Is there a way to loop variables from another file into my bash script? - bash

Sorry to be a pain, but I'm not sure how I can loop values from an outside file, into my bash script as variables. I have three variable names in my bash script:
$TAGBEGIN
$TAGEND
$MYCODE
In a separate varSrc.txt file, I have several variables:
# a - Some marker
tagBegin_a='/<!-- Begin A -->/'
tagEnd_a='/<!-- End A -->/'
code_a=' [ some code to replace in between tags ] '
# b - Some marker
tagBegin_b='/<!-- Begin B -->/'
tagEnd_b='/<!-- End B -->/'
code_b=' [ some code to replace in between tags ] '
# c - Some marker
...
I need my bash script to be able to loop through each "# marker"* section and perform a function:
source varSrc.txt
$TAGBEGIN
$TAGEND
$MYCODE
...
sed '
'"$TAGEND"' R '"$MYCODE"'
'"$TAGBEGIN"','"$TAGEND"' d
' -i $TARGETDIR
Note: sed code logic (not quoting mess) courtesy of Glenn J.
I need some kind of looping logic like:
for (var i = 0; i <= markers in varSrc.txt ; i++) {
// set bash vars equal to varSrc values
$TAGBEGIN= $tagBegin_i
$TAGEND= $tagEnd_i
$MYCODE= $code_i
// run the 'sed' replace command
sed '
'"$TAGEND"' R '"$MYCODE"'
'"$TAGBEGIN"','"$TAGEND"' d
' -i $TARGETDIR
}
Is this something that can be feasibly done in a bash script and is this a good approach? Any suggestions, pointers or guidance is very, very appreciated!
*(which I don't think is a real marker I can use)

[Answering the question as amended]
There's no need use use, iterate over, or think about markers at all. Leave them out.
source varSrc.txt
for beginVar in "${!tagBegin_#}"; do # Iterate over defined begin variable names
endVar=tagEnd_${var#tagBegin_} # Generate the name of the end variable
codeVar=code_${var#tagBegin_} # Generate the name of the code variable
begin=${!beginVar} # Look up the contents of the begin variable
end=${!endVar} # Look up the contents of the end variable
code=${!codeVar} # Look up the contents of the code variable
sed -e "$end R $code" -e "$begin,$end d" -i "$file"
done

[Answers original, pre-amended question]
source only works if your input file is valid bash syntax; it isn't. Thus, you'll need to parse it yourself, something like the following:
begin= end= code=
while IFS= read -r; do
case $REPLY in
#*)
# we saw a marker; process all vars seen so far
[[ $begin && $end && $code ]] || continue # do nothing if we have no vars seen
sed -e "$end R $code" -e "$begin,$end d" -i "$file"
;;
'$TAGBEGIN='*) begin=${REPLY#'$TAGBEGIN='} ;;
'$TAGEND='*) end=${REPLY#'$TAGEND='} ;;
'$MYCODE='*) code=${REPLY#'$MYCODE='} ;;
esac
done <varSrc.txt

What you can do is export your variables in your second file an the execute the script within your current environment (with a dot before the script) to get the variable names/markers you can parse the file and search for an $ or #

Related

how to assign each of multiple lines in a file as different variable?

this is probably a very simple question. I looked at other answers but couldn't come up with a solution. I have a 365 line date file. file as below,
01-01-2000
02-01-2000
I need to read this file line by line and assign each day to a separate variable. like this,
d001=01-01-2000
d002=02-01-2000
I tried while read commands but couldn't get them to work.It takes a lot of time to shoot one by one. How can I do it quickly?
Trying to create named variable out of an associative array, is time waste and not supported de-facto. Better use this, using an associative array:
#!/bin/bash
declare -A array
while read -r line; do
printf -v key 'd%03d' $((++c))
array[$key]=$line
done < file
Output
for i in "${!array[#]}"; do echo "key=$i value=${array[$i]}"; done
key=d001 value=01-01-2000
key=d002 value=02-01-2000
Assumptions:
an array is acceptable
array index should start with 1
Sample input:
$ cat sample.dat
01-01-2000
02-01-2000
03-01-2000
04-01-2000
05-01-2000
One bash/mapfile option:
unset d # make sure variable is not currently in use
mapfile -t -O1 d < sample.dat # load each line from file into separate array location
This generates:
$ typeset -p d
declare -a d=([1]="01-01-2000" [2]="02-01-2000" [3]="03-01-2000" [4]="04-01-2000" [5]="05-01-2000")
$ for i in "${!d[#]}"; do echo "d[$i] = ${d[i]}"; done
d[1] = 01-01-2000
d[2] = 02-01-2000
d[3] = 03-01-2000
d[4] = 04-01-2000
d[5] = 05-01-2000
In OP's code, references to $d001 now become ${d[1]}.
A quick one-liner would be:
eval $(awk 'BEGIN{cnt=0}{printf "d%3.3d=\"%s\"\n",cnt,$0; cnt++}' your_file)
eval makes the shell variables known inside your script or shell. Use echo $d000 to show the first one of the newly defined variables. There should be no shell special characters (like * and $) inside your_file. Remove eval $() to see the result of the awk command. The \" quoted %s is to allow spaces in the variable values. If you don't have any spaces in your_file you can remove the \" before and after %s.

