$options = table::join('table1', function($join) {
$join->on('table1.table_id','=','table.id');
$join->take(1);
})->get();
Is there a way to do this, i get error on take function.
the table and table1 has one to many relation, and i'd like to have on join just the first record of table1.
Thanks
Vincenzo
Related
I have 3 table
This is my first table cart_items .👇🏻
This is my second table ecomm_products.👇🏻
This is my Third table ecomm_sellers.👇🏻
$result = DB::table('cart_items')
->join('ecomm_products','ecomm_sellers',function($join){
$join->on('ecomm_products.id','=','cart_items.product_id')->where('cart_items.order_id','=',1);
$join->on('ecomm_products.seller_id','=','ecomm_sellers.id');
})
->where('cart_items.user_id','=',Auth::user()->id)
->select('ecomm_products.product_name','ecomm_products.showcase_image','ecomm_products.selling_price','cart_items.quantity','cart_items.id')
->get();
But I am getting an error ⛔⛔⛔
strtolower(): Argument #1 ($string) must be of type string, Closure given
When I have not included 3 tables (ecomm_sellers) till the query is running good but when I add it sends me some errors.
The question is: Why I am getting this error and why this query is not working, What else I can add so that my query working fine.
You cannot join two tables in by passing the table names as arguments to join. If you check the API documentation of the join method you can see that its signature is:
$this join(string $table, Closure|string $first, string|null $operator = null, string|null $second = null, string $type = 'inner', bool $where = false)
so you can only join two tables at a time and if you want to join more than two tables you chain another call to the join method.
try this:
$result = DB::table('cart_items')
->join('ecomm_products', 'ecomm_products.id', '=', 'cart_items.product_id')
->join('ecomm_sellers' , 'ecomm_products.seller_id', '=', 'ecomm_sellers.id')
->where('cart_items.order_id', '=', 1)
->where('cart_items.user_id', '=', Auth::user()->id)
->select([
'ecomm_products.product_name',
'ecomm_products.showcase_image',
'ecomm_products.selling_price',
'cart_items.quantity',
'cart_items.id'
])
->get();
You can find examples for Laravel query builder joins here
These day, i have studied GraphQL with Laravel framework, Lighthouse Library.
I have tried to do kind of SELECT Query.
As a result, I wonder GraphQL can select below SQL Query
SELECT * FROM TABLE_A WHERE type=1 AND chart_id=(SELECT id FROM TABLE_B WHERE phone='0000~~')
I expect, Client first get result from this query.
SELECT id FROM TABLE_B WHERE phone='0000~~'
And then Do Second query, i think i can get a result.
But i wonder I can get result from 1 request. Thanks.
You can try following
$phoneNumber = '0000~~';
$data = DB::table('tableA')->where('type',1)
->whereIn('chart_id',function($query) use ($phoneNumber) {
$query->select('id')
->from('tableB')
->where('phone', '=',$phoneNumber);
})->get();
If there is relationship between tableA and tableB you can do following
TableA::where('type',1)
->whereHas('tableBRelationshipName', function ($q) use ($phoneNumber) {
$q->select('id')
$q->where('phone','=',$phoneNumber);
})->get();
I've been working on a few tables where through a rather complex relationship (that I'm trying to clean up, but I still need reports made from the data through my Laravel).
At the moment, I can pull the data using the following SQL query to my MySQL database:
SELECT
customers.id,
customers.customer_name,
SUM(shipments.balance) AS shipmentBalance
FROM customers
LEFT JOIN shipments
ON customers.id = shipments.bill_to
AND balance > (SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = pro_number)
GROUP BY customers.id, customers.customer_name
ORDER BY shipmentBalance DESC
LIMIT 5;
I'm just not sure how to rewrite it properly into the whereRaw or DB::raw statements that Laravel Eloquent requires, as my previous attempts have failed.
Update
Here is the closest solution I have tried:
DB::table('customers')
->select('customers', DB::raw('SUM(shipments.balance) AS shipmentBalance'))
->leftJoin(
DB::raw('
(select shipments
ON customers.id = shipments.bill_to
AND balance > (SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = pro_number)'))
->groupBy('customers.id')
->orderByRaw('shipmentBalance DESC')
->limit(5)
->get();
Update 2
Edit for Dom:
Using everything as it stands with your answer, I get the following response:
SQLSTATE[42S22]: Column not found: 1054 Unknown column '' in 'on clause' (SQL: select customers.id, customers.customer_name,SUM(s.balance) AS shipmentBalance from `customers` left join `shipments` as `s` on `customers`.`id` = `s`.`bill_to` and s.balance > (SELECT IFNULL(SUM(payments_distributions.amount),0) FROM payments_distributions WHERE payments_distributions.shipment_id = s.pro_number) = `` group by `customers`.`id`, `customers`.`customer_name` order by SUM(s.balance) DESC limit 5)
But if I remove this section, it brings up the page and the customers (though in the wrong order as I have removed one of the necessary components:
$join->on(DB::raw('s.balance >
(SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = s.pro_number)
'));
Is there anything I can provide you with to get this specific statement to work with your entire answer?
