Convert SQL to Laravel Eloquent Statement - laravel

Question

I've been working on a few tables where through a rather complex relationship (that I'm trying to clean up, but I still need reports made from the data through my Laravel).
At the moment, I can pull the data using the following SQL query to my MySQL database:
SELECT
customers.id,
customers.customer_name,
SUM(shipments.balance) AS shipmentBalance
FROM customers
LEFT JOIN shipments
ON customers.id = shipments.bill_to
AND balance > (SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = pro_number)
GROUP BY customers.id, customers.customer_name
ORDER BY shipmentBalance DESC
LIMIT 5;
I'm just not sure how to rewrite it properly into the whereRaw or DB::raw statements that Laravel Eloquent requires, as my previous attempts have failed.
Update
Here is the closest solution I have tried:
DB::table('customers')
->select('customers', DB::raw('SUM(shipments.balance) AS shipmentBalance'))
->leftJoin(
DB::raw('
(select shipments
ON customers.id = shipments.bill_to
AND balance > (SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = pro_number)'))
->groupBy('customers.id')
->orderByRaw('shipmentBalance DESC')
->limit(5)
->get();
Update 2
Edit for Dom:
Using everything as it stands with your answer, I get the following response:
SQLSTATE[42S22]: Column not found: 1054 Unknown column '' in 'on clause' (SQL: select customers.id, customers.customer_name,SUM(s.balance) AS shipmentBalance from `customers` left join `shipments` as `s` on `customers`.`id` = `s`.`bill_to` and s.balance > (SELECT IFNULL(SUM(payments_distributions.amount),0) FROM payments_distributions WHERE payments_distributions.shipment_id = s.pro_number) = `` group by `customers`.`id`, `customers`.`customer_name` order by SUM(s.balance) DESC limit 5)
But if I remove this section, it brings up the page and the customers (though in the wrong order as I have removed one of the necessary components:
$join->on(DB::raw('s.balance >
(SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = s.pro_number)
'));
Is there anything I can provide you with to get this specific statement to work with your entire answer?

Answer 1

Use this:
DB::table('customers')
->select('customers.id', 'customers.customer_name', DB::raw('SUM(shipments.balance) AS shipmentBalance'))
->leftJoin('shipments', function($join) {
$join->on('customers.id', 'shipments.bill_to')
->where('balance', '>', function($query) {
$query->selectRaw('IFNULL(SUM(payments_distributions.amount),0)')
->from('payments_distributions')
->where('payments_distributions.shipment_id', DB::raw('pro_number'));
});
})
->groupBy('customers.id', 'customers.customer_name')
->orderByDesc('shipmentBalance')
->limit(5)
->get();

Answer 2

Without the Models containing relationships or being able to test on this specific project, this is the most eloquent way I can think of performing your task.
The benefit of starting with the Customer model is you will have a laravel collection and can paginate as needed. Also review the eloquent docs, they help you understand all the different options. Hope his helps.
P.S. Start by using your model in your controller or wherever you are placing this query with:
use App\Customer
The query
$theQuery = Customer::select(DB::raw('customers.id, customers.customer_name,SUM(s.balance) AS shipmentBalance'))
->leftJoin('shipments as s', function($join)
{
$join->on('customers.id', '=', 's.bill_to');
$join->on(DB::raw('s.balance >
(SELECT IFNULL(SUM(payments_distributions.amount),0)
FROM payments_distributions
WHERE payments_distributions.shipment_id = s.pro_number)
'));
})
->groupBy('customers.id', 'customers.customer_name')
->orderByRaw('SUM(s.balance) DESC')
->limit(5)
->get();