I have to start, stop a jar in a flow
1. I have to stop it if it is already running and then start
2. All this is being worked in Udeploy.
3. I'm installing the jar using the below command.
java -jar jarname.jar
When I use sc query servicename, it says the service is not installed as a Windows service. So, I can check, stop and start if it is only a windows service.
How can I install this as a windows service with a servicename to identify ?
You can use nssm to install a jar as a Windows service. No installation of nssm is needed. Just place it somewhere on the system (preferably somewhere in your PATH) and run it.
Here is the command to execute as a batch:
nssm.exe install "(service-name)" "{java.exe path from jre}" "-jar
{jar-name-absolute-path}"
nssm.exe set "{service-name}" AppDirectory "{jar-path}"
Related
I tried running the below command in administrator mode to install nginx as service
nssm install ztestservice "C:\Stack\nginx\nginx.exe"
nssm is installing the service but there is no reference to the application path in the registry. i.e. no parameters are set. When I try to start the service shows error "cant start service".
Please help.
I have been using nssm to run a php script. I find if you run just:
nssm install ztestservice
nssm will pop up a window that lets you set all the other parameters. Otherwise, you can set the parameters separately using the set command:
nssm set <servicename> <parameter> [<subparameter>] <value>
so:
nssm set ztestservice AppParameters "C:\Stack\nginx\nginx.exe"
However, watch out. On windows 2012r2 i'm experiencing an issue where it now hangs on the stop command so i'd watch out for that!
EDIT: You can also run nssm dump ztestservice' will also give you a list of the available parameters
EDIT2: (Will i ever stop editing this?)nssm edit ztestservice' to edit the service you just created, changing all params and having them set in the registry.
I'm trying to use the Non-Sucking Service Manager (NSSM) to create a service. Unfortunately, for whatever reason, NSSM won't play ball.
I'm trying to install the service using the following command:
nssm install "My Service" "C:\Program Files\Vendor\bin\windows\service-start.bat"
The service is successfully created. However, when I go to Services and Right-Click on "My Service" and view the properties the "Path to executable" field is set to the path of NSSM itself. In this case, 'C:\Program Files\nssm-2.24\win64\nssm.exe'.
I've attempted to change this using the following command:
nssm set "My Service" AppDirectory "C:\Program Files\Vendor\bin\windows\service-start.bat"
This doesn't make any difference and the executable path remains the same.
I'm trying to do this on Windows Server 2012 R2.
As CodeCaster mentioned, the 'Path to Executable' is correctly referring to nssm. Since nssm is a wrapper, you technically tell nssm to manage your service.
If you want to verify if your installed service actually refers to your service, you will need to check that in nssm instead. You can do so with below command:
nssm edit <servicename>
Here you can see what is configured for your service and you can do some extra configuration here as well.
I hope that clarifies things a bit.
NSSM is a wrapper which responds to SCM commands... which a batch file won't.
When registering the service, ...service-start.bat is configured as a commandline arguments to the NSSM executable.
I need to install Tomcat 7 as a Windows service and to start the service manually.
Referring to How to install Tomcat as a Windows service, I believe I would need to specify the following on the command line:
tomcat7 //IS//Tomcat7 --DisplayName="Apache Tomcat 7" --Install="C:\Tomcat7\bin\tomcat7.exe
Do I also need to specify all or some of the following on the command line like in the example? If only some, please specify which ones. If anything in the example is incorrect, please specify.
--Jvm=auto
--StartMode=jvm
--StopMode=jvm
--StartClass=org.apache.catalina.startup.Bootstrap
--StartParams=start
--StopClass=org.apache.catalina.startup.Bootstrap
--StopParams=stop
What I need for sure is to specify the following because I need to tell Tomcat to use a specific java home and not the java home set by the environment variable JAVA_HOME on the server where this will be installed.
