Errors in bash script. Syntax error near unexpected token - bash

Question

Do you know what is wrong with my script as I always get the error mesage:
position frac1 frac2
: command not found:
'/s1_met.sh: line 3: syntax error near unexpected token `do
'/s1_met.sh: line 3: `for lineF1 in $(cat $1); do
Code here:
export IFS=$'\n'
echo "position frac1 frac2";
for lineF1 in $(cat $1); do
if [ $(echo $lineF1 | cut -b 1-2) = "##" ]; then
echo "skip line" >&2;
else
startF1=$(echo $lineF1 | cut -f 4);
stopF1=$(echo $lineF1 | cut -f 5);
fracF1=$(echo $lineF1 | cut -f 9 | cut -d ";" -f 4 | cut -d "=" -f 2);
lineF2=$(grep "$startF1" $2);
if [ -z "$lineF2" ]; then
echo "position $startF1 cannot be found" >&2;
else
fracF2=$(echo $lineF2 | cut -f 9 | cut -d ";" -f 4 | cut -d "=" -f 2);
echo "$startF1 $fracF1 $fracF2";
fi;
fi
done;

Answer 1

There's nothing wrong with it, you must not be running it with BASH.
Edited to say you need to check your line endings, your comment below with the ^M means that you have extra characters on the line. See here.
https://stackoverflow.com/tags/bash/info
Try putting the "shebang" line in the script shebang docs
To do this, run which bash which will tell you something like /bin/bash. Your script should then be:
#!/bin/bash
echo "I'm running with bash!"
Try that, your syntax is OK.