How to iterate over multiple variables and echo them using Shell Script?

Consider the below variables which are dynamic and might change each time. Sometimes there might even be 5 variables, But the length of all the variables will be the same every time.
var1='a b c d e... upto z'
var2='1 2 3 4 5... upto 26'
var3='I II III IV V... upto XXVI'
I am looking for a generalized approach to iterate the variables in a for loop & My desired output should be like below.
a,1,I
b,2,II
c,3,III
d,4,IV
e,5,V
.
.
goes on upto
z,26,XXVI
If I use nested loops, then I get all possible combinations which is not the expected outcome.
Also, I know how to make this work for 2 variables using for loop and shift using below link
https://unix.stackexchange.com/questions/390283/how-to-iterate-two-variables-in-a-sh-script
With paste
paste -d , <(tr ' ' '\n' <<<"$var1") <(tr ' ' '\n' <<<"$var2") <(tr ' ' '\n' <<<"$var3")
a,1,I
b,2,II
c,3,III
d,4,IV
e...z,5...26,V...XXVI
But clearly having to add other parameter substitutions for more varN's is not scalable.
You need to "zip" two variables at a time.
var1='a b c d e...z'
var2='1 2 3 4 5...26'
var3='I II III IV V...XXVI'
zip_var1_var2 () {
set $var1
for v2 in $var2; do
echo "$1,$v2"
shift
done
}
zip_var12_var3 () {
set $(zip_var1_var2)
for v3 in $var3; do
echo "$1,$v3"
shift
done
}
for x in $(zip_var12_var3); do
echo "$x"
done
If you are willing to use eval and are sure it is safe to do so, you can write a single function like
zip () {
if [ $# -eq 1 ]; then
eval echo \$$1
return
fi
a1=$1
shift
x=$*
set $(eval echo \$$a1)
for v in $(zip $x); do
printf '=== %s\n' "$1,$v" >&2
echo "$1,$v"
shift
done
}
zip var1 var2 var3 # Note the arguments are the *names* of the variables to zip
If you can use arrays, then (for example, in bash)
var1=(a b c d e)
var2=(1 2 3 4 5)
var3=(I II III IV V)
for i in "${!var1[#]}"; do
printf '%s,%s,%s\n' "${var1[i]}" "${var2[i]}" "${var3[i]}"
done
Use this Perl one-liner:
perl -le '#in = map { [split] } #ARGV; for $i ( 0..$#{ $in[0] } ) { print join ",", map { $in[$_][$i] } 0..$#in; }' "$var1" "$var2" "$var3"
Prints:
a,1,I
b,2,II
c,3,III
d,4,IV
e,5,V
z,26,XXVI
The Perl one-liner uses these command line flags:
-e : Tells Perl to look for code in-line, instead of in a file.
-l : Strip the input line separator ("\n" on *NIX by default) before executing the code in-line, and append it when printing.
The input variables must be quoted with double quotes "like so", to keep the blank-separated words from being treated as separate arguments.
#ARGV is an array of the command line arguments, here $var1, $var2, $var3.
#in is an array of 3 elements, each element being a reference to an array obtained as a result of splitting the corresponding element of #ARGV on whitespace. Note that split splits the string on whitespace by default, but you can specify a different delimiter, it accepts regexes.
The subsequent for loop prints #in elements separated by comma.
SEE ALSO:
perldoc perlrun: how to execute the Perl interpreter: command line switches
perldoc perlvar: Perl predefined variables
The following is (almost) a copy of this answer with a few tweaks that make it fit this question.
The Original Question
First let’s assign a few variables to play with, 26 tokens in each of them:
var1="$(echo {a..z})"
var2="$(echo {1..26})"
var3="$(echo I II III IV \
V{,I,II,III} IX \
X{,I,II,III} XIV \
XV{,I,II,III} XIX \
XX{,I,II,III} XXIV \
XXV XXVI)"
var4="$(echo {A..Z})"
var5="$(echo {010101..262626..10101})"
Now we want a “magic” function that zips an arbitrary number of variables, ideally in pure Bash:
zip_vars var1 # a trivial test
zip_vars var{1..2} # a slightly less trivial test
zip_vars var{1..3} # the original question
zip_vars var{1..4} # more vars, becasuse we can
zip_vars var{1..5} # more vars, because why not
What could zip_vars look like? Here’s one in pure Bash, without any external commands:
zip_vars() {
local var
for var in "$#"; do
local -a "array_${var}"
local -n array_ref="array_${var}"
array_ref=(${!var})
local -ar "array_${var}"
done
local -n array_ref="array_${1}"
local -ir size="${#array_ref[#]}"
local -i i
local output
for ((i = 0; i < size; ++i)); do
output=
for var in "$#"; do
local -n array_ref="array_${var}"
output+=",${array_ref[i]}"
done
printf '%s\n' "${output:1}"
done
}
How it works:
It splits all variables (passed by reference (by variable name)) into arrays. For each variable varX it creates a local array array_varX.
It would be actually way easier if the input variables were already Bash arrays to start with (see below), but … we stick with the original question initially.
It determines the size of the first array and then blindly expects all arrays to be of that size.
For each index i from 0 to size - 1 it concatenates the ith elements of all arrays, separated by ,.
Arrays Make Things Easier
If you use Bash arrays from the very start, the script will be shorter and look simpler and there won’t be any string-to-array conversions.
zip_arrays() {
local -n array_ref="$1"
local -ir size="${#array_ref[#]}"
local -i i
local output
for ((i = 0; i < size; ++i)); do
output=
for arr in "$#"; do
local -n array_ref="$arr"
output+=",${array_ref[i]}"
done
printf '%s\n' "${output:1}"
done
}
arr1=({a..z})
arr2=({1..26})
arr3=( I II III IV
V{,I,II,III} IX
X{,I,II,III} XIV
XV{,I,II,III} XIX
XX{,I,II,III} XXIV
XXV
XXVI)
arr4=({A..Z})
arr5=({010101..262626..10101})
zip_arrays arr1 # a trivial test
zip_arrays arr{1..2} # a slightly less trivial test
zip_arrays arr{1..3} # (almost) the original question
zip_arrays arr{1..4} # more arrays, becasuse we can
zip_arrays arr{1..5} # more arrays, because why not

