no error.

Spring data rest ManyToMany mapping PUT/update operation is not replacing the nested object

I started to learn spring data rest. I'm doing PUT operation and it's not working for the nested objects for ManyToMany relationship, whereas it works fine for OneToMany relation.
Entities structures:
#Table(name="CONFIG_DTLS",schema = "app_txn")
#Entity
public class Config {
#Id
#GenericGenerator(name = "UUIDGenerator", strategy = "uuid2")
#GeneratedValue(generator = "UUIDGenerator")
#Column(name = "ID", updatable = false, nullable = false)
private UUID id;
#Column(name = "NAME", nullable = false, length = 75)
private String name;
/*Unable to replace the data in the MBR_CONFIG_MAPPING table in the put operation.
When the control comes to #HandleBeforeSave annotated method in PUT operation,
the request data contains the existing Member info instead of the one which i'm passing in the PUT request body */
#ManyToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE},fetch = FetchType.EAGER)
#JoinTable(schema = "app_txn", name = "MBR_CONFIG_MAPPING",
joinColumns ={#JoinColumn(name="CONFIG_ID",referencedColumnName = "ID")},
inverseJoinColumns = {#JoinColumn(name="MBR_ID",referencedColumnName = "ID")}
)
private Set<Member> members;
//able to replace the notifications completely in PUT operation
#OneToMany(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "CONFIG_ID",referencedColumnName = "ID")
private Set<Notification> notifications;
}
Member.java
#Table(name="MBR_DTLS",schema = "app_txn")
#Entity
public class Member {
#Id
#GenericGenerator(name = "UUIDGenerator", strategy = "uuid2")
#GeneratedValue(generator = "UUIDGenerator")
#Column(name = "ID", updatable = false, nullable = false)
private UUID id;
#Column(name = "OTHER_MBR_DATA", updatable = false)
private String otherMbrData;
}
Notification.java
#Table(name="NOTIFICATIONS",schema = "app_txn")
#Entity
public class Notification {
#Id
#GenericGenerator(name = "UUIDGenerator", strategy = "uuid2")
#GeneratedValue(generator = "UUIDGenerator")
#Column(name = "ID", updatable = false, nullable = false)
private UUID id;
#Column(name="LEVEL")
private String level;
#Column(name="EMAIL")
private String email;
}
Interfaces:
#RepositoryRestResource(collectionResourceRel = "configs", path="configs")
public interface ConfigRepo extends PagingAndSortingRepository<Config,UUID> {
}
#RepositoryRestResource(exported=false) // don't want to users to manipulate it directly.
public interface MemberRepo extends PagingAndSortingRepository<Member,Object> {
}
Here I don't want to add or modify anything in the MBR_DTLS table as it is loaded by another backend process. I want to update only the mapping details MBR_CONFIG_MAPPING table whenever user does the PUT/update operation. POST/create operation is working fine. Please share your thoughts on how to fix this and if you have any questions add it in the comment section.
PS: I referred some links online but that does not help much - Spring Data REST - PUT request does not work properly since v.2.5.7

Is there any way to delete entities from child entity using JPA?

I have 3 tables Table A, B, C. Table A is associated #OneToMany with Table B. Table B is associated #ManyToOne with Table C. Now when I find by Id of Table A, I am able to get details of A,B,C. But when I persist / delete, It is affecting only Table A&B. Table C is unaffected.
Is this possible in JPA to delete entities from child entity? Googled lot, but could not find any clue.
Below are the entity models of all the three tables
#Entity
#Table(name = "FEATUREMASTER")
#JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
public class FeatureMaster implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
#Id
#Column(name = "FGID")
private String featureid;
#Column(name = "FEATURENAME", nullable = false, unique = false)
private String featurename;
#Column(name = "DESCRIPTION", nullable = true, unique = false)
private String description;
#Column(name = "LIBNAME", nullable = true, unique = false)
private String libname;
#Column(name = "ISENABLED", nullable = false, unique = false)
private String isenabled;
#Column(name = "EDRULEGRP", nullable = true, unique = false)
private String edrulegrp;
// Do Not use - [orphanRemoval = true & CascadeType.ALL]- If used, deletion is not happening
#OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE})
#JoinColumn(name = "FGID")
private List<CfgMaster> parameters;
// Getters and Setters
}
#Entity
#Table(name = "CFGMASTER")
public class CfgMaster implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
#EmbeddedId
private CfgMasterPK id;
#Column(name = "CONFIGNAME", length = 45, nullable = true, unique = false)
private String parameter_name;
#Column(name = "CONFIGTYPE", length = 20, nullable = true, unique = false)
private String type;
#Column(name = "SUBPARAM", nullable = true, unique = false)
private Integer subparam;
#Column(name = "CONFIGDESCRIPTION", nullable = true, unique = false)
private String description;
#Column(name = "CONFIGLIMITFROM", nullable = true, unique = false)
private String from;
#Column(name = "CONFIGLIMITTO", nullable = true, unique = false)
private String to;
#ManyToOne(cascade = {CascadeType.ALL}, optional = true, fetch = FetchType.LAZY )
// #ManyToOne(cascade = {CascadeType.PERSIST, CascadeType.MERGE}, fetch = FetchType.LAZY)
#NotFound(action=NotFoundAction.IGNORE) // This is required to handle when no CfgData is found
#JoinColumns({
#JoinColumn(name = "FGID", insertable = false, updatable = false),
#JoinColumn(name = "DATAKEY", insertable = false, updatable = false)
})
private CfgData cfgData;
//Getters and Setters
}
#Entity
#Table(name = "CFGDATA")
public class CfgData implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
/*#EmbeddedId
private CfgDataPK id;*/
#Id
#Column(name = "FGID")
private String fgid;
#Id
#Column(name = "DATAKEY")
private String datakey;
#Column(name = "EPID", nullable = false, unique = false)
private int epid;
#Column(name = "RESERVED1", length = 45, nullable = true, unique = false)
private String reserved1;
#Column(name = "VALUE1", length = 100, nullable = true, unique = false)
private String value1;
#Column(name = "VALUE2", length = 100, nullable = true, unique = false)
private String value2;
//Getters and Setters
}
The problem I am facing is, I am not able to delete/save the entities of CfgData by passing FeatureMaster's primary id. Any operation I do is affecting only parent &child, not the grand child (CfgData) I tried a lot googling, but I cant find the solution.