--JavaHome="C:\Program Files\Java\jdk1.7.0_51
The reason: the server already has a different version of Tomcat (5.5) and it uses an older version of the JDK (1.5). I must not change JAVA_HOME on the server. I simply need to ensure Tomcat 7 uses JDK 1.7 and I have tried this line:
C:\tomcat7\bin>tomcat7 //IS//Tomcat7 --DisplayName="Apache Tomcat 7" --Install="C:\Tomcat7\bin\tomcat7.exe" --JavaHome="C:\Program Files\Java\jdk1.7.0_51"
When I attempt to Start the service, the following error message is displayed:
Windows could not start the Apache Tomcat 7 on Local Computer. For
more information, review the System Event Log. If this is a
non-Microsoft service, contact the service vendor, and refer to
service-specific error code 1.
I had a look at the System Event Viewer and it provides the following information:
The Apache Tomcat 7 service terminated with service-specific error Incorrect function..
I need to figure out these steps because I then need to provide the support team with the information to install this service on the production server. So any help would be greatly appreciated!
Use Chocolatey from Powershell command line:
first install Chocolatey
PS:\> iex ((new-object net.webclient).DownloadString('https://chocolatey.org/install.ps1'))
To install Tomcat
PS:\> choco install tomcat
To upgrade
PS:\> choco upgrade tomcat
Seems like a mismatch in your java JVM and tomcat version.
The tomcat7.exe wrapper program actually
"runs" the JVM, it must match the type of JVM that it runs, in terms
of 32bit/64bit version. If you try to start a 64-bit JVM with a 32-bit
tomcat7.exe, it won't work, and vice-versa.
Reference
This is because of shortage in physical RAM.
Check the Minimum System Requirements on Tomcat docs and try to close unnecessary programs if possible.
Use Chocolatey from Powershell command line:
PS> iex ((new-object net.webclient).DownloadString('https://chocolatey.org/install.ps1'))
To install Tomcat:
PS> choco install tomcat
To upgrade:
PS> choco upgrade tomcat
I have googled this extensively before posting it here. I've been trying to find out a way to enable JMX Access on a Tomcat instance installed as Windows service. Its quite straightforward when Tomcat is invoked via the startup.bat script, one just needs to set the CATALINA_OPTS environment variable to something like "-Dcom.sun.management.jmxremote.port=1234 -Dcom.sun.management.jmxremote.authenticate=false -Dcom.sun.management.jmxremote.ssl=false"
But how do i get the Tomcat Windows service to read these options? I tried this:
C:>tomcat\server\bin> service.bat install #install the Tomcat7 windows service
C:>tomcat\server\bin> tomcat7.exe //US//Tomcat7 ++JvmOptions "-Djava.io.tmpdir=$INSTDIR\server\temp;-XX:MaxPermSize
=256m;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.au
thenticate=false;-Dcom.sun.management.jmxremote.ssl=false" --JvmMs 256 --JvmMx 1
024 #update the installed service using the //US switch; set tmpdir, JMX access and heap size
When i start the service from Services panel, the service fails to start and i get the following error on the logs\tomcat7-stderr-yyyy-mm-dd.log file:
yyyy-mm-dd hh:mm:ss Commons Daemon procrun stderr initialized
Error: Invalid com.sun.management.jmxremote.port number: 8090 -Dcom.sun.management.jmxremote.authenticate=false -Dcom.sun.management.jmxremote.ssl=false
I don't have a Java background, am i trying to achieve something outlandish here? Please advise.
Answering my own question; turned out to be easier than i thought.
Following needs to be done, for enabling JMX access for Tomcat installed as a Windows service, that has a name "ApacheTomcatWindowsServer" for example:
Install Tomcat as Windows service, either using the command (first cd into \bin\ )
service.bat install
or your custom scripts.
Enable Apache Service Manager for the installed service using the following command:
tomcat7w.exe //MS//ApacheTomcatWindowsServer
This should start Apache Service Monitor program on your system tray. Click on its icon. select 'Configure', click on the 'Java' tab and append the following on the 'Java Options' text box, one option per line:
-Dcom.sun.management.jmxremote.port=8090
-Dcom.sun.management.jmxremote.authenticate=false
-Dcom.sun.management.jmxremote.ssl=false
Save and exit and restart the service.