Changing words in text files using multiple dictionaries

I have a bunch of files which need to be translated using custom dictionaries. Each file contains a line indicating which dictionary to use. Here's an example:
*A:
!
=1
*>A_intro
1r
=2
1r
=3
1r
=4
1r
=5
2A:maj
*-
In the file above, *A: indicates to use dictA.
I can translate this part easily using the following syntax:
sed -f dictA < myfile
My problem is that some files require a change of dictionary half way in the text. For example:
*B:
1B:maj
2E:maj/5
2B:maj
2E:maj/5
*C:
2F:maj/5
2C:maj
2F:maj/5
2C:maj
*-
I would like to write a script to automate the translation process. Using this example, I would like the script to read the first line, select dictB, use dictB to translate each line until it reads *C:, select dictC, and then keep going.
Thanks #Cyrus. That was useful. Here's what I ended up doing.
#!/bin/sh
key="sedDictNull.txt"
while read -r line || [ -n "$line" ] ## Makes sure that the last line is read. See http://stackoverflow.com/questions/12916352/shell-script-read-missing-last-line
do
if [[ $line =~ ^\*[Aa]:$ ]]
then
key="sedDictA.txt"
elif [[ $line =~ ^\*[Aa]#:$ ]]
then
key="sedDictA#.txt"
fi
echo "$line" | sed -f $key
done < $1
I assume your "dictionaries" are really sed scripts that search and replace, like this:
s/2C/nothing/;
s/2B/something/;
You could reorganize these scripts into sections, like this:
/^\*B:/, /^\*[^B]/ {
s/1B/whatever/;
s/2B/something/;
}
/^\*C:/, /^\*[^C]/ {
s/2C/nothing/;
s/2B/something/;
}
And, of course, you could do that on the fly:
for dict in B C
do echo "/^\\*$dict:/, /^\\*[^$dict]/ {"
cat dict.$dict
echo "}"
done | sed -f- dict.in