JPA Hibernate MapsId for grand child

I am trying to save an entity in JPA 2.1.
I have three tables - MVCollection, MVCollectionVersion (which is versions of MVCollection) and MVBelongsCollection(which is the items belonging to a version).
The Primary Key of MVCollection is a generated sequence number.
When I generate a collection with a version (without any items) I am using #MapsId, and the ID generated is used within the child. However I cannot seem to understand how I can replicate this with the items.
Here are snippets from the code so far :
#Entity
public class MVCollection {
#GeneratedValue(strategy = GenerationType.SEQUENCE,
generator = "MVCOLLECTION_SEQ")
#SequenceGenerator(name = "MVCOLLECTION_SEQ",
sequenceName = "VMD.MVCOLLECTION_SEQ")
#Id
#Column(name = "MVCOLLECTIONID")
private Long id;
MVCollectionVersion
#Entity
public class MVCollectionVersion {
#EmbeddedId
#AttributeOverrides({
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID")) })
private MVCollectionVersionId id;
#ManyToOne(fetch = FetchType.EAGER)
#JoinColumns({
#JoinColumn(name = "MVCOLLECTIONID", referencedColumnName = "MVCOLLECTIONID"),
})
#MapsId("mvCollectionId")
private MVCollection mvCollection;
#OneToMany(fetch = FetchType.LAZY, mappedBy="mvCollectionVersion", cascade={CascadeType.MERGE, CascadeType.PERSIST})
private List<MVBelongsCollection> mvCollectionItems;
MVCollectionId
#Embeddable
public class MVCollectionVersionId implements java.io.Serializable {
/**
*
*/
private static final long serialVersionUID = 2551937096790427792L;
private Long mvCollectionId;
private Integer versionId;
MVBelongsCollection
#Entity
public class MVCollectionItems
#EmbeddedId
#AttributeOverrides({
#AttributeOverride(name = "managedViewId", column = #Column(name = "MANAGEDVIEWID")),
#AttributeOverride(name = "mvCollectionId", column = #Column(name = "MVCOLLECTIONID")),
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID")) })
private MVBelongsCollectionId id;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumns({
#JoinColumn(name = "MVCOLLECTIONID", referencedColumnName = "MVCOLLECTIONID"),
#JoinColumn(name = "MVCVSNID", referencedColumnName = "MVCVSNID") })
private MVCollectionVersion mvCollectionVersion;
and finally MVBelongsCollectionId
#Embeddable
public class MVBelongsCollectionId implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
#Column ( name = "MANAGEDVIEWID", nullable = false, precision = 38)
private Long managedViewId;
#Column ( name = "MVCOLLECTIONID", nullable = false, precision = 38)
private Long mvCollectionId;
#Column ( name = "MVCVSNID", nullable = false, precision = 38)
private Integer versionId;
if I try to create a collection with a version and with belongsCollection items, the create fails as it states the mvCollectionId field is null
"ORA-01400: cannot insert NULL into ("VMD"."MVBELONGSCOLLECTION"."MVCOLLECTIONID")"
Therefore I tried to add #MapsId as I had done with MVCollectionVersion.
public class MVBelongsCollection {
/**
* primary key
*/
#EmbeddedId
#AttributeOverrides({
#AttributeOverride(name = "managedViewId", column = #Column(name = "MANAGEDVIEWID")),
//#AttributeOverride(name = "mvCollectionId", column = #Column(name = "MVCOLLECTIONID")),
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID")) })
private MVBelongsCollectionId id;
/**
* collection that this joins to.
*/
#ManyToOne(fetch = FetchType.LAZY)
#MapsId("mvCollectionId")
#JoinColumns({
#JoinColumn(name = "MVCOLLECTIONID", referencedColumnName = "MVCOLLECTIONID"),
#JoinColumn(name = "MVCVSNID", referencedColumnName = "MVCVSNID") })
private MVCollectionVersion mvCollectionVersion;
However in Eclipse, this shows an error on the #ManyToOne Annotation of
The type of the ID mapped by the relationship 'mvCollectionVersion' does not agree with the primary key class of the target entity.
If I start the process, I get
Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: MVBelongsCollection column: MVCVSNID (should be mapped with insert="false" update="false")
I have tried adding insertable = false, and updatable = false to my #JoinColumn, the #AttributeOVerride and the underlying ID class but still get the same error.
This only happens when the #MapsId is present.
I am now at a loss how I get the MVBelongsCollection to use the generated MVCollectionId, or how I can stop both the eclipse and the runtime error.
If anyone can help I would be grateful.
Thanks in advance
I found the error of my ways...
I needed to use the same embeddedId throughout.
Therefore the MVBelongsCollectionId needed to change to include the embedded id of the parent class:
#Embeddable
public class MVBelongsCollectionId implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
#Embedded
#AttributeOverrides( {
#AttributeOverride(name = "mvCollectionId", column = #Column(name = "MVCOLLECTIONID", nullable = false, precision = 38, scale = 0)),
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID", nullable = false, precision = 8, scale = 0))
})
MVCollectionVersionId collectionVersionId;
#Column ( name = "MANAGEDVIEWID", nullable = false, precision = 38)
private Long managedViewId;
....

