Error while reading from a file in Unix - bash

Question

I am new to Unix and need help with a certain code.
My if condition acts weird.
Suppose my data is as follows -
name1 place1 date1
name2 place2 date2
name3 place3 date3
name4 place4 date4
name5 place5 date5
This is what I had originally done -
SRC_PATH="/app/Informatica9.5.1/server/infa_shared/0149icadd/SrcFiles"
rm -f temp_con_total
cat $SRC_PATH/Control_Total.txt > temp_con_total
echo $SRC_PATH
i=0
while read line
do
echo $line
if [[[ $i -ge 0 ]]];
then
file_name=`echo -e $line | cut -d ' ' -f 2`
file_size=`echo -e $line | cut -d ' ' -f 3`
file_size=$(( $file_size ))
actual_size=`cat $SRC_PATH/$file_name | wc -l`
actual_size=`echo -e $actual_size | cut -d ' ' -f 1`
actual_size=$(( $actual_size - 1 ))
echo $file_name
echo $file_size
echo $actual_size
fi
i=$(( i + 1 ))
done < temp_con_total
in this case, it gave me only first 2 records.
Later, I removed one set of brackets from if condition -
if [ $i -ge 0 ];
in this case, it gave me only the first row.
later i put three brackets, as follows -
if [[[ $i -ge 0 ]]];
now, it did give me all rows but after each row it also gave me error as follows:
name1 place1 date1
loop.sh[10]: [[[: not found [No such file or directory]
name2 place2 date2
loop.sh[10]: [[[: not found [No such file or directory]
name3 place3 date3
loop.sh[10]: [[[: not found [No such file or directory]
name4 place4 date4
loop.sh[10]: [[[: not found [No such file or directory]
name5 place5 date5
loop.sh[10]: [[[: not found [No such file or directory]
Can someone please help me with this? Why is this happening?
loop.sh is the name of my script
What I need as output is, all rows in the file as follows-
name1 place1 date1
name2 place2 date2
name3 place3 date3
name4 place4 date4
name5 place5 date5
I want to know why is there an error after it prints each row? loop.sh[10]: [[[: not found [No such file or directory]
And how does the number of brackets affect the code?

Answer 1

Bash does not use square brackets. Not as brackets anyway. It looks like it does, but it doesn't.
There is a command called [ (that's its name, an opening bracket) that is much the same as the test command. That command takes a series of command line parameters, just like any other command, and it expects that the last parameter will be a closing bracket, ], but no actual bracket processing is done. This is why you always follow the closing bracket with a semi-colon, ;, to finish the command. If you look in /bin (or /usr/bin?) you'll see that /bin/[ exists as a file.
Likewise, there's another command called [[ (again, that's its name, two opening brackets together). This is the same idea as the [ command, but has slightly different features. This one doesn't usually have a file in /bin.
Both commands are implemented as bash builtins, for efficiency in the case of [ and because [[ has to be, I think, but that doesn't affect the syntax.
There is no command named [[[, hence "No such file or directory".
As for your script, the if is completely pointless because you test if $i is greater than, or equal to zero when there's no way it can't be. I think this should do what you want:
SRC_PATH="/app/Informatica9.5.1/server/infa_shared/0149icadd/SrcFiles"
rm -f temp_con_total
cp $SRC_PATH/Control_Total.txt temp_con_total
echo $SRC_PATH
while read line
do
echo $line
file_name=`echo -e $line | cut -d ' ' -f 2`
file_size=`echo -e $line | cut -d ' ' -f 3`
actual_size=`cat $SRC_PATH/$file_name | wc -l | cut -d ' ' -f 1`
(( actual_size-- ))
echo $file_name
echo $file_size
echo $actual_size
done < temp_con_total