bash script to modify and extract information

I am creating a bash script to modify and summarize information with grep and sed. But it gets stuck.
#!/bin/bash
# This script extracts some basic information
# from text files and prints it to screen.
#
# Usage: ./myscript.sh </path/to/text-file>
#Extract lines starting with ">#HWI"
ONLY=`grep -v ^\>#HWI`
#replaces A and G with R in lines
ONLYR=`sed -e s/A/R/g -e s/G/R/g $ONLY`
grep R $ONLYR | wc -l
The correct way to write a shell script to do what you seem to be trying to do is:
awk '
!/^>#HWI/ {
gsub(/[AG]/,"R")
if (/R/) {
++cnt
}
END { print cnt+0 }
' "$#"
Just put that in the file myscript.sh and execute it as you do today.
To be clear - the bulk of the above code is an awk script, the shell script part is the first and last lines where the shell just calls awk and passes it the input file names.
If you WANT to have intermediate variables then you can create/print them with:
awk '
!/^>#HWI/ {
only = $0
onlyR = only
gsub(/[AG]/,"R",onlyR)
print "only:", only
print "onlyR:", onlyR
if (/R/) {
++cnt
}
END { print cnt+0 }
' "$#"
The above will work robustly, portably, and efficiently on all UNIX systems.
First of all, and as #fedorqui commented - you're not providing grep with a source of input, against which it will perform line matching.
Second, there are some problems in your script, which will result in unwanted behavior in the future, when you decide to manipulate some data:
Store matching lines in an array, or a file from which you'll later read values. The variable ONLY is not the right data structure for the task.
By convention, environment variables (PATH, EDITOR, SHELL, ...) and internal shell variables (BASH_VERSION, RANDOM, ...) are fully capitalized. All other variable names should be lowercase. Since
variable names are case-sensitive, this convention avoids accidentally overriding environmental and internal variables.
Here's a better version of your script, considering these points, but with an open question regarding what you were trying to do in the last line : grep R $ONLYR | wc -l :
#!/bin/bash
# This script extracts some basic information
# from text files and prints it to screen.
#
# Usage: ./myscript.sh </path/to/text-file>
input_file=$1
# Read lines not matching the provided regex, from $input_file
mapfile -t only < <(grep -v '^\>#HWI' "$input_file")
#replaces A and G with R in lines
for((i=0;i<${#only[#]};i++)); do
only[i]="${only[i]//[AG]/R}"
done
# DEBUG
printf '%s\n' "Here are the lines, after relpace:"
printf '%s\n' "${only[#]}"
# I'm not sure what you were trying to do here. Am I gueesing right that you wanted
# to count the number of R's in ALL lines ?
# grep R $ONLYR | wc -l