Use this:
DB::table('customers')
->select('customers.id', 'customers.customer_name', DB::raw('SUM(shipments.balance) AS shipmentBalance'))
->leftJoin('shipments', function($join) {
$join->on('customers.id', 'shipments.bill_to')
->where('balance', '>', function($query) {
$query->selectRaw('IFNULL(SUM(payments_distributions.amount),0)')
->from('payments_distributions')
->where('payments_distributions.shipment_id', DB::raw('pro_number'));
});
})
->groupBy('customers.id', 'customers.customer_name')
->orderByDesc('shipmentBalance')
->limit(5)
->get();
Without the Models containing relationships or being able to test on this specific project, this is the most eloquent way I can think of performing your task.
The benefit of starting with the Customer model is you will have a laravel collection and can paginate as needed. Also review the eloquent docs, they help you understand all the different options. Hope his helps.
P.S. Start by using your model in your controller or wherever you are placing this query with:
use App\Customer
The query
$theQuery = Customer::select(DB::raw('customers.id, customers.customer_name,SUM(s.balance) AS shipmentBalance'))
->leftJoin('shipments as s', function($join)
{
$join->on('customers.id', '=', 's.bill_to');
$join->on(DB::raw('s.balance >
(SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = s.pro_number)
'));
})
->groupBy('customers.id', 'customers.customer_name')
->orderByRaw('SUM(s.balance) DESC')
->limit(5)
->get();
I am using laravel 5.3 and I have some left join query with error in laravel query method.
This is my normal query
SELECT bran.branchName,sch.schoolName From m_schoolbranch bran
LEFT JOIN m_students stu ON stu.schoolNo=bran.schoolNo AND stu.branchNo=bran.branchNo
LEFT JOIN m_school sch ON sch.schoolNo=stu.schoolNo where stu.userNo='0000000001';
And this is my new laravel Query
DB::table('m_schoolbranch')
->join('m_students', 'm_schoolbranch.schoolNo', '=', 'm_students.schoolNo')
->join('m_students', 'm_schoolbranch.branchNo', '=', 'm_students.branchNo')
->join('m_school', 'm_schoolbranch.schoolNo', '=', 'm_school.schoolNo')
->select('m_school.schoolName', 'm_schoolbranch.branchName')
->where('m_students.userNo',$userNo)
->get();
In these query I need to match two column in table m_students so I put like this
->join('m_students', 'm_schoolbranch.branchNo', '=', 'm_students.branchNo')
But i show error...
Tables in the query need to have unique names, otherwise the DB has no way of knowing which m_schoolbranch should be used when evaluating m_schoolbranch.schoolNo.
You could use unique table aliases in your join statements but I recommend using multiple conditions on the join. Just like you use in your original SQL query. See here: https://stackoverflow.com/a/20732468/4437888
DB::table('m_schoolbranch')
->join('m_students', function($join)
{
$join->on('m_schoolbranch.schoolNo', '=', 'm_students.schoolNo');
$join->on('m_schoolbranch.branchNo', '=', 'm_students.branchNo');
})
->join('m_school', 'm_schoolbranch.schoolNo', '=', 'm_school.schoolNo')
->select('m_school.schoolName', 'm_schoolbranch.branchName')
->where('m_students.userNo',$userNo)
->get();
I have the following working for laravel paginate
$query = DB::table('clients')
->leftJoin('radusergroup', 'clients.username', '=', 'radusergroup.username')
->leftJoin('recharge', 'clients.username', '=', 'recharge.soldto');
I want to join some values from two tables radusergroup and recharge. radusergroup always return one row as it has only one row stored whereas recharge table return multiple rows. I want only one row returned from recharge table which is latest entry.
Right now its return all the possible rows from recharge table and showing it on paginated view.
This is Laravel Official documentation
DB::table('clinets')
->leftJoin('radusergroup', 'clients.username', '=', 'radusergroup.username')
->leftJoin('recharge', function ($leftJoin) {
$leftJoin->on('clients.username', '=', 'recharge.soldto')
->where('recharge.create_date', '=', DB::raw("(select max(`create_date`) from recharge)"));
})
->get();
this is the case if you have create_date column in your table, if you haven't got it I strongly recommend to create that column.