To connect to the JMX console, fire jconsole from your JDK installation, click 'New Connection', specify 'Remote Process' and enter hostname:8090.
you can also uninstall the service by
service.bat remove
then edit the service.bat and add the parameters in your StartPath and add the options
-Djavax.management.builder.initial=;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.authenticate=false;-Dcom.sun.management.jmxremote.ssl=false
here is the sample StartPath in my file
--StartPath "C:\tomcat7\" --Startup auto --JvmOptions "-Dcatalina.home=%CATALINA_HOME%;-Dcatalina.base=%CATALINA_BASE%;-Djava.endorsed.dirs=%CATALINA_HOME%\endorsed;-Djava.io.tmpdir=%CATALINA_BASE%\temp;-Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager;-Djava.util.logging.config.file=%CATALINA_BASE%\conf\logging.properties;-Djava.rmi.server.hostname=;-Djavax.management.builder.initial=;-Dcom.sun.management.jmxremote.port=8090;-Dcom.sun.management.jmxremote.authenticate=false;-Dcom.sun.management.jmxremote.ssl=false" %JAVA_OPTS% ^
re-install the service by
service.bat install
then start Tomcat to apply changes
i have installed mongodb on win32 and i am trying to run it as a service.
I have followed the instructions posted here: http://www.deltasdevelopers.com/post/Running-MongoDB-as-a-Windows-Service.aspx
but when when windows tries to 'load'/'run' the service there is a problem. I see the service under the services control banner constantly in the 'starting' state.
The result: the service is not started and windows is constantly trying to start it without success.
The instructions i have followed are:
At the command line
C:\mongodb\mongod -install
then
C:\mongodb\mongod -service
Then i modified the Win Registry Entry for the MongoDB Service by setting the ImagePath key to the value of C:\mongodb\mongodb.exe -service
Any advice? What am i doing wrong?
Just for future reference: running mongo as a windows service
Also lots of people seem to be saying: specify the whole path to the mongod.exe:
c:\mongo\mongod.exe --logpath "c:\mongo\logs\mongo.log" --logappend --dbpath "c:\mongo\data" --directoryperdb --install
Also if you're running Windows 7 don't forget to run the command window as an administrator.
I'd do it this way just cause I like to customize/organize things better:
Unzip mongo to where you want.
I like putting all the configuration in a file (my preference, since I didnt like default location of C:/data/db, and didn't like all the options as commandline params)...
Looks something like:
[C:\dev\mongodb\data\mongodb.conf]
dbpath = C:\dev\mongodb\data\db
logpath = C:\dev\mongodb\data\mongodb.log.txt
logappend = false
Then I put C:\dev\mongodb\bin in my Env Variable's PATH (so can call mongo.exe from any dir), but not needed...
Then on command line to install the Windows Service:
$ cd C:\dev\mongodb\bin
$ mongod.exe -f C:\dev\mongodb\data\mongodb.conf --install
It will create a Windows Service which if you want, can start manually via:
$ net start MongoDB
//Use qoutes if changed service name (via -serviceName to mongod --install), like: net start "Mongo DB"
Specifying several parameters at once is a good choice.
mongod
--install
to install as a service
--rest
to enable rest access to mongodb
–master
to set up mongodb instance as master.
–logpath
this is mandatory when you install mongodb as service
--dbpath
this too is mandatory for mongodb to run.
Here is a step by step guide describing the installation of MongoDB Service on Windows 7.
I have been faced similar issue. And i tried above solutions still have not get any result.
finally below code is solved my issue.
-> Command prompt open as administrator.
-> Copy and paste the below code after changing the proper bin and config path.
sc.exe create MongoDB binPath= "\"d:\MongoDB\bin\mongod.exe\" --service --config=\"d:\MongoDB\mongo.cfg\"" DisplayName= "MongoDB" start= "auto"
Happy Coding !!!!!!
Regardless of whether you're running as a service or not, you need to specify the --dbpath argument to mongod.exe.
Also, you shouldn't have to edit the registry. You can just issue the command like this:
C:\mongodb\mongod.exe --dbpath C:\data\db --install