null id generated for composite PK - spring

Question

I have the following tables and the following relationship table too: , which has a composite PK as follow:
UserRole.java
#RooJavaBean
#RooJpaEntity(identifierType = UserRolePK.class, versionField = "", table = "UserRole", schema = "dbo")
#RooDbManaged(automaticallyDelete = true)
#RooToString(excludeFields = { "idApplication", "idRole", "idUserName" })
public class UserRole {
}
UserRole_Roo_DbManaged.aj
#ManyToOne
#JoinColumn(name = "IdApplication", referencedColumnName = "IdApplication", nullable = false, insertable = false, updatable = false)
private Application UserRole.idApplication;
#ManyToOne
#JoinColumn(name = "IdRole", referencedColumnName = "IdRole", nullable = false, insertable = false, updatable = false)
private Role UserRole.idRole;
#ManyToOne
#JoinColumn(name = "IdUserName", referencedColumnName = "IdUserName", nullable = false, insertable = false, updatable = false)
private Users UserRole.idUserName;
But also exist a PK table:
#RooIdentifier(dbManaged = true)
public final class UserRolePK {}
And its identifier class (UserRolePK_Roo_Identifier.aj)
privileged aspect UserRolePK_Roo_Identifier {
declare #type: UserRolePK: #Embeddable;
#Column(name = "IdRole", nullable = false)
private Long UserRolePK.idRole;
#Column(name = "IdUserName", nullable = false, length = 16)
private String UserRolePK.idUserName;
#Column(name = "IdApplication", nullable = false)
private Long UserRolePK.idApplication;
The way how I'm setting the service objec to save is:
UserRole userRole= new UserRole();
userRole.setIdApplication(app);
userRole.setIdRole(invited);
userRole.setIdUserName(user);
appService.saveURole(userRole);
app has been set and saved before (same transaction), as well as invited and user objects.
Since user (from Users table with composite PK: IdUserName which is a String ), is defined as follow, otherwise doesnt work.
#RooJavaBean
#RooJpaEntity(versionField = "", table = "Users", schema = "dbo")
#RooDbManaged(automaticallyDelete = true)
#RooToString(excludeFields = { "quotations", "taxes", "userRoles", "idCompany", "idPreferredLanguage" })
public class Users {
#Id
//#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "IdUserName", length = 16, insertable = true, updatable = true)
private String idUserName;
}
So, the error that I'm getting is:
org.springframework.orm.jpa.JpaSystemException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole; nested exception is javax.persistence.PersistenceException: org.hibernate.id.IdentifierGenerationException: null id generated for:class com.domain.UserRole

Answer 1

Try this:
public class UserRole {
#PrePersist
private void prePersiste() {
if (getId() == null) {
UserRolePK pk = new UserRolePK();
pk.setIdApplication(getIdApplication());
pk.setIdRole(getIdRole);
pk.setIdUserName(getIdUserName());
setId(pk);
}
}
}
Roo is generating the fields on UserRole entity and its id embedded class, but is not the same thing (UserRole.idRole is not the same than UserRole.id.idRole). In your example, you fill the UserRole fields, but not the id fields. This code makes it for you before entity is persisted.
Good luck!

Answer 2

In my case if the follow example tries to be persisted in DB, then similar Exception mentioned above is thrown:
EntityExample e = new EntityExample();
repositoryExample.save(e);
//throw ex
This is caused due to missing id field values which needs to be set something like that:
EntityExample e = new EntityExample();
e.setId(new EmbeddedIdExample(1, 2, 3));
repositoryExample.save(e);