Capturing multiple line output into a Bash variable

I've got a script 'myscript' that outputs the following:
abc
def
ghi
in another script, I call:
declare RESULT=$(./myscript)
and $RESULT gets the value
abc def ghi
Is there a way to store the result either with the newlines, or with '\n' character so I can output it with 'echo -e'?
Actually, RESULT contains what you want — to demonstrate:
echo "$RESULT"
What you show is what you get from:
echo $RESULT
As noted in the comments, the difference is that (1) the double-quoted version of the variable (echo "$RESULT") preserves internal spacing of the value exactly as it is represented in the variable — newlines, tabs, multiple blanks and all — whereas (2) the unquoted version (echo $RESULT) replaces each sequence of one or more blanks, tabs and newlines with a single space. Thus (1) preserves the shape of the input variable, whereas (2) creates a potentially very long single line of output with 'words' separated by single spaces (where a 'word' is a sequence of non-whitespace characters; there needn't be any alphanumerics in any of the words).
Another pitfall with this is that command substitution — $() — strips trailing newlines. Probably not always important, but if you really want to preserve exactly what was output, you'll have to use another line and some quoting:
RESULTX="$(./myscript; echo x)"
RESULT="${RESULTX%x}"
This is especially important if you want to handle all possible filenames (to avoid undefined behavior like operating on the wrong file).
In case that you're interested in specific lines, use a result-array:
declare RESULT=($(./myscript)) # (..) = array
echo "First line: ${RESULT[0]}"
echo "Second line: ${RESULT[1]}"
echo "N-th line: ${RESULT[N]}"
In addition to the answer given by #l0b0 I just had the situation where I needed to both keep any trailing newlines output by the script and check the script's return code.
And the problem with l0b0's answer is that the 'echo x' was resetting $? back to zero... so I managed to come up with this very cunning solution:
RESULTX="$(./myscript; echo x$?)"
RETURNCODE=${RESULTX##*x}
RESULT="${RESULTX%x*}"
Parsing multiple output
Introduction
So your myscript output 3 lines, could look like:
myscript() { echo $'abc\ndef\nghi'; }
or
myscript() { local i; for i in abc def ghi ;do echo $i; done ;}
Ok this is a function, not a script (no need of path ./), but output is same
myscript
abc
def
ghi
Considering result code
To check for result code, test function will become:
myscript() { local i;for i in abc def ghi ;do echo $i;done;return $((RANDOM%128));}
1. Storing multiple output in one single variable, showing newlines
Your operation is correct:
RESULT=$(myscript)
About result code, you could add:
RCODE=$?
even in same line:
RESULT=$(myscript) RCODE=$?
Then
echo $RESULT $RCODE
abc def ghi 66
echo "$RESULT"
abc
def
ghi
echo ${RESULT#Q}
$'abc\ndef\nghi'
printf '%q\n' "$RESULT"
$'abc\ndef\nghi'
but for showing variable definition, use declare -p:
declare -p RESULT RCODE
declare -- RESULT="abc
def
ghi"
declare -- RCODE="66"
2. Parsing multiple output in array, using mapfile
Storing answer into myvar variable:
mapfile -t myvar < <(myscript)
echo ${myvar[2]}
ghi
Showing $myvar:
declare -p myvar
declare -a myvar=([0]="abc" [1]="def" [2]="ghi")
Considering result code
In case you have to check for result code, you could:
RESULT=$(myscript) RCODE=$?
mapfile -t myvar <<<"$RESULT"
declare -p myvar RCODE
declare -a myvar=([0]="abc" [1]="def" [2]="ghi")
declare -- RCODE="40"
3. Parsing multiple output by consecutives read in command group
{ read firstline; read secondline; read thirdline;} < <(myscript)
echo $secondline
def
Showing variables:
declare -p firstline secondline thirdline
declare -- firstline="abc"
declare -- secondline="def"
declare -- thirdline="ghi"
I often use:
{ read foo;read foo total use free foo ;} < <(df -k /)
Then
declare -p use free total
declare -- use="843476"
declare -- free="582128"
declare -- total="1515376"
Considering result code
Same prepended step:
RESULT=$(myscript) RCODE=$?
{ read firstline; read secondline; read thirdline;} <<<"$RESULT"
declare -p firstline secondline thirdline RCODE
declare -- firstline="abc"
declare -- secondline="def"
declare -- thirdline="ghi"
declare -- RCODE="50"
After trying most of the solutions here, the easiest thing I found was the obvious - using a temp file. I'm not sure what you want to do with your multiple line output, but you can then deal with it line by line using read. About the only thing you can't really do is easily stick it all in the same variable, but for most practical purposes this is way easier to deal with.
./myscript.sh > /tmp/foo
while read line ; do
echo 'whatever you want to do with $line'
done < /tmp/foo
Quick hack to make it do the requested action:
result=""
./myscript.sh > /tmp/foo
while read line ; do
result="$result$line\n"
done < /tmp/foo
echo -e $result
Note this adds an extra line. If you work on it you can code around it, I'm just too lazy.
EDIT: While this case works perfectly well, people reading this should be aware that you can easily squash your stdin inside the while loop, thus giving you a script that will run one line, clear stdin, and exit. Like ssh will do that I think? I just saw it recently, other code examples here: https://unix.stackexchange.com/questions/24260/reading-lines-from-a-file-with-bash-for-vs-while
One more time! This time with a different filehandle (stdin, stdout, stderr are 0-2, so we can use &3 or higher in bash).
result=""
./test>/tmp/foo
while read line <&3; do
result="$result$line\n"
done 3</tmp/foo
echo -e $result
you can also use mktemp, but this is just a quick code example. Usage for mktemp looks like:
filenamevar=`mktemp /tmp/tempXXXXXX`
./test > $filenamevar
Then use $filenamevar like you would the actual name of a file. Probably doesn't need to be explained here but someone complained in the comments.
How about this, it will read each line to a variable and that can be used subsequently !
say myscript output is redirected to a file called myscript_output
awk '{while ( (getline var < "myscript_output") >0){print var;} close ("myscript_output");}'

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