JPA Hibernate MapsId for grand child - spring

Question

I am trying to save an entity in JPA 2.1.
I have three tables - MVCollection, MVCollectionVersion (which is versions of MVCollection) and MVBelongsCollection(which is the items belonging to a version).
The Primary Key of MVCollection is a generated sequence number.
When I generate a collection with a version (without any items) I am using #MapsId, and the ID generated is used within the child. However I cannot seem to understand how I can replicate this with the items.
Here are snippets from the code so far :
#Entity
public class MVCollection {
#GeneratedValue(strategy = GenerationType.SEQUENCE,
generator = "MVCOLLECTION_SEQ")
#SequenceGenerator(name = "MVCOLLECTION_SEQ",
sequenceName = "VMD.MVCOLLECTION_SEQ")
#Id
#Column(name = "MVCOLLECTIONID")
private Long id;
MVCollectionVersion
#Entity
public class MVCollectionVersion {
#EmbeddedId
#AttributeOverrides({
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID")) })
private MVCollectionVersionId id;
#ManyToOne(fetch = FetchType.EAGER)
#JoinColumns({
#JoinColumn(name = "MVCOLLECTIONID", referencedColumnName = "MVCOLLECTIONID"),
})
#MapsId("mvCollectionId")
private MVCollection mvCollection;
#OneToMany(fetch = FetchType.LAZY, mappedBy="mvCollectionVersion", cascade={CascadeType.MERGE, CascadeType.PERSIST})
private List<MVBelongsCollection> mvCollectionItems;
MVCollectionId
#Embeddable
public class MVCollectionVersionId implements java.io.Serializable {
/**
*
*/
private static final long serialVersionUID = 2551937096790427792L;
private Long mvCollectionId;
private Integer versionId;
MVBelongsCollection
#Entity
public class MVCollectionItems
#EmbeddedId
#AttributeOverrides({
#AttributeOverride(name = "managedViewId", column = #Column(name = "MANAGEDVIEWID")),
#AttributeOverride(name = "mvCollectionId", column = #Column(name = "MVCOLLECTIONID")),
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID")) })
private MVBelongsCollectionId id;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumns({
#JoinColumn(name = "MVCOLLECTIONID", referencedColumnName = "MVCOLLECTIONID"),
#JoinColumn(name = "MVCVSNID", referencedColumnName = "MVCVSNID") })
private MVCollectionVersion mvCollectionVersion;
and finally MVBelongsCollectionId
#Embeddable
public class MVBelongsCollectionId implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
#Column ( name = "MANAGEDVIEWID", nullable = false, precision = 38)
private Long managedViewId;
#Column ( name = "MVCOLLECTIONID", nullable = false, precision = 38)
private Long mvCollectionId;
#Column ( name = "MVCVSNID", nullable = false, precision = 38)
private Integer versionId;
if I try to create a collection with a version and with belongsCollection items, the create fails as it states the mvCollectionId field is null
"ORA-01400: cannot insert NULL into ("VMD"."MVBELONGSCOLLECTION"."MVCOLLECTIONID")"
Therefore I tried to add #MapsId as I had done with MVCollectionVersion.
public class MVBelongsCollection {
/**
* primary key
*/
#EmbeddedId
#AttributeOverrides({
#AttributeOverride(name = "managedViewId", column = #Column(name = "MANAGEDVIEWID")),
//#AttributeOverride(name = "mvCollectionId", column = #Column(name = "MVCOLLECTIONID")),
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID")) })
private MVBelongsCollectionId id;
/**
* collection that this joins to.
*/
#ManyToOne(fetch = FetchType.LAZY)
#MapsId("mvCollectionId")
#JoinColumns({
#JoinColumn(name = "MVCOLLECTIONID", referencedColumnName = "MVCOLLECTIONID"),
#JoinColumn(name = "MVCVSNID", referencedColumnName = "MVCVSNID") })
private MVCollectionVersion mvCollectionVersion;
However in Eclipse, this shows an error on the #ManyToOne Annotation of
The type of the ID mapped by the relationship 'mvCollectionVersion' does not agree with the primary key class of the target entity.
If I start the process, I get
Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: MVBelongsCollection column: MVCVSNID (should be mapped with insert="false" update="false")
I have tried adding insertable = false, and updatable = false to my #JoinColumn, the #AttributeOVerride and the underlying ID class but still get the same error.
This only happens when the #MapsId is present.
I am now at a loss how I get the MVBelongsCollection to use the generated MVCollectionId, or how I can stop both the eclipse and the runtime error.
If anyone can help I would be grateful.
Thanks in advance

Answer 1

I found the error of my ways...
I needed to use the same embeddedId throughout.
Therefore the MVBelongsCollectionId needed to change to include the embedded id of the parent class:
#Embeddable
public class MVBelongsCollectionId implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
#Embedded
#AttributeOverrides( {
#AttributeOverride(name = "mvCollectionId", column = #Column(name = "MVCOLLECTIONID", nullable = false, precision = 38, scale = 0)),
#AttributeOverride(name = "versionId", column = #Column(name = "MVCVSNID", nullable = false, precision = 8, scale = 0))
})
MVCollectionVersionId collectionVersionId;
#Column ( name = "MANAGEDVIEWID", nullable = false, precision = 38)
private Long managedViewId;
....