null id generated for composite PK

I have the following tables and the following relationship table too: , which has a composite PK as follow:
UserRole.java
#RooJavaBean
#RooJpaEntity(identifierType = UserRolePK.class, versionField = "", table = "UserRole", schema = "dbo")
#RooDbManaged(automaticallyDelete = true)
#RooToString(excludeFields = { "idApplication", "idRole", "idUserName" })
public class UserRole {
}
UserRole_Roo_DbManaged.aj
#ManyToOne
#JoinColumn(name = "IdApplication", referencedColumnName = "IdApplication", nullable = false, insertable = false, updatable = false)
private Application UserRole.idApplication;
#ManyToOne
#JoinColumn(name = "IdRole", referencedColumnName = "IdRole", nullable = false, insertable = false, updatable = false)
private Role UserRole.idRole;
#ManyToOne
#JoinColumn(name = "IdUserName", referencedColumnName = "IdUserName", nullable = false, insertable = false, updatable = false)
private Users UserRole.idUserName;
But also exist a PK table:
#RooIdentifier(dbManaged = true)
public final class UserRolePK {}
And its identifier class (UserRolePK_Roo_Identifier.aj)
privileged aspect UserRolePK_Roo_Identifier {
declare #type: UserRolePK: #Embeddable;
#Column(name = "IdRole", nullable = false)
private Long UserRolePK.idRole;
#Column(name = "IdUserName", nullable = false, length = 16)
private String UserRolePK.idUserName;
#Column(name = "IdApplication", nullable = false)
private Long UserRolePK.idApplication;
The way how I'm setting the service objec to save is:
UserRole userRole= new UserRole();
userRole.setIdApplication(app);
userRole.setIdRole(invited);
userRole.setIdUserName(user);
appService.saveURole(userRole);
app has been set and saved before (same transaction), as well as invited and user objects.
Since user (from Users table with composite PK: IdUserName which is a String ), is defined as follow, otherwise doesnt work.
#RooJavaBean
#RooJpaEntity(versionField = "", table = "Users", schema = "dbo")
#RooDbManaged(automaticallyDelete = true)
#RooToString(excludeFields = { "quotations", "taxes", "userRoles", "idCompany", "idPreferredLanguage" })
public class Users {
#Id
//#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "IdUserName", length = 16, insertable = true, updatable = true)
private String idUserName;
}
So, the error that I'm getting is:
org.springframework.orm.jpa.JpaSystemException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole; nested exception is javax.persistence.PersistenceException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole
Try this:
public class UserRole {
#PrePersist
private void prePersiste() {
if (getId() == null) {
UserRolePK pk = new UserRolePK();
pk.setIdApplication(getIdApplication());
pk.setIdRole(getIdRole);
pk.setIdUserName(getIdUserName());
setId(pk);
}
}
}
Roo is generating the fields on UserRole entity and its id embedded class, but is not the same thing (UserRole.idRole is not the same than UserRole.id.idRole). In your example, you fill the UserRole fields, but not the id fields. This code makes it for you before entity is persisted.
Good luck!
In my case if the follow example tries to be persisted in DB, then similar Exception mentioned above is thrown:
EntityExample e = new EntityExample();
repositoryExample.save(e);
//throw ex
This is caused due to missing id field values which needs to be set something like that:
EntityExample e = new EntityExample();
e.setId(new EmbeddedIdExample(1, 2, 3));
repositoryExample.save(e);

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